In the chapter on psychoactive drugs within this week's module, a table shows various
psychoactive drugs and the neurotransmitters that those drugs effect. Which of the following
neurotransmitters is effected by marijuana?
Serotonin
Blood
Acetylcholine
GABA

Answer:

F₁ = 499.61 N , this is the force that Bubba support

Explanation:

The trunk is in equilibrium with the two forces applied by man, let's use the equilibrium relation

let's set a reference frame at the extreme left and assume that the counterclockwise rotations are positive

Let's write the expression for the translational equilibrium

subscript 1 is for Bubba's mass and subscript 2 for his partner

               F₁ + F₂ -W = 0

                F₁ + F₂ = W

the expression for rotational equilibrium

               ∑ τ = 0

               F₁  2.2 + F₂  (6.2-0.9) - W  6.2/2 = 0

               2.2 F1 + 5.3 F2 = 3.1 W

let's write our system of equations

             F₁ + F₂ = W

             2.2 F₁ + 5.3 F₂ = 3.1 W

we solve for F₁ in the first equation and substitute in the second

            F₁ = W-F₂

            2.2 (W- F₂) + 5.3 F₂ = 3.1 W

            F₂ ( -2.2 +5.3) = W (3.1 - 2.2)

            F₂ = 704  0.9 / 3.1            

            F₂ = 204.39 N

This is the force that the partner supports

we look for F1

            F₁ = W-F₂

            F₁ = 704 - 204.39

             F₁ = 499.61 N

This is the force that Bubba support

Answer:

No

Explanation:

because there is no pressure

Answer:

A step down transformer is a device that can be connected to the switch and the appliance. There are two types of transformers that you should know about: step up and step down transformers. Step up transformers generally produce a higher output voltage than the input voltage.

Explanation:

Answer:

A: An object has potential energy (stored energy) when it is not in motion. Once a force has been applied or it begins to move the potential energy changes to kinetic energy (energy of motion).

Explanation:

Answer:

A stormy ocean, having the most kinetic energy means it moves more and faster

Track and field is an individual sport. This statement is True.

Track and field is a sport which includes jumping, running, and throwing. it is also know as track and field athletics, or track. This sport is organized in a stadium in which there are running tracks, set up for high jump and long jump and field for throwing. Hence the name is track and field. In this sport different participant participate to get one winner from each game from each weight group. The International Association of Athletics Federations(IAAF) is the international governing body for track and field.

The two most prestigious international track and field competitions are the athletics competition at the Olympic Games and the World Athletics Championships. World Athletics, formerly known as the International Association of Athletics Federations (IAAF),

Hence Track and field is an individual sport.

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Answer:

Total energy, T= 4704 Joules

Explanation:

Given the following data;

Mass = 8kg

Initial height, h1 = 100m

Final height, h2 = 40 m

We know that acceleration due to gravity is equal to 9.8 m/s².

To find the total energy, T;

T = mg(h1 - h2)

T = 8 * 9.8 * (100 - 40)

T = 78.4 * 60

Total energy, T= 4704 Joules

Explanation:

George Washington (1789–1797)

John Adams (1797–1801)

Thomas Jefferson (1801–1809)

James Madison (1809–1817)

James Monroe (1817–1825)

John Quincy Adams (1825–1829)

Andrew Jackson (1829–1837)

Martin Van Buren (1837–1841)

William Henry Harrison (1841)

John Tyler (1841–1845)

James K. Polk (1845–1849)

Zachary Taylor (1849–1850)

Millard Fillmore (1850–1853)

Franklin Pierce (1853–1857)

James Buchanan (1857–1861)

Abraham Lincoln (1861–1865)

.

George Washington, the 1st President of the United States

  John Adams, the 2nd President of the United States

 Thomas Jefferson, the 3rd President of the United States

 James Madison, the 4th President of the United States

James Monroe, the 5th President of the United States

John Quincy Adams, the 6th President of the United States

Andrew Jackson, the 7th President of the United States

Martin Van Buren, the 8th President of the United States

William Henry Harrison, the 9th President of the United States

John Tyler, the 10th President of the United States

James K. Polk, the 11th President of the United States

Zachary Taylor  THE 12TH PRESIDENT OF THE UNITED STATES

 Millard Fillmore, the 13th President of the United States

Franklin Pierce, the 14th President of the United States

James Buchanan, the 15th President of the United States

 Abraham Lincoln, the 16th President of the United States

Answer:

v = 4.233  m/s

Explanation:

By applying the rate of boiling from [tex]Q= mL_v[/tex];

the rate of the boiling can be described as:

[tex]\mathcal{P} = \dfrac{Q}{\Delta t} \\ \\ \mathcal{P} = \dfrac{mL_v}{\Delta t}[/tex]

The mode of the steam (water vapor) as an ideal gas can be illustrated by formula:

[tex]P_oV_o = nRT[/tex] --- (1)

where;

n = number of moles;

[tex]n = \dfrac{mass (m)}{Molar mass (M)}[/tex]

Then; equation (1) can be rewritten as:

[tex]P_oV_o = (\dfrac{m}{M}) RT \\ \\ \dfrac{P_oV}{\Delta T} = \dfrac{m}{\Delta t} ( \dfrac{RT}{M})[/tex]

∴

[tex]\dfrac{m}{\Delta t} = \dfrac{\mathcal{P}}{L_v}[/tex]

Then:

[tex]P_o \times A \times v= \dfrac{\mathcal{P}}{L_v}\Big ( \dfrac{RT}{M }\Big)[/tex]

making (v) the subject of the formula:

[tex]v= \Big ( \dfrac{\mathcal{P} RT}{M\times L_v \times P_o \times A }\Big)[/tex]

Given that:

[tex]\mathcal{P}[/tex] = 0.90  kW = 900 W

R(rate constant) = 8.314 J/mol.K

Temperature at 100° C = 373K

molar mass= 18.015 g/mol ≅ 0.0180 kg/mol

Latent heat of vaporisation [tex]L_v[/tex] = 2.26 × 10⁶ J/kg

Atmospheric pressure [tex]P_o = 1.013 \times 10^6 \ N/m^2[/tex]

Cross sectional area A =1.60 cm² = 1.60 × 10⁻⁴ m²

[tex]v= \Big ( \dfrac{900 W (8.314 \ J/mol.K)(373)}{0.0180 \ kg/mol) (2.26 \times 10^6 \ J/kg) (1.013 \times 10^5 \ N/m^2)(1.60 \times 10^{-4} \ m^2)}\Big)[/tex]

v = 4.233  m/s

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Answer:

[tex]0.01\ \text{A}[/tex]

[tex]0.0015\ \text{C}[/tex]

[tex]0.0608\ \text{s}[/tex]

Explanation:

[tex]V_0[/tex] = Voltage = 1.5 V

[tex]C[/tex] = Capacitance = [tex]1000\ \mu\text{F}[/tex]

[tex]R[/tex] = Resistance = [tex]150\ \Omega[/tex]

Current is given by

[tex]I=\dfrac{V_0}{R}\\\Rightarrow I=\dfrac{1.5}{150}\\\Rightarrow I=0.01\ \text{A}[/tex]

Current flowing in the resistor is [tex]0.01\ \text{A}[/tex].

Charge is given by

[tex]Q=CV\\\Rightarrow Q=1000\times 10^{-6}\times 1.5\\\Rightarrow Q=0.0015\ \text{C}[/tex]

The charge on the capacitor is [tex]0.0015\ \text{C}[/tex].

Voltage is given by

[tex]V=V_0e^{-\dfrac{t}{RC}}\\\Rightarrow t=-RC\ln\dfrac{V}{V_0}\\\Rightarrow t=-150\times 1000\times 10^{-6}\times\ln\dfrac{1}{1.5}\\\Rightarrow t=0.0608\ \text{s}[/tex]

Time taken to reach 1 V is [tex]0.0608\ \text{s}[/tex].

Answer:

6.69 kg

Explanation:

Given that:

The mass of the athlete = 89.2 kg

Height = 1.85 m

Resting HR = 47 bpm

BMI = ~26

The essence of the Wingate anaerobic test is to evaluate and access how much energy is released by phosphagen breakdown and anaerobic glycolysis. By applying a fixed amount of weight to that same cycle's weight tray, tension is added to the flywheel. The flywheel resistance is usually set at 0.075 kg per kilogram of body weight.

For athlete sprinters, the resistance is usually set at 1.0 kg which is then multiplied by the body mass up to 1.3 kg

Hence, the amount of the resistance applied for the athlete  = (0.075 × 89.2)kg

= 6.69 kg

Answer:

(a) 0.014 A

(b) 2 V

Explanation:

(a) Applying

V = IR'...................... Equation 1

Where V = Voltge, I = current, R = total resistance.

make I the subject of the equation

I = V/R'................... Equation 2

From the question,

Given: V = 12 V, R' = (122+232+500) ohms (The resistance are connected in series) = 854 ohms

Substitute these values into equation 2

I = 12/854

I = 0.014 A

(b)  Applying

V' = V(R₁)/(R₁+R₂+R₃)...................... Equation 3

Where V' = Voltage across the 100 ohms resistor.

From the question,

V = 12V, R₁ = 100 ohm, R₂ = 200 ohm, R₃ = 300 ohm.

Substitute these values into equation 3

V' = (12×100)/(100+200+300)

V' = 1200/600

V' = 2 V

60

because mass of an object never change

but weight can change for example if it's

mass is 60kg 5he wieght will be 60kg * 9.8m/s²

=588N

Answer: 0.553

Explanation:

Answer:

1568 J

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 80 Kg

Distance (d) = 5 m

Coefficient of kinetic friction (μ) = 0.4

Workdone (Wd) =?

Next, we shall determine the normal reaction. This can be obtained as follow:

Mass (m) = 80 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Normal reaction (N) =?

N = mg

N = 80 × 9.8

N = 784 N

Next, we shall determine force of friction. This can be obtained as follow:

Coefficient of kinetic friction (μ) = 0.4

Normal reaction (N) = 784 N

Force of friction (F) =?

F = μN

F = 0.4 × 784

F = 313.6 N

Finally, we shall determine the work done. This can be obtained as follow:

Distance (d) = 5 m

Force of friction (F) = 313.6 N

Workdone (Wd) =?

Wd = F × d

Wd = 313.6 × 5

Wd = 1568 J

Thus, the workdone is 1568 J

Answer:

Explanation:

(a) Electron Emission (Beta- decay):

When an unstable nucleus decays by the emission of Beta- particle, its charge number ‘Z’ increases by 1 but, its mass number ‘A’ remains unchanged. The transformation is represented by the equation:  

[tex]_zX^A\ -------->\ _{Z+1}Y^A\ +\ _{-1}e^0[/tex]

It is called ‘Negative Beta Decay’. It is more common than alpha decay.

Example:

[tex]_6C^{14}\ -------->\ _{7}N^{14}\ +\ _{-1}e^0[/tex]

Note:  

There are no electrons in a nucleus so, with the emission of a particle, one of the neutrons is converted to a proton and an electron.

[tex]_0n^1\ --------->\ _1P^1\ +\ _{-1}e^0[/tex]

(b) Positron Emission (Beta+ decay):

When an unstable nucleus decays by the emission of the positron, its charge number ‘Z’ decreases by 1 but,  its mass number ‘A’ remains unchanged. The transformation is represented by the equation:

[tex]_zX^A\ -------->\ _{Z-1}Y^A\ +\ _{+1}e^0[/tex]

Examples:

[tex]_{15}P^{30}\ -------->\ _{14}Si^{30}\ +\ _{+1}e^0[/tex]

Note:  

Inside the nucleus, only a proton can be transformed into a neutron with the emission of a positron (anti-particle of electron)

[tex]_1P^1\ -------->\ _0n^1\ +\ _{+1}e^0[/tex]

Answer:

Explanation:

1. All screws give the same M.A.

False - it depends on screw size and threads

2. A screw does its job by moving.

True - as far as screw as a machine

3. A screw with more threads has a smaller M.A.

False - more threads increase output force i.e. higher MA

4. Screws can be used to move things. *

True

Answer:

Explanation:

1. false

2. true

3. false

4. true

Answer:

λ = 266 nm

Explanation:

In this case, we need to determine first the separation of the second fringe from the central maximum. We can determine that with the following expression:

d sinθ = mλ   (1)

However, as the slits are very narrow, we can assume that sin θ ≈ θ and so θ = x/l

Replacing this in (1) we have:

d(x/l) = mλ

and solving for x:

x = mλl / d    (2)

Where:

x: separation of the 2nd fringe from the central maximum

m: order of the fringe

λ: wavelength of light

l: distance of the screen

d: distance between the slits

All the units must be in meters (m), so we can convert the units first or during the resolution. In this case, we'll do it in the resolution. Replacing the given data, we have:

x = 2 * (520 nm * 1m/10⁻⁹ nm) * 1.6 m / (0.66 mm * 1m/1000 mm)

x = 0.00252 m or just 2.52 mm

With this value, we can compute or determine the separation of the 2nd order fringe of the unknown light in the central maximum:

x₂ = 2.52 - 1.23 = 1.29 mm or 0.00129 m

Now, using (2) we can solve for λ:

λ = dx / ml   (3)

Replacing we have:

λ = (0.00129 * 0.0066) / (2 * 1.6)

Hope this helps

Answer:

I think its d matter accreted from a companion star unstable ignites on the surface of a white dwarf.

The cross-sectional area of the cylindrical copper wire is  1.7 x 10⁻⁹ m².

Resistivity is defined as the amount of electrical resistance of a conductor, per unit cross-sectional area and unit length.

Here,

Resistance of the wire, R = 10 Ω

Length of the wire, l = 1 m

Resistivity of the wire, ρ = 1.7 x 10⁻⁸ Ωm

The expression for the resistivity of a conductor is given as,

ρ = RA/l

where A is the cross-sectional area of the conductor.

Therefore, the area of cross-section of the copper wire,

A = ρl/R

A = 1.7 x 10⁻⁸ x 1/10

A = 1.7 x 10⁻⁹ m²

Hence,

The cross-sectional area of the cylindrical copper wire is  1.7 x 10⁻⁹ m².

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Answer:

law of Action and Reaction     F = 2250 N

Explanation:

The tractor and the trailer are two bodies that interact, therefore, by the law of Action and Reaction, the force that one applies on the other is equal to the force that the second body (trailer) applies on the first (tractor), but with opposite direction

          F = 2250 N

directed from trailer to tractor

Farenheit is an interesting unit so the conversions get a bit weird.

To convert from Farenheit to Celcius you follow this formula:

T(°C) = (T(°F) - 32) × 5/9

It is also easier to convert to Celcius to Kelvin shown in this formula:

T(K) = T(°C) + 273.15

To Answer your question:

105° F = 40.5°C

-25° F = -31.7°C

105° F = 313.65K

-25° F = 241.45K

Answer:

c

Explanation:

units c mark me brainless k

Explanation:

Given

mass of the rock is 10 kg

Force requires to hold the rock is equal to its weight

Weight is given by the product of mass and acceleration due to gravity

Weight on the earth surface

[tex]\Rightarrow W_e=10\times 9.8\\\Rightarrow W_e=98\ N[/tex]

Weight on the moon surface

[tex]\Rightarrow W_m=1.6\times 10\\\Rightarrow W_m=16\ N[/tex]

So, the force holding the rock on earth is approximately 6 times the force on the moon.

Answer:

1.a

2.b

3.d

4.c

5.d

Explanation: