Answer:
3x+3
Step-by-step explanation:
The given expression is "The first integer plus the next consecutive integer plus the next consecutive integer."
Let the first integer is x.
Next consecutive integer of x = x+1
Other next consecutive integer of x+1 = x+1+1=x+2
ATQ,
The expression is :
=x+x+1+x+1+1
=3x+3
A company sells widgets. The amount of profit, y, made by the company, is related to the selling price of each widget, x, by the given equation. Using this equation, find out what price the widgets should be sold for, to the nearest cent, for the company to make the maximum profit.
y=-10x^2+600x-3588
y=−10x
2
+600x−3588
Answer:
Step-by-step explanation:
The maximum profit will be found in the vertex of the parabola, which is what your equation is. You could do this by completing the square, but it is way easier to just solve for h and k using the following formulas:
[tex]h=\frac{-b}{2a}[/tex] for the x coordinate of the vertex, and
[tex]k=c-\frac{b^2}{4a}[/tex] for the y coordinate of the vertex.
x will be the selling price of each widget and y will be the profit. Usually, x is the number of the items sold, but I'm going off your info here for what the vertex means in the context of this problem.
Our variables for the quadratic are as follows:
a = -10
b = 600
c = -3588. Therefore,
[tex]h=\frac{-600}{2(-10)}=30[/tex] so the cost of each widget is $30. Now for the profit:
[tex]k=-3588-(\frac{(600)^2}{4(-10)})[/tex] This one is worth the simplification step by step:
[tex]k=-3588-(\frac{360000}{-40})[/tex] and
k = -3588 - (-9000) and
k = -3588 + 9000 so
k = 5412
That means that the profit made by selling the widgets at $30 apiece is $5412.
Hence,the profit made by selling the widgets at $[tex]30[/tex] apiece is $[tex]5412[/tex].
What is the maximum profit?
Maximum profit, or profit maximisation, is the process of finding the right price for your products or services to produce the best profit.
Here given that,
A company sells widgets. The amount of profit, [tex]y[/tex], made by the company, is related to the selling price of each widget, [tex]x[/tex], by the given equation.
As the maximum profit found in the vertex of the parabola,
Here, [tex]x[/tex] will be the selling price of each widget and [tex]y[/tex] will be the profit.
The number of items sold is [tex]x[/tex].
So, the quadratic equation is:-
[tex]a = -10b = 600c = -3588.[/tex]
Therefore, so the cost of each widget is $[tex]30[/tex].
For the profit:-
[tex]k = -3588 - (-9000) andk = -3588 + 9000 sok = 5412[/tex]
Hence,the profit made by selling the widgets at $[tex]30[/tex] apiece is $[tex]5412[/tex].
To know more about the maximum profit
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To make a shade of paint called jasper green, mix 4 quarts of green paint with cups of black paint. How much green paint should be mixed with 4 cups of black paint to make jasper green?
Answer:
8 quarts
Step-by-step explanation:
no explanation needed this should be correct.
At Henry's yearly physical, he measured 5 feet 8 inches tall. If there are 2.54 centimeters in 1 inch, what is Henry's height in centimeters?
Answer:
172.72 centimeters
Step-by-step explanation:
1. 5 ft. = 60 in.
2. 60 in. + 8 in. = 68 in.
3. 68 x 2.54 = 172.72
4. add unit of measurement to your answer
Henry's height in centimeters is 172.72 cm
What is unitary method ?"A process of finding the value of a single unit, and based on this value we can find the required value. "
For given question,
Henry measured 5 feet 8 inches tall.
There are 2.54 centimeters in 1 inch.
that is, 1 inch = 2.54 cm
First we convert Henry's height in inches.
We know that 1 feet = 12 inches
⇒ 5 feet = 60 inches
so, Henry's height in inches would be,
5 feet 8 inches
= (60 + 8) inches
= 68 inches
From given, 1 inch = 2.54 cm
⇒ 68 inches = 172.72 cm
Therefore, Henry's height in centimeters is 172.72 cm
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The body temperatures of a group of healthy adults have a bell-shaped distribution with a mean of 98.18 F and a standard deviation of 0.65 F. Using the empirical rule, find each approximate percentage below.
a.
What is the approximate percentage of healthy adults with body temperatures within 3 standard deviation of the mean, or between 96.23 F and100.3 F?
Answer:
99.7%
Step-by-step explanation:
Empirical rule formula states that:
• 68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ.
• 95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ.
• 99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ.
From the question, we have mean of 98.18 F and a standard deviation of 0.65 F
The approximate percentage of healthy adults with body temperatures between 96.23 F and100.13 F is
μ - 3σ
= 98.18 - 3(0.65)
= 98.18 - 1.95
= 96.23 F
μ + 3σ.
98.18 + 3(0.65)
= 98.18 + 1.95
= 100.13 F
Therefore, the approximate percentage of healthy adults with body temperatures between 96.23 F and 100.13 F which is within 3 standard deviations of the mean is 99.7%
Help!Asap!
The Surface areas of the two solids shown above are equal
A.true
B.false
Answer:
False
Step-by-step explanation:
For the one on the left I got 234 and the one on the right I got 248
Tickets for a drumline competition cost $5 at the gate and $3 in advance. One hundred more tickets were sold in advance than at the gate. The total revenue from ticket sales was $1990. How many tickets were sold in advance?
Answer:
The number of tickets sold at the gate is [tex] G = 211.25[/tex]
The number of tickets sold in advance is [tex] A = 311.25 [/tex]
Step-by-step explanation:
From the question we are told that
The cost of a tickets at the gate is [tex]a = \$ 5[/tex]
The cost of a ticket in advance is [tex]b = \$ 3[/tex]
Let the number of ticket sold in the gate be G
Let the number of ticket sold in advance be A
From the question we are told that
One hundred more tickets were sold in advance than at the gate and this can be mathematically represented as
[tex]G + 100 = A[/tex]
From the question we are told that
The total revenue from ticket sales was $1990 and this can be mathematically represented as
[tex]5 G + 3A = 1990[/tex]
substituting for A in the equation above
[tex]5 G + 3[G + 100]= 1990[/tex]
[tex]5 G + 3G + 300= 1990[/tex]
[tex] 8G + 300= 1990[/tex]
[tex] 8G = 1690[/tex]
=> [tex] G = 211.25[/tex]
Substituting this for G in the above equation
[tex]5 [211.25] + 3A = 1990[/tex]
=> [tex] 3A = 1990 - 1056.25[/tex]
=> [tex] A = 311.25 [/tex]
Select the correct answer from the drop-down menu.
A company sells its products to distributors and boxes of 10 units each. it's profits can be modeled by this equation, where p is the profit after selling n boxes.
p = -n² + 300n + 100,000
Use this equation to complete the statement.
The company breaks even, meaning the profits are only $0, when it sells _____ boxes.
Options for Blank:
A: 200 or 500
B: 500
C: 150
D: 200
Answer:
B. 500Step-by-step explanation:
Given the profit made by a company modeled by the function
p = -n² + 300n + 100,000
The company breaks even when p = 0
To get the number of boxes sold when the company breaks even, we will substitute p = 0 into the equation.
0 = -n² + 300n + 100,000
multiply through by -1
0 = n² - 300n - 100,000
n² - 300n - 100,000 = 0
(n² - 500n) + (200n - 100,000) = 0
n(n-500)+200(n-500) = 0
(n+200)(n-500) = 0
n+200 = 0 and n-500 = 0
n = -200 and n = 500
Since n cannot be negative
Hence n = 500
This means that the company breaks even when it sells 500 boxes
The product of which expression contains four decimal places?
Answer:
D.) 14.2*0.784
Step-by-step explanation:when you calculate it, there is 4 numbers behind the decimal point.
11. Mary just received her paycheck and would like to cash it. She does not have a checking account, where should she go to cash it? *
Answer:
Cash it at the issuing bank (this is the bank name that is pre-printed on the check)
Cash a check at a retailer that cashes checks (discount department store, grocery stores, etc.)
Cash the check at a check-cashing store.
Deposit at an ATM onto a pre-paid card account or checkless debit card account.
Step-by-step explanation:
Answer:
Amscot?
Step-by-step explanation:
The distribution of bladder volume in men is approximately Normal with mean 550 ml and standard deviation 100 ml.
Required:
a. What percent of men have a bladder volume smaller than 450 ml?
b. Between what volumes do the middle 95% of men’s bladders fall?
c. What proportion of male bladders are between 500 and 600 ml?
d. What volumes do the middle 90% of men’s bladder fall?
Answer:
a) 15.866%
b) Middle 95% = 350 ml to 750 ml
c) 0.3829
d) Middle 90% of men’s bladder fall = 385.5ml to 714.5 ml
Step-by-step explanation:
We solve using z score formula
z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.
The distribution of bladder volume in men is approximately Normal with mean 550 ml and standard deviation 100 ml.
Required:
a. What percent of men have a bladder volume smaller than 450 ml?
z = 450 - 550/100
= -1
P-value from Z-Table:
P(x<450) = 0.15866
Convert to percentage
0.15866 × 100
= 15.866%
b. Between what volumes do the middle 95% of men’s bladders fall?
Middle 95% falls between 2 standard deviation of the mean
μ ± 2σ
μ - 2σ
550 - 2(100)
= 550 - 200
= 350 ml
μ + 2σ
= 550 + 2(100)
= 550 + 200
= 750 ml
Middle 95% = 350 ml to 750 ml
c. What proportion of male bladders are between 500 and 600 ml?
For 500ml
z = 500 - 550/100
= -0.5
Probability value from Z-Table:
P(x = 500) = 0.30854
For 600ml
z = 600 - 550/100
= 0.5
Probabilty value from Z-Table:
P(x = 600) = 0.69146
Proportion of male bladders are between 500 and 600 ml
P(x = 600) - P(x = 500)
0.69146 - 0.30854
= 0.38292
≈ 0.3829
d. What volumes do the middle 90% of men’s bladder fall?
The z score for middle 90% + / – 1.645
Hence,
1.645 = x - 550/100
1.645 × 100 = x - 550
164.5 + 550 = x
x = 714.5 ml
-1.645 = x - 550/100
-1.645 × 100 = x - 550
- 164.5 + 550 = x
x = 385.5ml
Middle 90% of men’s bladder fall = 385.5ml to 714.5 ml
Josh’s walking stick is 4.875 feet long what is the same length written as a mixed number
Polynomial A: 4z + 724 - 7y+7
Polynomial B: 2.c + 12y - 12z - 7
What will be the coefficients for x, y, and z in the resulting sum?
Select all that apply.
-8
-5
-5
2
5
9
Asse
16
Sect
GO BACK
SUBMIT AND CONTINUE
284691-1307
Answer:
-8z +724 + 5y +2c
Step-by-step explanation:
Combine like terms
What formula is used to
determine the expected value for a variable?
What is the value of x?
20
35
60
70
Answer:
20°
Step-by-step explanation:
Step 1:
x + 40° = 3x Vertical ∠'s
Step 2:
40° = 2x Subtract x on both sides
Step 3:
x = 40° ÷ 2 Divide
Answer:
x = 20°
Hope This Helps :)
function rule y=3x-3
Answer:
-15, -9, -3, 3
Step-by-step explanation:
First One:
y =3(-4)-3 is -15
Second:
y= 3(-2)-3 is -9
Third:
y= 3(0)-3 is -3
Last One:
y= 3(2)-3 is 3
solve for z 3=(z+1) write your answers as integers or as proper or improper fractions
Answer:
z=2
Step-by-step explanation:
Just solve
1 + z = 3 (minus 1 on both sides)
z = 2
Plug in
3=(2+1)
3 = 3
Graph the line y-3=-1/3(x+2)
Slope: 1/2
y-intercept(s): (0, 7/3)
x: 0, 7
y: 7/3, 0
Step-by-step explanation:
y=-3 -1/3(1+2)=2/3.3=1.3=3
y=3
A basketball player made 55 baskets in a season. Of these, 20% were three-point shots. How many three-point shots did the player make?
Given:
A basketball player made 55 baskets in a season.
20% of these baskets were three-point shots.
To find:
The number of three-point shots.
Solution:
We have,
Total number of baskets = 55
Number of three-point shots = 20% of total baskets
Now,
[tex]\text{Number of three-point shots}=\dfrac{20}{100}\times 55[/tex]
[tex]\text{Number of three-point shots}=\dfrac{1}{5}\times 55[/tex]
[tex]\text{Number of three-point shots}=11[/tex]
Therefore, the number of three-point shots did made by the player is 11.
What is the greatest whole number that rounds to 2, 100when rounded to the nearest hundred? The least whole number?
Answer:
i am pretty sure it would be 8
Step-by-step explanation:
when it rounds to 2 but also rounds to 100, 8 would be the best bet.
A lumber supplier sells 96-inch pieces of oak. Each piece must be within ¼ of an inch of 96 inches. Write and solve an inequality to show acceptable lengths.
Answer:
[tex]95 \frac{3}{4} \: inch \leqslant x \leqslant 96 \frac{1}{4} \: inch[/tex]
Step-by-step explanation:
Given that a lumber supplier sells 96 inch Pieces of oak which must be within 1/4 of an inch.
This situation can be represented by the following absolute value inequality:
[tex]|x \: - 96| \: \leqslant \: \frac{1}{4} [/tex].
The absolute value can be thought of as the size of something because length cannot be negative. The length must be no more than 1/4 away from 96.
To simplify this, pretend this is a standard equality, |x-96| = 1/4. 1/4 is the range of acceptable length, 96 is the median of the range, and x is the size of the wood.
First apply the rule |x| = y → x = [tex]\pm[/tex]y
|x-96| = 1/4
x - 96 = [tex]\pm[/tex]1/4
x = [tex]96 \pm 1/4[/tex]
(These are just the minimum, and maximum sizes)
Now with a less than or equal to, the solutions are now everything included between these two values.
Therefore:
[tex]96 - 1/4 \: \leqslant x [/tex] [tex]\leqslant \: 96 + 1/4 [/tex]
With less than inequalities, you must have the lower value on the left, and the higher value on the right.
If x represents the size of the pieces, then the acceptable lengths are represented by this following inequality:
[tex]95 \frac{3}{4} \: inch \leqslant x \leqslant 96 \frac{1}{4} \: inch[/tex]
This is interpreted as x (being the size of the oak) is greater than or equal to 95 3/4, and less than or equal to 96 1/4 in inches.
Rectangle A’B’C’D’ is the image of rectangle ABCD after which of the following rotations?
Answer:
You're right!
Step-by-step explanation:
Answer:
Were you right?
Step-by-step explanation:
suppose that the life distribution of an item has the hazard rate function of what is the probability that
Answer:
that what
Step-by-step explanation:
From a circular sheet of paper with a radius 20 cm, four circles
of radius 5 cm each are cut out. What is the ratio of the uncut to
the cut portion?
Answer:
3 : 1
Step-by-step explanation:
The biggest circle has a radius of 20 cm
So that means, its area will be,
Area = [tex]\pi r^{2}[/tex]
Area = [tex]\pi * 20^{2}[/tex]
A = [tex]\pi * 400[/tex]
=> A = 400[tex]\pi[/tex]
We do not need to solve this because it is nit required
Then, one small circle has an area of,
Area = [tex]\pi r^{2}[/tex]
Area = [tex]\pi *5^{2}[/tex]
Area = [tex]\pi *25[/tex]
=> Area = 25[tex]\pi[/tex]
As there are 4 circles in, we get that the area covered by the small squares,
=> [tex]25\pi * 4[/tex]
=> [tex]100\pi[/tex]
So, the amount shaded = 100/400 (We can omit the [tex]\pi[/tex] at this stage because we are finding out a ratio)
=> 1/4
So, there is 1 cut region and the remaining is the uncut region,
As we need to find uncut to cut, the ratio will be,
=> remaining : 1
=> 3 : 1
If my answer helped, kindly mark me as the brainliest!!
Thanks!!
True or false: 8.9 x 10-7 = 0.000 008 9.
Every Sunday, Tamika sells pieces of homemade fudge at a local carnival. Each piece of fudge weighs 34 pound. Next Sunday, Tamika plans on
bringing 712 pounds of homemade fudge to sell.
How many pieces of fudge will Tamika be able to sell at the carnival next Sunday?
Answer:
The answer is c. 5 5/8.
Step-by-step explanation:
Its c because your supposed to multiply them. When you multiply them you get 5 5/8. Hope this helped,have a great day!
Brainliest will be given to the correct answer!
The formula for the area of a trapezoid is A = 1/2h (b1 + b2), where h is the height of the trapezoid, and b1 and b2 are the lengths of the bases.
Part A: Solve the formula for h. What is the height of a trapezoid that has an area of 91 cm2 and bases of 12 cm and 16 cm?
Part B: What method would you use to solve the formula for b1? What is the formula when solved for b1?
Part C: What is the length of the other base if one base of a trapezoid is 30 cm, the height of the trapezoid is 8.6 cm, and the area is 215 cm2?
Part D: If both bases of a trapezoid have the same length, can you find their lengths given the area and height of the trapezoid? Explain.
Answer:
A) The height of the trapezoid is 6.5 centimeters.
B) We used an algebraic approach to to solve the formula for [tex]b_{1}[/tex]. [tex]b_{1} = \frac{2\cdot A}{h}-b_{2}[/tex]
C) The length of the other base of the trapezoid is 20 centimeters.
D) We can find their lengths as both have the same length and number of variable is reduced to one, from [tex]b_{1}[/tex] and [tex]b_{2}[/tex] to [tex]b[/tex]. [tex]b = \frac{A}{h}[/tex]
Step-by-step explanation:
A) The formula for the area of a trapezoid is:
[tex]A = \frac{1}{2}\cdot h \cdot (b_{1}+b_{2})[/tex] (Eq. 1)
Where:
[tex]h[/tex] - Height of the trapezoid, measured in centimeters.
[tex]b_{1}[/tex], [tex]b_{2}[/tex] - Lengths fo the bases, measured in centimeters.
[tex]A[/tex] - Area of the trapezoid, measured in square centimeters.
We proceed to clear the height of the trapezoid:
1) [tex]A = \frac{1}{2} \cdot h \cdot (b_{1}+b_{2})[/tex] Given.
2) [tex]A = 2^{-1}\cdot h \cdot (b_{1}+b_{2})[/tex] Definition of division.
3) [tex]2\cdot A\cdot (b_{1}+b_{2})^{-1} = (2\cdot 2^{-1})\cdot h\cdot [(b_{1}+b_{2})\cdot (b_{1}+b_{2})^{-1}][/tex] Compatibility with multiplication/Commutative and associative properties.
4) [tex]h = \frac{2\cdot A}{b_{1}+b_{2}}[/tex] Existence of multiplicative inverse/Modulative property/Definition of division/Result
If we know that [tex]A = 91\,cm^{2}[/tex], [tex]b_{1} = 16\,cm[/tex] and [tex]b_{2} = 12\,cm[/tex], then height of the trapezoid is:
[tex]h = \frac{2\cdot (91\,cm^{2})}{16\,cm+12\,cm}[/tex]
[tex]h = 6.5\,cm[/tex]
The height of the trapezoid is 6.5 centimeters.
B) We should follow this procedure to solve the formula for [tex]b_{1}[/tex]:
1) [tex]A = \frac{1}{2} \cdot h \cdot (b_{1}+b_{2})[/tex] Given.
2) [tex]A = 2^{-1}\cdot h \cdot (b_{1}+b_{2})[/tex] Definition of division.
3) [tex]2\cdot A \cdot h^{-1} = (2\cdot 2^{-1})\cdot (h\cdot h^{-1})\cdot (b_{1}+b_{2})[/tex] Compatibility with multiplication/Commutative and associative properties.
4) [tex]2\cdot A \cdot h^{-1} = b_{1}+b_{2}[/tex] Existence of multiplicative inverse/Modulative property
5) [tex]\frac{2\cdot A}{h} +(-b_{2}) = [b_{2}+(-b_{2})] +b_{1}[/tex] Definition of division/Compatibility with addition/Commutative and associative properties
6) [tex]b_{1} = \frac{2\cdot A}{h}-b_{2}[/tex] Existence of additive inverse/Definition of subtraction/Modulative property/Result.
We used an algebraic approach to to solve the formula for [tex]b_{1}[/tex].
C) We can use the result found in B) to determine the length of the remaining base of the trapezoid: ([tex]A= 215\,cm^{2}[/tex], [tex]h = 8.6\,cm[/tex] and [tex]b_{2} = 30\,cm[/tex])
[tex]b_{1} = \frac{2\cdot (215\,cm^{2})}{8.6\,cm} - 30\,cm[/tex]
[tex]b_{1} = 20\,cm[/tex]
The length of the other base of the trapezoid is 20 centimeters.
D) Yes, we can find their lengths as both have the same length and number of variable is reduced to one, from [tex]b_{1}[/tex] and [tex]b_{2}[/tex] to [tex]b[/tex]. Now we present the procedure to clear [tex]b[/tex] below:
1) [tex]A = \frac{1}{2} \cdot h \cdot (b_{1}+b_{2})[/tex] Given.
2) [tex]b_{1} = b_{2}[/tex] Given.
3) [tex]A = \frac{1}{2}\cdot h \cdot (2\cdot b)[/tex] 2) in 1)
4) [tex]A = 2^{-1}\cdot h\cdot (2\cdot b)[/tex] Definition of division.
5) [tex]A\cdot h^{-1} = (2\cdot 2^{-1})\cdot (h\cdot h^{-1})\cdot b[/tex] Commutative and associative properties/Compatibility with multiplication.
6) [tex]b = A \cdot h^{-1}[/tex] Existence of multiplicative inverse/Modulative property.
7) [tex]b = \frac{A}{h}[/tex] Definition of division/Result.
5
4. y = 1
D
1
1
1
I
B
Answer:
not sure what you need but I would be happy to help
There were 75 sheep and 60 cows. What is the ratio of the number of cows to the number of sheep at mcneely’s farm
4/9
5/9
4/5
5/4
Answer:
4/5
Step-by-step explanation:
multiply the complex number by this complex conjugate.
16. 8+i
17. 3 - 2i
18. -7- 5i
Find the surface area of the cube shown below 2.3
Answer:
2 2/3 or 8/3
Step-by-step explanation:
Formula for each side = 2/3 x 2/3
2/3 x 2/3 = 4/9
6 sides
4/9 x 6 or 4/9 + 4/9 + 4/9 + 4/9 + 4/9 + 4/9
=2 2/3 or 8/3
Answer:
2 2/3
Is the answer