Answer:
physical science
Explanation:
i guess??
We are able to walk toward because…
a) we push on the air
b) we push on the ground
c) the air pushes on us
d) the ground pushes on us
We are able to walk toward because b) we push on the ground.
_
_
_
[tex] 😘 \: 😉 \: 😈 \; 😫 \: 😤 \: 😡 \: 😘[/tex]
Part B
Based on the information in the article, how could plants be used in the future to help counteract some human
emissions?
Answer:
Having more plants performing photosynthesis could help reduce the amount of carbon dioxide in the atmosphere.
Explanation:
sample answer
The plants can be used in the future to help counteract some human
emissions they absorb carbon dioxide from the air and release oxygen.
What is photosynthesis?It is a process carried out by photosynthetic autotrophic organisms, such as plants, algae and some prokaryotes. These organisms capture sunlight, convert it into chemical energy, which will be used to produce organic compounds, based on water and carbon dioxide.
Trees, like other plants, in the process called photosynthesis, absorb carbon dioxide from the air and release oxygen. They also make the air wetter and cooler. In this way, plants contribute to the good quality of the air we breathe.
See more about phtosynthesis at brainly.com/question/1388366
change 176°F to the Celsius and Kelvin scales. pura batana kese hua fir answer dena plzz
Formulas change from F to degree C : C = (F – 32) / 1.8
so we have (176-32) /1.8= 80 oC
Formulas change from F to degree K : K = 5 / 9 x (F – 32) + 273.15
so we have 5/9 x (176-32) + 273.15 = 353 oK
ok done. Thank to me :>
A 3.00 kg toy falls from a height of 10.0 m. Just before hitting the ground, what will its kinetic energy be? (Disregard air resistance; g = 9.81 m/s2.)
The kinetic energy of the toy before hitting the ground is 294.3 J
From the question given above, the following data were obtained:
Mass (m) = 3 Kg
Height (h) = 10 m
Acceleration due to gravity (g) = 9.81 m/s²
Kinetic energy (KE) =?Before the toy will hit the ground, the potential and kinetic energy of the toy will be the same.
KE = PE = mgh
KE = 3 × 9.81 × 10
KE = 294.3 JTherefore, the kinetic energy of the toy is 294.3 J
Learn https://brainly.com/question/10703928
What is the only force that can overcome the repulsion between two positively charged nuclei to bind them into an atomic nucleus
Answer:
Nuclear Fusion
Explanation:
At large distances, two nuclei repel one another because of the repulsive electrostatic force between their positively charged protons. If two nuclei can be brought close enough together, however, the electrostatic repulsion can be overcome by the attractive nuclear force, which is stronger at close distances.
Which element is in the 3rd period and group 16?
Answer:Thus for n=1 number of electrons is 2 and for n=2 the number of electrons is 8. Hence the electronic configuration of the element X is 2,8,6 and its atomic number is 16. In the Modern Periodic Table, the element Sulphur has atomic number 16. So, the solution is that the element X is Sulphur and it is non metallic.
Answer:
Explanation:
Answer: Thus for n=1 number of electrons is 2 and for n=2 the number of electrons is 8. Hence the electronic configuration of the element X is 2,8,6 and its atomic number is 16. In the Modern Periodic Table, the element Sulphur has atomic number 16. So, the solution is that the element X is Sulphur and it is non metallic.
a force that is at rest or moves in at a constant speed and in a constant direction is called a what force
The question is fishing for "balanced force".
But the description in the question is terrible.
PLEASE HELP! I NEED TO ANSWER THIS QUICKLY!
1. What are the uses of microwaves in society today? Give examples
2. What advantages and/or disadvantages have microwaves as a technology had for humans
a) health b) economy and c) human living conditions?
Answer:
I'm not a genius ok?
Explanation:
1. Radar communication, Analysis of the molecular and atomic structure, telephone communication
2. c
If a 5.00 kg box slides down a ramp inclined at 60.0° above the horizontal, what is the
acceleration of the box
Answer:
A 70 kg box is slid along the floor by a 400 n force. The coefficient of friction between the box and the floor is 0. 50 when the box is sliding
How much force is needed to accelerate a 70 kg rider and the 200kg motorcycle the
rider is on at 4m/s?
Answer: F = (200 kg + 70 kg) * 4 m/s² = 270 kg* 4m/s² = 1080 N
Answer:
F = 1080 N
Explanation:
Suppose measure the mass of an orange. Then you peel the orange and separate out the slices. If you measure the orange peel and all the slices, will that mass equal the mass of the whole orange?
Answer:
Yes
Explanation:
It's still the same orange with the same amount of stuff.
5. SEP Construct Explanations If the line on
a distance-versus-time graph and the line on
a speed-versus-time graph are both straight
lines going through the origin, can the two
graphs be displaying the motion of the same
object? Explain.
Answer:
If and only if the object has 0 speed. Any other case is a no.
Explanation:
In increasing math complexity:
If the graph of a distance/time is a straight line with a non-zero slope it means that the velocity-time graph is an horizontal line where every point has the same second coordinate, equal to the value of the slope of the first line (ie, if the first line has equation [tex]y=2t[/tex] the second line will have equation [tex]y=2[/tex] - I'm using y to denote either the distance or the speed, read it as "the non-time variable")
If the graph of a speed/time is a straight line, the graph of the distance/time is the area of the region of space beneath the straight line in the first graph, ie a triangle. And as you increase the sides of that triangle keeping the angles fixed, you get a parabolic curve.
Bonus case: if [tex]v(t)= 0; d(t) = 0[/tex], they are both straight lines, they both pass through the origin, and they are the exact same line.
With calculus (or: math becomes fun after you add the alphabet to it)
You are asking if the answer of the IVP
[tex]\left \{ {{x'=x} \atop {x(0)=0}} \right.[/tex]
is a linear function. The answer is: besides the obvious [tex]x(t)'=x(t)=0 \ \forall t[/tex] there are no other solutions, linear or otherwise.
If a train travels 25 miles in 2 hours 15 minutes, what is its average speed in miles per hour? 11. 1 mph 12. 5 mph 10 mph 9. 1 mph.
Answer:
11.1
Explanation:
2 hours 15 mins = 2 1/4 hours
2 1/4 hours = 25 miles
1 hour = 25 ÷ 2 1/4 = 25 ÷ 9/4 = 25 x 4/9 = 11.1 miles
Balanced forces are forces that have equal amount of ________. (word choices: force, repel, attract, motion)
Answer:
a
Explanation:
if forces on an object are balanced a moving object continues to move at the same speed and in the same direction
60W light bulb is left on for 5mins. How much energy does it use in KWH
Answer:
Energy = Power × Time
time must be hoursPower must be in kilowatts[tex]{ \tt{E = ( \frac{60}{1000} ) \times ( \frac{5}{60}) }} \\ \\ { \tt{E = 0.005 \: kwh {}^{ } }}[/tex]
How long does it take a plane, traveling at a constant speed of 200 m/s, to fly once around a circle whose radius is 2750 m
Answer:
2000 and 156300
jade it jawaban nya
How is "speed" defined in terms of physics?
Explanation:
In everyday use and in kinematics, the speed of an object is the magnitude of the rate of change of its position with time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.
An 8kg mass is placed on a 30 degrees frictionless inclines plane and is attached to a pulley to a hanging mass of 5kg
Calculate which direction will the system flow
B)what is the acceleration
C)the tension in the rope
Hi there!
We can begin by doing a summation of forces. Let the acceleration be positive in the direction of the DOWNWARD movement of the hanging block.
(A)
The system will flow in the direction of the hanging block's movement downwards.
(B)
Summation of forces of block on incline:
∑F = -M₁gsinФ + T
Summation of forces of hanging block:
∑F = M₂g - T
Sum both summations:
∑F = -M₁gsinФ + T + M₂g - T
∑F = M₂g -M₁gsinФ
According to Newton's Second Law:
∑F = ma
Thus:
(M₁ + M₂)a = M₂g -M₁gsinФ
[tex]a = \frac{M_2g -M_1gsin\theta}{M_1 + M_2}[/tex]
Plug in the values:
[tex]a = \frac{(5 * 9.8) -(8 * 9.8 * sin30)}{8 + 5} = \large\boxed{0.754 m/s^2}[/tex]
(C)
Calculate the rope's tension using one of the above equations:
∑F₂ = M₂g - T
Rearrange for T:
T = M₂g - m₂a
Plug in values:
T = 5(9.8) - 5(0.754) = 45.23 N
I need help making a chart (preferably a line graph) with this data. I'm not sure how to show that it will be a linear line in a graph. If you don't have excel can you explain to me how to do it.
note: these datasets are separate and arent related
Spring Constant (N/m) Displacement (m)
100 0.5m
300 0.167m
500 0.1m
700 0.071m
Applied force (N) Displacement (m)
20 0.2m
30 0.3m
50 0.5m
70 0.7m
Answer:
the graph plotted based on your data, you did not mention what are the variables on the x-axis and y- axis . and the graphs can be three small graphs of different material of one quality i.e. thickness or length
hope it helps
Explanation:
A wrecking ball has a mass of 650 kg. It swings from a cable that is 21 m long. The centripetal force on the ball is 56 N. What is the tangential speed of the wrecking ball? 1. 3 m/s 1. 8 m/s 46 m/s 870 m/s.
Hi there!
For an object moving in a circle:
Centripetal force = ∑F = mv²/r
Thus:
56 = mv²/r
Rearrange to solve for velocity:
√(56r/m) = v
√(56 × 21)/650 = 1.345 m/s
Answer:
AExplanation:
have a good day
The ______________ is all the surroundings of a living organism.
genetics
environment
temperature
heredity
a helicopter cruises at a constant velocity when the total thrust of the engines is 5,000 N. How much air resistance acts on the jet ??
Hi there!
[tex]\large\boxed{F_{A} = -5000N}}[/tex]
For an object to be moving at constant velocity:
∑F = 0 (The sum of the forces acting on the object MUST be 0 N)
We can do a summation of forces for this helicopter in the HORIZONTAL direction:
∑Fₓ = Ft (Force of Thrust) + Fa (Force of air resistance) = 0
Thus, if we substitute in the given value for Ft:
Ft = -Fa
5000N = -Fa
Fa = -5000N
what is the chemical and physical changes if making a starchs
Answer:
Chemical modification of starch is based on the chemical reactivity of the constituent glucose monomers which are polyhydroxyl and can undergo several reactions. Starch can undergo reactions such as hydrolysis, esterification, etherification and oxidation.
Explanation:
Hope this helps!
Who is the author "talking” to in the third stanza of Flanders field
Answer:
One of Canada's best-known poems, “In Flanders Fields” was written on May 2, 1915, when Canadian serviceman John McCrae was stationed at an army hospital in Flanders, Belgium, during World War I.
Explanation:
1 point
A roller coaster is 20 m high and traveling 11 m/s. If the roller coaster has a
mass of 150 kg, what is its total energy? (only put the number, no units or
commas)
Answer:
ETotal=38505J
Explanation:
Known values:
m=150kg
h=20m
v=11m/s
KE=mv^2/2
PE=mgh
ETotal=PE+KE
KE=(150(11^2))/2
KE=9075
PE=150(9.81)(20)
PE=29430
ETotal=9075+29430
ETotal=38505J
helppp
A crane accelerates a 175 kg load is upward. The tension in the cable is 2000 N. Find the magnitude and direction of the elevator's acceleration.
Hi there!
We can begin by summing forces acting on the load:
∑F = T - Mg (where g ≈10 m/s²)
ma = T - Mg
We can plug in the given values to solve:
ma = 2000 - 175(10)
175a = 250
a = 250/175 = 1.43 m/s² UPWARDS
Answer:
a = 1.63 m/s^2
Explanation:
m = 176kg
Ft = 2000N
2000 = 175 (9.8) +175(a)
2000 = 1715 +175a
-1715 -1715
285 = 175a
175 175
a = 1.63m/s^2
Find the velocity of a body of mass 100 g having kinetic energy of 20 J.
Answer:
Explanation:
Let v be the velocity of object ,
Given that mass of object , m=100 g=
1000
100
kg=0.1 kg
& kinetic energy of object =20 J
K.E =
2
1
mv
2
20=
2
1
×0.1v
2
⟹v
2
=400
⟹v=20 m/s
A balloon with a volume of 2. 0 L at 25°C is placed in a hot room at 35°C. The pressure on the balloon is constant at 1. 0 atm. How does the volume of the balloon change after moving it to the hot room?.
Answer:
25A°C=2L
35A°C=? More
=35/25×2L
=7/5×2L
=14L/5
=2.8L
1. A rocket is launched from a 300 cm rail. The upper Launch Lug is placed 1 point 150 cm from the bottom of the rocket. What is the effective distance of the Launch Rail? 300 cm 150 cm 3 m 300 m O 1m O 1.5 m
Answer:
i think its going to be 150 because its half of 300
Explanation:
Part IV Objects on an incline w/ Tension + Friction
1. A small 63 kg sleigh is pulled by a rein attached to horse up a 15'angle hill to the
horizontal. The tension of the rein is 510 N. The coefficient of kinetic friction is
0.25
a. What is the normal force that the sleigh exerts on the hill?
b. What are the magnitude and direction of the sleigh's acceleration?
(a) The normal force on the sleigh is 596.36 N.
(b) The magnitude and direction of acceleration of the sleigh is 3.2 m/s² upwards.
The given parameters;
mass of the sleigh, m = 63 kginclination of the hill, θ = 15⁰tension on the rein, F = 510 Ncoefficient of friction, μ = 0.25The normal force on the sleigh is calculated as follows;
[tex]F_n = mg \times cos(\theta)\\\\F_n = 63 \times 9.8 \times cos(15)\\\\F_n = 596.36 \ N[/tex]
The magnitude and direction of acceleration of the sleigh is calculated as follows;
[tex]\Sigma F= ma\\\\F - mgsin(\theta) - F_f = ma\\\\F - mgsin(\theta) - \mu F_n = ma\\\\510\ - \ 63 \times 9.8 \times sin15 \ -\ 0.25\times 596.36 = 63a\\\\201 .11 = 63a\\\\a = \frac{201.11}{63} \\\\a = 3.2 \ m/s^2 \ upwards[/tex]
Learn more here:https://brainly.com/question/19133846