Answer: For the given reaction [tex]Pb(NO_{3})_{2} + AlBr_{3}[/tex] the products are [tex]PBr_{2} + Al(NO_{3})_{3}[/tex].
Explanation:
A reaction in which two substances chemically combine together and results in the formation of a new substance is called a chemical reaction.
For example, [tex]3Pb(NO_{3})_{2} + 2AlBr_{3} \rightarrow 2Al(NO_{3})_{3} + 3PbBr_{2}[/tex]
Products are the species that are written on the right side of an arrow in a chemical reaction equation.
Hence, we can conclude that for the given reaction [tex]Pb(NO_{3})_{2} + AlBr_{3}[/tex] the products are [tex]PBr_{2} + Al(NO_{3})_{3}[/tex].
Given the following set of atoms, write a bond-line formula for a possible constitutional isomer for the compound. Show all formal charges and lone pairs.C atoms H atoms Other3 6 2 Br atoms
Answer:
Explanation:
Isomers are compounds with the same molecular formula but chemically distinctive structures. Compounds that vary in connectivity, or how the component atoms are related to one another, are known as constitutional isomers. They have distinct functional groups and bonding patterns according to the sequence in which the atoms are linked together.
From the information given:
The compound given is C₃H₆Br₂ and the constitutional isomer of the compound can be seen in the image attached below.
The formal charges are calculated as follows:
Formal charge = valence electron - 1/2(bonding electron) - lone electron
For Br:
Formal charge = 7 - 1/2(2) - 6
Formal charge = 7 - 1 - 6 = 0
For C:
Formal charge = 4 - 1/2(8) - 0
Formal charge = 4 - 4 = 0
For H:
Formal charge = 1 - 1/2(2)
Formal charge = 1 - 1 = 0
3. 78 mL of 2.5 M phosphoric acid is neutralized with 500 mL of potassium hydroxide. What is the
concentration of the base?
Given the following: 30 grams of H3PO4, find the number of moles
Answer:
Number of mole of H₃PO₄ = 0.306 mole
Explanation:
From the question given above, the following data were obtained:
Mass of H₃PO₄ = 30 g
Number of mole of H₃PO₄ =?
Next, we shall determine the molar mass of H₃PO₄. This can be obtained as follow:
Molar mass of H₃PO₄ = (3×1) + 31 + (4×16)
= 3 + 31 + 64
= 98 g/mol
Finally, we shall determine the number of mole in 30 g of H₃PO₄ as follow:
Mass of H₃PO₄ = 30 g
Molar mass of H₃PO₄ = 98
Number of mole of H₃PO₄ =?
Mole = mass / molar mass
Number of mole of H₃PO₄ = 30 / 98
Number of mole of H₃PO₄ = 0.306 mole
formula for dicyanoargentate (I) ion
Answer:
Potassium dicyanoargentate(I) | C2AgKN2 - PubChem.
Synonyms: Potassium dicyanoargentate(I)pota...
Molecular Formula: C2AgKN2
Explanation:
What area is affected by Earth’s gravitational field?
what ionic compounds contribute to climate change?
Answer:
sulphuric acid
nitric acid
carbolic acid
The ionic compounds contribute to climate change that is sulphuric acid, nitric acid and carbolic acid.
What is ionic compound?Ionic compounds were made up of ions kept together by the attraction of positive and negative ions. One of the most well-known ionic compounds is common salt (sodium chloride). Molecular compounds were made up of distinct molecules that also are kept together through electron sharing (covalent bonding).
What is climate change?Long-term variations in temperature but also weather systems are referred to as climate change.
Therefore, the ionic compounds contribute to climate change that is sulphuric acid, nitric acid and carbolic acid.
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balance this equation plz
SO2+O2+H2O------->H2SO4
Answer: The balanced equation is [tex]2SO_{2} + O_{2} + 2H_{2}O \rightarrow 2H_{2}SO_{4}[/tex].
Explanation:
A chemical equation which contains same number of atoms on both reactant and product side is called a balanced chemical equation.
For example, [tex]SO_{2} + O_{2} + H_{2}O \rightarrow H_{2}SO_{4}[/tex]
Here, number of atoms present on reactant side are as follows.
S = 1O = 5H = 2Number of atoms present on product side are as follows.
S = 1O = 4H = 2To balance this equation, multiply [tex]SO_{2}[/tex] by 2 and [tex]H_{2}O[/tex] by 2 on reactant side. Also, multiply [tex]H_{2}SO_{4}[/tex] by 2 on product side.
Hence, the equation can be re-written as follows.
[tex]2SO_{2} + O_{2} + 2H_{2}O \rightarrow 2H_{2}SO_{4}[/tex]
Now, the number of atoms present on reactant side are as follows.
S = 2O = 8H = 4Number of atoms present on product side are as follows.
S = 2O = 8H = 4Since, the atoms present on both reactant and product side are equal. Hence, the equation is now balanced.
Thus, we can conclude that the balanced equation is [tex]2SO_{2} + O_{2} + 2H_{2}O \rightarrow 2H_{2}SO_{4}[/tex].
STRONGEST METALL ON EARTH
Answer:
tungstun
Explanation:
Answer:
tungsten
Explanation:
strongest out of any natural metal (142,000 psi).
Which of a following elements has the Smallest atomic radius 1. Ge 2. SI 3. Carbon 4. Sn
Answer:
carbon
Explanation:
Atomic radius represents the distance from the nucleus to the outer shell of an element.
The element having the Smallest atomic radius is Carbon. Hence. Option (3) is correct
What is Atomic Radius ?The atomic radius of a chemical element is a measure of the size of its atom, usually the mean or typical distance from the center of the nucleus to the outermost isolated electron.
Atomic Radius Increases down the group.
All the given elements belongs to same group ie, 14th Carbon is the top most element of the group.
Therefore, The element having the Smallest atomic radius is Carbon. Hence. Option (3) is correct
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How many moles of I2 are there in 5.34 x 1025molecules of I2 ?
Explanation:
pls the question is not clear to me
Choose one:____.
A. FeBr3 is the Lewis acid, and FeBr4-1 is the Lewis base.
B. FeBr4-1 is the Lewis acid, and Br 1 is the Lewis base.
C. Br 1 is the Lewis acid, and FeBr4-1 is the Lewis base.
D. FeBr3 is the Lewis acid, and Br2 is the Lewis base.
E. Br 1 is the Lewis acid, and FeBr4-1 is the Lewis base.
F. FeBr4-1 is the Lewis acid, and FeBr3 is the Lewis base.
Answer:
FeBr3 is the Lewis acid, and FeBr4-1 is the Lewis base.
Explanation:
A Lewis acid is any specie that has empty orbitals into which it can receive a lone pair of electrons.
A Lewis base is any specie that donates a lone pair of electrons to another to form a dative covalent bond.
If we look at the species listed in the options, FeBr3 is lone pair acceptor hence it is a Lewis acid while FeBr4- is a lone pair donor hence it is Lewis base.
Suppose a current of 0.860A flows through a copper wire for 5.0 minutes. Calculate how many moles of electrons travel through the wire. Be sure your answer has the correct unit symbol and round your answer to 2 significant digits.
Answer:
2.7×10⁻³ mole
Explanation:
Applying
Q = it.............. Equation 1
Where Q = amount of charge, i = current, t = time
From the question,
Given: i = 0.860 A, t = 5 minutes = (5×60) seconds = 300 seconds
Subsitute these values into equation 1
Q = (0.860×300)
Q = 258 C
If one mole of electron has a charge of 96500 C
Then, x mole of electron will have a charge of 258 C
1 mole ⇒ 96500 C
X moles ⇒ 258 C
Solve for X
X = (258×1)/96500
X = 2.7×10⁻³ mole
PLEASE HELP
Let’s say a colleague working in the lab needs to create a solution containing 97.9 grams of NaCl. If she has a 3.0 M stock solution of NaCl dissolved in water, how many liters of the stock solution would she need to have 97.9 grams NaCl? Remember the molar mass of NaCl is 58.44 g/mol.
Answer: There are 0.558 liters of the stock solution would she need to have 97.9 grams NaCl.
Explanation:
Given: Molarity = 3.0 M
Mass of NaCl = 97.9 g
Molar mass of NaCl = 58.44 g/mol
As number of moles is the mass of substance divided by its molar mass.
So, moles of NaCl are calculated as follows.
[tex]Moles = \frac{mass}{molar mass}\\= \frac{97.9 g}{58.44 g/mol}\\= 1.675 mol[/tex]
Molarity is the number of moles of a substance present in liter of a solution.
Therefore, volume of given solution is calculated as follows.
[tex]Molarity = \frac{moles}{Volume (in L)}\\3.0 M = \frac{1.675 mol}{Volume}\\Volume = 0.558 L[/tex]
Thus, we can conclude that there are 0.558 liters of the stock solution would she need to have 97.9 grams NaCl.
Possible interaction between oxygen molecule and water is ______________.
Answer:
Hydrogen Bonds
Explanation:
Opposite charges attract one another. The slight positive charges on the hydrogen atoms in a water molecule attract the slight negative charges on the oxygen atoms of other water molecules. This tiny force of attraction is called a hydrogen bond.
The solubility of CaSO4 in pure water at 0oC is 1.09 gram(s) per liter. The value of the solubility product is g
Answer: See image attached!
Good luck with your future exams!
The value of the solubility of product for CaSO₄ in pure water at 0 °C is 1.1881
What is solubility of product?The solubility of product (Ksp) is defined as the concentration of products raised to their coefficient coefficients. This is illustrated below:
mA <=> nC + eD
Ksp = [C]^n × [D]^e
With the above information in mind, we can obtain the solubility of the product. This is illustrated below:
Dissociation equationCaSO₄(aq) → Ca²⁺(aq) + SO₄²⁻(aq)
From the balanced equation above,
1 mole of CaSO₄ contains 1 mole of Ca²⁺ and 1 mole of SO₄²⁻
How to determine the concentration of Ca²⁺ and SO₄²⁻From the balanced equation above,
1 mole of CaSO₄ contains 1 mole of Ca²⁺ and 1 mole of SO₄²⁻
Therefore,
1.09 g/L of CaSO₄ will also contain
1.09 g/L of Ca²⁺1.09 g/L of SO₄²⁻ How to determine the solubility of product Concentration of Ca²⁺ = 1.09 g/L Concentration of SO₄²⁻ = 1.09 g/L Solubility of product (Ksp) =?CaSO₄(aq) → Ca²⁺(aq) + SO₄²⁻(aq)
Ksp = [Ca²⁺] × [SO₄²⁻]
Ksp = 1.09 × 1.09
Ksp = 1.1881
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how many moles of al is needed to replace all the iron from 5.6 moles of fe2o3
Help plz and thanks I will Mark you as BRAINLIEST
Answer:
did not mean to type that sorry i'm pretty sure the answers are c and b.
Explanation:
Answer:
Question 9
Explanation:
An everyday chemical reaction is rusting and iron reacts with oxygen to form rust
Question 8
Chemical reactions do not include fusion and fission only nuclear reactions like radioactivity
How many jouls are required to boiling 21.1 g of water at 100 c
Answer:
The needed heat is 47,65 Joules.
The number of Joules of heat is required to change the 21.1g of liquid water into steam at 100°C is 47686 Joules.
What is the latent heat of vaporization?The latent heat of vaporization is defined as the amount of heat needed at a constant temperature for the conversion of a liquid at its boiling point to gas. The latent heat of vaporization is different for different liquids.
The particles of water vapor at 100°C have more energy than that of liquid water. Because the extra energy is in the form of latent heat of vaporization. The word “latent” from the Latin word “latere" means to cover up or hide.
Given, the amount of water, m= 21.1 g
We know that, the heat of vapourization of water = [tex]2260 J/g[/tex]
The latent heat of vaporization (q) is calculated as:
q = mH
q = (21.1 g) × (2260J/g)
q = 47686 J
Therefore, the 47686 Joules are required to boil 21.1 g of water at a temperature of 100°C.
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Sample of 200mls of 0.5 sulphuric acid,was asked to produce 1.2M of the new solution.Calculate the volume of the new solution
Answer: The volume of the new solution is 83.33 mL.
Explanation:
Given: [tex]V_{1}[/tex] = 200 mL, [tex]M_{1}[/tex] = 0.5 M
[tex]V_{2}[/tex] = ?, [tex]M_{2}[/tex] = 1.2 M
Formula used to calculate the volume of new solution is as follows.
[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]
Substitute the values into above formula as follows.
[tex]M_{1}V_{1} = M_{2}V_{2}\\0.5 M \times 200 mL = 1.2 M \times V_{2}\\V_{2} = 83.33 mL[/tex]
Thus, we can conclude that volume of the new solution is 83.33 mL.
Can y’all please help me with these 2? I had surgery and missed this entire unit and it’s due Monday
In the laboratory a student combines 47.8 mL of a 0.321 M aluminum nitrate solution with 21.8 mL of a 0.366 M aluminum iodide solution.
What is the final concentration of aluminum cation ?
M
Answer: The final concentration of aluminum cation is 0.335 M.
Explanation:
Given: [tex]V_{1}[/tex] = 47.8 mL (1 mL = 0.001 L) = 0.0478 L
[tex]M_{1}[/tex] = 0.321 M, [tex]V_{2}[/tex] = 21.8 mL = 0.0218 L, [tex]M_{2}[/tex] = 0.366 M
As concentration of a substance is the moles of solute divided by volume of solution.
Hence, concentration of aluminum cation is calculated as follows.
[tex][Al^{3+}] = \frac{M_{1}V_{1} + M_{2}V_{2}}{V_{1} + V_{2}}[/tex]
Substitute the values into above formula as follows.
[tex][Al^{3+}] = \frac{M_{1}V_{1} + M_{2}V_{2}}{V_{1} + V_{2}}\\= \frac{0.321 M \times 0.0478 L + 0.366 M \times 0.0218 L}{0.0478 L + 0.0218 L}\\= \frac{0.0153438 + 0.0079788}{0.0696}\\= 0.335 M[/tex]
Thus, we can conclude that the final concentration of aluminum cation is 0.335 M.
what is the molecular formula of something with an empirical formula CO that has a molar mass of 56g/mol ?
Answer:
C₂O₂
Explanation:
Step 1: Given data
Empirical formula: COMolar mass of the molecular formula: 56 g/molStep 2: Calculate the molar mass of the empirical formula
M(CO) = 1 × M(C) + 1 × M(O) = 1 × 12 g/mol + 1 × 16 g/mol = 28 g/mol
Step 3: Calculate "n"
We will use the following expression.
n = molar mass of molecular formula / molar mass of empirical formula
n = (56 g/mol) / (28 g/mol) = 2
The molecular formula is:
CO × n = CO × 2 = C₂O₂
How many grams are in 3.7 moles of Na2O?
Answer:
mass = moles x molar mass
m= 3.7 x (23x2+16)
m= 3.7x62
m= 229.4g
198.4 grams are there is 3.7 moles of Na₂O.
The number of moles is defined as the ratio between given mass and molar mass.
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}\\\\[/tex]
Given:
Number of moles= 3.7 moles
To find:
Mass=?
Molar mass of Na₂O= 62 g/mol
Thus substituting the values in the given formula
[tex]\text{Given mass}=\text{Number of moles}*\text{Molar mass}\\\\\text{Given mass}= 3.2 \text{moles}*62 \text{g/mol}\\\\\text{Given mass}=198.4 \text{g}[/tex]
Thus, 198.4 grams are there is 3.7 moles of Na₂O.
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A gas occupies a volume of 584 mL at a pressure of 770 mm of Hg. When the pressure is changed, the volume becomes 603 mL If the temperature stays constant, what is the new pressure in mm of Hg?
Please help!!
Answer:
[tex]P_2=795mmHg[/tex]
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to calculate the final pressure by using the Boyle's law as an inversely proportional relationship in pressure to volume at constant temperature:
[tex]\frac{P_2}{V_2} =\frac{P_1}{V_1}[/tex]
Thus, we solve for our target, P2, to obtain:
[tex]P_2=\frac{P_1V_2}{V_1} =\frac{770mmHg*603mL}{584mL}\\\\P_2=795mmHg[/tex]
Regards!
Select two compounds below that can be used to make a buffer solution. Aacetic acid Bformate ion Csulfite ion Dcarbonate ion Eacetate ion Fhydrogen sulfide
Answer: Two compounds below that can be used to make a buffer solution are acetic acid and acetate ion.
Explanation:
A solution that helps in resisting change in pH when a small amount of acid or base is added to it is called a buffer solution.
A buffer solution consists of a mixture of weak acid and its conjugate base.
Acetic acid has a chemical formula [tex]CH_{3}COOH[/tex] and its conjugate base is [tex]CH_{3}COO^{-}[/tex].
This base is also called acetate ion.
Acetic acid is a weak acid because it dissociates weakly when added to a solvent like water.
Therefore, acetic acid and acetate ion will form a buffer solution.
Thus, we can conclude that two compounds below that can be used to make a buffer solution are acetic acid and acetate ion.
What is wrong with the statement below?
All chemicals are harmful to the environment in some way.
A. Chemicals may be harmful, helpful, or have little effect on the
environment.
B. Chemicals are not harmful to the environment unless they are
present in large amounts.
C. Chemicals are only helpful to the environment.
D. Chemicals do not affect the environment.
SUBMIT
Identify each of the following reactions as balanced or unbalanced
Which reactions are you referring to?
Can you add an image please?
or the reactions you are asking about?
1.Consider the molecule azulene and
a) set the secular determinant for azulene within the huckel approximation and using the out of plane C2p orbitals as basis set.
b) Estimate pi electron binding energy within the Huckel approximation
c) Approximate the delocalization energy
What volume of water is required to prepare 0.1 M H3PO4 from 100 ml of 0.5 M solution?
Answer: A volume of 500 mL water is required to prepare 0.1 M [tex]H_{3}PO_{4}[/tex] from 100 ml of 0.5 M solution.
Explanation:
Given: [tex]M_{1}[/tex] = 0.1 M, [tex]V_{1}[/tex] = ?
[tex]M_{2}[/tex] = 0.5 M, [tex]V_{2}[/tex] = 100 mL
Formula used to calculate the volume of water is as follows.
[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]
Substitute the values into above formula as follows.
[tex]M_{1}V_{1} = M_{2}V_{2}\\0.1 M \times V_{1} = 0.5 M \times 100 mL\\V_{1} = 500 mL[/tex]
Thus, we can conclude that a volume of 500 mL water is required to prepare 0.1 M [tex]H_{3}PO_{4}[/tex] from 100 ml of 0.5 M solution.
Put the steps in order to show how crystals are formed.
Formation of ions:
Formation of crystals:
Formation of ionic bonds:
Formation of cubes:
This Should Be Your Answer:
Step 1: Formation of ions
Step 2: Formation of ionic bonds
Step 3: Formation of cubes
Step 4: Formation of crystals
I Hope This Helps? :)
Answer:
Black Cats?
Explanation: