2. Which of the following is a shortcut key to Exit from any operation?
a) Ctrl+R
b) Ctrl+Q
c) Ciri-Y
​

Answer:

Print 4 + 4

Explanation:

If you're writing this in the programming language called BASIC, this is how you would add any two numbers.

Answer:

The answer is below

Explanation:

The correct process for setting up a recurring project for the same client in Quickbooks Online Accountant is as follows:

1. Go to Work, then select create a project

2. Select the Repeat button, then set the frequency and duration

3. Formulate the project and save it.

4. Reopen the project

5. And select the Duplicate button for the proportion of times you want it to recur. This includes assigning the interval, day of the recurrence, and end time.

6. Then select Save.

Firstly, invent a separate project, then pick the repeat button on the right of the screen, specify the frequency and duration. Its frequency can indeed be weekly, biweekly, monthly, and so on.

Therefore, the answer is "first choice".

Learn more:

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Answer:

yes and

Explanation:

why do you need to know about a buildings security are you going to rob it ???

Answer:

mysql

Explanation:

try building mysql database

Answer:

In C++:

#include <iostream>

using namespace std;

int main(){

   double quiz1, quiz2, quiz3, exam1, exam2, finalexam,quiz;

   cout<<"Quiz 1: "; cin>>quiz1;

   cout<<"Quiz 2: "; cin>>quiz2;

   cout<<"Quiz 3: "; cin>>quiz3;

   cout<<"Exam 1: "; cin>>exam1;

   cout<<"Exam 2: "; cin>>exam2;

   cout<<"Final Exam: "; cin>>finalexam;

   if(quiz1<=quiz2 && quiz1 <= quiz3){        quiz=(quiz2+quiz3)/2;    }

   else if(quiz2<=quiz1 && quiz2 <= quiz3){        quiz=(quiz1+quiz3)/2;    }

   else{         quiz=(quiz1+quiz2)/2;     }

   int weight = 0.20 * quiz + 0.30 * ((exam1 + exam2)/2) + 0.50 * finalexam;

   cout<<"Average Weight: "<<weight<<endl;

   if(weight>=91 && weight<=100){        cout<<"Letter Grade: A";    }

   else if(weight>=81 && weight<=90){        cout<<"Letter Grade: B";    }

   else if(weight>=70 && weight<=80){        cout<<"Letter Grade: C";    }

   else{        cout<<"Letter Grade: F";    }

   return 0;

}

Explanation:

See attachment for complete program where comments were used to explain difficult lines

1 see what you can do and go from their

Answer:

In Python:

def main():

   n = int(input("List items: "))

   mylist = []

   for i in range(n):

       listitem = input(", ")

       if listitem.isdecimal() == True:

           mylist.append(int(listitem))

       else:

           mylist.append(listitem)

   print(game_of_eights(mylist))

def game_of_eights(mylist):

   retVal = "False"

   intOnly = True

   for i in range(len(mylist)):

       if isinstance(mylist[i],int) == False:

           intOnly=False

           retVal = "Please, enter only integers"

       if(intOnly == True):

           for i in range(len(mylist)-1):

               if mylist[i] == 8 and mylist[i+1]==8:

                   retVal = "True"

                   break

   return retVal

if __name__ == "__main__":

   main()

Explanation:

The main begins here

def main():

This gets the number of list items from the user

   n = int(input("List items: "))

This declares an empty list

   mylist = []

This iterates through the number of list items

   for i in range(n):

This gets input for each list item, separated by comma

       listitem = input(", ")

Checks for string and integer input before inserting item into the list

       if listitem.isdecimal() == True:

           mylist.append(int(listitem))

       else:

           mylist.append(listitem)

This calls the game_of_eights function

   print(game_of_eights(mylist))

The game_of_eights function begins here

def game_of_eights(mylist):

This initializes the return value to false

   retVal = "False"

This initializes a boolean variable to true

   intOnly = True

This following iteration checks if the list contains integers only

   for i in range(len(mylist)):

If no, the boolean variable is set to false and the return value is set to "integer only"

       if isinstance(mylist[i],int) == False:

           intOnly=False

           retVal = "Please, enter only integers"

This is executed if the integer contains only integers

       if(intOnly == True):

Iterate through the list

           for i in range(len(mylist)-1):

If consecutive 8's is found, update the return variable to True

               if mylist[i] == 8 and mylist[i+1]==8:

                   retVal = "True"

                   break

This returns either True, False or Integer only

   return retVal

This calls the main method

if __name__ == "__main__":

   main()

Answer:

In absolute cell reference, the reference of a cell does not change. 

Answer:

In Python

print("Instruction: 1. Rock, 2. Paper or 3. Scissors: ")

p1 = int(input("Player 1: "))

p2 = int(input("Player 2: "))

if p1 == p2:

   print("Tie")

else:

   if p1 == 1: # Rock

       if p2 == 2: #Paper

           print("P2 wins! Paper covers Rock")

       else: #Scissors

           print("P1 wins! Rock smashes Scissors")

   elif p1 == 2: #Paper

       if p2 == 1: #Rock

           print("P1 wins! Paper covers Rock")

       else: #Scissors

           print("P2 wins! Scissors cuts Paper")

   elif p1 == 3: #Scissors

       if p2 == 1: #Rock

           print("P2 wins! Rock smashes Scissors")

       else: #Paper

           print("P1 wins! Scissors cuts Paper")

Explanation:

This prints the game instruction

print("Instruction: 1. Rock, 2. Paper or 3. Scissors: ")

The next two lines get input from the user

p1 = int(input("Player 1: "))

p2 = int(input("Player 2: "))

If both input are the same, then there is a tie

if p1 == p2:

   print("Tie")

If otherwise

else:

The following is executed if P1 selects rock

   if p1 == 1: # Rock

If P2 selects paper, then P2 wins

       if p2 == 2: #Paper

           print("P2 wins! Paper covers Rock")

If P2 selects scissors, then P1 wins

       else: #Scissors

           print("P1 wins! Rock smashes Scissors")

The following is executed if P1 selects paper

   elif p1 == 2: #Paper

If P2 selects rock, then P1 wins

       if p2 == 1: #Rock

           print("P1 wins! Paper covers Rock")

If P2 selects scissors, then P2 wins

       else: #Scissors

           print("P2 wins! Scissors cuts Paper")

The following is executed if P1 selects scissors

   elif p1 == 3: #Scissors

If P2 selects rock, then P2 wins

       if p2 == 1: #Rock

           print("P2 wins! Rock smashes Scissors")

If P2 selects paper, then P1 wins

       else: #Paper

           print("P1 wins! Scissors cuts Paper")

Answer:

7

Explanation:

#include <stdio.h>

int max2(int x, int y) {

   int result = y;

   if (x > y) {

       result = x;

   }

   return result;

}

int max3(int x, int y, int z) {

   return max2(max2(x,y),z);

}

int main() {

   int a = 5, b = 7, c = 3;

   printf("%d",max3(a, b, c));

   printf("");

   return 0;

}

Hi, first of all, next time you post the question, it would be nice to copy and paste like above. This will help us to read the code easily. Thanks for your cooperation.

We start from the main function:

The variables are initialized → a = 5, b = 7, c = 3

max3 function is called with previous variables and the result is printed → printf("%d",max3(a, b, c));

We go to the max3 function:

It takes 3 integers as parameters and returns the result of → max2(max2(x,y),z)

Note that max2 function is called two times here (One call is in another call actually. That is why we need to first evaluate the inner one and use the result of that as first parameter for the outer call)

We go to the max2 function:

It takes 2 integers as parameters. If the first one is greater than the second one, it returns first one. Otherwise, it returns the second one.

First we deal with the inner call. max2(x,y) is max2(5,7) and the it returns 7.

Now, we need to take care the outer call max2(7, z) is max2(7, 3) and it returns 7 again.

Thus, the program prints 7.

Answer:Both A and B

Explanation:

Answer:

D. Plot

Explanation:

The plot is how the story develops, unfolds and move through time.

Answer:

supercomputer, mainframe, personal computer, minicomputer

Explanation:

Answer:

In computer programming, a return statement causes execution to leave the current subroutine and resume at the point in the code immediately after the instruction which called the subroutine, known as its return address. The return address is saved by the calling routine, today usually on the process's call stack or in a register. Return statements in many languages allow a function to specify a return value to be passed back to the code that called the function.

An expression that returns a value is known as a​ function. Check more about function  below.

A function is often seen as a kind of expression or rule, or law that often tells more about a relationship.

Conclusively, a function is known to often returns a value back to the instruction that is known also to be the function. This is regarded as the differences that exist between a method and a function.

Learn more about function  from

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Answer:

c. 172.16.0.0 / 255.255.248.0

Explanation:

The address will be 172.16.0.0 while the netmask will be 255.255.248.0.

Thus, option C is correct.

Answer:

See Explanation

Explanation:

The question is incomplete as the cells that contains donation and streaming revenues are not given

So, I will make the following assumption:

H4 = Donations

G4 =  Streaming Revenues

So, the profit will be:

Enter the following formula in cell I4

=(G4 - H4)

To get the actual solution in your case, replace G4 and H4 with the proper cell names

Answer:

Explanation:

The following code is written in Java it goes through the queue that was passed as an argument, loops through it and removes all the odd numbers, leaving only the even numbers in the queue. It does not add any more data structures and finally returns the modified queue when its done.

  public static Queue<Integer> evens(Queue<Integer> queue) {

       int size = queue.size();

       for(int x = 1; x < size+1; x++) {

           if ((queue.peek() % 2) == 0) {

               queue.add(queue.peek());

               queue.remove();

           } else queue.remove();

       }

       return queue;

   }

Answer: Resolution or DPI, deliverables, and file types are important technical and visual demands to consider when planning a project.

Explanation: Keep in mind whether or not the project will be published in print or on the Web.

Answer in python:

import random

money = 10

winnings = 0

def main():

global winnings

global money

dice_num = random.randrange(1,6)

input_str = "Guess the dice number. You have $"+str(money)+" > "

input_num = input(input_str)

if int(input_num) == dice_num:

 money = money + 10

 winnings = winnings + 10

else:

 money = money - 1

if money < 0:

 print("You lose. You won "+str(winnings)+" times. Press enter to try again")

 useless_variable = input()

 main()

else:

 main()  

main()

Explanation:

Answer:

In Python:

import random

p1name = input("Player 1: "); p2name = input("Player 2: ")

p1score = 0; p2score = 0

playerTurn = 1

print(p1name+" starts the game")

roll = True

while(roll):

   if playerTurn == 1:

       p1 = random.randint(1,6)

       print(p1name+"'s roll: "+str(p1))

       if p1 == 1:

           playerTurn = 2

           roll = True

       else:

           p1score+=p1

           another = input("Another Roll (y/n): ")

           if another == "y" or another == "Y":

               roll = True

           else:

               playerTurn = 2

               roll = True

   else:

       p2 = random.randint(1,6)

       print(p2name+"'s roll: "+str(p2))

       if p2 == 1:

           playerTurn = 1

           roll = True

       else:

           p2score+=p2

           another = input("Another Roll (y/n): ")

           if another == "y" or another == "Y":

               roll = True

           else:

               playerTurn = 1

               roll = True

   if p1score >= 50 or p2score >= 50:

       roll = False

print(p1name+":\t"+str(p1score)+"\t"+p2name+":\t"+str(p2score))

Explanation:

Note that the dice rolling is simulated using random number whose interval is between 1 and 6

This imports the random module

import random

This line gets the name of both players

p1name = input("Player 1: "); p2name = input("Player 2: ")

This line initializes the scores of both players to 0

p1score = 0; p2score = 0

This sets the first play to player 1

playerTurn = 1

This prints the name of player 1 to begin the game

print(p1name+" starts the game")

This boolean variable roll is set to True.

roll = True

Until roll is updated to False, the following while loop will be repeated

while(roll):

If player turn is 1

   if playerTurn == 1:

This rolls the dice

       p1 = random.randint(1,6)

This prints the outcome of the roll

       print(p1name+"'s roll: "+str(p1))

If the outcome is 1, the turn is passed to player 2

       if p1 == 1:

           playerTurn = 2

           roll = True

If otherwise

       else:

Player 1 score is updated

           p1score+=p1

This asks if player 1 will take another turn

           another = input("Another Roll (y/n): ")

If yes, the player takes a turn. The turn is passed to player 2, if otherwise

           if another == "y" or another == "Y":

               roll = True

           else:

               playerTurn = 2

               roll = True

If player turn is 2

   else:

This rolls the dice

       p2 = random.randint(1,6)

This prints the outcome of the roll

       print(p2name+"'s roll: "+str(p2))

If the outcome is 1, the turn is passed to player 1

       if p2 == 1:

           playerTurn = 1

           roll = True

If otherwise

       else:

Player 2 score is updated

           p2score+=p2

This asks if player 2 will take another turn

           another = input("Another Roll (y/n): ")

If yes, the player takes a turn. The turn is passed to player 1, if otherwise

           if another == "y" or another == "Y":

               roll = True

           else:

               playerTurn = 1

               roll = True

If either of both players has scored 50 or above

   if p1score >= 50 or p2score >= 50:

roll is updated to False i.e. the loop ends

       roll = False

This prints the name and scores of each player

print(p1name+":\t"+str(p1score)+"\t"+p2name+":\t"+str(p2score))

Answer:

What Language? Once you respond with a comment, I will be happy to write the code for you. I write code 24/7 (Because I have nothing better to do), so I will wait for you to comment. Also is there any pre-existing code?

Explanation:

Answer:

1+ 2^31= 2,146,483,649 pennies.

in Dollars- $21,464,836.49

edit for total=

42, 929,672. 97

Explanation:

,

Answer: number 2 is the correct way to do it

Explanation:

Answer:

2 newWord = word1 + word2

Explanation:

Answer:

Explanation:

[tex]\text{This is a math function that is integrated using a trapezoidal rule } \\ \\[/tex]

[tex]\text{import math}[/tex]

def [tex]\text{trapezint2(f,a,b):}[/tex]

      [tex]\text{midPoint=(a+b)/2}[/tex]

       [tex]\text{return .5*((midPoint-a)*(f(a)+f(midPoint))+(b-midPoint)*(f(b)+f(midPoint)))}[/tex]

[tex]\text{trapezint2(math.sin,0,.5*math.pi)}[/tex]

[tex]0.9480594489685199[/tex]

[tex]trapezint2(abs,-1,1)[/tex]

[tex]1.0[/tex]

In this exercise we have to use the knowledge of computational language in python to write the code.

the code can be found in the attachment.

In this way we have that the code in python can be written as:

   h = (b-a)/float(n)

   s = 0.5*(f(a) + f(b))

   for i in range(1,n,1):

       s = s + f(a + i*h)

   return h*s

from math import exp  # or from math import *

def g(t):

   return exp(-t**4)

a = -2;  b = 2

n = 1000

result = Trapezoidal(g, a, b, n)

print result

See more about python at brainly.com/question/26104476

Answer:

The reason that a satellite must have a distinct uplink and downlink set of frequencies is because they help avoid any type of interference that may occur. The uplink receives the signal and amplifies it so that it can be transmitted to another frequency (downlink).

Answer:

Throughout the clarification below, the description of the query is mentioned.

Explanation:

Answer: drafting

Explanation:

Answer:

In Python

def getpointValue(subject):

   if subject >= 75:        point = 4; grade = 'A'

   elif subject >= 60:        point = 3; grade ='B'

   elif point >= 50:        point = 2; grade = 'C'

   elif point >= 40:        point = 1; grade = 'D'

   else:        point = 0; grade = 'F'

   return point,grade

subjects= ["Accounting","Marketing","Economics","MIS"]

acct = int(input(subjects[0]+": "))

mkt = int(input(subjects[1]+": "))

eco = int(input(subjects[2]+": "))

mis = int(input(subjects[3]+": "))

acctgrade = getpointValue(acct)

print(subjects[0]+" Grade: "+str(acctgrade[1]))

mktgrade = getpointValue(mkt)

print(subjects[1]+" Grade: "+str(mktgrade[1]))

ecograde = getpointValue(eco)

print(subjects[2]+" Grade: "+str(ecograde[1]))

misgrade = getpointValue(mis)

print(subjects[3]+" Grade: "+str(misgrade[1]))

totalpoint = (acctgrade[0] + mktgrade[0] + ecograde[0] + misgrade[0]) * 3

gpa = totalpoint/12

print("GPA: "+str(gpa))

Explanation:

The solution I provided uses a function to return the letter grade and the point of each subject

I've added the explanation as an attachment where I used comment to explain difficult lines