A rubber band has a spring constant of 45 N/m. A classmate stretches it a length of 0.2 m before firing it at Mr. C. Ouch. Calculate the elastic
potential energy of the rubber band.

Answers

Answer 1

Answer:

0.9 Joules

Explanation:

Elastic potential energy of a spring= 1/2 × Spring constant × displacement²

following calculations you will get ur answer!!


Related Questions

Help me please
There’s 2 questions.

Answers

Answer:

50 Joules of work on the system Total distance is 1m W= F ×D 50 Joules = F × 1m F= 50 Newtons W= 1234 J D= 451234= F × 45 meters F= 27.42 Newtons I do exams and quizzes if ur interested

Action-reaction forces are always the same ____ but are in opposite ____​

Answers

Answer:

Magnitude, direction

Explanation:

Magnitude, direction

Abby is writing a biography of Isaac Newton. He was a brilliant English scientist who developed the law of universal gravitation in the 1600s. Newton also developed laws of motion and ideas about inertia. His laws and ideas were used in many subjects such as physics, astronomy, and mathematics. Explain inertia using Newton's first law of motion. Give an example of inertia.

Answers

Answer:

Over several years, Newton worked until he had developed the law of universal gravitation, which debuted in his book Mathematical Principles of Natural Philosophy (1869). This idea stood until the concepts of quantum theory and relativity were posed in the mid 19th century.

Explain inertia using Newton's first law of motion?Newton's  first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. This is normally taken as the definition of inertia. The motion of a kite when the wind changes can also be described by the first law.Newton 's First Law = InertiaNewton 's First Law = Inertia An object's inertia causes it to continue moving the way it is moving unless it is acted upon by an (unbalanced) force to change its motion. An unbalanced force is a net force.

Examples of Inertia of Motion:You try to stop suddenly, but part of your body continues on forward.Car stops suddenly. You keep going forward until either the seat belt stops you or you hit something in front of you.Car is going very slowly. Gear shifted to neutral or clutch pushed in. Car continues going forward even without power pushing it.You throw a ball forward. The ball keeps going after it leaves your hand. It accelerates downward, but continues going horizontally.You turn off a fan, it keeps spinning until it gradually slows down. (A little bit of friction slows it down.)Car turns sharply left. You feel pulled to the right. Your body’s trying to continue going in a straight line.

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Un bloque de 3 kg en reposo se deja libre a una altura de 5 m sobre una rampa curva y sin rozamiento. Al pie de la rampa se encuentra un resorte de constante k = 400 N/m, como se muestra en la fig. El objeto desliza por la rampa y llega a chocar contra el resorte comprimiéndolo una distancia x antes de que quede en reposo momentáneamente. Determinar: a) La velocidad con la que el bloque alcanza al resorte. ____________________ b) La distancia x que el bloque comprime al resorte. __________________ c) La velocidad con la que el bloque es expulsado por el resorte. ____________________ d) La altura que alcanza sobre la parte curva. ________________ e) ¿Alcanzará la misma altura si la rampa no está libre de rozamiento? ___________________

Answers

Answer:

a) La velocidad del bloque cuando llega al resorte es de aproximadamente 9,9 m / s

b) La distancia a la que se comprime el resorte es de aproximadamente 0,86 m

c) La velocidad con la que el resorte expulsa el bloque es de aproximadamente 9,9 m / s

d) La altura que alcanza el bloque es de 5 metros.

e) El bloque no alcanzará la misma altura si la rampa no está libre de fricción

Explanation:

a) Los parámetros dados del bloque son;

La masa del bloque, m = 3 kg

La altura a la que se coloca el bloque, h = 5 m

La constante de resorte, k = 400 N / m

La aceleración debida a la gravedad, g = 9,8 m / s²

La energía potencial de un cuerpo, P.E. = m · g · h

Por tanto, la energía potencial inicial del bloque, P.E. se da como sigue;

P.E. = 3 kg × 9,8 m / s² × 5 m = 147 julios

P.E. = 147 julios

La energía cinética del bloque al pie de la rampa, K.E. = 1/2 · m · v²

Dónde;

v = La velocidad del bloque cuando llega al resorte

Por lo tanto, para el bloque dado tenemos;

K.E. = 1/2 · m · v² = 1/2 × 3 kg × v²

Por el principio de conservación de la energía, tenemos;

El PE. del bloque en reposo a una altura de 5 m = La energía cinética al pie de la rampa. K.E.

∴ P.E. = K.E.

147 J = 1/2 × 3 kg × v²

v² = 147 J / (1/2 × 3 kg) = 98 m² / s²

v = √ (98 m² / s²) = 7 · √2 m / s

v = 7 · √2 m / s ≈ 9,9 m / s

b) La energía recibida por el resorte comprimido, E = 1/2 · k · x²

Dónde;

k = La constante del resorte = 400 N / m

x = La distancia a la que se comprime el resorte

Por el principio de conservación de la energía, tenemos;

La energía recibida por el resorte comprimido, E = La energía potencial inicial del resorte, P.E.

∴ E = 1/2 · k · x² = P.E.

De lo que tenemos;

E = 1/2 × 400 N / m × x² = 147 julios

x² = 147 Julios / (1/2 × 400 N / m) = 0,735 m²

x = √ (0,735 m²) = 0,7 · √ (3/2) m ≈ 0,86 m

La distancia a la que se comprime el resorte = x ≈ 0.86 m

c) La velocidad con la que el resorte expulsa el bloque se indica a continuación;

La energía en el resorte = 1/2 · k · x² = La energía cinética dada al bloque, 1/2 · m · v²

∴ 1/2 · k · x² = 1/2 · m · v²

∴ La velocidad con la que el bloque es expulsado por el resorte, v = La velocidad con la que el bloque llega al resorte = 7 · √2 m / s

La velocidad con la que el resorte expulsa el bloque, v = 7 · √2 m / s ≈ 9,9 m / s

d) La altura que alcanza el bloque también viene dada por la siguiente relación anterior;

P.E. = K.E.

∴ m · g · h = 1/2 · m · v²

v = 7 · √2 m / s

De donde tenemos h = La altura inicial del bloque en la rampa = 5 metros

e) El bloque no alcanzará la misma altura si la rampa no está libre de fricción porque se utilizará energía para superar la fuerza de fricción

a) La velocidad final del bloque es aproximadamente 9.903 metros por segundo.

b) El resorte se deforma 0.858 metros.

c) Por el principio de la conservación de energía y sabiendo la ausencia de fuerzas disipativas, la velocidad del objeto expulsado del resorte es aproximadamente 9.903 metros por segundo.

d) Por el principio de la conservación de energía y si existieran fuerzas disipativas, la altura máxima sería menor a la hallada en el punto a).

a) Conforme a la situación de este problema, la energía cinética traslacional final ([tex]K[/tex]), en joules, es igual a la energía potencial gravitacional inicial ([tex]U[/tex]), en joules.

[tex]U = K[/tex] (1)

Por las definiciones de las energías cinética traslacional y potencial gravitacional expandimos la ecuación anterior:

[tex]m\cdot g\cdot h = \frac{1}{2}\cdot m\cdot v^{2}[/tex] (1)

Ahora despejamos la velocidad de esa ecuación:

[tex]v = \sqrt{2\cdot g\cdot h}[/tex]

Donde:

[tex]m[/tex] - Masa del bloque, en kilogramos.[tex]g[/tex] - Aceleración gravitacional, en metros por segundo al cuadrado.[tex]h[/tex] - Altura inicial del bloque, en metros.[tex]v[/tex] - Velocidad final del bloque, en metros por segundo.

Si sabemos que [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] y [tex]h = 5\,m[/tex], entonces la velocidad final del bloque es:

[tex]v = \sqrt{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (5\,m)}[/tex]

[tex]v\approx 9.903\,\frac{m}{s}[/tex]

La velocidad final del bloque es aproximadamente 9.903 metros por segundo.

b) Por el principio de conservación de la energía, la energía cinética traslacional inicial es igual a la energía potencial elástica final, cuyas fórmula es la siguiente:

[tex]\frac{1}{2}\cdot k\cdot x^{2} = \frac{1}{2}\cdot m \cdot v^{2}[/tex] (2)

Where:

[tex]k[/tex] - Constante de resorte, en newtons por metro.[tex]x[/tex] - Deformación del resorte, en metros.

Ahora despejamos la deformación del resorte:

[tex]x = \sqrt{\frac{m}{k} }\cdot v[/tex] (3)

Si sabemos con [tex]k = 400\,\frac{N}{m}[/tex], [tex]m = 3\,kg[/tex] y [tex]v \approx 9.903\,\frac{m}{s}[/tex], entonces la deformación del resorte es:

[tex]x = \sqrt{\frac{3\,kg }{400\,\frac{N}{m} } }\cdot \left(9.903\,\frac{m}{s} \right)[/tex]

[tex]x \approx 0.858\,m[/tex]

El resorte se deforma 0.858 metros.

c) Por el principio de la conservación de energía y sabiendo la ausencia de fuerzas disipativas, la velocidad del objeto expulsado del resorte es aproximadamente 9.903 metros por segundo.

d) Por el principio de la conservación de energía y si existieran fuerzas disipativas, la altura máxima sería menor a la hallada en el punto a).

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Which muscles help you sit up from laying down?​

Answers

Answer: abdominal muscles.

Explanation:

Abdominal muscles I think

Temperature and Thermal Energy
Quiz
Active
2
6
7
8
10
TIME REMAINING
47:44
What happens when the thermal energy of a substance increases?
The motion of the particles in the substance increases, and the temperature of the substance decreases.
The motion of the particles in the substance decreases, and the temperature of the substance increases.
O Both the motion of the particles in the substance and the temperature of the substance decrease.
Both the motion of the particles in the substance and the temperature of the substance increase.

Answers

Answer:

the temperature increas

hey, what is rectilinear propagation of light ?​

Answers

Rectilinear propagation of light refers to the propensity of light to travel along a straight line without any interference in its trajectory. When light travels through a medium, say air or water, it follows a straight line.

Please leave a thanks <3

To those against whom war is made, permission is given (to fight), because they are wronged;- and verily, Allah is most powerful for their aid.

Answers

Answer:

allah is pog

Explanation:

PLEASE HELP !! A 10 ohm resistor is connected to a 9V battery how much current is flowing through the circuit?

Answers

Resitance (R)= 10 Ohm

Potential difference (V) = 9V

V= IR

I= V/R

I= 9/10

I= 0.9 Ampere

Therefore 0.9 Ampere of current is flowing through the circuit.

The current through the circuit can be calculated using Ohm's law. The  current flowing through the circuit with a resistance of 10 ohm and 9 V is 0.9 ampere.

What is Ohm's law?

Ohm's law states that the potential difference or voltage across a circuit is the product of the current  and resistance through the circuit. Thus  as current or resistance increases, voltage across the circuit also increases.

According to Ohm's law, V= IR.

Given  the voltage V = 9 V

Resistance R = 10 ohm

Current = voltage/ resistance (V/R)

             =  9 V/ 10 Ω.

             = 0.9 A.

Therefore, the current passing  through the circuit is 0.9 A.

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Two identical soccer balls are rolled toward each other. What will be true after they collide headon? (2 points)

Answers

Complete Question:

Two identical soccer balls are rolled toward each other. What will be true after they collide headon?

Group of answer choices.

A. they will both stop rolling immediately after they collide head–on.

B. One ball will stop rolling and the other will roll backward at a slower speed.

C. They will both roll back at the same speed they had before the collision

D.They will both roll to the side at a faster speed after the collision

Answer:

C. They will both roll back at the same speed they had before the collision

Explanation:

Newton's Third Law of Motion which states that, for every action there is an equal but opposite reaction.

This ultimately implies that, in every interaction, there is a pair of forces acting on the two interacting objects.

In this scenario, two identical soccer balls are rolled toward each other. Thus, after they collide headon, they will both roll back at the same speed they had before the collision in accordance with Newton’s Third Law of Motion.

Additionally, The law of conservation of momentum states that the total linear momentum of any closed system would always remain constant with respect to time.

This ultimately implies that, if the two identical soccer balls exert forces only on each other, their total momentum is conserved

You are planning an investigation that explores the properties of matter. Which of the following will help you discover a physical property?


Experiment: place a powder into a beaker that contains a liquid/Result: the beaker gets hotter

Experiment: place a powder into a beaker that contains a liquid/Result: the solid dissolves into the liquid

Experiment: place a powder into a beaker that contains a liquid/Result: the mixture begins to fizz and bubble

Experiment: place a powder into a beaker that contains a liquid/Result: the mixture catches fire and burns down the lab

Answers

Answer:

I will post your answer soon

Explanation:

If you are planning an investigation that explores the properties of matter, then experiment: place a powder into a beaker that contains a liquid Result : the beaker gets hotter will help you discover a physical property.

What is experiment ?

An experiment is a technique used to confirm or deny a hypothesis, as well as assess the possibility or effectiveness of something that has never been done before. Experiments show what happens when a certain component is modified, which sheds light on cause-and-effect relationships. The purpose and scope of experiments vary widely, but they always rely on a repeatable process and a rational examination of the outcomes. Natural experimental experiments are also a thing.

While a child may conduct simple experiments to better understand how objects fall to the ground, scientific teams may spend years conducting thorough research to increase their understanding of a phenomenon.

This experiment shows enthalpy is positive, heat is absorbed in this experiment. this breaks the atoms and it needed the energy.

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Hurry pls I need help

Answers

Answer:

away from each other

Explanation:

Thus, two negative charges repel one another, while a positive charge attracts a negative charge. The attraction or repulsion acts along the line between the two charges. The size of the force varies inversely as the square of the distance between the two charges.

How many seconds does it take for net force 20N to change the velocity to a 5kg mass by 2m/s?

Answers

Answer:

0.5 second

Explanation:

We are given that

Force, F=20 N

Mass, m=5 kg

Change in velocity,=2m/s

We have to find the time taken to change the velocity .

We know that

Force, F=ma

Where

Acceleration, a=Change in velocity/time

[tex]a=\frac{2}{t}[/tex]

Substitute the values

[tex]20=5\times \frac{2}{t}[/tex]

[tex]t=\frac{5\times 2}{20}[/tex]

[tex]t=0.5 s[/tex]

A hair dryer transfers 48K J of energy in one minute. What is the power rating of the hairdryer? *

Answers

Answer:

800W

Explanation:

48,000/60=800

The power rating of the hairdryer is 800W.

What is Power?

Power can be defined as the rate at which work is done by an object. The S.I unit of power is Watt(W).

The formula of power will be

Power = Work done/time

A hair dryer transfers 48K J of energy in one minute.

1 minute = 60 seconds

P = 48,000/60

P = 800 W

Hence, the power rating of the hairdryer is 800W.

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What is the velocity of a ball that is thrown in the air 16 meters? The ball reaches the ground in 25 seconds

v = d/t

please be quick ​

Answers

Answer:

0.64

Explanation:

v = d/t

v= 16/25

v= 0.64

PLEASE Help! Physics Question​

Answers

Answer:

hundred metre race on sports day started by a gun firing when the gun is fired a pop of smoke comes out of the gunners will you suggest about trigonometry right here is the sound of the explosion before or at it seems of of smoking containers out of the governor ke this answer about something I don't know I am sorry

An initially motionless test car is accelerated to 115 km/h in 8.58 s before striking a simulated deer. The car is in contact with the faux fawn for 0.815 s, after which the car is measured to be traveling at 60.0 km/h. What is the magnitude of the acceleration of the care before the collision? What is the magnitude of the average acceleration of the car during the collision?

Answers

Answer:

a)       a = 3.72 m / s², b)    a = -18.75 m / s²

Explanation:

a) Let's use kinematics to find the acceleration before the collision

             v = v₀ + at

as part of rest the v₀ = 0

             a = v / t

Let's reduce the magnitudes to the SI system

              v = 115 km / h (1000 m / 1km) (1h / 3600s)

              v = 31.94 m / s

              v₂ = 60 km / h = 16.66 m / s

l

et's calculate

             a = 31.94 / 8.58

             a = 3.72 m / s²

b) For the operational average during the collision let's use the relationship between momentum and momentum

            I = Δp

            F Δt = m v_f - m v₀

            F = [tex]\frac{m ( v_f - v_o)}{t}[/tex]

            F = m [16.66 - 31.94] / 0.815

            F = m (-18.75)

Having the force let's use Newton's second law

            F = m a

            -18.75 m = m a

             a = -18.75 m / s²

How can I skip class:

A: Fake sick.
B: Have a heating pad on my heat to have a fake fever.
C: Fake barf
D: Act fine until a test the neb sick

Answers

Answer:

c gl

Explanation:

::::::::::::::::::::::::

Thanks for the free points I would do C

What energy is this in the image

Answers

Answer:

chemical energy

Explanation:

Gives you energy to burn off

Answer:

yea what she said

Explanation:

what ever she said

A bike travels at 120 meters in 60 seconds. What is the speed of the bike?

Answers

Answer:

2 m/s

Explanation:

Which is an example of physical weathering?

a- limestone in rock dissolving when acid rain flows across it

b- bits of rock rusting when exposed to oxygen and water

c- wind blowing off bits of a rock over time

d- oxidation of certain metals in rock

Answers

C
I’m pretty sure the answer is C because physical weathering means is when rock is broken down through mechanical processes such as wind, and C is the only one talking about breaking down (not dissolving) the rock.
I could be wrong.?

An example of physical weathering is the wind that is blowing off bits of a rock over time. This results into breaking down of large rocks. Thus, the correct option is C.

What is Physical weathering?

Physical weathering is also called as mechanical weathering. It is a process which causes the disintegration of large rocks, minerals, and large soil particles without any chemical change. The primary process in physical weathering is the abrasion, it is the process by which clasts and other particles are reduced in size and mix up with soil.

Physical weathering occurs when large rocks are broken down through mechanical processes such as wind blowing, water, gravitational force, freeze-thaw cycles, or the growth of roots into the rocks.

Therefore, the correct option is C.

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what is the momentum of a bicycle with a mass of 18 kg traveling at 20 m/s?

Answers

Answer:360 kg m/s

Explanation:Momentum refers to an object's quantity of motion.

Formula for Momentum: p=mv

p = refers to the momentum

m = refers to the object's mass (this is represented by the unit kg or kilogram)

v = this refers to the object's velocity (this is represented by the unit m/s or meter per second)

So, given that the bike has a mass of 18 kg and is traveling at 20 m/s, then you can already get the momentum by multiplying both of these values.

p = the bike's momentum (what is being asked here)

m = 18 kg

v = 20 m/s

Thus, p = 18kg × 20 m/s = 360 kg m/s

The bike's momentum is 360 kg m/s.

Brainlist please

. Calculate the unbalanced force acting on a 0.50 kg toy rocket that accelerates at a constant rate with a velocity of 20 m/s (up) to 45 m/s (up) in 0.7 s.

Answers

Answer:

17.85N

Explanation:

Given data

m= 0.5kg

u= 20m/s

v= 45m/s

t= 0.7second

From

F= mΔv/t

substitute

F=0.5*(45-20)/0.7

F=0.5*25/0.7

F=12.5/0.7

F=17.85

Hence the force is 17.85N

A box has a 20 N force applied to it to move it 5 m. What is the work done on the box? 4 J 4 N 25 J 100 J

Answers

100 J

Explanation:
multiply the force by the distance
20 N x 5 meters = 100 J
please mark brainliest
to solve for work you would need to take your force and multiply it by your displacement which would be 20F*5m=100J

Question 5 of 10
A dog pushes against the front door for 3 seconds with a force of 88 N. What
impulse has the
dog applied to the door?
A. 264 kg•m/s
O B. 77.2 kg•m/s
O C. 29.3 kg•m/s
OD. 128 kg•m/s
SLEMT

Answers

Answer:

265 Kg.m/s

Explanation:

Impulse = Force × time

So 88× 3 =264!!

Answer:

264 kg*m/s

Explanation:

I know the answer but what type of energy is this.

Answers

Answer:

Elastic potential energy

Explanation:

Answer:

elastic energy

Explanation:

1. Which of the following is an example of a force?
-0.1 Newtons to the left
-5 m/s/s
-0.5 m/s/s
-10 Newtons

Answers

10 Newton’s thank me later



A steel ball bearing is released from a height H and

rebounds after hitting a steel plate to a height H.

What is true about the collision with the steel plate?

Answers

Answer:

ELASTIC collision

kinetic energy is conservate

Explanation:

As the ball bounces to the same height, it can be stated that the impact with the floor is ELASTIC.

As the floor does not move the conservation of the moment

            po = pf

            -mv1 = m v2

- v1 = v2

So the speed with which it descends is equal to the speed with which it rises

Therefore the kinetic energy of the ball before and after the collision is the same

Answer:

CORRECT (SELECTED)

It is elastic since kinetic energy was conserved.

Explanation:

PLEASE HELP WILL GIVE BRAINLIEST (I NEED TWO PICKED) PLZzZZZZ AND THxS

Answers

Answer:

A and B

Explanation:

They contain Chlorophyll

They are relatively tall

A free body diagram represents all of the following except:
a)the object
b)forces as vectors
c)forces exerted by the object
d)forces exerted on the object

Answers

Answer:

c

Explanation:

A free body diagram doesn't show forces exerted by the object.

A free body diagram represents all the given choices except the one which is "forces exerted by the object"

Diagrams that represent the approximate magnitude as well as the direction of all pressures exerted on either an item throughout a particular condition.Drawing such a free-body schematic or the model seems to be a key step towards pattern recognition throughout mechanical because it allows you to see every one of the influences operating on a particular element.

Thus the above answer is right.

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