Answer:
Total amount to be paid back = $29971
Step-by-step explanation:
Formula used to calculate the final amount of the loan to be paid,
Total amount to be paid = [tex]P(1+\frac{r}{n})^{nt}[/tex]
Where P = Principal amount of loan taken
r = rate of interest
n = Number of compounding in a year
t = duration of investment
By substituting the values in the formula,
Total amount to be paid after loan maturity = [tex]18000(1+\frac{0.04}{1})^{13\times 1}[/tex]
= [tex]18000(1.04)^{13}[/tex]
= 18000(1.66507)
= $29971.32
≈ $29971
Total amount to be paid after loan maturity will be $29971.
Find the value of EB
Answer:
31Step-by-step explanation:
Given,
AD = 38
EB = 7x - 4
FC = 6x - 6
Now, we have to find the value of X
[tex]eb \: = \frac{1}{2} (ad \: + fc \: )[/tex] ( Mid segment Theorem )
Plug the values
[tex]7x - 4 = \frac{1}{2} (38 + 6x - 6)[/tex]
Calculate the difference
[tex]7x - 4 = \frac{1}{2} (32 + 6x)[/tex]
Remove the parentheses
[tex]7x - 4 = \frac{32}{2} + \frac{6x}{2} [/tex]
[tex]7x - 4 = 16 + 3x[/tex]
Move variable to L.H.S and change its sign
Similarly, Move constant to R.H.S and change its sign
[tex]7x - 3x = 16 + 4[/tex]
Collect like terms
[tex]4x = 16 + 4[/tex]
Calculate the sum
[tex]4x = 20[/tex]
Divide both sides of the equation by 4
[tex] \frac{4x}{4} = \frac{20}{4} [/tex]
Calculate
[tex]x = 5[/tex]
The value of X is 5
Now, let's find the value of EB
EB = 7x - 4
Plug the value of X
[tex] = 7 \times 5 - 4[/tex]
Calculate the product
[tex] = 35 - 4[/tex]
Calculate the difference
[tex] = 31[/tex]
The value of EB is 31
Hope this helps..
Best regards!!
the numbers of students in the 10 schools in a district are given below. ( Note that these are already ordered from Least to Greatest) 198, 216, 220, 236, 246, 252, 253, 260, 290, 319. Suppose that the number 319 from this list changes to 369. Answer the following what happens to the median? what happens to the mean?
Answer:median:249
Step-by-step explanation:
median:198] 216} 220] 236] 246 252 [253[ 260 {290[ 369
246 +252=498
498/2=249
as for the mean i will give you that later
a cylinder has a diameter 14cm and height of 11cm calculate the curved surface area of the cylinder (take pi=22/7 up
Answer:
484 cm^2.
Step-by-step explanation:
The length of the circumference = diameter * pi
= 14 * 22/7
The area of the curved surface = circumference * height
= 14 * 22/7 * 11
= 484.
Evaluate the expression. 1/2 x (4+8)
Answer:
Hey there!
1/2 x (4+8)
1/2 x (12)
6
Hope this helps :)
Answer: 6x
Step-by-step explanation:
.5x*(4+8)
.5x*(12)
6x
Hope it helps <3
Which expression is equivalent to 0.83¯ ?
Answer:
Hello There!!
Step-by-step explanation:
Your answer will be 83/99. Because, We have to expressed the 0.83¯ as a fraction in simplest form. Let x = 0.83¯ = 0.8383. Then, We have to multiply by 100 to both sides we have: 100x = 83.8383. After, Subtract (One) to (Two) we will have: 99x = 83. Then, We will divide both sides by 99 we have: x = 83/99. Therefore, the 0.83¯ as a fraction in simplest form is, 83/99. Hope This Helps!!~ Sorry, If the example confusing...
6th grade math help me, please :)
Answer:
B. 168 students
Step-by-step explanation:
Given that there are a total of 600 students.
28% of the students pack their lunch.
To find:
Total number of students who pack their lunch = ?
Solution:
Percentage of a given number is calculated using the following method.
[tex]y\%[/tex] of a number [tex]x[/tex] is given by:
[tex]x \times \dfrac{y}{100}[/tex]
i.e. multiply the number by percentage to be found and divide by 100.
So, we have to find 28% of 600 here, to find the answer to the question.
[tex]\therefore[/tex] Number of students who pack their lunch is given as: (Multiply the given number 600 with 28 and divide by 100.)
[tex]600 \times \dfrac{28}{100}\\\Rightarrow 6 \times 28\\\Rightarrow \bold{168}[/tex]
So, the correct answer is:
B. 168
A certain forest covers an area of 2100 km². Suppose that each year this area decreases by 3.5%. What will the area be after 5 years
Use the calculator provided and round your answer to the nearest square kilometer.
Answer:
[tex]\large\boxed{\sf \ \ \ 1757 \ km^2 \ \ \ }[/tex]
Step-by-step explanation:
Hello,
I would recommend that you checked the answers I have already provided as this is the same method for all these questions, and maybe try to solve this one before you check the solution.
At the beginning the area is 2100
After one year the area will be
2100*(1-3.5%)=2100*0.965
After n years the area will be
[tex]2100\cdot0.965^n[/tex]
So after 5 years the area will be
[tex]2100\cdot0.965^5=1757.34027...[/tex]
So rounded to the nearest square kilometer is 1757
Hope this helps
Answer: 1757 km²
Step-by-step explanation:
Because 3.5% = 0.035, first do 1-.035 to get .965. Then do 2100*.965*.965*.965*.965*.965 to get 1757.34027.
The length, width and height are consecutive whole numbers. The volume is 120 cubic inches.
Answer:
4, 5 and 6
Step-by-step explanation:
Consecutive means right next to each other.
4 x 5 x 6 = 120 cubic inches.
4 X 5 = 20
20 X 6 = 120
The values of the consecutive numbers will be 4, 5, and 6.
Let the numbers be represented by a, a+1, and a+2.
Therefore, a(a+1)(a+2) = 120
a³ + 3a² + 2a = 120
a = 4
Therefore, a + 1 = 4+1 = 5
a + 2 = 4 + 2 = 6
Therefore, the values will be 4, 5, and 6.
Read related link on:
https://brainly.com/question/18962438
f(x) = x + 2
g(x) = x - 4
(fg)(x) =
Answer:
Step-by-step explanation:pleased to help u....
help me pls pls pls
Answer:
i think it is E
Step-by-step explanation:
Edgar accumulated $5,000 in credit card debt. If the interest rate is 20% per year and he does not make any payments for 2 years, how much will he owe on this debt in 2 years by compounding continuously? Round to the nearest cent.
Answer:
$7200
Step-by-step explanation:
The interest rate on $5,000 accumulated by Edgar is 20%.
He does not make any payment for 2 years and the interests are compounded continuously.
The amount of money he owes after 2 years is the original $5000 and the interest that would have accumulated after 2 years.
The formula for compound amount is:
[tex]A = P(1 + R)^T[/tex]
where P = amount borrowed = $5000
R = interest rate = 20%
T = amount of time = 2 years
Therefore, the amount he will owe on his debt is:
[tex]A = 5000 (1 + 20/100)^2\\\\A = 5000(1 + 0.2)^2\\\\A = 5000(1.2)^2\\[/tex]
A = $7200
After 2 years, he will owe $7200
Answer:7,434.57
Explanation: A= 5000(1+0.2/12)^12•2
If sinθ = 12/13 and θ is an acute angle, find cotθ.
Answer:
[tex]\displaystyle \cot \theta = \frac{5}{12}[/tex]
Step-by-step explanation:
We are given that:
[tex]\displaystyle \sin \theta = \frac{12}{13}[/tex]
Where θ is an acute angle, and we want to find cot(θ).
Recall that sine is the ratio of the opposite side over the hypotenuse. In other words, our opposite side is measures 12 units and our hypotenuse measures 13 units.
Find the adjacent side:
[tex]\displaystyle \begin{aligned} a^2 + b^2 & = c^2 \\ \\ (12)^2 + b^2 & = (13)^2 \\ \\ b & = 5\end{aligned}[/tex]
Hence, our adjacent side is 5, our opposite side is 12, and our hypotenuse is 13.
Recall that cotangent is the ratio of the adjacent side to the opposite side. Therefore:
[tex]\displaystyle \cot \theta = \frac{5}{12}[/tex]
In conclusion:
[tex]\displaystyle \cot \theta = \frac{5}{12}[/tex]
Answer:
-5/12
Step-by-step explanation:
I just completed Quiz 2: Evaluation of Functions. Of which, this was one of the questions.
Select the correct answer from each drop-down menu. The graph represents the piecewise function.
Answer:
1). f(x) = x² if ∞ < x < 2
2). f(x) = 5 if 2 ≤ x < 4
Step-by-step explanation:
The graph attached shows the function in two pieces.
1). Parabola
2). A straight line parallel to the x-axis.
Standard equation of a parabola is,
y = a(x - h)² + k
where (h, k) is the vertex.
Vertex of the given parabola is (0, 0).
Equation of the parabola will be,
y = a(x - 0)² + 0
Therefore, the function will be,
f(x) = ax²
Given parabola is passing through (-1, 1) also,
1 = a(-1)²
a = 1
Therefore, parabolic function will be represented by,
f(x) = x² if ∞ < x < 2
2). Straight line parallel to the x-axis,
y = 5 if 2 ≤ x < 4
Function representing the straight line will be,
f(x) = 5 if 2 ≤ x < 4
Answer:
Please mark me as Brainliest :)
Step-by-step explanation:
3
Easton mixed
kg of flour with
kg of sugar.
6
Determine a reasonable estimate for the amount of flour and sugar combined.
Choose 1 answer:
1
Less than
2
kg
B
More than
1
kg but less than 1 kg
2
More than 1 kg
Which value of x makes the equation 0.75( x + 20) = 2 + 0.5(x - 2) true?
Answer:
0.75x+15=2+0.5x-1
0.25x=1-15
0.25x=-14
x=-56
Step-by-step explanation:
Could someone answer the question with the photo linked below? Then explain how to solve it?
Answer:
b = sqrt(57)
Step-by-step explanation:
Since this is a right triangle, we can use the Pythagorean theorem
a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse
8^2 + b^2 = 11^2
64+ b^2 = 121
Subtract 64
b^2 = 121-64
b^2 =57
Take the square root of each side
b = sqrt(57)
a food snack manufacturer samples 9 bags of pretzels off the assembly line and weights their contents. If the sample mean is 14.2 oz. and teh sample devision is 0.70 oz, find the 95% confidense interval of the true mean
Answer:
13.7≤[tex]\mu[/tex]≤14.7Step-by-step explanation:
The formula for calculating the confidence interval is expressed as shown;
CI = xbar ± Z(б/√n)
xbar is the sample mean
Z is the value at 95% confidence interval
б is the standard deviation of the sample
n is the number of samples
Given xbar = 14.2, Z at 95% CI = 1.96, б = 0.70 and n = 9
Substituting this values into the formula;
CI = 14.2 ± 1.96(0.70/√9)
CI = 14.2 ± 1.96(0.70/3)
CI = 14.2 ± 1.96(0.2333)
CI = 14.2 ± 0.4573
CI = (14.2-0.4573, 14.2+0.4573)
CI = (13.7427, 14.6537)
Hence, the 95% confidence interval of the true mean is within the range
13.7≤[tex]\mu[/tex]≤14.7 (to 1 decimal place).
Need help with this math problem
Answer:
4
Step-by-step explanation:
f(x) = 4 ^ ( x-2)
Let x=3
f(3) = 4 ^ ( 3-2)
= 4 ^ 1
= 4
Answer:
4
Step-by-step explanation:
4^(x - 2)
Plug x as 3.
4^(3 - 2)
Subtract.
4^(1)
4^1 = 4
Help Please! Solve this problem without the law of cosines.
Answer:A
Step-by-step explanation:
if ade has 23hand bag and he sells one for 409$ and he sells 22 for toby what will be the amount
Step-by-step explanation:
Hello there!
Its simple,
Given that, Ade had 23 hand bags.
selling price of each bag=$409
total sold bags= 22.
now, total amount he got was = no.of sold bag×sp of each bag.
so, total amount = 22×$409
=$8998.
Therefore, he has $ 8998 now.
Hope it helps...
cual es la derivada de ()=√x sin
Answer:
[tex] f(x) =\sqrt{x} sin (x)[/tex]
And on this case we can use the product rule for a derivate given by:
[tex] \frac{d}{dx} (f(x)* g(x)) = f'(x) g(x) +f(x) g'(x)[/tex]
Where [tex] f(x) =\sqrt{x}[/tex] and [tex] g(x) =sin (x)[/tex]
And replacing we have this:
[tex] f'(x)= \frac{1}{2\sqrt{x}} sin (x) + \sqrt{x}cos(x)[/tex]
Step-by-step explanation:
We assume that the function of interest is:
[tex] f(x) =\sqrt{x} sin (x)[/tex]
And on this case we can use the product rule for a derivate given by:
[tex] \frac{d}{dx} (f(x)* g(x)) = f'(x) g(x) +f(x) g'(x)[/tex]
Where [tex] f(x) =\sqrt{x}[/tex] and [tex] g(x) =sin (x)[/tex]
And replacing we have this:
[tex] f'(x)= \frac{1}{2\sqrt{x}} sin (x) + \sqrt{x}cos(x)[/tex]
Here is a sample distribution of hourly earnings in Paul's Cookie Factory:
Hourly Earning $6 up to $9 $9 up to $12 $12 up to $15
Frequency 16 42 10
The limits of the class with the smallest frequency are:_________
A) $6.00 and $9.00.
B) $12.00 and up to $14.00.
C) $11.75 and $14.25.
D) $12.00 and up to $15.00.
Answer:
The correct answer is:
$12.00 and up to $15.00 (D)
Step-by-step explanation:
Let us arrange the data properly in a tabular format.
Hourly Earnings($) 6 - 9 9 - 12 12 - 15
Frequency 16 42 10
The frequency of a distribution is the number of times that distribution occurs in a particular group of data or intervals.
From the frequency table above the following observations can be made:
Highest frequency = 42 (hourly earnings of $9 - $12)
smallest frequency = 10 ( hourly earnings of $12 - $15)
This means that among a total of 68 workers (16 + 42 + 10), the people earning $12 - $15 form the smallest group (only 10 people), while 42 workers earn $9 - $12, forming the largest majority
The service life of a battery used in a cardiac pacemaker is assumed to be normally distributed. A random sample of ten batteries is subjected to an accelerated life test by running them continuously at an elevated temperature until failure, and the following lifetimes (in hours) are obtained: 25.5, 26.1, 26.8, 23.2, 24.2, 28.4, 25.0, 27.8, 27.3, and 25.7. The manufacturer wants to be certain that the mean battery life exceeds 25 hours in accelerated lifetime testing.
Construct a 90%, two sided confidence interval on mean life in the accelerated test.
Answer:
The confidence interval is [tex]25.16 < \mu < 26.85[/tex]
Step-by-step explanation:
From the question we are given a data set
25.5, 26.1, 26.8, 23.2, 24.2, 28.4, 25.0, 27.8, 27.3, and 25.7.
The mean of the this sample data is
[tex]\= x = \frac{\sum x_i}{n}[/tex]
where is the sample size with values n = 10
[tex]\= x = \frac{25.5+ 26.1+ 26.8+23.2+ 24.2+ 28.4+ 25.0+ 27.8+ 27.3+ 25.7}{10}[/tex]
[tex]\= x = 26[/tex]
The standard deviation is evaluated as
[tex]\sigma = \sqrt{\frac{\sum (x-\= x)}{n} }[/tex]
substituting values
[tex]= \sqrt{\frac{ ( 25.5-26)^2, (26.1-26)^2, (26.8-26)^2, (23.2-26)^2}{10} }[/tex]
[tex]\cdot \ \cdot \ \cdot \sqrt{\frac{ ( 24.2-26)^2, (28.4-26)^2+( 25.0-26)^2+ (27.8-26)^2+( 27.3-26)^2+( 25.7-26)^2}{10} }[/tex]
[tex]\sigma = 1.625[/tex]
The confidence level is given as 90% hence the level of significance is calculated as
[tex]\alpha = 100 -90[/tex]
[tex]\alpha =10[/tex]%
[tex]\alpha = 0.10[/tex]
Now the critical values of [tex]\frac{\alpha }{2}[/tex] is obtained from the normal distribution table as
[tex]Z_{\frac{\alpha }{2} } = 1.645[/tex]
The reason we are obtaining the critical values of [tex]\frac{\alpha }{2}[/tex] instead of [tex]\alpha[/tex] is because we are considering two tails of the area under the normal curve
The margin of error is evaluated as
[tex]MOE = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }[/tex]
substituting values
[tex]MOE = 1.645 * \frac{1.625 }{\sqrt{10} }[/tex]
[tex]MOE = 0.845[/tex]
The 90%, two sided confidence interval is mathematically evaluated as
[tex]\= x - MOE < \mu < \= x + MOE[/tex]
[tex]26 - 0.845 < \mu < 26 + 0.845[/tex]
[tex]25.16 < \mu < 26.85[/tex]
Given that the lower and the upper limit is greater than 25 then we can assure the manufactures that the battery life exceeds 25 hours
A train covers certain distance in two parts. Distance covered in first part is 200% more than the distance covered in second part while speed of train is in the ratio 2 : 1 in first and second part respectively. If average speed of train is 64 km/hr, then find the speed of train in first part? (in kmph)
Answer:
Part A speed=96*2=192km/h
Step-by-step explanation:
Two parts, parts A and part B
Part A=200% more than B
Let part B=x
Part A=200 more than B
=2x
Speed ratio=2:1
Average speed of train=64km/h
Let Part A speed=2x
Part B speed=x
A:B=2:1
Total ratio =3
Speed in the part A can be calculated thus:
Totatl speed= ratio of speed in part A / total ratio
64=2x/3
192=2x
x=96km/h
Part A speed=96*2=192km/h
Simplify 3 (2x + 1) - 2 (x + 1)
Let's simplify step-by-step.
3(2x+1)−2(x+1)
Distribute:
=(3)(2x)+(3)(1)+(−2)(x)+(−2)(1)
=6x+3+−2x+−2
Combine Like Terms:
=6x+3+−2x+−2
=(6x+−2x)+(3+−2)
=4x+1
4x+1 is the answer to the question
Se golpea (chuta) un balón sobre el piso y sale dando botes parabólicos cada vez menores. Si se lanzo inicialmente con una velocidad de 32m/s, y un ángulo de 60º y se sabe que en cada bote pierde un cuarto de su velocidad y el ángulo se reduce en 10º, determinar el alcance total logrado al termino del tercer bote y el tiempo empleado en ello Gracias a la persona Desconocida
Answer:
a)d = 180,91 m
b)t = 11,76 seg
Step-by-step explanation:
Para el lanzamiento de proyectil, la ecuación que nos da la velocidad en V(y) es:
V(y) = Voy - g*t
en donde Voy = Vo * senα ( donde Vo es la velocidad inicial, α el angulo del disparo.
Si en esta ecuación hacemos V(y) = 0 estamos en el punto donde el componente en el eje y de la velocidad del proyectil es cero, ese punto es el punto medio del recorrido.
0 = Vo*sen 60⁰ - g*t
g*t = Vo* √3/2
t = { 32 [m/s] * √3 }2*9,8 [m/s²]
t = 16*√3 / 9,8
t = 2,8278 seg
El tiempo total del primer recorrido es entonces por simetría
t₁ = 2 * 2,8278 t₁ = 5,6556 seg
La distancia del primer impacto al suelo es:
x = Vox * t₁ ( Vox es constante Vx = Vo*cos 60⁰ )
x = 32 * (1/2) * 5,6556
x₁ = 90,49 m
Aplicando los mismos criterios ahora para el segundo bote
Ahora Vo = 32 - 32*(1/4)
V = 24 m/s
g*t = 24 * sen 50⁰
t = 24* 0,7660/ 9,8
t = 1,8759
2*t = 2*1,8759
t₂ = 3,7518 seg
x₂ = Vox * t₂
x₂ = 24* 0,6428*3,7518
x₂ = 57,88 m
Y para el tercer bote Vo = 24 - 24(1/4) Vo = 18 m/s α = 40⁰
t = 18 *0,6428/9,8
t = 1,18
2t = t₃ = 2*1,18
t₃ = 2,36 seg
x₃ = Vox * 2,36 Vox = Vo*cos 40 Vox = 18*0,7660
Vox = 13,79
x₃ = 13,79*2,36
x₃ = 32,54 m
La distancia total será
d = x₁ + x₂ + x₃
d = 90,49 + 57,88 + 32,54
d = 180,91 m
y el tiempo total será la suma de los tiempos
t = t₁ + t₂ + t₃
t = 5,65 + 3,75 + 2,36
t = 11,76 seg
which of the following descriptions represent the transformation shown in the image? Part 1d
Answer:
(C) Translation of 2 units right, 1 up, and a reflection over the y-axis.
Step-by-step explanation:
Ideally, we are looking for a reflection of the red image over the y-axis, and to do that, we can see how we need to move the black image.
In order for points Q and Q' to be a reflection of each other, they need to have the same y value, and be the exact same distance from the y axis, so the point that Q has to be at is (-1,-3).
Q is right now at (-3,-4) so we can translate this.
To get from -3 to -1 in the x-axis, we go right by 2 units.
To get from -4 to -3 in the y-axis, we go up one unit.
Now, if we reflect it, the triangles will be the same.
Hope this helped!
Answer:
C.
Step-by-step explanation:
When you study the images, it is clear that the black triangle has to be reflected over the y-axis to face the same direction as the red triangle. So, choice A is eliminated.
Once you reflect the black triangle across the y-axis, you have points at (-1, -1), (3, -4), and (3, -2). Meanwhile, the red triangle's coordinates are at (-3, 0), (1, -3), and (1, -1). From these points, you can tell that the x-values differ by 2 units and the y-values differ by 1 unit.
All of these conditions match the ones put forth in option C, so that is your answer.
Hope this helps!
What are the solutions of the quadratic equation (x – 8)2 - 13(x - 8) + 30 = 0? Use u substitution to solve.
Ox=-11 and x = -18
x= -2 and x = 5
x= 2 and x = -5
x= 11 and x = 18
Answer:
Its D
Step-by-step explanation:
x=11 and x=18
A cryptarithm is a math puzzle in which the digits in a simple equation are replaced with letters. Each digit is represented by only one letter, and each letter represents a different digit. So, for example, we might represent 51+50 = 101 as AB + AC = BCB. In the cryptarithm SEND + MORE = MONEY, what digit does the letter Y represent?
Answer:
[tex]\large \boxed{\sf \begin{aligned}9567&\\+1085&\\----&-\\10652&\\\end{aligned}}[/tex]
Step-by-step explanation:
Hello, let's do it step by step and see what we can find.
[tex]\begin{aligned}\text{ SEND}&\\+\text{ MORE}&\\-----&-\\\text{ MONEY}&\\\end{aligned}[/tex]
We assume that M is different from 0, otherwise we could find several different solutions I would think.
It means that S + M is greater than 10, otherwise the number of digit of the result would have been 4 and not 5.
The only possible number for M is then 1. M = 1
[tex]\begin{aligned}\text{ SEND}&\\+\text{ \boxed{1}ORE}&\\-----&-\\\text{ \boxed{1}ONEY}&\\\end{aligned}[/tex]
But then, S can only by 9, otherwise S + 1 < 10. S = 9
S + 1 = 10 + O if there is no carry over, so S = 9 + O
1 + S + 1 = 10 + O if there is a carry, so S = 8 + O
So O = 0 or O = 1. Wait !? M is already equal to 1 so O must be 0
E cannot be equal to N so 1 + E = N, meaning that there must be a carry over from column second from the right.
and E < 9 as we know that there is no carry over from column 3 from the right.
N + R = 10 + E => 1 + E + R = 10 + E => R = 9, impossible, as S=9
or 1 + N + R = 10 + E => 1 + 1 + E + R = 10 + E => R = 8
And there is a carry over from the column 1 from the right, so:
Y cannot be 0 or 1, as already used so D + E > 11
8 and 9 are already taken so we could have 7 + 5 = 12, 7 + 6 = 13 and that's it.
It means that E is 7 or D is 7.
If E is 7 then E+1=9=N, impossible, so D = 7
Then, E is 5 or 6
if E = 6 E + 1 = N = 7, impossible, so E = 5 and N = 6.
And 7 + 5 = 12 so Y = 2.
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
find the value of a, b, c, and d,
type exact answers and use radicals as needed
Step-by-step explanation:
Using trigonometrical functions we can obtain the required side lengths.
[tex] \sin 45\degree = \frac{a}{16\sqrt 2}\\\\
\therefore \frac{1}{\sqrt 2}= \frac{a}{16\sqrt 2}\\\\
\therefore a = \frac{16\sqrt 2}{\sqrt 2}\\\\
\huge\red {\boxed {\therefore a = 16}} \\\\
\cos 45\degree = \frac{c}{16\sqrt 2}\\\\
\therefore \frac{1}{\sqrt 2}= \frac{c}{16\sqrt 2}\\\\
\therefore c = \frac{16\sqrt 2}{\sqrt 2}\\\\
\huge\purple {\boxed {\therefore c = 16}} \\\\
\sin 30\degree = \frac{a}{b}\\\\
\therefore \frac{1}{2}= \frac{16}{b}\\\\
\therefore b = {16\times2}\\\\
\huge\orange{\boxed {\therefore b = 32}} \\\\
\tan 30\degree = \frac{a}{d}\\\\
\therefore \frac{1}{\sqrt 3}= \frac{16}{d}\\\\
\therefore d = {16\times\sqrt 3}\\\\
\huge\pink {\boxed {\therefore d = 16\sqrt 3}} \\\\
[/tex]