Find the zeros of y = 4x2 – 12x – 16

Answer:

(c) 3360

Step-by-step explanation:

Given

The above arithmetic series where:

[tex]T_1 = 12[/tex] --- first term

[tex]d = 6[/tex] --- the common difference (18 - 12 = 6)

[tex]T_n = 198[/tex] --- The last term

Required

The value of the series

First, we calculate n using:

[tex]T_n = T_1 + (n - 1)d[/tex]

This gives:

[tex]198 = 12 + (n - 1)*6[/tex]

Collect like terms

[tex]198 - 12 = (n - 1)*6[/tex]

[tex]186 = (n - 1)*6[/tex]

Divide both sides by 6

[tex]31 = (n - 1)[/tex]

Make n the subject

[tex]n = 31 + 1[/tex]

[tex]n=32[/tex]

The sum of the series is:

[tex]S_n= \frac{n}{2}(T_1 + T_n)[/tex]

So, we have:

[tex]S_n= \frac{32}{2}(12 + 198)[/tex]

[tex]S_n= \frac{32}{2}*210[/tex]

[tex]S_n= 16*210[/tex]

[tex]S_n= 3360[/tex]

The square of z varies inversely as the square root of e. If z=36 when w=16, then value of z is 24 when w=81.

A ratio is an ordered pair of numbers a and b, written a / b where b does not equal 0.

The square of z varies inversely as the square root of e.

If z=36 when w=16

The value of z when w is 81 we need to find

z²=k/√e

where k is a proportionality constant

36²=k/√16

36²=k/4

Apply cross multiplication

1296(4)=k

5184=k

Now let us find when k is 5184 and w is 81

z²=5184/9

z²=576

Take square root on both sides

z=24

Hence, the value of z is 24 when w is 81.

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Answer:

.83

Step-by-step explanation:

we want

(sports∩Senior)/Senior

we can see that sports∩senior= 25

and senior= 25+5+5=30

25/30= .83

Step-by-step explanation:

Edge 2021

Answer:      g(x) = Negative two-fifths(10)x

Step-by-step explanation:

In order to reflect a function over the x-axis, you have to multiply the function by minus one.

Given the function:

f(x) = 2/5(10)^x

Its reflection over the x-axis is:

-f(x) = -2/5(10)^x = g(x)

Answer:Hence.the answer is 14.

Step-by-step explanation:

Got it right on my test

Answer:

The correct answer is B.

Step-by-step explanation:

The opposite of Square root is squaring, which is ².

Answer:

[tex] \frac{ \sqrt{a} }{ \sqrt{b} } = x \\ [/tex]

squaring both the sides

[tex]{( \frac{ \sqrt{a} }{ \sqrt{b} }) }^{2} = x ^{2} \\ [/tex]

B. [tex] \frac{ {a} }{ {b} } = x {}^{2} \\ [/tex]

Answer:

Supplementary is your answer

Answer:

The correct answer is 5 2/15

Step-by-step explanation:

Since the numerators on both numbers are opposite, you have to go through an equation to make them equal.

4/5 and 1/3 don't have the same numerator. Because of this, you have to find the least common multiple.

5, 10, 15

3, 6, 9, 12, 15

Now that we found said number, we have to multiply the denominators so they match as well. How we do that is by multiplying the number by how many times the numerator has been multiplied to.

Since 5 had to be multiplied by 3 to get to 15, you would multiply 4 by three, giving you 12/15. Same goes with the other fraction, 3 times 5 got us 15, so we would multiply 1 by 5, giving us 5/15.

Now it's as simple as adding. 12/15 + 5/15 = 17/15, which will make 1 2/15. Add that to the whole numbers you have and you will get 5 2/15. (Note: You cannot simplify 2/15, so you leave it as is)

Answer:

=13 :D

Step-by-step explanation:

Im bIg BrAiN

Answer:

x=13

Step-by-step explanation:

See image below:)

If square C is 64 in^2, then its dimensions are 8 x 8.

If square D is 81 in^2, then its dimensions are 9 x 9.

Since D is bigger than C and I sits in that extra space, then the dimensions of I are 1 x 1.

Since H is smaller than C, specifically I smaller, than its dimensions are 7 x 7.

Then, H and C make up one side of B, so 7 + 8 = 15. The dimensions of B are 15 x 15.

Since E is bigger than D by I, then the dimensions of E are 10 x 10.

If we find the length of the right side (B + C + D), which is 15 + 8 + 9 = 32, then we know that F + E + D must also add up to 32. F + 10 + 9 = 32 || F = 13. The dimensions of F are 13 x 13.

Then, F is E + G, so 13 = 10 + G. G = 3. The dimensions of G are 3 x 3.

Lastly, since we know the side length of the whole square is 32, then A + F must equal 32. 32 = A + 13. A = 19. The dimensions of A are 19 x 19.

A = 19 x 19 = 361 in^2

B = 15 x 15 = 225 in^2

C = 8 x 8 = 64 in^2

D = 9 x 9 = 81 in^2

E = 10 x 10 = 100 in^2

F = 13 x 13 = 169 in^2

G = 3 x 3 = 9 in^2

H = 7 x 7 = 49 in^2

I = 1 x 1 = 1 in^2

Hope this helps!! :)

Answer:

cosine

Step-by-step explanation:

fundamental trigonometric identities

Answer:

[tex]12.6\pi\:\mathrm{km^2}\:\text{or }\frac{63}{5}\pi\:\mathrm{km^2}[/tex]

Step-by-step explanation:

The area of a sector with measure [tex]\theta[/tex] in degrees is given by [tex]r^2\pi\cdot\frac{\theta}{360}[/tex], where [tex]r[/tex] is the radius of the sector.

What we're given:

Substituting given values, we get:

[tex]A_{sec}=6^2\pi \cdot\frac{126}{360}=\boxed{12.6\pi\:\mathrm{km^2}}[/tex]

Step-by-step explanation:

6% of 35000

6/100×35000

=2100

hope it helps you

Step-by-step explanation:2100

Answer:

your image has the answer

Step-by-step explanation:

you can go type triangle calculator and type in everything

Answer:

C

Step-by-step explanation:

Open up = positive number that multiplies x^2

x - value of the vertex = -b/2a

C -> -10/2 = -5

Answer:

its 4 or B for the value of X

Answer:

[tex](a)\ P(x = 0) = 0.2725[/tex]

[tex](b)\ P(x \ge 1) =0.7275[/tex]

[tex](c)\ P(x \le 2) = 0.8948[/tex]

Step-by-step explanation:

Given

[tex]n = 8[/tex] --- 8 friends

[tex]p = 15\%[/tex] --- proportion that one-time fling

This question is an illustration of binomial probability, and it is represented as:

[tex]P(X = x) = ^nC_x* p^x * (1 - p)^{n-x}[/tex]

Solving (a): P(x = 0) --- None has done one time fling

[tex]P(x = 0) = ^8C_0* (15\%)^0 * (1 - 15\%)^{8-0}[/tex]

[tex]P(x = 0) = 1* 1 * (1 - 0.15)^{8}[/tex]

[tex]P(x = 0) = 0.85^8[/tex]

[tex]P(x = 0) = 0.2725[/tex]

Solving (b): [tex]P(x \ge 1)[/tex]

To do this, we make use of compliment rule:

[tex]P(x = 0) + P(x \ge 1) =1[/tex]

Rewrite as:

[tex]P(x \ge 1) =1 - P(x = 0)[/tex]

[tex]P(x \ge 1) =1 - 0.2725[/tex]

[tex]P(x \ge 1) =0.7275[/tex]

Solving (c): [tex]P(x\le 2)[/tex]--- Not more than 2 has one time fling

This is calculated as:

[tex]P(x\le 2) = P(x = 0) + P(x =1) + P(x = 2)[/tex]

We have:

[tex]P(x = 0) = 0.2725[/tex]

[tex]P(x = 1) = ^8C_1* (15\%)^1 * (1 - 15\%)^{8-1}[/tex]

[tex]P(x = 1) = 8* (0.15) * (1 - 0.15)^7[/tex]

[tex]P(x = 1) = 0.3847[/tex]

[tex]P(x = 2) = ^8C_2* (15\%)^2 * (1 - 15\%)^{8-2}[/tex]

[tex]P(x = 2) = 28* (0.15)^2 * (1-0.15)^6[/tex]

[tex]P(x = 2) = 0.2376[/tex]

So:

[tex]P(x\le 2) = P(x = 0) + P(x =1) + P(x = 2)[/tex]

[tex]P(x \le 2) = 0.2725 + 0.3847 + 0.2376[/tex]

[tex]P(x \le 2) = 0.8948[/tex]

Answer:

A) x = 0 and x = 3π∕4

Step-by-step explanation:

cot 0° = oo (infinite)

4/3 x = 0

=> x = 0

cot 180° = oo (infinite)

4/3 x= 180

x = 3/4 × 180

= 135°

= ¾π

Answer:

x=2at/(1+t²)

dx/dt =[(1+t²)(2at)'-(2at)(1+t²)']/(1+t²)²

dx/dt=[(1+t²)(2a)-(2at)(2t)]/(1+t²)²

dx/dt=[2a+2at²-4at²]/(1+t²)²

dx/dt=[2a-2at²]/(1+t²)²

y=[b(1-t²)]/(1+t²)

dy/dt=[(1+t²)(b(1-t²))'-b(1-t²)(1+t²)']/(1+t²)²

dy/dt=[((1+t²)(-2bt)-b(1-t²)(2t)]/(1+t²)²

dy/dt=(-2bt-2bt³-2bt+2bt³)/(1+t²)²

dy/dt=(-4bt)/(1+t²)²

dy/dx=(dy/dt)/(dx/dt)

dy/dx=[(-4bt)/(1+t²)²]/[(2a-2at²)/(1+t²)²]

Cancelling common denominator

dy/dx=(-4bt)/(2a-2at²)

dy/dx=(-2bt)/(a-at²)

dy/dx=(2bt)/(at²-a)

Differentiating the above equation

y''=d²y/dx²=D[(2bt)/(at²-a)]

y''=[(at²-a)D(2bt)-(2bt)D(at²-a)]/(at²-a)²

y''=[(at²-a)(2b)(dt/dx)-(2bt)(2at)(dt/dx)]/(at²-a)²

dt/dx=(1+t²)²/(2a-2at²)

y''=[(at²-a)(2b)[(1+t²)²/(2a(1-t²))]-

(4abt²)[(1+t²)²/(2a-2at²)]/(at²-a)²

y''=[(-b)(1+t²)²-(2bt²)[(1+t²)²/(1-t²)]/(at²-a)²

y''=[(-b)(1+t²)²(1-t²)-(2bt²)(1+t²)²]/[(1-t²)(at²-a)²]

y''=[b(1+t²)²(t²-1)-2bt²(1+t²)²]/[(1-t²)(at²-a)²]

Step-by-step explanation:

Answer:

add two and five is the first step beacuse there in ()

Step-by-step explanation:

Answer:

Parentheses. Add 2 and 5.

Step-by-step explanation:

Use the P.E.M.D.A.S expression. (Parentheses, Exponents, Multiplication, Division, Addition, Subtraction.) As you can see, there are parentheses in your expression, so use PEMDAS to do order of operations problems like this.

Answer:

the answer is 24%

Step-by-step explanation:

quizzes.com

Answer:

13. zero slope

14. 1/2

15. undefined slope

16.-3/2 slope

Answer:

−0.2542372881

Answer:

Step-by-step explanation:

We first turn 3x+4y=12 into standard form:

4y=-3x+12

y=-3/4x+3

By knowing the 2nd line is parallel to the first, the slopes are the same:

y=-3/4x+b

Plugging in (5,4) into the equation:

4=-15/4+b

b=1/4

Final equation=y=-3/4+1/4.

The required speed of the driver is 33.4 mph.

To determine how fast was a driver going and if it left skid marks that were 63 feet long on wet concrete. (The coefficient of friction is 0.97)?

Speed is the ratio of distance traveled to time taken to travel that distance.

Friction is defined as resistance force from one surface to the other between two solid materials caused by reciprocal movement is called friction. And the force applied is called friction force.

Since from given
f = 0.97
left skid marks that were 63 feet long on wet concrete.
d = 63 feets
g = 9.8

V = √( 2g * F * D )
V = √(2 * 9.8 * 0.97 * 63 )
V = 33.4mph

Thus, The required speed of the driver is 33.4 mph.

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[tex]\huge\textsf{Hey there!}[/tex]

[tex]\mathsf{f(x) = 2\dfrac{1}{2}-3\dfrac{1}{3}}[/tex]

[tex]\rightarrow\mathsf{y = 2\dfrac{1}{2}- 3\dfrac{1}{3}}[/tex]

[tex]\rightarrow\mathsf{y = \dfrac{5}{2}- \dfrac{10}{3}}[/tex]

[tex]\rightarrow\mathsf{y =( \dfrac{5}{2}\times\dfrac{3}{3}) - (\dfrac{10}{3}\times\dfrac{2}{2})}[/tex]

[tex]\mathsf{5\times3=\boxed{\bf 15}}\\\\\mathsf{2\times3=\boxed{\bf 6}}}\\\\\mathsf{10\times2=\boxed{\bf 20}}\\\\\mathsf{3\times2=\boxed{\bf 6}}[/tex]

[tex]\rightarrow{\mathsf{y =\dfrac{15}{6}-\dfrac{20}{6}}[/tex]

[tex]\rightarrow\mathsf{y = \dfrac{15-20}{6}}[/tex]

[tex]\mathsf{15-20=\boxed{\bf -5}}\\\\\\\mathsf{6= \boxed{\bf 6}}\textsf{ because \underline{6} is the LCD (\underline{L}east \underline{C}ommon \underline{D}enominator}[/tex]

[tex]\boxed{\mathsf{y =\bf -\dfrac{5}{6}}}[/tex]

[tex]\boxed{\boxed{\large\textsf{Answer: \bf y = }\mathsf{\bf -\dfrac{5}{6}}}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

its jess

here is ur ans

first option is your answer

• ANGLE 2 AND ANGLE 6 ARE CONGRUENT BECAUSE THEY ARE CORRESPONDING ANGLES.

Answer:

(-8,-3)

(-4,-1)

(0,1)

(2,2)

(6,4)

Step-by-step explanation:

One by one, substitue the x values and solve for y

Answer:

negative 4

Step-by-step explanation:

go