Does the point (-7, 5) satisfy the inequality y > -3/7x +2

There is not evidence that the population mean waiting time is different from 3.6 ​minutes.

What is the p-value?

A statistical measurement known as a p-value is employed to check a hypothesis' validity against actual data. A p-value calculates the likelihood of getting the outcomes that were observed, presuming that the null hypothesis is correct. The statistical significance of the difference that was found increases with decreasing p-value.

From the question, we know that the size (n), the mean (x), and the standard deviation (s) of the sample are 81, 3.45 minutes and 0.9 minutes. Additionally, we are going to decide if the waiting time is different or not from 3.6 minutes, so the null and alternative hypotheses are:

H0: m=3.6

H1:  m≠3.6

Where m is the mean of the population.

Then, we don't need to be concerned about the shape of the population distribution because the value of the n is bigger than 30 and we can use the statistic z as:

[tex]z = \frac{x-m}{\frac{a}{\sqrt{n} } }[/tex]

So, replacing the values, the test statistic is:

[tex]z = \frac{3.45 - 3.6}{\frac{0.9}{\sqrt{81} } }[/tex]

= 2.50

On the other hand, the p-value for this test is calculated as:

p-value = 2P(z >2.50) = 2(0.0668) = 0.134

Taking into account that the p-value is bigger than the level of significance 0.01, the null hypothesis is not rejected, and there is not evidence that the population mean waiting time is different from 3.6 ​minutes.

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Given that a population proportion represents the proportion of successes within a population and that there must be two outcomes (categories), success and failure, a confidence interval about a population proportion only makes sense for qualitative variables.

A confidence interval (CI) is a range of estimates for an unknown parameter in frequentist statistics.

The 95% confidence level is the most popular, however other levels, such 90% or 99%, are occasionally used when computing confidence intervals.

The percentage of related CIs over the long run that include the parameter's actual value is represented by the confidence level. For instance, 95% of all intervals calculated at the 95% confidence level should include the parameter's actual value.

The sample size, sample variability, and confidence level are all variables that have an impact on the CI's width

Assuming all other factors remained constant, a larger sample would result in a narrower confidence range. Additionally, more sample variability results in a wider range of.

Hence,  a population proportion represents the proportion of successes within a population and that there must be two outcomes (categories), success and failure, a confidence interval about a population proportion only makes sense for qualitative variables.

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Answer:

seven and seven hundred nintey three thousandths

Step-by-step explanation:

Mathematically, three dwarf hamsters can live in the cage Harriet purchased.

The number of dwarf hamsters that can live in Harriet's cage is determined using mathematical operations, including multiplication and division.

Mathematical operations involve the manipulation of numbers, variables, and mathematical operands to determine mathematical results.

The result of an addition is known as the sum while for a subtraction operation is the difference.

The result of a multiplication operation is known as the product like a dvision operation (also called the quotient).

The height of the cage = 12 inches or 1 foot

The length of the cage = 2¹/₃  feet

The area of the cage = 2¹/₃ ft² (1 x 2¹/₃)

The living space required by each dwarf hamster = ²/₃ ft²

The number of dwarf hamsters that can live in the cage = 3.499 (2¹/₃ ÷ ²/₃).

= 3

Thus, using mathematical operations, we can determine that the highest number of dwarf hamsters that can live in Harriet's cage is three.

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Answer:

[tex]\boxed{\tt v < 6.8}[/tex]

Step-by-step explanation:

[tex]\tt 0.5v+0.06 < 3.46[/tex]

Multiply both sides by 100:-

[tex]\tt 0.5v\times\:100+0.06\times\:100 < 3.46\times\:100[/tex]

[tex]\tt 50v+6 < 346[/tex]

Subtract 6 from both sides:-

[tex]\tt 50v < 340[/tex]

Divide both sides by 50:-

[tex]\tt \cfrac{50v}{50} < \cfrac{340}{50}[/tex]

[tex]\tt v < \cfrac{34}{5}[/tex]

Or

[tex]\tt v < 6.8[/tex]

Therefore, your answer is v < 6.8!!! :)

______________________

Hope this helps!

Have a great day!

The total number of hours spend on the communicating is 11.2 hours each day..

As the stated question-

Average number of waking hour per day = 16.

Communicating hours = 70% of total hours.

Thus,

Communicating hours =  70 x 16 / 100

Communicating hours = 11.2 hours

Thus, the total number of hours spend on the communicating is 11.2 hours.

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Answer: 3 boxes

Step-by-step explanation:

6 x 5 = 30

36(closest multiple of 12 to 30) divided by 12 = 3

Answer:

2.5 boxes

Step-by-step explanation:

So, if each friend wants 5 cookies then you would multiply 6*5 which =30. Then you would divide 30 by 12 boxes which = 2.5. So you need 2.5 boxes or 3 if they need to be whole.

Equation 1 needs to be multiplied with + 2

Equation 2 needs to be multiplied with  + 5.

Step-by-step explanation:

Here, the given system of equation is given as:

Equation 1 : 6 x − 5 y = -4

Equation 2: 4 x + 2 y = 28

Here, in equation 1, the coefficient of y  = - 5

Also, in the equation 2, the coefficient of  y = + 2

Now, in order to eliminate the y coefficients,

Coefficient  of y in  1  =   -  Coefficient of y in  2

Now, to make -5 and  + 2 to eliminate each other,

Multiply -5 with 2, we get            -5 x 2  = -10

And Multiply the coefficient + 2 with 5, we get   +2 x 5  = + 10

The new coefficient of y is equation 1 = - 10 y

The new coefficient of y in equation 2  = + 10 y

They will cancel out each other, when both equations are ADDED.

Hence, equation 1 needs to be multiplied with + 2

and the equation 2 needs to be multiplied with  + 5.

Round to the closest whole percent, 23% of the participants in the event are under the age of 20.

For the stated question-

Total number of people = 30 + 50 + 40 + 10

Total number of people = 130

Number of participants are under the age of 20 = 30.

Let 'x' be the % of the participants are under the age of 20.

Thus,

x% of 130 = 30

x = 30 x 100 / 130

x = 23.07

x = 23%

Thus, round to the closest whole percent, 23% of the participants in the event are under age of 20.

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Answer: 0.69

Step-by-step explanation:

0.44 + 0.25 = 0.69

The correct answer is [tex]\boxed{0.69}[/tex]

For this question we will be adding the numbers given.

Given:

[tex]0.44\\0.25[/tex]

Therefore, the equation is:

[tex]\boxed{0.44 +0.25}[/tex]

Therefore, the correct answer is [tex]\boxed{0.69}[/tex]

The number of fish in year 6 will be;

⇒ y = 438.60

What is an expression?

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

The exponential regression equation is,

⇒ y = 14.08 × 2.08ˣ

Where, x is represent the year.

Now,

Since, The exponential regression equation is,

⇒ y = 14.08 × 2.08ˣ

Where, x is represent the year.

Hence, The number of fish in year 6 will be;

⇒ y = 14.08 × 2.08ˣ

⇒ y = 14.08 × 2.08⁶

⇒ y = 14.08 × 31.15

⇒ y = 438.60

Thus, The number of fish in year 6 will be;

⇒ y = 438.60

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Answer:

The answer might be C.(x=0)

Step-by-step explanation:

hope this helps!

Answer:

Step-by-step explanation:

You need to set the problem up like this:

         back in for all the 'x's

        should be 20

Consider a sequence of random variables X1, X2, X3, ⋯ that is defined on an underlying sample space S. For simplicity, let us assume that S is a finite set, so we can write

                                    S = {s₁, s₂,⋯,sₙ }.

Remember that each Xₙ is a function from S to the set of real numbers. Thus, we may write

                       Xₙ (sₐ) = xₙₐ,           for a=1,2,⋯,k.

After this random experiment is performed, one of the sₐ' s will be the outcome of the experiment, and the values of the Xₙ's are known. If sₐ is the outcome of the experiment, we observe the following sequence:

x₁ₐ ,x₂ₐ,x₃ₐ,⋯.

Let [Xₙ] be a sequence of square integral random variables defined on a sample space Omega. We say that [Xₙ] is mean-square convergent (or convergent in mean-square) if and only if there exists a square integral random variable X such that

                                   [tex]\lim_{n \to \infty} E[ X_{n} - X^{2} ][/tex]

Convergence in distribution is in some sense the weakest type of convergence. All it says is that the CDF of Xₙ's converges to the CDF of X as n goes to infinity. It does not require any dependence between the Xₙ's and X. We saw this type of convergence before when we discussed the central limit theorem. To say that Xₙ converges in distribution to X, we write:

                                       Xₙ →d X.

Convergence in probability is stronger than convergence in distribution. In particular, for a sequence X₁, X₂, X₃, ⋯ to converge to a random variable X, we must have that P(|Xₙ−X|≥ϵ) goes to 0 as n→∞, for any ϵ>0. To say that Xₙ converges in probability to X, we write:

                                                Xₙ →p X.

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The values that represent the solution to [tex]cos (\frac{\pi }{4} - x) = \frac{\sqrt{2} }{2} sin x[/tex] ,

x ∈ [0, 2·π) are:

              [tex]x = (\frac{\pi }{2} , \frac{3\pi }{2} )[/tex]

Sine and Cosine are trigonometric functions of an angle. The sine and cosine of an acute angle are defined in the context of a right triangle: for the specified angle, its sine is the ratio of the length of the side that is opposite that angle to the length of the longest side of the triangle (the hypotenuse), and the cosine is the ratio of the length of the adjacent leg to that of the hypotenuse. For an angle θ the sine and cosine functions are denoted simply as sinθ and cos θ.

Once such a triangle is chosen, the sine of the angle is equal to the length of the opposite side, divided by the length of the hypotenuse:

Sin (α) = [tex]\frac{opposite}{Hypotenuse}[/tex]  and  Cos (α) = [tex]\frac{Adjacent}{Hypotenues}[/tex]

Given in the question:

The given function is presented as follows;

[tex]cos (\frac{\pi }{4} - x) = \frac{\sqrt{2} }{2} sin x[/tex]

Where;

x ∈ [0, 2·π)

We have;

cos(A - B) = cos(A)·cos(B) - sin(A)·sin(B)

[tex]cos (\frac{\pi }{4} ) = \frac{\sqrt{2} }{2} , sin( \frac{\pi }{4)} =\frac{\sqrt{2} }{2}[/tex]

Which gives

[tex]cos(\frac{\pi }{4} - x ) = \frac{\sqrt{2} }{2} cos x +\frac{\sqrt{2} }{2} sinx[/tex]

Therefore, we get;

[tex]\frac{\sqrt{2} }{2} cos x = \frac{\sqrt{2} }{2} sinx - \frac{\sqrt{2} }{2} = 0[/tex]

cos x = 0

[tex]cos (\frac{\pi }{2} ) =0[/tex]

Therefore;

The possible solutions (x-values) to cos x = 0 are;

                             [tex]0\leq \frac{n.\pi }{2} \leq 2\pi[/tex]

Where;

n = 1, 3, 5, ...

x ∈ [0, 2·π)

We get;   [tex]x = \frac{\pi }{2} or \frac{3\pi }{2}[/tex]

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Answer:

Step-by-step explanation:

Answer:

(10) x=1, y=-3

(12) x=3, y=22

(13) x= 6, y= 7

Step-by-step explanation:

[10] 6x -9 =-3x

6x+3x=9

9x=9

x=9,

the standard deviation of the sample means:

σ(x) = σ/[tex]\sqrt{n}[/tex]

The central limit theorem states that if you have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement text annotation indicator, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large (usually n > 30). If the population is normal, then the theorem holds true even for samples smaller than 30. In fact, this also holds true even if the population is binomial, provided that min(np, n(1-p))> 5, where n is the sample size and p is the probability of success in the population. This means that we can use the normal probability model to quantify uncertainty when making inferences about a population mean based on the sample mean.

For the random samples we take from the population, we can compute the mean of the sample means:

μ (x) = μ

and the standard deviation of the sample means:

σ(x) = σ/[tex]\sqrt{n}[/tex]

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The value of the definite integral is 10 after breaking the limits of the integral.

It is defined as the mathematical approach to calculating the smaller parts or components.

It is given that:

The piecewise function is given:

[tex]\rm \int\limits^4_0 {x} \, dx = \int\limits^2_0 {2} \, dx +\int\limits^4_2 {x} \, dx[/tex]

[tex]\rm \int\limits^4_0 {x} \, dx = x^2|^2_0+(1/2)x^2|^4_2[/tex]

= 4 + (1/2)[16 - 4)

= 4 + 6

= 10

Thus, the value of the definite integral is 10 after breaking the limits of the integral.

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(767.47, 777.13) is the confidence interval in the given situation.

A confidence interval is a range of estimates for an unknown parameter in frequentist statistics.

The 95% confidence level is the most popular, but other levels, like 90% or 99%, are occasionally used when computing confidence intervals.

[tex]\begin{aligned}&\mathrm{CI}=(772.3-4.83,772.3+4.83) \\&\mathrm{CI}=(767.47,777.13)\end{aligned}[/tex]

Therefore, (767.47, 777.13) is the confidence interval in the given situation.

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Wyatt can husk anywhere from 12 to  18 dozen ears of corn per hour.

To find the possible amount we need to calculate the maximum and minimum time period in hours

Thus, if we need to find the time taken to husk 72 dozen ears of corn, the maximum time would be  ,

=72 / 12 hours

​ =6 hours

And the minimum time would be  used for the does wyatt takes to husk the 72 dozen of corn

=72/18 hours

​=4 hours

Thus, depending on his speed, Wyatt takes anywhere from  4  to 6 hours to husk  72 dozen ears of corn.

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Answer:

8 pounds of oranges for $12.

Step-by-step explanation:

The area of the piece of land is 849 ft².

The area of the piece of land

=22 x 30 x [tex]\frac{1}{2}[/tex] x 2 + (30-12) x 21 x [tex]\frac{1}{2}[/tex]

=660 + 18 × 21×[tex]\frac{1}{2}[/tex]

=660 + 189

=849 ft²

The area is the amount that expresses the volume of a place on the plane or on a curved surface. The location of an aircraft region or aircraft place refers back to the area of a shape or planar lamina, at the same time as floor region refers to the location of an open floor or the boundary of a three-dimensional object. the area may be understood as the amount of fabric with a given thickness that could be essential to style a model of the shape, or the amount of paint vital to cowl the surface with a single coat. it's miles the 2-dimensional analog of the length of a curve (a one-dimensional concept) or the extent of a strong (a three-dimensional concept).

The place of a shape can be measured by way of evaluating the form to squares of a hard and fast size. inside the global gadget of devices (SI), the usual unit of the vicinity is the rectangular meter (written as m²), that's the location of a rectangle whose sides are one meter long. A shape with a place of three rectangular meters would have the equal region as 3 such squares. In mathematics, the unit square is described to have placed one, and the location of another shape or floor is a dimensionless real variety.

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the ratio of blue marvel is 4/3

the ratio of Al marbles to blue is 7/3

Step-by-step explanation:

easiest example : multiply both (it is important to do it to both) by 2 :

2×2 = 4 cups of yellow

3.5×2 = 7 cups of blue

will make the same shade of green, as the mixing ratio is the same.

just, instead of 5.5 cups, it gives us 11 cups of green paint (surprise, surprise, this is also twice as much) .

Answer:

a = 40

Step-by-step explanation: