Answer:

Explanation:

For a body on a ramp with mass m, the forces acting on the body along the vertical component are the weight and the normal reaction.

The weight of the body acts in the negative y direction while the normal reaction acts in the positive y direction

Taking the sum of forces along the y component

Sum Fy = -W+R = ma

Since acceleration is zero

-W+R = m(0)

-W+R = 0

-W = -R

W = R

Hence the Normal reaction force acting on the on the body is equal to normal force

Please provide explanation!!!

Thank you.

**Answer:**

(a) 102 cm/s

(b) 0.490 cm²

**Explanation:**

(a) Use Bernoulli equation.

P₁ + ½ ρ v₁² + ρgh₁ = P₂ + ½ ρ v₂² + ρgh₂

0 + ½ ρ v₁² + ρgh₁ = 0 + ½ ρ v₂² + 0

½ ρ v₁² + ρgh₁ = ½ ρ v₂²

½ v₁² + gh₁ = ½ v₂²

½ (25.0 cm/s)² + (980 cm/s²) (5.00 cm) = ½ v²

v = 102 cm/s

(b) The flow rate is constant.

v₁ A₁ = v₂ A₂

(25.0 cm/s) (2.00 cm²) = (102 cm/s) A

A = 0.490 cm²

How much work is done lifting a 5 kg ball from a height of 2 m to a height of 6 m? (Use 10 m/s2 for the acceleration of gravity.)

A) 100 J B) 200 J C) 300 J D) 400 J

**Answer:**

B) 200 [J]

**Explanation:**

In order to solve this problem we must remember the definition of work which tells us that it is equal to the product of force by a distance, in this case, the force is the weight of the ball. The distance traveled is 4 [m] since 6-2 = 4[m]

F = m*g

where:

m = mass = 5 [kg]

g = gravity acceleration = 10 [m/s^2]

F = 5*10 = 50 [N]

w = F*d

where:

F = force = 50 [N]

d = 4 [m]

w = 50*4 = 200 [J]

what is the meaning of the word physics

**Answer:**

the scientific study of natural forces such as light, sound, heat, electricity, pressure, etc.

**Explanation:**

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One airplane is approaching an airport from the north at 181 kn/hr. A second airplane approaches from the east at 278 km/hr. Find the rate at which the distance between the planes changes when the southbound plane is 30 km away from the airport and the westbound plane is 15 km from airport.

Answer:

The value is [tex] \frac{dR}{dt} = -286.2 \ km/hr [/tex]

Explanation:

From the question we are told that

The speed of the airplane from the north is [tex]\frac{dN}{dt} = -181 \ km /hr[/tex]

The negative sign is because the direction is towards the south

The speed of the airplane from the east is [tex]\frac{dE}{dt} = -278 \ km/hr[/tex]

The negative sign is because the direction is towards the west

The distance of the southbound plane from the airport is [tex]N = 30 \ km[/tex]

The distance of the westbound plane is [tex]E = 15 \ km[/tex]

Generally the distance between the plane is mathematically represented using Pythagoras theorem as

[tex]R^2 = N^2 + E^2[/tex]

Next differentiate implicitly this equation to obtain the rate at which the distance between the planes changes

So

[tex]2R\frac{dR}{dt} = 2N \frac{dN}{dt} + 2E\frac{dE}{dt}[/tex]

Here

[tex]R = \sqrt{N^2 + E^2}[/tex]

=> [tex]R = \sqrt{30^2 + 15^2}[/tex]

=> [tex]R = \sqrt{30^2 + 15^2}[/tex]

=> [tex]R =33.54 \ m [/tex]

[tex]2(33.54) * \frac{dR}{dt} = 2( 30)*(-181) + 2*15*(-278)[/tex]

=> [tex] 67.08 * \frac{dR}{dt} = -19200[/tex]

=> [tex] \frac{dR}{dt} = -286.2 \ km/hr [/tex]

The **rate **of change of the **distance **between the **planes **is **286.23 km/hr.**

The given parameters;

The **distance **between the two **planes **is calculated by applying **Pythagoras theorem** as shown below;

[tex]d^2 = n^2 + e^2\\\\d = \sqrt{n^2 + e^2} \\\\d = \sqrt{30^2 + 15^2} \\\\d = 33.54 \ km[/tex]

The **rate **of **change **of the **distance **between the **planes **is calculated as follows;

[tex]d^2 = e^2 + n^2\\\\2\frac{dd}{dt} = 2e\frac{de}{dt} + 2n\frac{dn}{dt} \\\\d\frac{dd}{dt} = e\frac{de}{dt} + n\frac{dn}{dt}\\\\(33.54) \frac{dd}{dt} = (15)(278) \ + (30)(181)\\\\(33.54) \frac{dd}{dt} = 9600\\\\\frac{dd}{dt} = \frac{9600}{33.54} \\\\\frac{dd}{dt} = 286.23 \ km/hr[/tex]

Thus, the **rate **of change of the **distance **between the **planes **is **286.23 km/hr.**

Learn more here:https://brainly.com/question/11488002

when hydrogen shares electrons with oxygen the outermost shell of the hydrogen atoms are full with how many electrons? and oxygens valence shell is full with how many electrons? because the valence shells of these atoms are full,the atoms are stable.

**Answer:**

2 and 8

**Explanation:**

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A soccer ball accelerates from rest and rolls 6.5m down a hill in 3.1 s. It then bumps into a tree. What is the speed of the ball just before it hits the tree.

Answer:

2.096m/s

Explanation:

The speed of this soccer ball can be calculated using the formula;

Speed = distance/time

According to this question, the distance of the ball before it hits the tree is 6.5m, the time it takes is 3.1s, hence;

Speed = 6.5/3.1

Speed of the ball = 2.096m/s

Therefore, the speed of the ball before hitting the tree is 2.096m/s

The following summary transactions occurred during 2021 for Bluebonnet Bakers: Cash Received from: Collections from customers $490,000 Interest on notes receivable 11,500 Collection of notes receivable 54,000 Sale of investments 34,000 Issuance of notes payable 175,000 Cash Paid for: Purchase of inventory 235,000 Interest on notes payable 7,500 Purchase of equipment 90,000 Salaries to employees 95,000 Payment of notes payable 40,000 Dividends to shareholders 35,000 The balance of cash and cash equivalents at the beginning of 2021 was $26,000. Required: Prepare a statement of cash flows for 2021 for Bluebonnet Bakers. Use the direct method for reporting operating activities
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