How do I solve this

Answer:

y > x+1 (D)

Step-by-step explanation:

this equation forms the same graph as shown in the question

Answer:

25h+12

Step-by-step explanation:

Combine Like Terms:

21h+−10h+16+−9+14h+5

(21h+−10h+14h)+(16+−9+5)

25h+12

Same thing, no difference.

Hope this helped! :)

Answer:

1. Yes

2. Yes

3. No

Step-by-step explanation:

Answer:

The answer is 1/4 or 0.25

Step-by-step explanation:

The question is very simple. All we have to do is figure out what -12 multiplied by ______ equals -3

So we can just divide -3 by -12 to find the answer.

-3 / -12 = 0.25

So the answer is 0.25 or 1/4 in fraction form.

Hope this helps! :)

૮ ・ﻌ・ა

Answer:

x = 1/4

Step-by-step explanation:

−12x = − 3

Step 1: Divide both sides by -12.

-12x/-12 = -3/-12

Answer:

x = 1/4

Answer:

Step-by-step explanation:

f(x) = (3x+3)/(x-2)

Use a graphing program such as DESMOS.  See attachment.

The asymptotes are:

The asymptotes are:

y = ± infinity as x  reaches 2

x = ± infinity as y  reaches 3

Answer:

65

Step-by-step explanation:

it is the largest cup so it is 65

The inequality that models the situation is:

[tex]15000 + 4s \geq 450000[/tex]

Solving it, it is found that they need to sell at least 108,750 shirts.

During the day:

Hence, the earnings are:

[tex]T = 15000 + 4s[/tex]

They want to earn at least 450,000, hence:

[tex]T \geq 450000[/tex]

[tex]15000 + 4s \geq 450000[/tex]

Solving it:

[tex]15000 + 4s \geq 450000[/tex]

[tex]4s \geq 435000[/tex]

[tex]s \geq \frac{435000}{4}[/tex]

[tex]s \geq 108750[/tex]

They need to sell at least 108,750 shirts.

A similar problem is given at https://brainly.com/question/24514895

First make note of the domain of the left hand side.

• √(x + 1) is defined for x + 1 ≥ 0, or x ≥ -1.

• √(2 + √(x + 1)) is defined for 2 + √(x + 1) ≥ 0. If x ≥ -1, then this condition is satisfied.

• √(7 + √(2 + √(x + 1))) is defined for 7 + √(2 + √(x + 1)) ≥ 0. This condition is also satisified automatically if x ≥ -1.

Now solve the equation. Taking the square of both sides of

√(7 + √(2 + √(x + 1))) = 3

yields

7 + √(2 + √(x + 1)) = 3² = 9

√(2 + √(x + 1)) = 2

Squaring both sides again gives

2 + √(x + 1) = 2² = 4

√(x + 1) = 2

And once more,

x + 1 = 2² = 4   ⇒   x = 3

The distance between points (a) and (b) is the number of units between the points.

Formula for halfway two

Assume the lesser point is point (a)

To locate the halfway between points (a) and (b)

The above steps is represented as:

[tex]P = a + \frac{|a - b|}{2}[/tex]

Using the above formula, the halfway point between 5 and 11 would be 8

The formula can be used to calculate the distance between negative points, and absolute values are used to determine the number of units between the points

Real world circumstance

The formula can be used to calculate the halfway distance between two points on a track

Fractional distance

To determine the fractional distance, we simply replace the 1/2 in the original formula with the appropriate fraction.

Take for instance, three-fourths from (a) to (b) would be:

[tex]P = a + \frac{3|a - b|}{4}[/tex]

Read more about distance at:

https://brainly.com/question/9935574

In other words, write it in exponential form.

To write a as a power of 2, your log form should be written this way: log_2 (5) = a.

We can then then write it in exponential form showing a as a power of 2.

Here it is:

2^(a) = 5

Answer:

option C can be used.

Step-by-step explanation:

hope this helps you.

Answer:

x = 3y + 4x

its how graphs work

Answer:16.667%

Step-by-step explanation:

140 - 120 = 20

20 / 120 = 16.667%

Answer:

I  think that would be 1/5

Explanation:

Hope this helps!

We have ( 4x + 3y ) : ( 3x + 4y ) = 24 : 25

[tex]\\ \sf\longmapsto \: \frac{4x + 3y}{3x + 4y} = \frac{24}{25} [/tex]

[tex]\\ \sf\longmapsto \: 25(4x + 3y) = 24(3x + 4y)[/tex]

[tex]\\ \sf\longmapsto \: 100x + 75y = 72x + 96y[/tex]

[tex]\\ \sf\longmapsto \: 100x - 72x = 96y - 75y[/tex]

[tex]\\ \sf\longmapsto \: 28x = 21y[/tex]

[tex]\\ \sf\longmapsto \: \frac{x}{y} = \frac{21}{28} = \frac{3}{4} [/tex]

Hence ,

[tex]\\ \sf\longmapsto \dfrac{4x+3y}{3x+4y}=\dfrac{24}{25}[/tex]

[tex]\\ \sf\longmapsto 24(3x+4y)=25(4x+3y)[/tex]

[tex]\\ \sf\longmapsto 72x+96y=100x+75y[/tex]

[tex]\\ \sf\longmapsto 96y-75y=100x-72x[/tex]

[tex]\\ \sf\longmapsto 21y=28x[/tex]

[tex]\\ \sf\longmapsto \dfrac{x}{y}=\dfrac{21}{28}[/tex]

[tex]\\ \sf\longmapsto \dfrac{x}{y}=\dfrac{3}{4}[/tex]

[tex]\\ \sf\longmapsto x:y=3:4[/tex]

Answer:

god help you

Step-by-step explanation:

i think we should add all the ratio together.......

Step-by-step explanation:

how do we find the difference between 2 numbers ? by subtracting one from the other.

p - 6 = -14

p = -8

Answer: g(x) = (x-2)^2 - 6

Step-by-step explanation: The graph of x^2 is a parabola opening downward. The (x+1) stands for 1 unit to the left and -7 is 7 units down. Once you have graph f(x) = (x+1)^2-7, there you should be able to graph g(x)=(x-2)^2-6. From there, its asks to go 3 units right which gives (x-2) and 1 unit up which gives -6.

(x+1) is x=-1 and (x-2) = 2.

Hope this helps.

Answer:

nope

Step-by-step explanation:

A-(b-c)=(A-b)-c

let a be 2, b be 3 and c be 4

2-(3-4)=(2-3)-4

2-(-1)=(-1)-4

2+1=-1-4

3=-5

therefore, association is not goot under subtraction

Answer:

No, the associative property does not hold good for the subtraction of integers.

Answer:

Word Problem: The length of a shoelace is 4 and 3/8    meters. How many shoelaces can be made from an 8-meter lace?

Step-by-step explanation:

Answer:

Absolute value is the distance from numbers on a number line. The absolute value of -7 is 7 b/c it is 7 units from 0. The absolute value of 5 is 5 b/c it is 5 units from 0.

A negative number is a number that is negative. On a horizontal number line negative numbers are to the left.

A positive number is a number that is positive. On a horizontal number line positive numbers are to the right.

I don't understand the last paragraph though. Hope this helped :D

Step-by-step explanation: