Answer:
The correct answer is:
2.6 m3 (B)
Explanation:
SF unit stands for Stowage factor unit. Stowage factor is the volume occupied by one unit of mass (weight) when stowed in cargo space. SF expresses the unit in cubic meters (m³) or cubic feet. SF is a unit of measurement that indicates how much space (volume) a particular unit of cargo occupies in a ship's cargo compartment
4. A solution contains 62.1 g of ethylene glycol dissolved in 250.0 g of H2O. Calculate the mass % of ethylene glycol
Answer:
Explanation:
% mass of Ethylene glycol =( mass of ethylene glycol/ mass of solution )x100%
= 62.1 g/ (62.1 + 250 ) x 100%
= 24.24%
Mass percentage is a term that represents the concentration, basically mass by mass percentage. It tells about the percentage of a component in a whole component. Therefore, the mass % of ethylene glycol is 24.24%.
What is percentage by mass?Mass percentage represents the the percentage of each element that is making a particular compound. Mass percentage does not have any unit as numerator and denominator contains the same unit.
Mathematically,
Percentage of mass = (component’s mass ÷ total mass) x 100%
% mass of Ethylene glycol =( mass of ethylene glycol/ mass of solution)x100%
% mass of Ethylene glycol = 62.1 g/ (62.1 + 250 ) x 100
= 24.24%
Therefore, the mass % of ethylene glycol is 24.24%.
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or the solution containing Zn2+(aq), n is 2, so the MM/n ratio will be the molar mass of Zn divided by 2: MM/n = (65.39 g/mol) / 2 = 32.70 g/mol Compare this theoretical value with your experimental result. If the plating efficiency is significantly less than 1, say it is 0.55, how would the observed MM/n ratio compare to the theoretical value?
Answer:
MM/n will be less than the theoretical value
Explanation:
Provided that
The plating efficiency is proportional to the element weight
i.e.
[tex]\frac{Zn^2}{(aq)}[/tex]
That represents [tex]\frac{MM}{n\ value}[/tex]
So,
MM by N value is
= 65.39 g /mol ÷ 2
= 32.70 g/mol
Also, the experimental plating value is 0.55 that represents that it is much lesser than the normal value
So it would be concluded that the MM by N would be lower than the theoretical value
Question you have about rocks or minerals
what is formed when polyatomic ions bond with other ions.
A) ionic compounds.
B) neutral compounds.
C) ionic elements.
D) neutral elements.
Answer:
iconic compounds is your anwser
Answer:
Iconic Compounds
Explanation:
I watched a video about it.
Have a nice Friday!
In which of does the convection only occur in
A. Gases
B. Fluids
C. Liquids
D. Solids
Answer:
B. Fluids
I hope this helps!
Answer:
B
Explanation:
To obtain the number of meters from a distance measured in centimeters, you must
By the number
Answer:
Divide by 100
Explanation:
55:55
The MSDS for benzene indicates that it is a clear liquid that has a substantial vapor pressure. It has a health rating of
2, a fire rating of 3, and a reactivity rating of O. It is a cancer-causing agent.
Based on this information, which statement about benzene is accurate?
O Benzene readily reacts with moist air.
O Benzene explodes if the container is shaken.
O Benzene must be kept away from flames.
O Benzene must be stored under high pressure.
Answer:
Benzene must be kept away from flames.
Explanation:
Hello,
In this case since MSDS tables show the potential risks of chemical compounds, for benzene which which has a substantial vapor pressure and a fire rating of 3, which means that is highly flammable (very likely to get on fire), we conclude then that benzene must be kept away from flames due to its high risk. The other options are incorrect since it has 0 reactivity, it is nor fragile so it is not affected by shaking and it could be storage at standard pressures since it is a liquid at standard conditions as well.
Regards.
why is a lot of energy needed to break covalent bonds
Answer:
The strength of a bond between two atoms increases as the number of electron pairs in the bond increases.
Explanation:
Which charts or graphs always use axes both labeled with quantitative values and show individual points of data, meaning that each point matches with one value on the x-axis and one value on the y-axis? Check all that apply.
The graphs which use axes both labeled with quantitative values and show individual points of data include:
Scatter plotsLine graphsBar graphs.What is a Graph?Thus is defined as a pictorial representation of data or variables in an organized or definite manner.
The graphs mentioned above always have each point matching with one value on the x-axis and one value on the y-axis.
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From a 2.875 g sample containing only iron, sand, and salt, 0.660 g of iron and 1.161 g of sand were separated and recovered. What was the percent of salt in the original sample
Answer:
36.66%
Explanation:
Step 1: Given data
Mass of iron: 0.660 gMass of sand: 1.161 gMass of the sample: 2.875 gMass of salt: ?Step 2: Calculate the mass of salt
The mass of the sample is equal to the sum of the masses of the components.
m(sample) = m(iron) + m(sand) + m(salt)
m(salt) = m(sample) - m(iron) - m(sand)
m(salt) = 2.875 g - 0.660 g - 1.161 g
m(salt) = 1.054 g
Step 3: Calculate the percent of salt in the sample
We will use the following expression.
%(salt) = m(salt) / m(sample) × 100%
%(salt) = 1.054 g / 2.875 g × 100% = 36.66%
The percent of salt in the original sample containing only iron, sand, and salt is 36.66%.
What is salt?Salt is a mineral made up of primarily sodium chloride.
Seawater contains a vast amount of salt.
Given,
The total mass of the sample is 2.875 g
Mass of iron is 0.660 g
Mass of sand is 1.161 g
Step 1: To find the mass of salt
The total mass of the sample = the sum of the masses of the compounds
m(sample) = m(iron) + m(sand) + m(salt)
2.875 g = 0.660 g + 1.161 g + m(salt)
m(salt) = 2.875 g - 0.660 g - 1.161 g
m(salt) = 1.054 g
Step 2: Calculate the percent of salt in the sample
[tex]\%(salt) = \dfrac{m(salt) }{m(sample)} \times 100\%\\\\\\\%(salt) = \dfrac{1.054 g }{2.875 g} \times 100\% = 36.66\%[/tex]
Thus, the percentage of salt in the sample is 36.66%.
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I am timed please help
Answer:
the substance is element.
because an element is pure substance which is made of only one kind of atom.
2. The four parts, or blocks, on the
periodic table are _d, and f.
s, P
a, b
Answer:
s, p
Explanation:
The four parts, or orbitals, on the periodic table are s, p, d, and f.
In run 1, you mix 7.9 mL of the 43 g/L MO solution (MO molar mass is 327.33 g/mol), 3.13 mL of the 0.040 M SnCl2 in 2.0 M HCl solution, 5.49 mL of 2.0 M HCl solution, and 3.43 mL of 2.0M NaCl solution. What is the [H3O+]? Remember that there is a contribution of H3O+ from two solutions.
Answer:
Concentration of H3O⁺ [H3O⁺] = 0.864 M
Explanation:
Given that:
The mass concentration of MO = 43 g/L
The volume of MO = 7.9 mL = 7.9 × 10⁻³ L
Recall that
The mass number of MO = Mass concentration of MO × Volume of MO
The mass number of MO = (43 g/L) * (7.9 × 10⁻³ L)
The mass number of MO = 0.3397 g
number of moles of MO = (mass number of MO) / (molar mass of MO)
number of moles of MO = (0.3397 g) / (327.33 g/mol)
moles of MO = 0.00104 mol
The total volume = 7.9 mL + 3.13 mL + 5.49 mL + 3.43 mL
The total volume = 19.95 mL = 19.95 × 10⁻³ L
Concentration of MO [MO} =(number of moles of MO) / (total volume)
[MO] = 0.00104 mol / 19.95 × 10⁻³ L
[MO] = 5.2130 × 10⁻⁸ M
the number of moles of H3O⁺ = molarity of HCl in the solution × the volume of HCl in solution
the number of moles of H3O⁺ = [(2.0 M) * (3.13 mL)] + [(2.0 M) * (5.49 mL)]
the number of moles of H3O⁺ = 17.24 mmol
Concentration of H3O⁺ [H3O⁺] = (the number of moles of H3O⁺) / (total volume)
Concentration of H3O⁺ [H3O⁺] = (17.24 mmol) / (19.95 mL)
Concentration of H3O⁺ [H3O⁺] = 0.864 M
The Concentration of H3O⁺ [H3O⁺] is 0.864 M
Calculation of the H3O⁺ concentration:But before that following calculations should be needed.
The mass number of MO = Mass concentration of MO × Volume of MO
= (43 g/L) * (7.9 × 10⁻³ L)
= 0.3397 g
Now
number of moles of MO = (mass number of MO) / (molar mass of MO)
= (0.3397 g) / (327.33 g/mol)
= 0.00104 mol
Now
The total volume = 7.9 mL + 3.13 mL + 5.49 mL + 3.43 mL
= 19.95 mL
= 19.95 × 10⁻³ L
Now
Concentration of MO [MO} =(number of moles of MO) / (total volume)
= 0.00104 mol / 19.95 × 10⁻³ L
5.2130 × 10⁻⁸ M
Now
the number of moles of H3O⁺ = molarity of HCl in the solution × the volume of HCl in solution
= [(2.0 M) * (3.13 mL)] + [(2.0 M) * (5.49 mL)]
= 17.24 mmol
Now
Concentration of H3O⁺ [H3O⁺] = (the number of moles of H3O⁺) / (total volume)
= (17.24 mmol) / (19.95 mL)
= 0.864 M
Hence, The Concentration of H3O⁺ [H3O⁺] is 0.864 M
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Explain how plastic can be both beneficial and detrimental at the same time.
Answer:
Detrimental- Toxic chemicals leach out of plastic and are found in the blood and tissue of nearly all of us. Exposure to them is linked to cancers, birth defects, impaired immunity, endocrine disruption and other ailments
Beneficial- Plastic packaging helps protect and preserve goods, while reducing weight in transportation,
Draw the product formed when 2-butanol undergoes reaction with TsCl and Et3N. CH3C6H4SO2Cl.
Answer:
Explanation:
In organic chemistry, the reaction between 2-butanol with TsCl and Et3N is known as the tosylation of the alcohol hydroxyl group. Alcohol is being changed to tosylate by the use of tosyl chloride under the influence of a base. Tosylation of alcohol is an example of a nucleophilic substitution reaction. From the image attached below, we will see how the reaction between 2-butanol proceed into the product by using tosyl chloride and a base(Et3N).
Use the drop-down menus to identify the career that matches each description Helos employees and management negotiate: Oversees payment of employees Maintains employee records, such as contact information: Oversees the Human Resources department of a company.
Answer:
✔ Labor Relations Specialist
✔ Compensation and Benefits Manager
✔ Human Resources Assistant
✔ Human Resources Manager
B
D
A
C
Answer:
Helps employees and management negotiate:
✔ Labor Relations Specialist or B.)
Oversees payment of employees:
✔ Compensation and Benefits Manager or D.)
Maintains employee records, such as contact information:
✔ Human Resources Assistant or A.)
Oversees the Human Resources department of a company:
✔ Human Resources Manager or C.)
The value of ΔG°′ΔG°′ for the conversion of glucose-6-phosphate to fructose-6-phosphate (F6P) is +1.67 kJ/mol+1.67 kJ/mol . If the concentration of glucose-6-phosphate at equilibrium is 2.95 mM2.95 mM , what is the concentration of fructose-6-phosphate? Assume a temperature of 25.0°C25.0°C .
Answer:
The concentration of fructose-6-phosphate is 1.50x10⁻³M
Explanation:
Gibbs Free energy, ΔG°, is defined as:
ΔG° = -RTln K
Where ΔG° = 1670J/mol
R is gas constant = 8.314J/molK
T is absolute temperature (25°C + 273.15 = 298.15K)
Thus, equilibrium constant, k, is:
1670J/mol = -8.314J/molK* 298.15K ln K
-0.6737 = ln K
0.5098 = K
K of the reaction:
G6P ⇄ F6P
is:
K = 0.5098 = [F6P] / [G6P]
As [G6P] is 2.95x10⁻³M:
0.5098 = [F6P] / [2.95x10⁻³M]
[F6P] = 1.50x10⁻³M
The concentration of fructose-6-phosphate is 1.50x10⁻³MWhat property of matter is a
measure of the force of
gravity on an object?
Answer:
No matter where that object is in the vast universe, it will have the same mass. Weight, on the other hand, is a measure of how much gravitational force is exerted on an object.
Cuci
what is the formula?
Answer:
Copper(I) chloride, commonly called cuprous chloride, is the lower chloride of copper, with the formula CuCl. The substance is a white solid sparingly soluble in water, but very soluble in concentrated hydrochloric acid. Impure samples appear green due to the presence of copper(II) chloride.
Explanation:
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I need help on this!!!!!
Identify the characteristics of a good recrystallization solvent. Select one or more: Dissolves a chemical sample well at high temperatures. Is not an organic liquid with a low boiling point. Does not dissolve a chemical sample well at low temperatures. Does not dissolve a chemical sample well at high temperatures. Dissolves a chemical sample well at low temperatures. g
Answer:
Dissolves a chemical sample well at high temperatures.
Does not dissolve a chemical sample well at low temperatures.
Explanation:
Recrystallization involves the dissolution of the solute in a solvent at high temperature. As the solution cools, it becomes saturated and the solute crystallizes out of the solution.
A good recrystallization solvent must only dissolve the solute at high temperature and must not dissolve it at low temperature. Hence, these are the two conditions required for any good recrystallization solvent.
How many sig figs are there
5.00000008
Answer:
2 sig figs.
Explanation:
Sig Fig Rules:
Any non-zero digit is a significant figure.
Any zeros between 2 non-zero digits are significant figures.
Trailing zeros after the decimal are significant figures.
Imagine that you are developing a TLC plate, but you get distracted and forget to take the TLC plate out. Later, when you remove your TLC plate from the developing chamber, you notice that the solvent front has reached the top of the TLC plate. How will the Rf values from this TLC plate compare with those of a student who stopped developing their TLC plate before the solvent front reached the top of the plate
Answer:
The full form of TLC is Thin layer chromatography which is used in separating non volatile mixtures.
Explanation:
In the context, the Rf values could not be read properly or determined properly and accurately if the solvent front flows to the top of the plate. If the solvent reaches the plate's top, then the Rf values reading will be different from the TLC plate where the solvent did not reach the plate's top.
If the solvent front reaches the top, then it is not possible to accurately determine draw the line and to determine how far the spot went. And thus it would be difficult to solve the ratio as the plate would keep advancing or developing and also the compound spot keeps rising. As a result, spots reaches higher or rises than the normal rise but the solvent front does not change, it remains same. Thus, the Rf value would be completely off.
A cannonball made of iron has a volume of 110. cm3. What is the mass, in kilograms, of the cannonball?
Answer:
1 cubic centimeter (cu cm) = 0.001 kilogram (kg)
110cm³ =110*0.001=0.11kg
Explanation:
The volume has been the space occupied by the object and substances and uses the derived units. The mass of the iron ball with a volume of 110 cubic centimeters is 0.11kg.
What is volume?
Volume has been the three-dimensional space that an object has been using in space. The volume can be measured differently for the various states of matter in various units. Volume is the physical parameter to measure the states of matter.
The estimation of the volume can be given by density or mass and has been expressed by the various units like liters, milliliters, cubic meters, cubic centimeters, kiloliters, cubic decimeters, gallons, etc.
The unit cubic centimeter can be converted into kilogram (kg) as:
1 cubic centimeter = 0.001 kilogram
Given,
The volume of a cannonball made of iron = 110 cubic centimeters
The unit conversion from cubic centimeter to kg is shown as:
1 cubic centimeter = 0.001 kg
110 cubic centimeters = 0.11 Kg
Therefore, 0.11 kilogram is the mass of a cannonball made of iron.
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How many atoms are represented by one formula unit of aluminum carbonate A12(CO2)3
Answer:
well ,if I have done my sum rights there are
14 atom in the one formula unit of aluminium carbonate.
Answer:
14 atoms
Explanation:
b.) If the half-life of Carbon-14 is 5230 years and I start with 100 grams, how long will it take for the
Carbon-14 to decay to 3.125 grams?
Answer:
26150 years
Explanation:
First we need to determine the number of half lives -- not years -- it'll take for 100g (of any element) to decay to 3.125 g
First Half Life 100/2 = 50
Seconf Half Life 50/2 = 25
Third Half Life 25/2 = 12.5
Fourth Half Life 12.5/2 = 6.25
Fifth Half Life 6.25/2 = 3.125
So it'll take 5 half lives for 100g to decay to 3.125g.
If the Half Life of Carbon-14 is 5230 and it will take 5 half lives, to determine the number of years we just need to multiply 5*5230
5*5230 = 26150
This means that it will take 26150 years for 100g Carbon-14 to decay to 3.125g.
Hope this helps!
I can sort the way each object moves by
Answer:
By the way they move
Explanation:
hope this helps
The flask contains 10.0 mL of HCl and a few drops of phenolphthalein indicator. The buret contains 0.160 M NaOH. It requires 18.2 mL of the NaOH solution to reach the end point of the titration. A buret filled with a titrant is held above a graduated cylinder containing an analyte solution. What is the initial concentration of HCl
Answer:
Approximately [tex]0.291\; \rm M[/tex] (rounded to two significant figures.)
Explanation:
The unit of concentration [tex]\rm M[/tex] is the same as [tex]\rm mol \cdot L^{-1}[/tex] (moles per liter.) On the other hand, the volume of both the [tex]\rm NaOH[/tex] solution and the original [tex]\rm HCl[/tex] solution here are in milliliters. Convert these two volumes to liters:
[tex]V(\mathrm{NaOH}) = 18.2\; \rm mL = 18.2 \times 10^{-3}\; \rm L = 0.0182\; \rm L[/tex].[tex]V(\text{$\mathrm{HCl}$, original}) = 10.0\; \rm mL = 10.0\times 10^{-3}\; \rm L = 0.0100\; \rm L[/tex].Calculate the number of moles of [tex]\rm NaOH[/tex] in that [tex]0.0182\; \rm L[/tex] of [tex]0.160\; \rm M[/tex] solution:
[tex]\begin{aligned} n(\mathrm{NaOH}) &= c(\mathrm{NaOH})\cdot V(\mathrm{NaOH})\\ &= 0.160\; \rm mol \cdot L^{-1} \times 0.0182\; \rm L \approx 0.00291\; \rm mol\end{aligned}[/tex].
[tex]\rm HCl[/tex] reacts with [tex]\rm NaOH[/tex] at a one-to-one ratio:
[tex]\rm HCl\; (aq) + NaOH\; (aq) \to NaCl\; (aq) + H_2O\; (l)[/tex].
Coefficient ratio:
[tex]\displaystyle \frac{n(\mathrm{HCl})}{n(\mathrm{NaOH})} = 1[/tex].
In other words, one mole of [tex]\rm NaOH[/tex] would neutralize exactly one mole of [tex]\rm HCl[/tex]. In this titration, [tex]0.291\; \rm mol[/tex] of [tex]\rm NaOH\![/tex] was required. Therefore, the same amount of [tex]\rm HC[/tex] should be present in the original solution:
[tex]\begin{aligned}&n(\text{$\mathrm{HCl}$, original})\\ &= n(\mathrm{NaOH})\cdot \frac{n(\mathrm{HCl})}{n(\mathrm{NaOH})} \\ &\approx 0.00291\; \rm mol \times 1 = 0.00291\; \rm mol\end{aligned}[/tex].
Calculate the concentration of the original [tex]\rm HCl[/tex] solution:
[tex]\displaystyle c(\text{$\mathrm{HCl}$, original}) = \frac{n(\text{$\mathrm{HCl}$, original})}{V(\text{$\mathrm{HCl}$, original})} \approx \frac{0.00291\; \rm mol}{0.0100\; \rm L} \approx 0.291\; \rm M[/tex].
The particles in a gas have more space between them because
Answer:
They are more spread out.
Explanation:
The atoms and molecules in gases are much more spread out than in solids or liquids. They vibrate and move freely at high speeds. A gas will fill any container, but if the container is not sealed, the gas will escape. Gas can be compressed much more easily than a liquid or solid.
Answer:
Explanation:
Explanation:
Gas – In a gas, particles are in continual straight-line motion. The kinetic energy of the molecule is greater than the attractive force between them, thus they are much farther apart and move freely of each other. In most cases, there are essentially no attractive forces between particles
Convert a speed of 933 cm/s to units of inches per minute
Answer:
220000 in/min
Explanation:
Step 1: Write out conversions
1 in ≈ 2.54 cm
60 sec = 1 min
Step 2: Set up dimensional analysis
[tex]\frac{933cm}{s} (\frac{60s}{1min} )(\frac{1in}{2.54cm} )[/tex]
Step 3: Evaluate
220039.4 in/min
Step 4: Sig figs
There are 3 sig figs
220039.4 in/min ≈ 220000 in/min