Arrange these source charges in order from least to greatest magnitude.

A. A, B, C, D
B. B, D, C, A
C. C, A, B, D
D. D, B, A, C

Arrange These Source Charges In Order From Least To Greatest Magnitude.A. A, B, C, DB. B, D, C, AC. C,

Answers

Answer 1

Answer:

option c is the right answer

Answer 2

Answer:

D, B, A, C

Explanation:

The more lines, the greater the charge.


Related Questions

Compare the inner planets with the outer planets.

Answers

Answer:

Inner Planets:

- Rocky

- Small

- Only 3 moons total

- Very close to each other (for space)

- Underweight

Outer Planets:

- Gassy oop-

- GIANT

- Over 200 moons total

- VERY far from each other

- Obese

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Good luck foe.

Lb.

Question 5
Joan wants to decrease her BMI number. How can she achieve her goal?

A. Joan can lose some weight
B. Joan can stretch and get taller
C. Joan can have her blood pressure checked.
D. Joan can take medication


Answers

A. Is the most reasonable answer consider that BMI means Body Mass Index your weight divided by your height in meters and so on B. Doesn’t work. C. B just makes more sense and D. Best to try something on your own then switching to medication

Solar energy heats the surface of the Earth, including the ground, rocks, and even roadways. As the temperature of these surfaces increases, heat energy is released back into the atmosphere, forming a pocket of warm air. As the warm air pocket rises, it is replaced by cooler air. This process is responsible for many of the weather patterns in our atmosphere and is known as

Answers

Answer:

convection

Explanation:

I hope this helps

14. Which of the following ideas is NOT a part of cell theory?
A. There are only plant and animal cells
B. All living things contain at least one cell
C. Cells come from other cells of the same kind
D. Cells are the basic unit of structure and function of living things

Answers

Cell theory states that all living things contain at least one cell, and there are certainly more types of living things than simply plants and animals. For example bacteria and fungi.

So your answer would be A.

Answer: C

Explanation:

all the other ones are part of the cell theory

Answer the question?

Answers

I don’t know the answer to your question BUT DONT CLICK THE LINK THE BOT GAVE YOU THEY CAN HACK YOU JUST REPORT

True or false question scientists can predict when an earthquake will occur

Answers

Answer:

False

Explanation:

Neither the USGS nor any other scientists have ever predicted a major earthquake. USGS scientists can only calculate the probability that a significant earthquake will occur in a specific area within a certain number of years.

The Law of Conservation of Mass states that mass can be destroyed during a chemical change.

True
False

Answers

The law of conservation of mass states that mass can be destroyed during a chemical change is TRUE

Three charges lie along the x-axis. One positive charge, q1 = 4.80*10^-18 C, is at x = 3.72 m, and another positive charge, q2 = 1.60*10^-19 C, is at the origin.
At what point on the x-axis must a negative charge, q3, be placed so that the resultant force on it is zero?

Answers

Answer:

The third charge needs to be placed at [tex]x \approx 0.57\; \rm m[/tex].

Explanation:

Both [tex]q_1[/tex] and [tex]q_2[/tex] would attract [tex]q_3[/tex].

These two electrostatic attractions need to balance one another. Hence, they need to be opposite to one another. Therefore, [tex]q_1[/tex] and [tex]q_2[/tex] need to be on opposite sides of [tex]q_3[/tex]. That is possible only if [tex]q_3 \![/tex] is on the line segment between [tex]q_1 \![/tex] and [tex]q_2 \![/tex].

Assume that [tex]q_3[/tex] is at [tex]x\; \rm m[/tex], where [tex]0 < x < 3.72[/tex] (in other words, [tex]q_3 \![/tex] is on the line segment between [tex]q_1[/tex] and [tex]q_2[/tex], and is [tex]x\; \rm m \![/tex] away from [tex]q_2 \![/tex].)

Let [tex]k[/tex] denote Coulomb's constant.

The magnitude of the electrostatic attraction between [tex]q_1[/tex] and [tex]q_3[/tex] would be:

[tex]\displaystyle \frac{k\cdot q_1 \cdot q_3}{(3.72 - x)^{2}}[/tex].

Similarly, the magnitude of the electrostatic attraction between [tex]q_2[/tex] and [tex]q_3[/tex] would be:

[tex]\displaystyle \frac{k\cdot q_2 \cdot q_3}{x^{2}}[/tex].

The magnitudes of these two electrostatic attractions need to be equal to one another for the resultant electrostatic force on [tex]q_3[/tex] to be [tex]0[/tex]. Equate these two expressions and solve for [tex]x[/tex]:

[tex]\displaystyle \frac{k\cdot q_1 \cdot q_3}{(3.72 - x)^{2}} = \frac{k\cdot q_2 \cdot q_3}{x^{2}}[/tex].

[tex]\displaystyle \frac{q_1}{(3.72 - x)^{2}} = \frac{q_2}{x^{2}}[/tex].

[tex]\displaystyle \frac{x^2}{(3.72 - x)^{2}} = \frac{q_2}{q_1}[/tex].

[tex]\displaystyle \frac{x^2}{(3.72 - x)^{2}} = \frac{q_2}{q_1} = \frac{1}{30}[/tex].

By the assumption that [tex](0 < x < 3.72)[/tex], it should be true that [tex](x > 0)[/tex] and [tex](3.72 - x > 0)[/tex]. Therefore, [tex]\displaystyle \frac{x}{(3.72 - x)} > 0[/tex].

Take the square root of both sides of the equation [tex]\displaystyle \frac{x^2}{(3.72 - x)^{2}} = \frac{1}{30}[/tex].

[tex]\displaystyle \sqrt{\frac{x^2}{(3.72 - x)^{2}}} = \sqrt{\frac{1}{30}}[/tex].

[tex]\displaystyle \frac{x}{3.72 - x} = \frac{1}{\sqrt{30}}[/tex].

[tex]\sqrt{30}\, x = 3.72 - x[/tex].

Therefore:

[tex]\left(1 + \sqrt{30}\right)\, x = 3.72[/tex].

[tex]\displaystyle x = \frac{3.72}{1 + \sqrt{30}} \approx 0.57[/tex].

Hence, [tex]q_3[/tex] should be placed at [tex]x \approx 0.57\; \rm m[/tex].

Explain how a current is induced in the wire?

Answers

Answer:

If a coil of wire is placed in a changing magnetic field, a current will be induced in the wire. This current flows because something is producing an electric field that forces the charges around the wire. (It cannot be the magnetic force since the charges are not initially moving). ... that determines the induced current.

Which of the following is an example of an electromagnetic wave ?

Answers

Answer:

Its a wave

Explanation:

THis is one

Answer: a light wave

Explanation: a pex

how does displacement, acceleration, time, and velocity affect motion?

Answers

Answer:

The relation between velocity and time is a simple one during uniformly accelerated, straight-line motion. The longer the acceleration, the greater the change in velocity. Change in velocity is directly proportional to time when acceleration is constant.

~Hoped this helped~

~Brainiliest?~

Answer:

We describe motion in terms of velocity and acceleration. Velocity: The rate of change of displacement of an object (displacement over elapsed time) is velocity. Velocity is a vector since it has both magnitude (called speed) and direction. ... Acceleration: The rate of change of velocity is acceleration.

Explanation:

Displacement is a vector which points from the initial position of an object to its final position. ... Instantaneous velocity, on the other hand, describes the motion of a body at one particular moment in time. Acceleration is a vector which shows the direction and magnitude of changes in velocity.

Displacement is the vector difference between the ending and starting positions of an object. Velocity is the rate at which displacement changes with time. ... The average velocity over some interval is the total displacement during that interval, divided by the time.

Hope this helps      :)

What is the mass of an apple with a potential energy of 8 Joules that is on a shelf that is 4 meters high?
A; 32kg
B; 15Kg
C;4kg
D:2kg

Answers

Hello I’m pretty sure the answer is b I’m sorry if it’s wrong
It’s b I promise , it’s b cus it can’t be the rest

Hi people; there's a question that has been so confusing for me and a friend of mine.
0°C + 0°C = 64°F
Is this correct or wrong?

Answers

Answer:

The correct answer is: 0°C + 0°C = 32°F

Explanation:

We need to remember the conversion equation from Celsius to Fahrenheit:

[tex]y^{\circ}F=(x^{\circ}C * \frac{9}{5})+32[/tex]

In our case x = 0, then y will be:

[tex](0^{\circ}C * \frac{9}{5})+32=32[/tex]

[tex]y=32^{\circ}F[/tex]

Now 0°C + 0°C is just 0°C because if we add a body at a certain temperature to another body with the same temperature the total temperature will the same.

Then, knowing that 0°C = 32°F we can conclude that:

[tex]0^{\circ}C+0^{\circ}C=32^{\circ}F[/tex]

I hope it helps you!              

all of the following describe the motion of an object except
mass
speed
velocity
acceleration ​

Answers

all describe an objects motion except : mass

I need help asap

What is a homopolar motor?
a. The first electric motor ever made.
b. A motor made by in the North Pole.
c. A motor used in homes in the winter.

Answers

Answer: The answer is A

Explanation:

A car travels 52 mph for 6 minutes, 46 mph for 3 minutes, 40 mph for the remaining time during a 30 minute journey. find the total distance travelled​​

Answers

Answer:

21.5 miles

Explanation:

Distance = Speed * time

Distance  traveled in first 6 minutes = 52 * [tex]\frac{6}{60}[/tex]  = 5.2 miles

Distance  traveled in next 3  minutes = 46 *[tex]\frac{3}{60}[/tex] = 2.3 miles

Remaining minutes = 30 - 6 -3 = 21 minutes

Distance  traveled in 21 minutes = 40 * [tex]\frac{21}{60}[/tex] = 14 miles

Total distance traveled = 5.2 + 2.3 + 14 = 21.5 miles

He likes to eat (into passive voice)​

Answers

Answer:

yes he does

Explanation:

Simplify the expression in part H. Following the five payments, what is the net change in the loan amount from Qulana's viewpoint?

Answers

Answer:

I'm not sure but, this video's pretty cool: gestyy.com/eyRkH2

Explanation:

pretty scary gameplay

Answer:

After five monthly payments, Quiana’s loan amount changes by $1,237.15.

Explanation:

Give examples to show that friction is both friend and foe ?​

Answers

Answer:

friction as friend

It helps us to hold or catch any objectit alos helps us to walk easily

friction as foe

It causes wear and tear of tyresit also cause great damages to parts of machine

hope it helps

Answer:

Wear and tear of soles of our shoes is due to friction.

When a tyre deflates, it is difficult to move the vehicle because of increased friction between the tyre and the road surface.

Machines get heated up and produce noise because of friction.

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