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A .63 kg ball is moving at 4.3m/s. What is the momentum of the ball?

Answers

Answer 1

Answer:

Given Mas (m) =63kg

velocity (v) =4.3m/s

momentum (p) =?

p=mv

63kgx4.3m/s

270.9kg.m/s

the momentum =270.9kg.m /s

Answer 2

If a ball of mass 0.63 kilograms is moving at 4.3 meters/seconds, then the momentum of the ball would be 2.709-kilogram meters/second.

What is momentum?

It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle.

Momentum = mass of the object × velocity of the object

As given in the problem we have to calculate the momentum of the ball if it has a mass of 0.63 kilograms and moving with a speed of  4.3 meters/seconds,

The momentum of the ball = 0.63× 4.3

                                             

                                             =2.709 kilogram meters/second

Thus, the momentum of the ball comes out to be 2.709-kilogram meters/second.

To learn more about momentum from here, refer to the link;

brainly.com/question/17662202

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Related Questions

When naming the compound containing lithium and chlorine, change the
suffix of the anion's name to
O A. ide
B. ite
C. cation
D. anion

Ape_x

Answers

Answer: Ide

Explanation:

Just got it right on the quiz

Answer:Ide

Explanation: thats the answer for a pex

1.A motorcycle’s velocity at the top of the hill is 11.0 m/s. 4.0 seconds later it reaches the bottom of the hill with a velocity of 20.0 m/s. What is the acceleration of the motorcycle?

2.A motorcycle’s velocity at the top of the hill is 11.0 m/s. 4.0 seconds later it reaches the bottom of the hill with a velocity of 20.0 m/s. What is the acceleration of the motorcycle?

Answers

Answer:

1) as far as I remember

Let's take 20 as vf (final velocity) and 11 as (initial velocity) and 4 as time

So we would use this formula a=vf-vi/t

So 20-11/4

Asnwer 2.25

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