9.Water flows'along a horizontal pipe of cross sectional area 48cm2 which has a constriction of
cross sectional area 12cm2 at one place. If the speed of the water at the constriction is 36m/s,
calculate the speed in the wider section,
(3mk)

Answers

Answer 1

Answer:

v₁ = 9 m/s

Explanation:

Here, we can use the continuity equation, as follows:

[tex]A_1v_1 = A_2v_2[/tex]

where,

A₁ = Cross-sectional area of the wider section = 48 cm²

A₂ = Cross-sectional area of the constriction = 12 cm²

v₁ = speed of flow in wider section = ?

v₂ = speed flow in constriction = 36 m/s

Therefore,

[tex](48\ cm^2)v_1 = (12\ cm^2)(36\ m/s)\\\\v_1 = \frac{(12\ cm^2)(36\ m/s)}{(48\ cm^2)} \\\\[/tex]

v₁ = 9 m/s


Related Questions

Please help with all three questions

Answers

Answer:

The correct answer is D C A

Un corredor hace los 400 metros lisos en 50 seg. Calcula la velocidad en la carrera.

Answers

Answer:

8 meters/second

Explanation:

Rate x Time = Distance

R x T = D

R x 50sec = 400meters

R x 50sec/50sec = 400meters/50sec

R = 8meters/sec

A 1500 kg tractor pulls a 750 kg trailer north and applies a 2250 N force on it. What is the force on the tractor?

Answers

Answer:

law of Action and Reaction     F = 2250 N

Explanation:

The tractor and the trailer are two bodies that interact, therefore, by the law of Action and Reaction, the force that one applies on the other is equal to the force that the second body (trailer) applies on the first (tractor), but with opposite direction

          F = 2250 N

directed from trailer to tractor

A solid, uniform sphere of mass 2.0 kg and radius 1.8 m rolls from rest without slipping down an inclined plane of height 7.5 m. What is the angular velocity of the sphere at the bottom of the inclined plane

Answers

Answer:

[tex]w^2=5.5rads/s[/tex]

Explanation:

From the question we are told that:

Mass [tex]m=2.0kg[/tex]

Radius [tex]r=1.8m[/tex]

Height [tex]h=7.5m[/tex]

Generally the equation for Potential energy is mathematically given by

Potential energy=Kinetic energy+Rotational energy

 [tex]mgh=\frac{1}{2}mv^2+\frac{1}{2}Iw^2[/tex]

Since there is no slipping

 [tex]v=rw[/tex]

Therefore

 [tex]mgh=\frac{1}{2}mr^2w^2+\frac{1}{2}Iw^2[/tex]

Where

      [tex]I=\frac{1}{2}mr^2[/tex]

      [tex]l=3.24m[/tex]

 [tex]2*9.81*7.5=\frac{1}{2}(2)(1.8)^2w^2+\frac{1}{2}(3.24)w^2\\\\[/tex]

 [tex]147.15=3.24w^2+1.62w^2[/tex]

 [tex]w^2=\frac{147.15}{4.86}[/tex]

 [tex]w^2=\sqrt{\frac{147.15}{4.86}}[/tex]

 [tex]w^2=5.5rads/s[/tex]

Two people are carrying a uniform 704.0 N log through the forest. Bubba is 2.2 m from one end of the log (x), and his partner is 0.9 m from the other end (y). The log is 6.2 m long (z). What weight is Bubba supporting

Answers

Answer:

F₁ = 499.61 N , this is the force that Bubba support

Explanation:

The trunk is in equilibrium with the two forces applied by man, let's use the equilibrium relation

let's set a reference frame at the extreme left and assume that the counterclockwise rotations are positive

Let's write the expression for the translational equilibrium

subscript 1 is for Bubba's mass and subscript 2 for his partner

               F₁ + F₂ -W = 0

                F₁ + F₂ = W

the expression for rotational equilibrium

               ∑ τ = 0

               F₁  2.2 + F₂  (6.2-0.9) - W  6.2/2 = 0

               2.2 F1 + 5.3 F2 = 3.1 W

let's write our system of equations

             F₁ + F₂ = W

             2.2 F₁ + 5.3 F₂ = 3.1 W

we solve for F₁ in the first equation and substitute in the second

            F₁ = W-F₂

            2.2 (W- F₂) + 5.3 F₂ = 3.1 W

            F₂ ( -2.2 +5.3) = W (3.1 - 2.2)

            F₂ = 704  0.9 / 3.1            

            F₂ = 204.39 N

This is the force that the partner supports

we look for F1

            F₁ = W-F₂

            F₁ = 704 - 204.39

             F₁ = 499.61 N

This is the force that Bubba support

A uniform rod of length 80cm rotated in the xy plane about a frictionless pin passing through one end (as shown in figure). If the angular
velocity of the rod is 4rad/s, find the linear velocity (in m/s) of its mid-point C
Rod
Pin
С
Select one:
O a. 0.5
O b. 1.6
O c. 1.3
O d. 0.8​

Answers

Answer:

Linear velocity (in m/s) = 1.6 m/s

Explanation:

Given:

Length of rotational plane = 80 cm

Angular  velocity of the rod = 4rad/s

Find:

Linear velocity (in m/s)

Computation:

Radius from mid point C = Length of rotational plane / 2

Radius from mid point C = 80 / 2

Radius from mid point C = 40 cm

Radius from mid point C = 0.4 m

Linear velocity (in m/s) = Angular  velocity of the rod x Radius from mid point C

Linear velocity (in m/s) = 0.4 x 4

Linear velocity (in m/s) = 1.6 m/s

Water in an electric teakettle is boiling. The power absorbed by the water is 0.90 kW. Assuming that the pressure of vapor in the
kettle equals atmospheric pressure, determine the speed of effusion of vapor from the kettle's spout if the spout has a cross-
sectional area of 1.60 cm2. Model the steam as an ideal gas.​

Answers

Answer:

v = 4.233  m/s

Explanation:

By applying the rate of boiling from [tex]Q= mL_v[/tex];

the rate of the boiling can be described as:

[tex]\mathcal{P} = \dfrac{Q}{\Delta t} \\ \\ \mathcal{P} = \dfrac{mL_v}{\Delta t}[/tex]

The mode of the steam (water vapor) as an ideal gas can be illustrated by formula:

[tex]P_oV_o = nRT[/tex] --- (1)

where;

n = number of moles;

[tex]n = \dfrac{mass (m)}{Molar mass (M)}[/tex]

Then; equation (1) can be rewritten as:

[tex]P_oV_o = (\dfrac{m}{M}) RT \\ \\ \dfrac{P_oV}{\Delta T} = \dfrac{m}{\Delta t} ( \dfrac{RT}{M})[/tex]

[tex]\dfrac{m}{\Delta t} = \dfrac{\mathcal{P}}{L_v}[/tex]

Then:

[tex]P_o \times A \times v= \dfrac{\mathcal{P}}{L_v}\Big ( \dfrac{RT}{M }\Big)[/tex]

making (v) the subject of the formula:

[tex]v= \Big ( \dfrac{\mathcal{P} RT}{M\times L_v \times P_o \times A }\Big)[/tex]

Given that:

[tex]\mathcal{P}[/tex] = 0.90  kW = 900 W

R(rate constant) = 8.314 J/mol.K

Temperature at 100° C = 373K

For water vapor:

molar mass= 18.015 g/mol ≅ 0.0180 kg/mol

Latent heat of vaporisation [tex]L_v[/tex] = 2.26 × 10⁶ J/kg

Atmospheric pressure [tex]P_o = 1.013 \times 10^6 \ N/m^2[/tex]

Cross sectional area A =1.60 cm² = 1.60 × 10⁻⁴ m²

[tex]v= \Big ( \dfrac{900 W (8.314 \ J/mol.K)(373)}{0.0180 \ kg/mol) (2.26 \times 10^6 \ J/kg) (1.013 \times 10^5 \ N/m^2)(1.60 \times 10^{-4} \ m^2)}\Big)[/tex]

v = 4.233  m/s

A horizontal wire supports it weight in a 0.001T magnetic field, oriented orthogonally to the wire. This is due to current running from left to right in the wire. Calculate the current through this wire that will just support the weight of the wire (over the length of the wire). The length of the wire is 0.5 m, and the mass of the 0.5 m section is 50 g. [give your answer in units of Amps]

Answers

Answer:

Explanation:

Force on a current carrying wire in a magnetic field

= B i L where B is magnetic field , i is current and L is length of the wire .

Putting in the given values in the question

force on a current carrying wire in a magnetic field  = .001 T x i x .5 m

5 x 10⁻⁴ i  N .

weight of the wire = .050 kg x 9.8 m/s²

= .49 N .

For equilibrium

5 x 10⁻⁴ i  = .49

i = 980 A .

Future space stations could create an artificial gravity by rotating. Consider a cylindrical space station that rotates with a period of 28 seconds about its axis. Astronauts walk on the inside surface of the space station, and they experience an Earth-like gravitational acceleration of 9.8 m/s2. What is the diameter of the space station?
510m
145m
660m
390m​

Answers

Answer:

P = 2 pi R / v    period of space station

F / m = v^2 / R    centripetal force per unit of mass

So F / m = 4 pi^2 R^2 / (P^2 * R) = 4 pi^2 R / P^2

Also, F / m = 9.8 m/s^2   earth's gravitational attraction

So 9.8 = 4 pi^2 R / P^2    or    R = 9.8 P^2 / 4 * pi^2) = 195 m

Or D = 2 R = 390 m the diameter required

If a body of mass 2 kg is moving with a velocity of 30 m/s, then on doubling its velocity the momentum becomes______.
a-60kgm/s
b-120kgm/s
c-90kgm/s
D-30kgm/s​

Answers

I think it’s B. So 120kgm/s

what determines the strength of a base?

Answers

The higher the dissociation constant the stronger the acid or base. Since electrolytes are created as ions are freed into solution there is a relationship between the strength of an acid, a base, and the electrolyte it produces. Acids and bases are measured using the pH scale.

The higher the dissociation constant the stronger the acid or base. Since electrolytes are created as ions are freed into solution there is a relationship between the strength of an acid, a base, and the electrolyte it produces. Acids and bases are measured using the pH scale.

Explain the mode of operation of x-ray​

Answers

Answer:

If x-rays get in touch with our body tissues, they create a picture of a metal film. The high energizing rays are unable to penetrate soft tissue, such as skin and organs and travel through the laser. The places where the x-rays pass soft tissues are Black areas of an X-ray.

Answer:

Explanation:

Mode of Operation: In the X-ray tube a Low voltage high p.d is applied between the hot cathode and the anode. Electrons are emitted from the cathode and are accelerated to an extremely high speed. ... They are produced by increasing the p.d. between the cathode and anode.

if something is frictionless does it have thermal energy

Answers

Answer:

No

Explanation:

because there is no pressure

A 1800-kg Jeep travels along a straight 500-m portion of highway (from A to B) at a constant speed of 10 m/s. At B, the Jeep encounters an unbanked curve of radius 50 m. The Jeep follows the road from B to C traveling at a constant speed of 10 m/s while the direction of the Jeep changes from east to south. What is the magnitude of the acceleration of the Jeep as it travels from A to B

Answers

Answer:

a = 0 m/s²

Explanation:

From A to B the jeep travels in a straight line with a constant speed of 10 m/s. Acceleration is defined as the rate of change in velocity. In the current scenario, the velocity of the jeep remains constant. The direction of the jeep does not change as it travels in the straight path. Also, the magnitude of the velocity is constant at 10 m/s.

Therefore, there is no change in the velocity of the jeep from A to B. Hence, the will be no acceleration from A to B.

a = 0 m/s²

write the formula of mechanical advantage​

Answers

Answer:

the formula of mechanical advantage is

MA = load / effort

VR = effort distance / load distance

hope it is helpful to you

Select the correct answer from each drop-down menu.
After World War II, political leaders from various countries discussed ways to strengthen individual-as well as
economies. They began promoting
to boost production and exports,

Answers

Answer: I think it’s Global for the 1st one

And free trade for the 2nd one

Explanation:

The correct answer is: "After World War II, political leaders from various countries discussed ways to strengthen individual economies." They began promoting economic policies to boost production and exports.

What happened after World War II?

After World War II, many countries were left with weakened economies and infrastructure, and there was a need for economic recovery and growth. To achieve this, political leaders from different countries came together to discuss ways to strengthen their individual economies and also promote international economic cooperation. One of the ways they did this was by promoting economic policies that aimed to boost production and exports. This involved policies that encouraged businesses to increase their output and create more jobs, as well as policies that made it easier for countries to trade with each other.

Hence, after World War II, political leaders from various countries discussed ways to strengthen their individual economies. They began promoting economic policies to boost production and exports.

Learn more about World War II's aftermath here.

https://brainly.com/question/27327667

#SPJ5

Convert 0.00553s to cs

Answers

Answer: 0.553

Explanation:

0.553 hope it helps ur welcome

The instrument measuring the temperature change between inspired cool air and expired warm air is called?​

Answers

Answer:

It's called a Spirometer

You throw a ball straight up. Compare the sign of the work done by gravity while the ball goes up with the sign of the work done by gravity while it goes down.

a. Work is + on the way up and + on the way down
b. Work is + on the way up and - on the way down
c. Work is - on the way up and + on the way down
d. Work is - on the way up and - on the way down

Answers

Answer:

c. Work is - on the way up and + on the way down

Explanation:

Work done is given as the product of the applied force and the displacement of the object.

Work done = F x d

Work done = mg x d

where;

g is acceleration due to gravity = 9.8 m/s²

When the ball goes up, it moves against the force of gravity which tends to pull every object downwards. Since the ball moves against gravity, the work done is negative.

Also, when the ball goes down, it moves in the direction of gravity which acts downwards. Since the ball moves in the same direction as gravity, the work done is positive.

The correct option is "C. Work is negative (-) on the way up and positive (+) on the way down"

which of the following changes will increase the frequency of an oscillating pendulum?
a. an increase in the mass of the pendulum.
b. an increase in the initial height of release.
c. an increase in the length of the rope.
d. more than one of the above
e. none of the above
explain your answer in your own words.
NO LINKS.​

Answers

Answer:

b (i think)

Explanation:

Does the law of attraction actually have a basis in physics?

Answers

Answer:

Scientific theories are cited by proponents of the Law of Attraction as evidence in its favor. It, on the other hand, has no theoretical basis. A variety of scientists have questioned the promoters' abuse of scientific principles.

Any is 160 cm tall and stands 50 cm in front of a plane mirror. The image of Amy is ?

Answers

Answer:

Option A. 160 cm tall and 100 cm in front of Amy

Explanation:

To know the the correct answer to the question, we must recognise that the image formed by plane mirror is:

I. Same size as the object.

II. Same distance as the object from the mirror.

III. Laterally inverted.

IV. Virtual

With the above information, we obtained the answer to the question as follow:

Object height = 160 m

Thus,

Image height = 160 m

Distance of object from mirror = 50 cm

Therefore,

Distance of image from the mirror = 50 cm

Distance between the object and image = 50 + 50 = 100 cm

Thus, option A gives the correct answer to the question because the image of Amy is 160 cm tall and 100 cm in front of her.

You drop a 10 kg bowling ball off a 2 story building, what is the force generated by
the bowling ball when it hits the ground

Answers

Answer:i

Explanation:

PLS HELPP MEEE
Fiber-optic cables rely on total internal reflection.


Please select the best answer from the choices provided

T
F

Answers

the answer would be true

What is the frequency of microwaves of wavelength 3 cm?
Give your answer to the
nearest GHz and without units.

Answers

Answer:

10 GHz

Explanation:

Applying,

v = λf.................... Equation 1

Where v = speed of microwave, λ = wavelength, f = frequency.

make f the subject of the equation

f = v/λ................ Equation 2

Note: Microwave is an electromagnetic wave, and all electromagnetic wave have the same speed, which is 3×10⁸ m/s

From the question,

Given: λ = 3 cm = 0.03 m

Constant; v = 3×10⁸ m/s

Substitute these values into equation 2

f = 3×10⁸/(0.03)

f = 10¹⁰ Hz

f = (10¹⁰/10⁹) GHz

f = 10 GHz

In the diagram shown below, the distance from the dotted line to Point A, or the distance from the dotted line to Point D is known as the

Answers

Answer:

The dotted line connecting two points is known as the distance traveled.

Explanation:

The distance traveled is a physical quantity that refers to the total displacement of a body. This distance is usually shown as a dotted line that connects two points in an image. In general, we can say that the distance traveled is calculated by adding all the distances that an element makes when leaving one point and reaching another point, which is its final position.

An example of this can be seen in the image shown below, where the red line represents the displacement of a body that left point A and arrived at point B. The blue dotted line represents the distance traveled and refers to the total displacement of that body, showing all the distances it covered while walking from point A to point B.

a particle covers 10m distance in 2sec. if final velocity is 8m/s, find initial velocity​

Answers

Answer:

vi =2

Explanation:

Δx = 1/2 (vi + vf) t

10 = 1/2 ( vi + 8 ) 2

10 = vi + 8

10-8 = vi

vi = 2 m/s

vi= initial velocity

vf= final velocity

Δx= distance

t= time

An ant is crawling along a straight wire, which we shall call the x axis, from A to B to C to D (which overlaps A), as shown in the figure below. O is the origin. Suppose you take measurements and find that AB is 31 cm , BC is 12 cm , and AO is 7 cm .(Figure 1)


A. What is the ant’s position at point A?


B. What is the ant’s position at point B?


C. What is the ant’s position at point C?


D. What is the ant’s position at point D?

Answers

Answer:

Ants position at point A = -7 cm

Ants position at point B = 38 cm

Ants position at point C = 26 cm

Ants position at point D = -7 cm

Explanation:

In this question, we are dealing with displacement which is the change in position of an object.

Now, we are told the journey began from A to B and then from C to D.

Now, AB = 31 cm and AO = 7cm

But along AB, we have the origin O.

Since A is on the left hand side of the origin, it means it is negative. Thus, position A = -7cm

Then position B = 31 - (-7) = 31 + 7 = 38 cm

Since BC = 12cm, then position C = 38 - 12 = 26 cm

Position D is same as position A = -7cm

URGENT!!!!!!!!!: If an electromagnetic wave has a frequency of 6 x 10^5 Hz, what is its
wavelength? Use v/f. The speed of light is 3 x 10^8 m/s.

Answers

Answer:

A

Explanation:

because the speed divide by the frequency is equal to the wavelength(in meters)

5×10² m

Typical novae occur when (a) a red-giant star ejects a planetary nebula; (b) two neutron stars merge, forming a more massive neutron star; (c) an extremely massive star collapses, and also ejects its outer atmosphere; (d) matter accreted from a companion star unstably ignites on the surface of a white dwarf; or (e) a neutron star’s magnetic field becomes strong enough to produce two oppositely directed jets of rapidly moving particles.

Answers

Answer:

I think its d matter accreted from a companion star unstable ignites on the surface of a white dwarf.

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