Answer:
y = -6/7x + 16
Step-by-step explanation:
Use the slope intercept equation, y = mx + b
Plug in the slope and given point, then solve for b:
y = mx + b
4 = -6/7(14) + b
4 = -12 + b
16 = b
Plug in the slope and b into the equation:
y = mx + b
y = -6/7x + 16
So, the equation is y = -6/7x + 16
PLS HELP ASAP! THANK YOU.
PS, WILL MARK BRAINLIEST
Answer:
V =110 in ^3
Step-by-step explanation:
The volume is
V = l*w*h
V = 10 * 2 * 5.5
V =110 in ^3
Solve tan(x+π2)+tan(x−π2)=2 for 0≤x<2π
In the interval 0≤x <π, the solution is
Answer:
[tex]x = \pi \div 4 [/tex]
In the figure below, ZAPE and ZEPD are congruent.
What is the arc measure of major arc BAD on circle P in degrees?
Answer:
54degrees
Step-by-step explanation:
From the given diagram;
2<P + 136 + 74 + 42 = 360 (sum of angle at a point is 360degrees)
2<P +252 = 360
2<P = 360 - 252
2<P = 108
<P = 108/2
<P = 54
Hence the measure of <P is 54degrees
The mean arrival rate of flights at O'Hare Airport in marginal weather is 195 flights per hour with a historical standard deviation of 16 flights. To increase arrivals, a new air traffic control procedure is implemented. In the next 30 days of marginal weather, the mean arrival rate is 200 flights per hour.
207 204 175 193 208 187 213 220 176 213
204 206 224 216 186 184 216 204 209 186
215 204 216 224 184 197 176 181 197 175
Required:
Set up a right-tailed decision rule at α = 0.025 to decide whether there has been a significant increase in the mean number of arrivals per hour.
Answer:
that there is no significant evidence that there is an increase in mean number of arrivals per hour
Step-by-step explanation:
The hypothesis :
H0 : μ = 195
H1 : μ > 195
We obtain the test statistic :
(xbar - μ) ÷ (σ/√(n))
xbar = 200 ; n = 30 ; σ = 16
Test statistic :
(200 - 195) ÷ (16/√(30))
5 ÷ 2.9211869
= 1.712
Using the Pvalue calculator :
Pvalue from Test statistic = 0.043
At α = 0.025
Pvalue > α ; we fail to reject the Null and conclude that there is no significant evidence that there is an increase in mean number of arrivals per hour.
For the piecewise function, find the values h(-9), h(O), h(2), and h(7).
- 5x - 13, for x< -7
h(x) = { 2,
for - 75x<2
X+9,
for x 22
h(-9) = 32
h(0)= 2
h(2) =11
h(7)= 16
Choose ALL the right triangles.
Answer:
Bottom left corner and bottom right corner
Step-by-step explanation:
the orange one and the blue one on the bottom
Please help! What is the area in square units?
9514 1404 393
Answer:
103 square units
Step-by-step explanation:
There is a way to find the area by counting grid points, but the fairly large number of them suggests that could be both tedious and prone to error. Instead, we'll chop up the figure into a trapezoid and two triangles.
From the top corner of the right edge draw a horizontal line across the figure. This will make the bottom portion a trapezoid and the top portion two triangles. The length of that horizontal line is 13 units, the height of the trapezoid, and the sum of the triangle bases.
The bottom trapezoid has a left-side base of 7 units and a right-side base of 6 units. Its area is ...
A = 1/2(b1 +b2)h
A = 1/2(7 +6)(13) = 1/2(13)(13) = 169/2 = 84.5 . . . square units.
The right top triangle has a base of 11 and a height of 3, so its area is ...
A = 1/2bh
A = 1/2(11)(3) = 33/2 = 16.5 . . . square units
The left top triangle has a base and height of 2 units each, so its area is ...
A = 1/2(2)(2) = 2 . . . square units
Then the total area of the figure is ...
84.5 +16.5 +2 = 103 . . . square units
_____
Check
Here is the check by counting grid points. The number of grid points on the outline of the figure is i=22. The number of grid points inside the figure appears to be b=93. Then the area by Pick's theorem is ...
b +i/2 -1 = 93 + 22/2 -1 = 103 . . . square units
Find tan(B) in the triangle.
c. 5/12
Step-by-step explanation:
tan= opposite/adjacent
[tex]{\huge{\underline{\bf{\pink{Hello \: mate \: (◕ᴗ◕✿)}}}}} \\ \\ = > \mathcal\blue{tan \beta = perpendicular \: \div base\: } \\ \\ \mathcal\blue{=>perpendicular = 5 \: } \\ \\\blue{=>Base = 12 \: } \\ \\ \\ \huge\mathfrak\red{=>tan \beta = 5 /12\: } \\ \\ {\huge{\boxed{\sf{\green{✓✓venom✓✓}}}}}[/tex]
hey found that 27 occurred in the Spring, 39 in the Summer, 31 in the Fall, and 53 in the Winter. Can it be concluded at the 0.05 level of significance that car accidents are not equally distributed throughout the year
This question is incomplete, the complete question is;
A Driver's Ed program is curious if the time of year has an impact on numer of car accidents in the U.S.
They assume that weather may have a significant impact on the ability of drivers to control their vehicles. They take a random sample of 150 car accidents and record the seasons each occurred in. They found that 27 occurred in the Spring, 39 in the Summer, 31 in the Fall, and 53 in the Winter. Can it be concluded at the 0.05 level of significance that car accidents are not equally distributed throughout the year
a) Yes, because the p-value = 0.0145
b) No, because the p-value = 0.0145
c) Yes, because the p-value = 0.0291
d) No, because the p-value = 0.0291
Answer:
p-value = 0.0145
Since p-value ( 0.0145 ) is less than Significance level ∝ ( 0.05 ),
We reject Null hypothesis.
Hence, There is sufficient evidence to conclude that car accidents are NOT equally distributed through out the year.
[ Option a) Yes, because the p-value = 0.0145 ] is the correct answer.
Step-by-step explanation:
Given the data in the question;
number of car accident = 150
Observed Frequencies O are;
Spring = 27
Summer = 39
Fall = 31
Winter = 53
Significance level ∝ = 0.05
Hypothesis
Null hypothesis H₀ : The car accidents are equally distributed through out the year
Alternative hypothesis H₀ : The car accidents are NOT equally distributed through out the year
Now, Expected Frequency E will be;
Spring = 150/4 = 37.5
Summer = 150/4 = 37.5
Fall = 150/4 = 37.5
Winter = 150/4 = 37.5
Test Statistics;
[tex]X^2_{stat^[/tex] = ∑[ ( O-E )² / E ]
so
[tex]X^2_{stat^[/tex] = [ ( 27-37.5 )² / 37.5 ] + [ ( 39-37.5 )² / 37.5 ] + [ ( 31-37.5 )² / 37.5 ] + [ ( 53-37.5 )² / 37.5 ]
[tex]X^2_{stat^[/tex] = 2.94 + 0.06 + 1.1267 + 6.4067
[tex]X^2_{stat^[/tex] = 2.94 + 0.06 + 1.1267 + 6.4067
[tex]X^2_{stat^[/tex] = 10.5334
Degree of Freedom DF = n-1 = 4 -1 = 3
Now,
p-value = P( [tex]X^2[/tex] - [tex]X^2_{stat^[/tex] ) = P( [tex]X^2[/tex] - 10.5334 ) = 0.0145
p-value = 0.0145
Since p-value ( 0.0145 ) is less than Significance level ∝ ( 0.05 ),
We reject Null hypothesis.
Hence, There is sufficient evidence to conclude that car accidents are NOT equally distributed through out the year.
[ Option a) Yes, because the p-value = 0.0145 ] is the correct answer.
Please I need help! Thank you
Step-by-step explanation:
everything can be found in the picture
Answer:
h = [tex]\frac{K^2}{17}[/tex]
Step-by-step explanation:
Given
K = [tex]\sqrt{17h}[/tex] ( square both sides )
K² = 17h ( divide both sides by 17 )
[tex]\frac{K^2}{17}[/tex] = h
\int\limits^0_∞ cos{x} \, dx
Answer:
[tex]\displaystyle \int\limits^0_\infty {cos(x)} \, dx = sin(\infty)[/tex]
General Formulas and Concepts:
Pre-Calculus
Unit CircleTrig GraphsCalculus
LimitsLimit Rule [Variable Direct Substitution]: [tex]\displaystyle \lim_{x \to c} x = c[/tex]IntegralsIntegration Rule [Fundamental Theorem of Calculus 1]: [tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]Trig IntegrationImproper IntegralsStep-by-step explanation:
Step 1: Define
Identify
[tex]\displaystyle \int\limits^0_\infty {cos(x)} \, dx[/tex]
Step 2: Integrate
[Improper Integral] Rewrite: [tex]\displaystyle \lim_{a \to \infty} \int\limits^0_a {cos(x)} \, dx[/tex][Integral] Trig Integration: [tex]\displaystyle \lim_{a \to \infty} sin(x) \bigg| \limits^0_a[/tex][Integral] Evaluate [Integration Rule - FTC 1]: [tex]\displaystyle \lim_{a \to \infty} sin(0) - sin(a)[/tex]Evaluate trig: [tex]\displaystyle \lim_{a \to \infty} -sin(a)[/tex]Evaluate limit [Limit Rule - Variable Direct Substitution]: [tex]\displaystyle -sin(\infty)[/tex]Since we are dealing with infinity of functions, we can do a numerous amount of things:
Since -sin(x) is a shift from the parent graph sin(x), we can say that -sin(∞) = sin(∞) since sin(x) is an oscillating graph. The values of -sin(x) already have values in sin(x).Since sin(x) is an oscillating graph, we can also say that the integral actually equates to undefined, since it will never reach 1 certain value.∴ [tex]\displaystyle \int\limits^0_\infty {cos(x)} \, dx = sin(\infty) \ or \ \text{unde}\text{fined}[/tex]
Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Improper Integrals
Book: College Calculus 10e
The defensive coaches had hoped that the average number of tackles of the opponent’s QB would increase during the game in a distribution of 15% of the tackles in the first quarter,15% in the second,30% in the third, and 40% in the fourth. The mean number of tackles for the 2007 season was as follows: 37, 35, 73, 40. Did the mean sacks per game fit the desired distribution? Let a = 0.10.
Beth has to carry 9 grocery bags into the house. each grocery bag weighs 5 6/10 pounds. how many pounds does beth carry in all? steps??
Answer: [tex]50\frac{2}{5}[/tex] or 50.4 pounds
Step-by-step explanation:
You multiply:
[tex]9*5\frac{6}{10} \\\\=9*\frac{56}{10} (5\frac{6}{10} =\frac{5(10)+6}{10} =\frac{50+6}{10} =\frac{56}{10} )\\\\=\frac{9*56}{10} =\frac{504}{10}\\\\ =\frac{2(252)}{2(5)}=\frac{252}{5} =50.4[/tex]
Which of the statement(s) about the graph shown are true? Select all that apply.
Answer: Is there a picture?
Step-by-step explanation:
PLS PLS PLSSSSSSSSSSS
Answer:
20%decrease? id.k if its decrease or increase but its 20%
Step-by-step explanation:
Surface area helpp needed
Answer:
144 un²
Step-by-step explanation:
Front Parallelogram = 5 x 11 = 55
Two triangles = 3 x 4 = 12
Back Parallelogram = 3 x 11 = 33
Bottom rectangle = 4 x 11 = 44
Total =
55 + 12 + 33 + 44 = 144
units = un²
144 un²
If my answer is incorrect, pls correct me!
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-Chetan K
Duncan is investigating if residents of a city support the construction of a new school. He is curious about the difference of opinion between residents in north and south parts of the city. He obtained separate random samples of voter from each region. Here are results:
Support Construction North South
Yes 274 240
No 726 520
Total 1000 760
Duncan wants to use these results to construct a 95% confidence of interval to estimate the difference in the proportion of the residents in these regions who support the construction (PN-Ps). Assume that all of the condition for inference have been met.
Answer:
The 95% confidence of interval to estimate the difference in the proportion of the residents in these regions who support the construction is (-0.0849, 0.0013).
Step-by-step explanation:
Before building the confidence interval, we need to understand the central limit theorem and subtraction of normal variables.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
Subtraction between normal variables:
When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.
North:
274 out of 1000. So
[tex]p_N = \frac{274}{1000} = 0.274, s_N = \sqrt{\frac{0.274*0.726}{1000}} = 0.0141[/tex]
South
240 out of 760. So
[tex]p_S = \frac{240}{760} = 0.3158, s_S = \sqrt{\frac{0.3158*0.6842}{760}} = 0.0169[/tex]
Distribution of the difference:
[tex]p = p_N - p_S = 0.274 - 0.3158 = -0.0418[/tex]
[tex]s = \sqrt{s_N^2+s_S^2} = \sqrt{0.0141^2+0.0169^2} = 0.022[/tex]
Confidence interval:
The confidence interval is:
[tex]p \pm zs[/tex]
In which
z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].
95% confidence level
So [tex]\alpha = 0.05[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].
Lower bound:
[tex]p - zs = -0.0418 - 1.96*0.022 = -0.0849[/tex]
Upper bound:
[tex]p + zs = -0.0418 + 1.96*0.022 = 0.0013[/tex]
The 95% confidence of interval to estimate the difference in the proportion of the residents in these regions who support the construction is (-0.0849, 0.0013).
Given the proportion and number of residents in the North and South of
0.274, 1000, and approximately 0.316, 760, we have;
The 95% Confidence interval for the difference in proportion of those in support of the construction is; C.I. = (-0.085, 0.00109)How can the confidence interval be found?The given parameter presented in a tabular form are;
[tex]\begin{array}{|c|c|c|}Support \ Constructtion&North&South\\Yes&274&240\\No&726&520\\Total & 1000& 760\end{array}\right][/tex]
Which gives;
Proportion of the North resident that support, [tex]\mathbf{\hat p_N}[/tex] = 274 ÷ 1000 = 0.274
The number of people sampled in the north, n₁ = 1,000
Proportion of the South resident that support, [tex]\mathbf{\hat p_S}[/tex] = 240 ÷ 760 ≈ 0.316
The number of people sampled in the south, n₂ = 760
The confidence interval for the difference of two proportions are given
as follows;
[tex]\hat{p}_N-\hat{p}_S\pm \mathbf{ z^{*}\sqrt{\dfrac{\hat{p}_N \cdot \left (1-\hat{p}_N \right )}{n_{1}}+\dfrac{\hat{p}_S \cdot \left (1-\hat{p}_S \right )}{n_{2}}}}[/tex]
Where;
The z-score at 95% confidence level is 1.96
Which gives;
[tex]C.I. = \left(0.274-0.316 \right)\pm 1.96 \times \sqrt{\dfrac{0.274 \times \left (1-0.274 \right )}{1000}+\dfrac{0.316 \times \left (1-0.316 \right )}{760}}[/tex]
C.I. ≈ (-0.085, 0.00109)
The 95% confidence interval, C. I. of the difference in the proportion of
the residents in the regions who support the construction, [tex]\hat p_N[/tex] - [tex]\hat p_S[/tex] is
therefore;
[tex]\underline{C.I. = (-0.085, \, 0.00109)}[/tex]Learn more calculating the confidence interval here:
https://brainly.com/question/15308274
what is 0.61 recurring as a fraction?
Answer:
11/18
no clue how i got it just got it
Answer:
61/99
Step-by-step explanation:
Usually, all reoccurring double digit numbers have the denominator of 99. Also, if you have a TI-30XIIS calculator, just put the repeating decimal, and press 2nd and then PRB. It will show up as a fraction!
what's the meaning of bobo?
A box contains 35 gems, of which 10 are real diamonds and 25 are fake diamonds. Gems are randomly taken out of the box, one at a time without replacement. What is the probability that exactly 2 fakes are selected before the second real diamond is selected
Answer:
Step-by-step explanation:
The total number of ways of selecting 3 gems of any kind without replacement is 35 * 34 * 33 = 39270
Now selecting 2 gems from 25 is 25C2
25 C 2 = 25 * 24/2 = 300
Selecting one good gem is 10
Total selection = 300 * 10 = 3000
P(gems) = 3000 / 39270
P(gems) = 300/3927
P(gems) = 100/1309
someone please help!
HELP PLEASE I need help please
9514 1404 393
Answer:
A) B. 18-6
B) 20÷4
C) 20
Step-by-step explanation:
Part A
The order of operations tells you that the first step is to evaluate any expressions in parentheses. Here, that means you first evaluate (18 -6).
__
Part B
After parentheses have been removed, the next step is to perform multiplication and division. Here, there is only one term involving division, so you divide 20 by 4 as your second step.
__
Part C
After you have done parts A and B, your expression is ...
3 + 12 + 5
The value of this sum is 20.
. An aquarium contains 50 gallons of water. When the plug is pulled, water drains from the aquarium at a rate of 2 gallons per minute. How many gallons of water still remain in the aquarium after 8 minutes?
Answer:
34 gallons
Step-by-step explanation:
Water in tank = starting amount - rate * time
water in tank = 50 - 2 * time
Let the time = 8 minutes
water in tank = 50 - 2 * 8
= 50 - 16
= 34
Answer:
34 gallons still remain after 8 minutes.
Step-by-step explanation:
Variable x = gallons of water after 8 mins
2 gallons = 1 min
x gallons = 8 mins
Set up an equation:
2/1 = x/8
Cross multiply:
2 × 8 = 1 × x
16 = x
16 gallons of water are drained after 8 minutes.
Find the difference:
50 - 16 = 34
34 gallons still remain after 8 minutes.
ASAP what’s the answerrr step by step pleaseee
If you know how to solve this, Please answer it. Thank You
Please show your work and the steps.
The first one to answer the question right, will get Brainlist!
I PROMISE!!!!!
The answer is in the picture. To be honest, I am not 100% sure about it.
A triangle has sides with lengths of 12 yards, 16 yards, and 20 yards. Is
it a right triangle? Yes or No
What measure of positions divides the data into 100?
Answer:
the answer to this question would be percentiles
Which equation is correct regarding the measure of
<1?
O m_1 = {(a-c)
O mz1 = = {(a + c)
Om 1 =
= {(6-0)
O m_1 = {(b + )
Answer:
m<1 = ½(b - d)
Step-by-step explanation:
Recall: when two secants intersect to form an exterior angle outside a circle, the measure of the exterior angle equals half of the difference of the major and minor arcs intersected.
Thus, in the problem given,
m<1 is the exterior angle
b and d are the arcs intersected.
Therefore,
m<1 = ½(b - d)
The equation that is correct regarding the measure of <1 is; m<1 = ½(b - d)
What is the Secant theorem of a circle?
According to the secant theorem, it states that when two secants intersect to form an exterior angle outside a circle, then the measure of the exterior angle will be equal to half of the difference of the major and minor arcs intersected.
In the given question, we can see that;
The exterior angle = m<1
The arcs intersected are b and d
Thus, from applying the secant theorem, we can express that;
m<1 = ½(b - d)
Read more about the secant theorem at; https://brainly.com/question/26340897
Will mark Brainlest Help me
(If the antecedent of a ratio is 15 and the value of ratio is 5, what is the consequent)
step by step i will promise mark brainlest
Answer:
3
Step-by-step explanation:
A ratio is always expressed in the form a : b = a / b ; where, a = antecedent ; b = consequent
With antecedent = 15 ; consequent = b
Value of ratio = 5
15 / b = 5
Cross multiply
15 = 5b
b = 15 / 5
b = 3
In 8 hours Jose can bake 288 cupcakes how many cupcakes per hour can he Bake
Answer:
36 cupcakes per hour
Step-by-step explanation:
288 cupcakes divided by 8 hours
288/8=36