A 12 ounce bag of rice costs $4.08. A 16-ounce bag of the same rice costs $5.76. Which bag is the better by
and by how much

Answer:

Option D is the correct answer.

Step-by-step explanation:

The equation of the function is in vertex form. Thus, we can analyze the equation to determine the x and y values of the vertex. We know that the template format of a vertex form equation is as follows:

f(x) = a(x – h)2 + k . The only constants we need are h and k, where 'h' is the x-value of our vertex and 'k' is the y-value of our vertex.

The value of 'k' can be found quite simply by looking at the equation: -9.

The value of 'h' is a little trickier, as we must take into account the 'subtract' sign of the template equation, meaning that the '+7' in the given equation actually means that we are subtracting negative seven. Thus, the value of 'h' is -7.

Thus, the vertex of this graph is (-7,-9).

This means that option D is correct.

Answer:

The vertex is at ( -7, -9)

Step-by-step explanation:

y = (x+7)^2 -9

This is written in vertex form

y = a( x-h)^2 +k where ( h,k) is the vertex

y = ( x - -7)^2 + -9

The vertex is at ( -7, -9)

Answer:

30 cm

Step-by-step explanation:

let x be the lenght of the two sides of equal lenghts, so the other is x+3

and the perimeter is x+x +x +3

P=3x+3

P=3(x+1)

93=3(x+1)

31=x+1

x=30

so the shorter sides are of 30 centimeters and the longest is 33

Answer:

2 ( x+4) ( x+1)

Step-by-step explanation:

2x^2+10x+8

Factor out 2

2 ( x^2 +5x+4)

What two numbers  multiply to 4 and add to 5

4*1 = 4

4+1 = 5

2 ( x+4) ( x+1)

[tex] \large{ \underline{ \underline{ \bf{ \pink{To \: factorise}}}}}[/tex]

By middle term factorisation,

⇛ 2x² + 2x + 8x + 8

⇛ 2x(x + 1) + 8(x + 1)

⇛ (2x + 8)(x + 1)

⇛ 2(x + 4)(x + 1)

☃️ Now you can break it down and check which are the factors of the polynomial according to options.

━━━━━━━━━━━━━━━━━━━━

Answer:

[tex]x > -1[/tex] or

[tex]x > 2[/tex] or

[tex]x > 3[/tex]

Step-by-step explanation:

Given

[tex](x + 1)(x - 2) (x - 3) > 0[/tex]

Required

Solve; with steps

[tex](x + 1)(x - 2) (x - 3) > 0[/tex]

Start by splitting the inequality as follows

[tex]x + 1 > 0[/tex] or [tex]x - 2 > 0[/tex] or  [tex]x - 3 > 0[/tex]

Solve the inequalities one after the other

Solving: [tex]x + 1 > 0[/tex]

Subtract 1 from both sides

[tex]x + 1 - 1 > 0 - 1[/tex]

[tex]x > -1[/tex]

Solving: [tex]x - 2 > 0[/tex]

Add 2 to both sides

[tex]x - 2 +2 > 0 +2[/tex]

[tex]x > 2[/tex]

Solving: [tex]x - 3 > 0[/tex]

Add 3 to both sides

[tex]x - 3 +3> 0+3[/tex]

[tex]x > 3[/tex]

Hence, the solution to the inequality is

[tex]x > -1[/tex] or

[tex]x > 2[/tex] or

[tex]x > 3[/tex]

Answer:

Brainliest! Hope I helped!

Step-by-step explanation:

you know its greater than 1cm and less than 2cm,

1 and 7hundreths cm is = 1.07 cm

thats not right because you know it is greater than that for sure!

so the only answer left is 1.7 cm

You answer is 1.7 cm

another way...

read the ruler and see the answer

Answer:

1.7 cm.

Step-by-step explanation:

The midpoint of 1 - 2 is 5 so count the lines after 5 and you get .7 to add to one cm.

Hope this helps, have a good day :)

Answer:

[tex]x = 2-t[/tex] and [tex]y = -5\cdot t +21[/tex]

Step-by-step explanation:

Given that [tex]y = 5\cdot x + 11[/tex] and [tex]t = 2-x[/tex], the parametric equations are obtained by algebraic means:

1) [tex]t = 2-x[/tex] Given

2) [tex]y = 5\cdot x +11[/tex] Given

3) [tex]y = 5\cdot (x\cdot 1)+11[/tex] Associative and modulative properties

4) [tex]y = 5\cdot \left[(-1)^{-1} \cdot (-1)\right]\cdot x +11[/tex] Existence of multiplicative inverse/Commutative property

5) [tex]y = [5\cdot (-1)^{-1}]\cdot [(-1)\cdot x]+11[/tex] Associative property

6) [tex]y = -5\cdot (-x)+11[/tex]  [tex]\frac{a}{-b} = -\frac{a}{b}[/tex] / [tex](-1)\cdot a = -a[/tex]

7) [tex]y = -5\cdot (-x+0)+11[/tex] Modulative property

8) [tex]y = -5\cdot [-x + 2 + (-2)]+11[/tex] Existence of additive inverse

9) [tex]y = -5 \cdot [(2-x)+(-2)]+11[/tex] Associative and commutative properties

10) [tex]y = (-5)\cdot (2-x) + (-5)\cdot (-2) +11[/tex] Distributive property

11) [tex]y = (-5)\cdot (2-x) +21[/tex] [tex](-a)\cdot (-b) = a\cdot b[/tex]

12) [tex]y = (-5)\cdot t +21[/tex] By 1)

13) [tex]y = -5\cdot t +21[/tex] [tex](-a)\cdot b = -a \cdot b[/tex]/Result

14) [tex]t+x = (2-x)+x[/tex] Compatibility with addition

15) [tex]t +(-t) +x = (2-x)+x +(-t)[/tex] Compatibility with addition

16) [tex][t+(-t)]+x= 2 + [x+(-x)]+(-t)[/tex] Associative property

17) [tex]0+x = (2 + 0) +(-t)[/tex] Associative property

18) [tex]x = 2-t[/tex] Associative and commutative properties/Definition of subtraction/Result

In consequence, the right answer is [tex]x = 2-t[/tex] and [tex]y = -5\cdot t +21[/tex].

Answer:

[tex]here \: the \: two \: sides \: are \: equal \: so \: \\ the \: triangle \: is \: issosceles \\ then \: x = 40 \\ thank \: you[/tex]

Answer:

a

Step-by-step explanation:

g(1)=5

f(g(1))=f(5)

f(5)=2

I know tje answer

x+6kkkkkkkk

Answer:

X=75°;AND Y=30°

Step-by-step explanation:

Angle( x+75°)+(y)=180°

Angle(2x)+(y)=180°

[by subtracting both the equation we get;]

-1x=-75

x=75°

Now,value of y;

2x+y=180

2×75+y=180

150+y=180

y=180-150

y=30°

Answer:

The dice has 6 options:

if the outcome is 5, player wins 50

if the outcome is 6, player wins 200

if the outcome is another number, the player does not win anything.

Now, remember that the expected value can be written as:

E = ∑xₙpₙ

where xₙ is the event n, and pₙ is the probability of that event.

for a dice, the probabilty for each number is 1/6

The expected value is:

E = (1/6)*(0 + 0 + 0 + 0 + 50 + 200) = 41.66

The expected gain will be E - 100 (because the player pays 100 in order to play)

Then the expected gain is:

G = 41.66 - 100 = -58.33

The standard deviation can be written as:

s = √( ∑(x - x)^2/n)

where x is the mean, in this case the mean is:

(200 + 50 + 4*0)/6 = 41.66  and n = 6.

s = √( (1/6)*(4*(0 - 41.66)^2 + (50 - 41.66)^2 + (200 - 41.66)^2) ) = 73

So we have a lot of standard deviation on Y.

Answer:

see below

Step-by-step explanation:

4,7,12,19

We are adding 3,5,7,9..... each time

The sequence is not arithmetic because we are not adding a constant.  It is not geometric since we are not multiplying by a constant term each time

There is no common difference  or common ratio.

The explicit formula is

an =n^2 +3

The recursive formula is

(n+1)^2 +3 - (n^2 +3)

    n^2 +2n+1+3 - ( n^2+3)

      2n+1

a sub(n+1) = a sub( n) + 2n+1

The 10th term

an      = n^2 +3

Let n=10

an = 10^2+3

    = 100+3

    = 103

summation

see image

since the numbers are increasing and greater than 1 the sum does not exist

Answer:

x=50

Step-by-step explanation:

22•2=44

44+6=50

Answer:

50

Step-by-step explanation:

22×2=44+6=50.

jjjjjjjjjjjjjjjjjj

Step-by-step explanation:

Circumference = 76cm

Circumference = 2(π)(r)

r -> radius

=> 2(π)(r) = 76

=> (π)(r) = 76/2

=> (π)(r) = 38

=> 3r = 38

=> r = 38/3

=> r = 13cm (Approx.)

Diameter = 2r = 2(13) = 26cm

Area = π(r)^2

        = 3(13)^2

        = 3(169)

        = 507 cm^2

Answer

d=25.34cm

a=160.53cm

cf=12.67cm

Step-by-step explanation:

circumference=cf

diameter=d

radius=r

area=a

d=2r

=2×12.67cm

=25.34cm

cf=2πr

76cm=2(3)r

76cm=3r

2

38cm=r

3

r=12.66^cm

r=12.67cm

find the area

a=πr^2

a=12.67×12.67πcm

a=160.53πcm(it is near to this)

Answer:

volume of  redwood tree is 6400 π ft^3(option 4)

Step-by-step explanation:

concept =

volume of cylinder = πr^2l

where r is the radius and l is the length of cylinder

circumference of cylinder = 2πr

_____________________________________

shape of  redwood tree can be taken as cylindrical

given

circumference of a redwood tree trunk is 16π ft

2πr = 16π

=> r = 16π/2π = 8

Thus, radius is 8 feet

Therefore volume of  redwood tree = πr^2l = π8^2*100 = π*64*100

volume of  redwood tree =6400 π ft^3

Answer:

6,400π ft3

Step-by-step explanation:

took test and got it right

Answer:

2/3

Step-by-step explanation:

Your −3x + 3 −1 is not an equation and thus has no solution.

If, on the other hand, you meant

−3x + 3 = 1

then -3x = -2, and  x = 2/3

Answer:

a) 0.36

b) 0.3

c) Yes

Step-by-step explanation:

Given:

Probability of no traffic delay in one period, given no traffic delay in the preceding period = P(No_Delay) = 0.9

Probability of finding a traffic delay in one period, given a delay in the preceding period = P(Delay) = 0.6

Period considered = 30 minutes

a)

Let A be the probability that for the next 60 minutes (two time periods) the system will be in the delay state:

As the Probability of finding a traffic delay in one period, given a delay in the preceding period is 0.6 and one period is considered as 30 minutes.

So probability that for the next two time periods i.e. 30*2 = 60 minutes, the system in Delay is

P(A) = P(Delay) * P(Delay) =  0.6 * 0.6 = 0.36

b)

Let B be the probability that in the long run the traffic will not be in the delay state.

This statement means that the traffic will not be in Delay state but be in No_Delay state in long run.

Let C be the probability of one period in Delay state given that preceding period in No-delay state :

P(C) =  1 - P(No_Delay)

        = 1 - 0.9

P(C) = 0.1

Now using P(C) and P(Delay) we can compute P(B) as:

P(B) = 1 - (P(Delay) + P(C))

      = 1 - ( 0.6 + 0.10 )

      = 1 - 0.7

P(B) = 0.3

c)

Yes this assumption should be questioned for this traffic problem because it implies that  traffic will be in Delay state for the 30 minutes and just after 30 minutes, it will be in No_Delay state. However, traffic does not work like this in general and it makes this scenario unrealistic. Markov process model can be improved if probabilities are modeled as a function of time instead of being presented as constant (for 30 mins).

Answer:

nbbhhghhhjjjjjjjjjkjjjjnnmmmmmmmmbv b b j

Answer:

Domain all reals

Range  all reals

Step-by-step explanation:

The domain is the values that x can take, or the values of the input

x can be any real number

The range is the values that y can take, or the values of the output

y can be any real number

Answer:

C)

Step-by-step explanation:

it's fully continous, linear function thus all values are possible for both, x and y

Option a) -10

[tex] f(x)=-|x^2-5x+4|[/tex]

put $x=-1$

$f(-1)=-|(-1)^2-5(-1)+4|$

$\implies f(-1)=-|1+5+4|=-|10|=10$

Answer:

option a

Step-by-step explanation:

Option a) -10

put $x=-1$

$f(-1)=-|(-1)^2-5(-1)+4|$

$\implies f(-1)=-|1+5+4|=-|10|=10$

Answer:

One solution (-1,2)

Step-by-step explanation:

Since these two linear equations have different slopes, different y-intercepts, and are indeed linear, these equations will only have one crossing when graphed, and hence one solution.

To find that solution, we can simply set the equations equal to each other.

y = -x + 1

y = 2x + 4

-x + 1 = 2x + 4

-3 = 3x

-1 = x

Now plug that value back into one of the equations:

y = -x + 1

y = -(-1) + 1

y = 2

So now you know the crossing for these two equations occurs at (-1,2).

Cheers.

Answer:

A)0.126775 B)0.000004325376 C) 0.07548

Step-by-step explanation:

Given the following :

A.) a. n = 15, p = 0.4, find P(4 successes)

a = number of trials p=probability of success

P(4 successes) = P(x = 4)

USING:

nCx * p^x * (1-p)^(n-x)

15C4 * 0.4^4 * (1-0.4)^(15-4)

1365 * 0.0256 * 0.00362797056

= 0.126775

B)

b. n = 12, p = 0.2, find P(2 failures),

P(2 failures) = P(12 - 2) = p(10 success)

USING:

nCx * p^x * (1-p)^(n-x)

12C10 * 0.2^10 * (1-0.2)^(12-10)

66 * 0.0000001024 * 0.64

= 0.000004325376

C) n = 20, p = 0.05, find P(at least 3 successes)

P(X≥ 3) = p(3) + p(4) + p(5) +.... p(20)

To avoid complicated calculations, we can use the online binomial probability distribution calculator :

P(X≥ 3) = 0.07548

Answer:

Surface area of the box = 168 cm²

Step-by-step explanation:

Amount of cardboard needed = Surface area of the box

Since the given box is in the shape of a triangular prism,

Surface area of the prism = 2(surface area of the triangular bases) + Area of the three rectangular lateral sides

Surface area of the triangular base = [tex]\frac{1}{2}(\text{Base})(\text{height})[/tex]

                                                           = [tex]\frac{1}{2}(6)(4)[/tex]

                                                           = 12 cm²

Surface area of the rectangular side with the dimensions of (6cm × 9cm),

= Length × width

= 6 × 9

= 54 cm²

Area of the rectangle with the dimensions (9cm × 5cm),

= 9 × 5

= 45 cm²

Area of the rectangle with the dimensions (9cm × 5cm),

= 9 × 5

= 45 cm²

Surface area of the prism = 2(12) + 54 + 45 + 45

                                           = 24 + 54 + 90

                                           = 168 cm²

Answer:

or,x2-x=6

or,x2-x-6=0

or,x2-3x+2x-6=0

or,x(x-3)+2(x-3)=0

or,(x-3)(x+2)=0

so either x=3

or x=-2

Answer:

I was surprised that a plane parallel to the vertical axis creates a rectangular cross-section. I guess I was expecting to always see a circle or a circular shape in the cross-section, not purely straight edges as seen in a rectangle.

Step-by-step explanation:

edmentum answer

Answer:

The circles were the least surprising because the base of the cone is a circle. The curves that look like bent rods were the most surprising because I have not seen geometric figures like those before.

Step-by-step explanation:

Answer:

[tex]\Large \boxed{{6x \ \mathrm{and} \ -3x}}[/tex]

Step-by-step explanation:

Like terms have identical variables and exponents, the coefficients don’t have to be the same.

The like terms from the expression are 6x and -3x.

Step-by-step explanation:

Hey, there!!

6x and -3x are like terms.

Like terms in algebraic terms are those terms which has same variable or exponents. In This expression "6x+8xy-3x+9y4x^2"

6x and -3x has "x" common in them so, The answer is 6x and -3x.

Hope it helps..

Answer:

  (c) 1.02

Step-by-step explanation:

(c) The tangent is the ratio of Opposite to Adjacent. Its lowest value will be found where Opposite is lowest, and Adjacent is highest:

  min tan(A) = (min BC)/(max AB) = 75/73.5 ≈ 1.020408...(42-digit repeat)

Answer:

Step-by-step explanation:

#include <stdio.h>

int main()

{

  int num1, num2, flag_var, i, j;

  /* Ask user to input the from/to range

   * like 1 to 100, 10 to 1000 etc.

   */

  printf("Enter two range(input integer numbers only):");

  //Store the range in variables using scanf

  scanf("%d %d", &num1, &num2);

  //Display prime numbers for input range

  printf("Prime numbers from %d and %d are:\n", num1, num2);

  for(i=num1+1; i<num2; ++i)

  {

     flag_var=0;

     for(j=2; j<=i/2; ++j)

     {

        if(i%j==0)

        {

           flag_var=1;

           break;

        }

     }

     if(flag_var==0)

        printf("%d\n",i);

 }

 return 0;

}

Answer:

Option E, 4, 4√3

Step-by-step explanation:

s = 4

q = 4√3