A simple harmonic oscillator (SHO) has a spring constant of 280 N/m, Total energy of 150 J, and a mass of 4.00 kg. What is its
maximum velocity?
Numerical answer is in units of m/s

Answers

Answer 1

The maximum velocity is 8.66 m/s²

As we know, simple harmonic motion refers to a to-and-fro motion in a periodic manner and spring constant refers to the force required to stretch or compress a spring.

The spring constant for a simple harmonic oscillator is given as 280 N/m, the total energy is 150 J and the mass is 4 kgs. We have to find the maximum velocity of the given simple harmonic motion.

We know that Energy = force x perpendicular distance

In an SHM, energy is in the form of Kinetic Energy. Hence, we use the formula for kinetic energy.

To find the maximum velocity, we will apply the formula for kinetic energy.

Since Kinetic Energy = 1/2 mass x velocity²

Therefore, 150 = 1/2 mass x velocity² ; velocity = 8.66 m/s²

Hence, the maximum velocity for the given system of SHM is 8.66 m/s²

To know more about simple harmonic oscillators,

https://brainly.com/question/30262862


Related Questions

The temperature of a aluminum bar rises by 10.0°C when it absorbs 4.73 kJ of energy by heat. The mass of the bar is 525 g. Determine the specific heat of aluminum from these data. Answer is in kJ/kg · °C.

Answers

Answer:

Certainly! We can use the formula:

q = mcΔT

where q is the amount of heat absorbed, m is the mass of the aluminum bar, c is the specific heat capacity of aluminum, and ΔT is the change in temperature.

Substituting the given values, we get:

4.73 kJ = (0.525 kg) x c x (10.0°C)

Solving for c, we get:

c = 0.901 kJ/kg · °C

Therefore, the specific heat of aluminum is 0.901 kJ/kg · °C.

Explanation:

A satellite weighing 5,400 kg is launched into orbit 3.6400 x 107 m above the center of the earth.

The mass of Earth is 6.0 × 1024 kg. The gravitational constant is 6.673 × 10–11 N•m2/kg2.

The gravitational force of Earth on the satellite is ___



Group of answer choices

9.1 x 10^4

1.6 x 10^3

2.1 x 10^6

Answers

Answer:

[tex]\tt F=1.63*10^3 N[/tex]

Explanation:

Gravitational force is defined as the force of attraction between two objects with mass. It is a fundamental force of nature, and it is what keeps us on the ground and what keeps the planets in orbit around the Sun.

The gravitational force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers

For the Question:

We can use the following formula to calculate the gravitational force between the Earth and the satellite:

[tex]\boxed{\tt F =\frac{ G * M * m }{ r^2}}[/tex]

Where:

F is the gravitational force

G is the gravitational constant[tex]\tt (6.673 * 10^{-11} Nm^2/kg^2)[/tex]

M is the mass of the Earth [tex]\tt (6.0 * 10^24 kg)[/tex]

m is the mass of the satellite[tex]\tt (5,400 kg)[/tex]

r is the distance between the satellite and the center of the Earth [tex]\tt (3.6400 * 10^7 m)[/tex]

Plugging in these values, we get the following:

[tex]\tt F = \frac{6.673 * 10^{-11} * 6.0 * 10^{24}* 5,400 }{ (3.6400 * 10^7 )^2}[/tex]

[tex]\tt F=1.63*10^3 N[/tex]

Therefore, answer is [tex]\tt F=1.63*10^3 N[/tex]

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