Answer:
6 moles
Explanation:
because if conducting a moles ratio for oxygen and water it is 1:2 so the moles would calculate up to 6 moles after cross multiplication.
help please hurry lots of points
Compound X has the molecular formula C6H10. X decolorizes bromine in carbon tetrachloride. X also shows IR absorption at about 3300 cm-1 . When treated with excess hydrogen and a nickel catalyst, X yields 2-methylpentane. The most likely structure for X is:
Answer:
The correct answer is - option D. (check image)
Explanation:
Alkynes and alkenes both decolorized bromine in carbon tetrachloride. The absorption of the IR at about 3300 cm-1 for the X here that are found in the terminal alkynes absorption range only. In presence of excess hydrogen and a nickel catalyst, x gives the 2-methyl pentane.
The most likely structure for X is: CH3-CH3-ch-CH2-C≡CH
A compound having double and triple bonds is called alkenes and alkynes. The most likely structure of the compound will be 2 -methyl -4- hexyne.
What is the molecular formula?
The molecular formula represents the chemical atomic proportions of the compound or the molecule through the symbols, and numbers.
Bromine is decolorized by the alkynes and alkenes. The absorption range is followed by the terminal alkynes and in excess hydrogen yields 2-methyl pentane.
Therefore, 2 - methyl - 4 - hexyne is most likely to be X.
Learn more about molecular formulas here:
https://brainly.com/question/9669153
How many moles of solute are in a 1.50 M solution of HCl with a volume of 7.98 liters?
Answer:
[tex]\boxed {\boxed {\sf x\approx 12.0 \ moles \ HCl}}[/tex]
Explanation:
Molarity is a measure of concentration in moles per liter.
[tex]molarity= \frac{moles \ of \ solute}{liters \ of solution}[/tex]
We know the solution has a volume of 7.98 liters and it has a molarity of 1.50 M HCl.
1 molar (M) is 1 mole per liter, so the molarity is also 1.50 moles of HCl per liter.We know 2 values for the variables, but the value for moles of solute is unknown, so we use x.
molarity= 1.50 mol HCl/L moles of solute=xliters of solution = 7.98 LSubstitute the values into the formula.
[tex]1.50 \ mol \ HCl/L=\frac{x}{7.98 \ L}[/tex]
We are trying to solve for x, the moles of solute, so we must isolate the variable. It is being divided by 7.98 liters and the inverse of division is multiplication. Multiply both sides of the equation by 7.98 liters.
[tex]7.98 \ L *1.50 \ mol \ HCl/L=\frac{x}{7.98 \ L} * 7.98 \ L[/tex]
[tex]7.98 \ L *1.50 \ mol \ HCl/L=x[/tex]
The units of liters (L) cancel each other out.
[tex]7.98 *1.50 \ mol \ HCl=x[/tex]
[tex]11.97 \ mol \ HCl=x[/tex]
The original measurements of molarity and volume both have 3 significant figures, so our answer must have the same. For the number we found, that is the tenths place.
The 9 in the hundredth place tells us to round the 1 to a 2. We leave a 0 in the tenths place to ensure there are 3 significant figures.
[tex]12.0 \ mol \ HCl \approx x[/tex]
There are approximately 12.0 moles of solute in the solution.
Explain why the coefficients on the left side of the equation don’t necessarily equal the coefficients on the right side of the equation. Is this possible if mass is being conserved?
Answer:
Explanation:
Short answer: Yes.
The coefficients may not be conserved, but mass always has to be. Take this equation as an example
2 Mg3P2 ===> 6Mg + P4
There is a 2 on the left side and 6 and 1 on the right. I hope you mean that the coefficient 2 is not equal to 7.
But let's look a little closer. You have to look at the molecular structure of the left and right side.
2Mg3P2 has 6 Mgs and 4 Ps on the left side.
6Mg is on the right. They are free standing.
P4 has 1 molecule consisting of 4 Ps.
Everything balances.
This is a terrific question to be asking. You need to understand the internal balance numbers vs the molecular ones on the out side.
That sounds like a bit of gobbledygook and it takes a bit of study.
2 Mg3P2 means that Mg3P2 is written twice.
Mg3P2 ==> "3 Mg2+ + 2P3+ and there is another one written the same way.
Mg3P2 ==> "3 Mg2+ + 2P3+
If ammonium phosphate reacts with sodium chloride in aqueous solution, what are the products?
Answer:
[tex](NH_4)_3PO_4(aq)+3NaCl(aq)\rightarrow 3NH_4Cl(aq)+Na_3PO_4(aq)[/tex]
Explanation:
Hello there!
In this case, according to the given information, we can set up the appropriate chemical equation when ammonium phosphate reacts with sodium chloride in aqueous solution:
[tex](NH_4)_3PO_4(aq)+NaCl(aq)\rightarrow NH_4Cl(aq)+Na_3PO_4(aq)[/tex]
Which stands for a double replacement reaction, whereby ammonium changes phosphate to chloride and sodium changes chloride to phosphate on the products side. In addition, we can balance the aforementioned equation as shown below:
[tex](NH_4)_3PO_4(aq)+3NaCl(aq)\rightarrow 3NH_4Cl(aq)+Na_3PO_4(aq)[/tex]
Regards!
PLSS HELPP ME i dont knowww
Answer:
non polar. polar ionic substance
Brainiest and 10 Points
What is the name of the rays the human eye can see?
A. Radio Rays
B. Water Waves
C. Visible Light Rays
D. X Rays
I believe the answer for this is:
C. Visible Light Rays
I hope this helps! :D
Answer:
C, visible light rays :)
Explanation:
Hope i could help
Calculate the molecular mass of sodium trioxocarbonate (iv) decahydrate
Answer:
106.180
Explanation:
maybe this is the correct answer
I SAID MAYBE
When aqueous solutions of potassium nitrite and nitric acid are mixed, an aqueous solution of potassium nitrate and nitrous acid results. Write the net ionic equation for the reaction.
Nitric acid and potassium nitrite reacted together potassium nitrate and nitrous acid forms. The net ionic equation for the reaction is given below:
[tex]\rm K^{+} (aq)+ NO_{3} ^{-} (aq)\rightarrow KNO_{3}(s)[/tex]
What is ionic equation?A balanced reaction represents all the reactants and products in perfect stoichiometry. Thus, each element have to be equal in number on both side.
A balanced ionic equation represents all the ions participating in a reaction and with their charges balanced on both side and state of the reaction is given in brackets. Net ionic equation represents the formation of a solid precipitate.
The complete ionic equation of reaction of one mole of potassium nitrite with one mole of nitric acid is given below:
[tex]\rm K^{+} + NO_{2}^{-}(aq) + H^{+} (aq) +NO_{3}^{-}(aq) \rightarrow H^{+} (aq) + NO_{2}^{-}(aq) + KNO_{3} (s)[/tex]
Cancelling the aqueous ions from both sides we get the net ionic equation representing the formation of solid potassium nitrate as shown here:
[tex]\rm K^{+} (aq)+ NO_{3} ^{-} (aq)\rightarrow KNO_{3}(s)[/tex]
To find more on ionic equations, refer here:
https://brainly.com/question/15467502
#SPJ5
Explain why this combination of compounds can or cannot make a buffer solution. Hint: apply definition of a buffer, mechanism of its action and consider whether the compound is acid (weak/strong) or base (weak/strong). HF (0.2 mol) and NaOH (0.1 mol)
Answer:
This combination can make a buffer
Explanation:
A buffer is defined as an aqueous mixture of a weak acid and its conjugate base, or vice versa.
In the problem, HF is a weak acid, and its conjugate base is F⁻.
When NaOH reacts with HF, F⁻, Na⁺ and H₂O are produced as follows:
NaOH + HF → F⁻ + Na⁺ + H₂O
As there are initially 0.2mol of HF and 0.1mol NaOH, after the reaction you will have:
0.1mol HF and 0.1mol F⁻. As both, the weak acic and the conjugate base are present:
This combination can make a buffera. acidic
b. basic
; neutral
d. will not be affected
Find the molarity of 10% NaOH.[MOE 2003
a. 1.5
b! 2.5
c. 4
d. 0.4
10 ml of 2.5 N NaOH is mixed with 20 ml of
N HCI. The mixture is diluted to 100 ml. WI
is the nature of mixture?
IMOF 20
1. You didn't post the question to Number 1.
2.
10% means There's 10g in 100ml of this solution.
This is the weight/volume(w/v) expression of concentration.
So
We have Mass =10g
volume =100ml
Molarity = Moles of solute/volume of solution(in LITRES)
Moles=Mass/Molar mass
Molar mass of NaOH=40g/mol
Mole=10/40
=0.25mole
Volume =100ml =0.1Litres
MOLARITY=0.25/0.1 =
=2.5M
OPTION B.
3. NOTE: THE MOLARITY AND NORMALITY OF NAOH AND HCL ARE THE SAME(This doesn't happen for all compounds tho)
So We can take 2.5N(Normality) of NaOH to be 2.5M(Molarity) NaOH
I think you forgot to write the Normality of the second one. I'll take it to be 1N. Maybe you can then Input supposed value when you're solving on your own
So
1N HCl is same as 1M HCL
We were given their respective volumes
2.5M NaOH can also be written as 2.5mole/volume(in Liters)
The volume of NaOH =10ml or 0.01L
Moles = 2.5mole/L x 0.01L
You notice that Liters on top and bottom cancels out... leaving the moles
So
Mole=0.01x2.5 = 0.025moles of NaOH
we're gonna do the same for 1N HCl in 20ml(0.02L)
So
Mole = 1 x 0.02 =0.02moles
Total Mole = 0.02 + 0.025 =0.045moles
The Final Volume is 100ml as stated in the question. It was diluted to 100ml or 0.1L
So
Final Concentration In Molarity
= Total Moles/Volume in L
=0.045/0.1
=0.45M.
Difference between brain and spinal cord
Pls help
Pure magnesium metal is often found as ribbons and can easily burn in the presence of oxygen. When 3.31 g of magnesium ribbon burns with 8.45 g of oxygen, a bright, white light and a white, powdery product are formed. Enter the balanced chemical equation for this reaction. Be sure to include all physical states.
Answer:
2Mg(s) + O2(g) ----->2MgO(s)
Explanation:
In writing a balanced chemical reaction equation, the rule of thumb is that the number of atoms of each element on the reactant side must be the same as the number of atoms of the same elements on the products side.
Hence for the reaction of magnesium and oxygen shown below;
2Mg(s) + O2(g) ----->2MgO(s)
We notice that there are two atoms each of magnesium and oxygen on both sides of the reaction equation hence the equation is balanced.
2) A 0.77 mg sample of nitrogen gas reacts with chlorine gas to form 6.61 mg of a nitrogen
chloride compound. What is the empirical formula of the nitrogen chloride compound?
Answer:
NCl₃
Explanation:
From the question given above, the following data were obtained:
Mass of nitrogen (N) = 0.77 mg
Mass of chlorine (Cl) = 6.61 mg
Empirical formula =?
The empirical formula of the compound can be obtained as follow:
N = 0.77 mg
Cl = 6.61 mg
Divide by their molar mass
N = 0.77 / 14 = 0.055
Cl = 6.61 / 35.5 = 0.186
Divide by the smallest
N = 0.055 / 0.055 = 1
Cl = 0.186 /0.055 = 3
Therefore, the empirical formula of the compound is NCl₃
If the atomic number of an element is 14, the identity of the element must be
A. Nitrogen
B. Silicon
C. Carbon
D. Niobium
Answer:
silicon
Explanation:
because silicon has 14 electrons and protons
To double-check a chemical in lab before using it, sniff near the opening of the container, true or false?
When an acetic acid solution is titrated with sodium hydroxide, the slope of the titration curve (pH versus volume of NaOH added) increases when sodium hydroxide is first added. This change shows that ________
Answer:
When an acetic acid solution is titrated with sodium hydroxide, the slope of the titration curve (pH versus volume of NaOH added) increases when sodium hydroxide is first added. This change shows that acetic acid is being converted to sodium acetate.
Explanation:
ABOUT TITRATION - Titration is a chemical analysis method for determining the amount of a constituent in a sample by adding an exact known quantity of another substance to the measured sample with which the desired constituent reacts in a specific, known proportion. A burette, which is essentially a long, graduated measuring tube with a stopcock and a delivery tube at the bottom end, is used to gradually administer a standard solution of titrating reagent, or titrant.
It is feasible to identify a good visual color indicator for many titration processes that will signify the end point at, or very near to, the equivalence point.
Acid-base titrations, precipitation titrations, complex-formation titrations, and oxidation-reduction (redox) titrations are examples of such titrations, which are categorised according to the nature of the chemical reaction that occurs between the sample and the titrant.
Titrations of metal ions with the reagent disodium ethylenediaminetetraacetate are the most important titrations based on complex-formation processes (a salt of edetic acid, or EDTA).
Hence , the answer is that acetic acid is converted into sodium acetate.
It took 10.40 mL of a NaOH solution to neutralize 0.307 g of KHP. What is the molarity of the NaOH solution
Answer:
0.144 M
Explanation:
First we convert 0.307 g of KHP (potassium hydrogen phthalate, KHC₈H₄O₄) into moles, using its molar mass:
0.307 g ÷ 204.22 g/mol = 0.0015 mol KHP1 mol of KHP reacts with 1 mol of NaOH, that means that in 10.40 mL of the NaOH solution there were 0.0015 moles of NaOH.
Now we calculate the molarity of the NaOH solution:
10.40 mL / 1000 = 0.0104 LMolarity = 0.0015 mol / 0.0104 L = 0.144 MA plot of binding energy per nucleon (Eb/ A) versus the mass number (A) shows that nuclei with a small mass number have a small binding energy per nucleon, as the mass number increases the binding energy per nucleon increases, and the value for the binding energy per nucleon has a maximum value for nuclei with a mass number around 60. Verify that this is the case by determining the binding energy per nucleon for each of the following four nuclei. (Let the mass of a proton be 1.0078 u, the mass of a neutron be 1.0087 u, the mass of 2H be 2.0141 u, the mass of 7Li be 7.0160 u, the mass of 62Ni be 61.9283 u, and the mass of 110Cd be 109.9030 u.
a. 2H
b. 7Li
c. 62Ni
d. 110Cd
Answer:
a) 1.12 MeV / nucleon
b) 5.62 MeV / nucleon
c) 8.80 MeV / nucleon
d) 8.56 MeV / nucleon
we can conclude that the binding energy has a maximum value for nuclei with a mass around 60
Explanation:
Binding energy = ( Δm * 931.5 ) MeV
Binding energy per nucleon = Binding energy in / Number of nucleon
a) ²H = 1 neutron , 1 proton = 2 nucleons
Given that the theoretical mass = 2.0141 u
Actual mass = 1.0078 u + 1.0087 u = 2.0165 u
Δm = 2.0165 u - 2.0141 u = 2.4 * 10^-3 u
∴ Binding energy per nucleon = ( 2.4 * 10^-3 * 931.5 ) MeV / 2 nucleons
= 1.12 MeV / nucleon
b) ⁷Li = 3 protons , 4 neutrons = 7 nucleons
theoretical mass = 7.0160 u
Actual mass = ( 3 * 1.0078 ) + ( 4 * 1.0087 ) = 7.0582 u
Δm = ( 7.0582 u - 7.0160 u ) = 0.0422 u
∴ Binding energy per nucleon = ( 0.0422 * 931.5 ) / 7
= 5.62 MeV / nucleon
C) ⁶²Ni = 28 protons , 34 neutrons = 62 nucleons
Theoretical mass = 61.9283 u
Actual mass = ( 28 * 1.0078 ) u + ( 34 * 1.0087 ) u
= 62.5142 u
Δm = 0.5859 u
∴ Binding energy per nucleon = ( 0.5859 * 931.5 ) / 62
= 8.80 MeV / nucleon
D) ¹¹⁰Cd = 48 protons , 62 neutrons = 110 nucleons
Theoretical mass = 109.9030 u
Actual mass = ( 48 * 1.0078 ) + ( 62 * 1.0087 )
= 110.9138 u
Δm = ( 110.9138 - 109.9030 ) = 1.0108 u
∴ Binding energy per nucleon = ( 1.0108 * 931.5 ) / 110
= 8.56 MeV / nucleon
hence we can conclude that the binding energy has a maximum value for nuclei with a mass around 60
HELP! ASAP! Iron (Fe) and copper (II) chloride (CuCl2) combine to form iron (III) chloride (FeCl3) and copper (Cu). If you start with 155,8 grams of
iron (Fe), how many grams of copper (Cu) will be produced?
2Fe + 3CuCl2 à 2FeCl3 + 3Cu
Answer: 30.978
Explanation:
From the equation 2 moles of Fe will result in 3 moles copper
so .325 moles Fe will result in .4875 moles Cu
Cu weights 63.546 gm per mole
.4875 moles * 63.546 gm / mole = 30.978 gm of Cu
What do all fossil fuels have in common?
O A. They are all liquids.
OB. They all contain crude oil.
O C. They all produce nitrogen as a combustion product.
O D. They are all nonrenewable energy sources.
Answer:
Your answer would be D, they are all non-renewable energy sources. Hope this helps!
Answer:
D. They are all nonrenewable energy sources.
Statement which represents following chemical reaction.
Answer:
Third option is the correct answer
Explanation:
A solution of sodium chloride and a precipitate of barium sulphate is formed.
Pea plants have green seeds only if a plant receives an allele for green seeds from each of its parents. What kind of allele produces green seeds in pea plants?
Your answer:
Hybrid
Dominant
Recessive
Mutated
Answer:If two heterozygous parents with a genotype of Yy are crossed, the possible combination of genotypes in their offspring would be YY, Yy, Yy, and yy. Therefore, the genotypic ratio of the offspring produced is 1:2:1.
Explanation:If two heterozygous parents with a genotype of Yy are crossed, the possible combination of genotypes in their offspring would be YY, Yy, Yy, and yy. Therefore, the genotypic ratio of the offspring produced is 1:2:1.
plz help me asap i need this plz
Why is it sometimes not practical to use to scale models when representing objects in space?
The area of a telescope lens is 6507 x 10^3 mm^2. What is the area in square feet, enter your answer in scientific notation. If it takes a technician 51.6 s to polish 1.68 x 10^2 mm^2 how long does it take her to polish the entire lens ?
Answer: the area of the telescope lens is \textit{0,08507 ft}
Explanation: Happy I could help!
. Suppose an infrared photon with a wavelength of 853 nm were combined with another infrared photon with a wavelength of 865 nm, what would be the wavelength of the new 'combined' photon, in nm
Answer:
Explanation:
Given the data in the question;
wavelength λ₁ = 853 nm = 853 × 10⁻⁹ m
wavelength λ₂ = 865 nm = 865 × 10⁻⁹ m
we determine the energy of each photons using the following expression;
[tex]E_{photon[/tex] = hc / λ
where h is Planck's constant ( 6.626 × 10⁻³⁴ J.s )
c is speed of light ( 3 × 10⁸ m/s )
For Photon with wavelength λ₁ = 853 × 10⁻⁹ m
[tex]E_{photon1[/tex] = hc / λ
we substitute
= ( ( 6.626 × 10⁻³⁴ J.s )( 3 × 10⁸ m/s ) ) / (853 × 10⁻⁹ m)
= 1.9878 × 10⁻²⁵ / 853 × 10⁻⁹
= 2.33 × 10⁻¹⁹ J
For Photon with wavelength λ₂ = 865 × 10⁻⁹ m
[tex]E_{photon2[/tex] = ( ( 6.626 × 10⁻³⁴ J.s )( 3 × 10⁸ m/s ) ) / (865 × 10⁻⁹ m)
= 1.9878 × 10⁻²⁵ / 865 × 10⁻⁹
= 2.298 × 10⁻¹⁹ J
We know that; energy of the combined photon will be equal to the sum of energies of the two photons.
so
Energy of the combined photon = [tex]E_{photon1[/tex] + [tex]E_{photon2[/tex]
[tex]E_{combined[/tex] = 2.33 × 10⁻¹⁹ J + 2.298 × 10⁻¹⁹ J
[tex]E_{combined[/tex] = 4.628 × 10⁻¹⁹ J
so wavelength of the new combined photon will be;
[tex]E_{combined[/tex] = hc / λ[tex]_{combined[/tex]
[tex]E_{combined[/tex]λ[tex]_{combined[/tex] = hc
λ[tex]_{combined[/tex] = hc / [tex]E_{combined[/tex]
we substitute
λ[tex]_{combined[/tex] = ( ( 6.626 × 10⁻³⁴ J.s )( 3 × 10⁸ m/s ) ) / 4.628 × 10⁻¹⁹ J
= 1.9878 × 10⁻²⁵ / 4.628 × 10⁻¹⁹
= 4.2952 × 10⁻⁷ m
= ( 4.2952 × 10⁻⁷ × 10⁹ )nm
= 429.5 nm
Therefore, Wavelength of the new 'combined' photon is 429.5 nm
C. Balance these fossil-fuel combustion reactions. (1 point)
The question is incomplete. The complete question is :
C. Balance these fossil-fuel combustion reactions. (1 point)
C8H18(g) + 12.5O2(g) → ____CO2(g) + 9H2O(g) + heat
CH4(g) + ____O2(g) → ____CO2(g) + ____H2O(g) + heat
C3H8(g) + ____O2(g) → ____CO2(g) + ____H2O(g) + heat
C6H6(g) + ____O2(g) → ____CO2(g) + ____H2O(g) + heat
Solution :
C8H18(g) + 12.5O2(g) → __8__CO2(g) + 9H2O(g) + heat
When 1 part of octane reacts with 12.5 parts of oxygen, it gives 8 parts of carbon dioxide and 9 parts of water along with liberation of energy.
CH4(g) + __2__O2(g) → __1__CO2(g) + __2__H2O(g) + heat
When 1 part of methane reacts with 2 parts of oxygen, it gives 1 part of carbon dioxide and 2 parts of water along with liberation of energy.
C3H8(g) + __5__O2(g) → __3__CO2(g) + __4__H2O(g) + heat
When 1 part of propane reacts with 5 parts of oxygen, it gives 3 part of carbon dioxide and 4 parts of water along with liberation of energy.
C6H6(g) + __1/2__O2(g) → __6__CO2(g) + __3__H2O(g) + heat
When 1 part of propane reacts with 1/2 parts of oxygen, it gives 6 part of carbon dioxide and 3 parts of water along with liberation of energy.
What transition energy corresponds to an absorption line at 460 nm?
A. 6.52 x 10-19 J
B. 4.32 x 10-19 J
C. 4.45 x 10-19 J
D. 2.31 x 10-19 J
Answer:
B. 4.32 x 10-19 J is correct via a p e x
Explanation:
How many atoms in total are there in 7.35 mol of magnesium oxide (MgO)
molecules?
Answer:
4.42 x 10^24
Explanation:
A 0.200 M solution of a week acid, HA, is 9.4% ionized. The molar concentration of H+ is 0.0188 M. the Acid-dissociation constant, Ka, for HA is...?
We are given:
Initial concentration of HA: 0.200 Molar
The acid is 9.4% ionized
Dissociation constant (α) = (Percent Ionized) / 100 = 0.094
Molar concentration of H+ = 0.0188
Let's Chill! (making the ICE box):
Reaction: HA ⇄ H⁺ + A⁻
Initial: 0.200M - -
Equilibrium: 0.200(1-α) 0.200α 0.200α
while we're here, let's confirm the given equilibrium concentration of H⁺ ions
from the table here, we can see that the equilibrium concentration of H⁺ ions is 0.200α, we know that α = 0.094
[H⁺] = 0.200α = 0.200 * 0.094 = 0.0188 M
which means that we're on the right track
We're basically scientists at this point (finding the dissociation constant):
Acid dissociation is nothing but the equilibrium constant, but for the dissociation of Acids
From the reaction above, we can write the equation of the acid dissociation constant:
Ka = [H⁺][A⁻] / [HA]
now, let's take the values from the 'equilibrium' row of the ice box the plug those in this equation
Ka = (0.200α)(0.200α) / [0.200(1-α)]
Ka = (0.200α)²/[0.200(1-α)]
plugging the value of α
Ka = (0.200*0.094)² / [0.200(0.906)]
Ka = (0.0188)² / 0.1812
Ka = 1.95 * 10⁻³