A man can walk three blocks east and four blocks north in 20 min. He can drive 12 times that distance in the same amount of time. How far can the man
drive in 20 min? Assume that each block is 0.3 kilometers.

Answers

Answer 1

Answer:  25.2 km

Explanation:

3 blocks east and four blocks east = 7 blocks

1 block = 0.3 km  --> 7 blocks = 2.1 km

12 times 2.1 km = 25.2 km


Related Questions

Please help. Brainliest will be given! 25 points. Show all work.

Answers

Explanation:

Given:

v₀ₓ = 15 m/s cos 20° = 14.10 m/s

aₓ = 0 m/s²

v₀ᵧ = 15 m/s sin 20° = 5.13 m/s

aᵧ = -9.8 m/s²

t = 1.5 s

Find: Δx and Δy

Δx = v₀ₓ t + ½ aₓ t²

Δx = (14.10 m/s) (1.5 s) + ½ (0 m/s²) (1.5 s)²

Δx = 21.1 m

Δy = v₀ᵧ t + ½ aᵧ t²

Δy = (5.13 m/s) (1.5 s) + ½ (-9.8 m/s²) (1.5 s)²

Δy = -3.33 m

Which of these results in kinetic energy of an object? a position b motion c mass d volume

Answers

Answer:

Option B

Explanation:

Kinetic Energy is the energy possessed by the body due to "motion".

The answer is:

B. Motion

PLZ HELP Sound is a form of wave. List at least three reasons to support the idea that sound is a wave

Answers

Answer:

Sound is a form of wave . Wave is defined as a periodic disturbance in medium.

Reasons:  

1. It follows all properties of light at a boudary.

2. Noise cancelling headphones.

3. It carry energy from one place to another.

Explanation:

I hope this will help you guy.

Sound wave is a mechanical type of wave because it requires a material medium for its propagation.

The following are three reasons sound is classified as a wave.

Reflection: sound waves are reflected like other waves when they strike a plane surface. This effect results to a phenomenon called Echo. Echo is the sound heard after the reflection of sound waves from a plane surface.Interference: sound wave like other form of wave exhibits interference. Interference of sound occurs when two waves of same frequency emitted by two close sources are superposed.Refraction: sound wave like other forms of wave also exhibits changes in  velocity, frequency and wavelength when it moves from one medium to another.  

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We weigh less in water than in air. Why? ​

Answers

It is because of the buoyang force
We actually are the same weight as they are on dry land due to gravity acting at a constant acceleration on the mass of the object. Objects due however "appear" to weigh less in water. This is due to what is known as buoyancy. Buoyancy is actually the upward force of a liquid acting on an object that is placed in it.

If you hold a bar magnet in each hand and bring your hands together, will the force be attractive or repulsive if the magnets are held:
a) with the two north poles together?
b) with a north pole and south pole together

Answers

Answer:

Part A:

They will repel each other because same poles repel each other.

Part B)

They will attract each other because different poles attract each other..

You notice the flagpole at school vibrating in the breeze. You count the vibrations and find that
the flagpole makes 20 complete vibrations in 10 seconds. You read somewhere that this
flagpole vibrates at a speed of 25 m/s when the wind is blowing. Find the wavelength of these
vibrations

Answers

Answer:

Wavelength =50 m

Explanation:

Given:

n=20

t=10sec

V=25m/s

Wavelength =?

Solution:

Wavelength = frequency ×velocity ---> eq 1

Time period=time/no of vibrations

T=10/20=0.5sec

Frequency =1/Time period(T)

f=1/0.5=2

Put the value of frequency in eq 1

Wavelength =2×25

Wavelength =50m...

Hope you understand!

Have a nice day!

Just after taking off, the aeroplane continues to accelerate as it gains height. State two forms of energy that increase during this time.

Answers

Answer:

The two forms of energy that increase during the time after take off are;

1) The kinetic energy KE

1) The potential energy PE

Explanation:

1) Given that the airplane is accelerating, we have that the velocity, v, of the airplane is increasing, such that the we have the kinetic energy, KE, for a given mass, m, of the airplane increasing as follows;

KE₂ = 1/2×m×v₂² > KE₁ = 1/2×m×v₁²

2) Also, as the height, h, of the airplane increases during the ascent, we have that the potential energy increasing along side as follows;

PE₂ = m × g × h₂ > PE₁ = m × g × h₁

Therefore, the two forms of energy that increase during the time after take off are the kinetic  and the potential  energy.

What distance does a mobile travel that with a constant acceleration of 3m / s increases its speed from 6m / s to 12m / s

Answers

Answer:

18 m

Explanation:

Given:

v₀ = 6 m/s

v = 12 m/s

a = 3 m/s²

Find: Δx

v² = v₀² + 2aΔx

(12 m/s)² = (6 m/s)² + 2 (3 m/s²) Δx

Δx = 18 m

Average acceleration. Please help!

Answers

Answer:

8.43 m/s²

Explanation:

Average acceleration is the change in velocity over change in time.

a = Δv/Δt

First, convert km/h to m/s.

45 km/h = 12.5 m/s

500 km/h = 138.9 m/s

Now find the acceleration.

a = (138.9 m/s − 12.5 m/s) / 15.0 s

a = 8.43 m/s²

Please HELP!!! I will give brainliest to whoever gives honest help!!! A 500 kg satellite experiences a gravitational force of 3000 N, while moving in a circular orbit around the earth. Determine the radius of the circular orbit. Determine the speed of the satellite. Determine the period of the orbit.

Answers

Given that,

Mass of satellite = 500 kg

Gravitational force = 3000 N

We need to calculate the radius of the circular orbit

Using formula of gravitational force

[tex]F_{g}=\dfrac{GMm}{(R+h)^2}[/tex]

Where, G = gravitational constant

R = radius of earth

h = radius of the circular orbit

M = mass of earth

m = mass of satellite

Put the value into the formula

[tex]3000=\dfrac{6.67\times10^{-11}\times500\times6\times10^{24}}{(6.4\times10^{6})^2+h^2}[/tex]

[tex]h^2=\dfrac{6.67\times10^{-11}\times500\times6\times10^{24}-3000\times(6.4\times10^{6})^2}{3000}[/tex]

[tex]h=\sqrt{\dfrac{6.67\times10^{-11}\times500\times6\times10^{24}-3000\times(6.4\times10^{6})^2}{3000}}[/tex]

[tex]h=5073460.35\ m[/tex]

[tex]h=5.1\times10^{6}\ m[/tex]

(II). We need to calculate the speed of the satellite

Using formula of velocity

[tex]v=\sqrt{\dfrac{GM}{r}}[/tex]

Put the value into the formula

[tex]v=\sqrt{\dfrac{6.67\times10^{-11}\times6\times10^{24}}{5.1\times10^{6}}}[/tex]

[tex]v=8858.36\ m/s[/tex]

[tex]v=8.8\times10^{3}\ m/s[/tex]

[tex]v=8.8\ km/s[/tex]

(III). We need to calculate the period of the orbit

Using formula of  time period

[tex]T=2\pi\sqrt{\dfrac{r^3}{GM}}[/tex]

Put the value into the formula

[tex]T=2\pi\sqrt{\dfrac{(5.1\times10^{6})^3}{6.67\times10^{-11}\times6\times10^{24}}}[/tex]

[tex]T=3617.40\ sec[/tex]

[tex]T=1.00\ hr[/tex]

Hence, (I). The radius of the circular orbit is [tex]5.1\times10^{6}\ m[/tex]

(II). The speed of the satellite is 8.8 km/s.

(III). The period of the orbit is 1.00 hr.

answer the following question​

Answers

Answer:

A) OA, AB, BC

B) 25m/s^2

C) see explanation

D) 25

E) Rest

Explanation:

From the Velocity time graph shown:

The positive slope = OA ; This is positive because, it is the point of uniform acceleration on the graph.

Constant slope = AB, the slope here is constant because, AB on the graph is the point of constant velocity.

-ve slope = BC

B) Acceleration of body in path OA.

Acceleration = change in Velocity / time

Acceleration = (150 - 0) / 6

Acceleration = 150/6 = 25m/s^2

C) Path AB is Parallel to the because it marks the period of constant velocity (that is Velocity does not increase or decrease during the time interval).

D) Length of BC

BC corresponds to the distance moved, that velocity / time

Velocity = 150 ; time = 6

Therefore Distance (BC) = 150/6 = 25

E.) Velocity =0 ; Hence body is at rest

If a star is located 100 light years from Earth, what can you conclude about the light from the star?
The light will take 100 years to reach Earth.
The light will take 100 seconds to reach Earth.
The light will take 300,000 years to reach Earth.
The light will travel a total of 300,000 kilometers to reach Earth.

Answers

Answer:

Light from star would take 100 years to reach the Earth.

Explanation:

1 light year = speed of light × 1 year

1 light year = 9.46 × 10¹⁵ m

hope i helped

-lvr

Answer:

a

Explanation:

;)

1.what are some of the impacts of modern communication in our socio economic life?

2.how is possible to make a call to our relatives residing in other part of country ?explain?​

Answers

Answer:

The impacts of modern communication in our socio economic life includes;

a) Staying connected

b) Carrying out business transaction

c) Exceeding boundaries

d) Overcoming weakness and disability

e) Reaching out to a wider audience

2. It is possible to make long distant call to our relatives in other part of the country by direct distance dialing (DDD)

Explanation:

The telecommunication service called direct distance dialing allows a caller to make a call to a location outside the area where they are calling without the assistance of an operator. To make a direct dialing call, a subscriber or caller will be required to include extra prefix digits to the original number than for numbers within hers or his particular local area code.

a 2500kg car is travelling at a constant speed of 14 m/s along an icy, but straight and level road. the driver of the car, seeing an approaching traffic light turn red., slams on the brakes. Wheels locked and ttired skidding, the car slide to a halt in a distance of 25m. What is the coefficient of friction

Answers

Answer:

0.40

Explanation:

Given that :

the mass of the caer = 250 kg

initial speed = 14 m/s

final speed = 0 m/s

distance  s = 25 m

Using the equation of motion

[tex]v^2 = u^2 + 2as[/tex]

making a the subject of the formula ; we have:

[tex]v^2-u^2 = 2as[/tex]

[tex]a= \dfrac{v^2-u^2 }{2 \ s}[/tex]

[tex]a= \dfrac{(0)^2-(14)^2 }{2 \ (25)}[/tex]

[tex]a= \dfrac{0-196 }{50}[/tex]

[tex]a= \dfrac{-196 }{50}[/tex]

a = -3.92 m/s²

However; the relation for the coefficient of the kinetic static friction can be expressed as:

[tex]f= \mu_k *mg= ma[/tex]

[tex]f= \mu_k *g= a[/tex]

[tex]f= \mu_k = \dfrac{a}{g}[/tex]

[tex]f= \mu_k = \dfrac{3.92}{9.8}[/tex]

[tex]f= \mu_k = 0.40[/tex]

A flat polished area is turned through 15 degrees. If the angle of incidence is 20 degrees, what is the angle between the incident ray and the reflected ray of the turned surface?

Answers

Answer:

50°

Explanation:

Angle of rotation of the flat polished surface [tex]\theta[/tex] = 15°

angle of incidence i = 20°

Since the polished surface is turned at an angle of 15°, the angle of reflection

r = 2[tex]\theta[/tex] (Note that the angle of rotation only have effect of the angle of reflection)

r = 2*15 = 30°

The angle between the reflected ray and the incident ray will be equal to the sum of the angle of incidence and the angle of reflection i.e i+r

The angle between the reflected ray and the incident ray = 20°+ 30° = 50°

the coefficient of friction between a hard rubber and normal street pavement is 0.8 What is the steepest incline on which a car can be safely parked​

Answers

Answer:

38.7°

Explanation:

Draw a free body diagram of the car.  There are three forces:

Weight force mg pulling down,

Normal force N pushing up perpendicular to the incline,

and friction force Nμ pushing parallel up the incline.

Sum of forces in the perpendicular direction:

∑F = ma

N − mg cos θ = 0

N = mg cos θ

Sum of forces in the parallel direction:

∑F = ma

Nμ − mg sin θ = 0

Nμ = mg sin θ

μ = (mg sin θ) / N

μ = (mg sin θ) / (mg cos θ)

μ = tan θ

Given μ = 0.8:

θ = tan⁻¹(0.8)

θ = 38.7°

A neutral atom has the same number of protons as it does neutrons.
A. True
O B. False
SUBMIT

Answers

Answer:

The answer is False

Hope this helps you

It is false that a neutral atom has the same number of protons as it does neutrons. The correct option is B.

The claim that "A neutral atom has the same number of protons as it does neutrons" is untrue. Protons and electrons in a neutral atom are equal in number, but neutron counts can change.

Electrons have a negative charge, whereas protons have a positive charge. A neutral atom has a net charge of zero because the protons' positive charge is balanced by the electrons' negative charge.

Neutrons don't have an electric charge, though. Within a single element, the amount of neutrons can change, giving rise to many isotopes.

Isotopes contain the same amount of protons, but their atomic masses vary depending on how many neutrons they have.

Thus, the correct option is B. False.

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PLZ HELP What is necessary condition for production of waves?

Answers

Answer:

The length of the rope must be an integral multiple of the wavelength of the wave.

Explanation:

Answer:

The condition necessary for formation or a standing wave is that the length of the rope (or the length over which the wave is distributed) must be an integral multiple of the wavelength of the wave. Therefore, l=nλ where n is a positive integer.

can we investigate that which fuel
is cheapest

Answers

Answer:

yeah..

as we all know that the cheapest fuel is petrol because it is the last product of petroleum.

hope it helps...

If three vectors added together, forms a triangle, the resultant will be equal to  twice the vector  zero  doubled the magnitude  none of the above

Answers

Answer:

the resultant vector will be a null vector or with 0 magnitude

Explanation:


a 35g ball is lifted up from 1.0m to 3.0m. How much work is done?

Answers

[tex]\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}[/tex]

Actually Welcome to the Concept of the Work And Energy.

So we here use the formula as,

W= Mgh

so after solving we get as,

W = 0.686 Joules

any ss2 here (11th Grade)

Answers

Answer:

a) 50°b) 40°

Explanation:

Check the complete diagram n the attachment below

a) The angle of incidence on a plane surface is the angle between the incidence ray and the normal ray acting on a plane surface. The normal ray is the ray perpendicular to the surface while the incidence ray is the ray striking a plane surface.

According to the diagram, the angle of reflection r₂ on M₂ is 90°-g where g is the angle of glance.

Given angle of glance on M₂ to be 40°, r₂ = 90-40 = 50°

According the second law of reflection, the angle of incidence = angle of reflection, therefore i₂ = r₂ = 50° (on M₂)

Also ∠OO₂O₁ =  ∠OO₁O₂ = 40° (angle of glance on M){alternate angle}

The angle of incidence on M₁ = 90° - 40° = 50°

b) The angle of incidence to the surface of M₁(∠PO₁A)will be the angle of glance on M₁ which is equivalent to 40°

What is the net force acting on the buggy. ?The net force is pointing to the ?

Answers

Answer: 390, right

explanation: The net force is just the sum of all of these forces acting on an object. ... This equation is the sum of n forces acting on an object. The magnitude of the net force acting on an object is equal to the mass of the object multiplied by the acceleration of the object, as shown in this formula.

the net force acting on the buggy is 390 and The net force is pointing to the is right

The following information should be considered:

The net force should be the sum of all of these forces that acted an object.This equation is the sum of n forces acting on an object. The magnitude of the net force acting on an object is equivalent to the mass of the object and multiplied by the acceleration of the object

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ULIULIOL
THIS. AJUSI
A bus is moving with a velocity of 72 km/hr. On seeing the red signal of traffic
at 27 m ahead on the road, the driver applied brakes and the bus stopped at a
distance of 25 m. Calculate the time taken by the car to come at rest. (Ans: 2.5 s)
with
of 60 km/hr. On seeing a child at 11m ahead on
A
a​

Answers

Answer:

The time taken by the car to come at rest is 2.5 seconds

Explanation:

The parameters given are;

Speed of bus = 72 km/hr

Distance at which bus stopped = 25 m

Given that the speed and the distance covered before stopping are j=known, we have;

v² = u² - 2·a·s

Where:

v = Final velocity = 0

a = Deceleration of the bus

s = Distance covered while decelerating = 23 m

u = Initial  velocity = 72 km/hr = 20 m/s

Which gives;

0² = (20 m/s)² - 2×a×25 m

20² = 2×a×25 m

a = 20²/(2×25) = 8 m/s²

The time, t, it takes for the car to come at rest is given by the relation;

v = u - at

0 = 20 - 8×t

t = 20/8 = 2.5 s.

What is the effect of the medium on the speed of the sound? In which medium sound travels more faster: air, solid, or liquid? Justify your answer?

Answers

The phase of matter has a large impact upon the elastic properties of a medium. In general, the bond strength between particles is strongest in solid materials and is weakest in the gaseous states As a result, sound waves travel faster in solids than in liquids, and faster in liquids than in gasses.

Hope this helps

Answer:

Sound travels fastest through solids. This is because molecules in a solid medium are much closer together than those in a liquid or gas, allowing sound waves to travel more quickly through it. In fact, sound waves travel over 17 times faster through steel than through air.

two masses are kept 2 metre apart there is gravitational force of 2 Newton what is the gravitational force when they are kept at 4 metre apart​

Answers

Answer: 0.5N

Explanation:

Gravitational force is calculated using the formula :

F = Gm1m2/r^2

Where G is the gravitational constant (6.67 × 10^-11)

At a distance 'r' of 2metres apart:

Mass of objects are m1 and m2

Gravitational force 'F1' = 2N

Inputting values into the formula :

2 = Gm1m2 / 2^2 - - - - - (1)

At a distance 'r' of 4meters apart:

Mass of objects are m1 and m2

Gravitational force 'F2' = y

Inputting values

F2 = Gm1m2 / 4^2 - - - - - (2)

Dividing equations 1 and 2

2 = Gm1m2 / 2^2 ÷ F2 = Gm1m2 / 4^2

2 / F2 = (Gm1m2 / 4) / (Gm1m2 / 16)

2 / F2 = (Gm1m2 / 4) × (16 / Gm1m2)

2/F2 = 16 / 4

Cross multiply

2 × 4 = 16 × F2

8 = 16F2

F2 = 8/16

F2 = 0.5N

In an obstacle course, runners must jump hurdles that are .84 m high. If the speed of one of the athletes when he is 1.63 meters from the fence is 4m / s on the horizontal axis and 4m / s on the vertical axis. Calculate the maximum height reached and indicate whether or not the jump was successful for that runner. Help :c

Answers

Answer:

0.82 m

Explanation:

Given:

v₀ᵧ = 4 m/s

aᵧ = -9.8 m/s²

Find: Δy when vᵧ = 0 m/s

vᵧ² = v₀ᵧ² + 2aᵧΔy

(0 m/s)² = (4 m/s)² + 2 (-9.8 m/s²) Δy

Δy = 0.82 m

The maximum height reached by the athlete is 0.82 meters.  The jump is not successful.

Which is a negative effect of deforestation on the environment? A. habitat restoration B. desertification C. soil production D. urbanization

Answers

Answer:Deforestation refers to the decrease in forest areas across the world that are lost for other uses such as agricultural croplands, urbanization, or mining activities. Greatly accelerated by human activities since 1960, deforestation has been negatively affecting natural ecosystems, biodiversity, and the climate. The UN’s Food and Agriculture Organization estimates the annual rate of deforestation to be around 1.3 million km2 per decade.

Explanation:

The negative effect of deforestation on the environment is desertification. The correct option is B.

What is desertification?

Desertification is the process by which fertile land becomes desert, typically as a result of drought, deforestation, and inappropriate agriculture or land use practices. It occurs when land that was once able to support vegetation and life becomes increasingly dry, barren, and unable to sustain crops, livestock, or human populations. This can be due to natural causes such as prolonged droughts, but it is often exacerbated by human activities such as deforestation, overgrazing, and soil degradation. Desertification can have devastating effects on the environment, leading to soil erosion, loss of biodiversity, and reduced productivity of the land. It can also cause social and economic problems, such as displacement of people, food shortages, and conflicts over resources.

Here in the question,

Deforestation is the clearing of trees and other vegetation from an area, leading to the loss of habitat and biodiversity, and disruption of water cycles. It can also cause soil erosion, which can result in the depletion of soil nutrients, reduced productivity, and eventually lead to desertification. Additionally, deforestation contributes to climate change by releasing carbon dioxide into the atmosphere, which can cause global warming and other environmental problems. Habitat restoration, soil production, and urbanization are not negative effects of deforestation but can be impacted by it.

Therefore, The correct answer is B i. e Desertification.

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1. Light from a laser shines through two narrow slits 0.300 mm apart and produces an interference pattern on a screen 4.35 m away consisting of 9 bright fringes over a distance of 6.4 cm. a) Draw a labeled diagram of this scenario and briefly explain how the interference pattern is created b) Calculate the wavelength of the laser. What color is it?

Answers

Answer:

Explanation:

slit separation d = .3 x 10⁻³ m

screen distance D = 4.35 m

fringe width = 6.4 x 10⁻² / 9

= .711 x 10⁻² m

a ) Interference pattern on the screen is created due to interference of two light waves coming from two slits and falling in screen . When they fall on different points on the screen they travel different distance . This is called path difference . When their path difference is equal to their wave length or its integral multiple , they reinforce each other and at that point the brightness increases . On the other hand when at a point the path difference is equal to odd multiple of half wavelength , they kill or destroy each other and darkness is found at that point . In this way dark band and bright band appear on the screen . This is called interference pattern .

b )

Fringe width  = λ D / d

Putting the values

.711 x 10⁻² = λ x 4.35 /  0.3 x 10⁻³

λ = .049 x 10⁻⁵

= 490 x  10⁻⁹

= 490 nm

The colour of this wavelength will be blue .

A 5000 kg mass rocket “breaks the engine” when it is 100 m high and climbing at a speed of 75 m / s. Calculate:
1) The maximum height it will reach
2) The speed with which it will hit the ground after the fall.

Answers

Answer:

1:281.25m

2:75m/s

Explanation:

using the equation

[tex]v^{2} = u^{2} + 2gs[/tex]

at maximum height v is zero so using that you can make s the subject of the formula

[tex]h \: max = u^{2} \div \: 2g[/tex]

so substitute the velocity 75 and the constant g-10m/s^2

as for the returning velocity we say displacement is zero since you go and come back the same distance

so

[tex]v = { + or - }u[/tex]

u is the initial speed in this case it's positive since going in the direction of gravity

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