Beverly has a bag of marbles that weighs 30 grams. She knows that each marble weighs 1.5 grams and the bag weighs 1.5 grams. Which equation could she use to determine how many marbles are in the bag? Select all that apply. (1.5)x + 1.5 = 30 30 – x = 2(1.5) (1.5)(30) = 1.5x 1.5 + x = 30 1.5x = 30 – 1.5

Answer:

Step-by-step explanation:

we can replace 5 with [tex]\sqrt{5}^{2}[/tex]

then.

[tex]\sqrt{5}^{n-1+2}=\sqrt{5}^{n+1}[/tex]

The length of the segment QR, obtained using the angle bisector theorem is; SR ≈ 11.4 units

The angle bisector theorem states an angle bisector in a triangle, intersects opposite side, such that the ratio of the two segments formed by the point of intersection is the same as the ratio of the other two sides of the triangle.

The angle congruence marks at angle ∠Q, indicates that the angle ∠PQS and the angle ∠SRQ are congruent.

Therefore, the segment QS is an angle bisector of the angle ∠PQR.

The angle bisector theorem, indicates that we get;

30/12 = PS/SR

PS = PR - SR, therefore;

30/12 = 5/2 = (PR - SR)/SR

Plugging in the values, we get;

5/2 = (40 - SR)/SR

5 × SR = 2 × (40 - SR) = 80 - 2 × SR

5 × SR + 2 × SR = 80

7 × SR = 80

SR = 80/7 ≈ 11.4

The length of the segment SR is about 11.4 units

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A sample of customers from barnsboro national bank shows an average account balance of 315 with a standard deviation of 87. a sample of customers from wellington savings and loan shows an average account balance of 8350 with a standard deviation of 1800. Option A: Barnsboro Bank has more variation.So, the correct option is A) Barnsboro Bank has more variation.

The given data is:

A sample of customers from Barnsboro National Bank shows an average account balance of 315 with a standard deviation of 87.

A sample of customers from Wellington Savings and Loan shows an average account balance of 8350 with a standard deviation of 1800.

To compare the variation in the account balances of both banks, we use the coefficient of variation (CV).

CV = Standard deviation / Mean

CV of Barnsboro National Bank = 87/315 ≈ 0.2762

CV of Wellington Savings and Loan = 1800/8350 ≈ 0.2150

The CV of Barnsboro National Bank is greater than the CV of Wellington Savings and Loan.

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Option P(A) = 5/6 is correct using the probability concept for the scenario n(A')=6.

The scenario is you roll two standard 6-sided dice if n(A′) = 6.
Here, we need to use the concept of probability to solve the problem.

Probability is the branch of mathematics that deals with the measurement of the chance of occurrence of a particular event. It can be defined as the ratio of the number of favorable outcomes to the number of total possible outcomes.

Given that the two standard 6-sided dice are rolled. Now, we need to find the probability of rolling a 7.
Here, the sum of the numbers on the two dice must be 7. We can obtain this sum in the following ways:
(1,6), (2,5), (3,4), (4,3), (5,2), and (6,1)
Thus, the number of ways to roll a 7 is 6 which is n(A') = 6.
Therefore, P(A') = n(A')/n(S) = 6/36 = 1/6.

Now, we are given that n(A′) = 6, which means that the number of ways to roll a 7 is 6.
Thus, the number of ways to not roll a 7 is 36 - 6 = 30.
Therefore, P(A) = n(A)/n(S) = 30/36 = 5/6.

Hence, the correct option is P(A) = 5/6.

Your question is incomplete, but most probably your full question was

For the scenario where you roll two standard 6-sided dice, if n(A′)=6, then:

P(A)=6/36

n(A′)= number of ways to not roll a 7

P(A′)=30/36

n(A)= number of ways to roll a 7

P(A)=5/6​

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The expression 27/(27x + 18) can be rewritten as 3/(3x + 2).

What are common factors?

Common factors are factors that two or more numbers share. In other words, they are factors that divide into two or more numbers without leaving a remainder. For example, the common factors of 12 and 18 are 1, 2, 3, and 6. These are the numbers that divide evenly into both 12 and 18.

Finding common factors is useful in simplifying fractions and factoring expressions. When simplifying a fraction, you can divide both the numerator and denominator by a common factor to reduce the fraction to its simplest form. When factoring an expression, you can factor out a common factor to simplify the expression and make it easier to work with.

It's worth noting that the greatest common factor (GCF) is the largest common factor that two or more numbers share. For example, the GCF of 12 and 18 is 6, which is the largest number that divides evenly into both 12 and 18.

To rewrite the expression 27/(27x + 18), we can factor out the greatest common factor in the denominator, which is 9. This gives:

27 / (9 * (3x + 2))

We can simplify this expression further by dividing both the numerator and denominator by 9, which results in:

3 / (3x + 2)

Therefore, the expression 27/(27x + 18) can be rewritten as 3/(3x + 2).

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Check the picture below.

let's notice the polygon has 6 sides, so

[tex]\underset{in~degrees}{\textit{sum of all interior angles}}\\\\ S = 180(n-2) ~~ \begin{cases} n=\stackrel{number~of}{sides}\\[-0.5em] \hrulefill\\ n=6 \end{cases}\implies S=180(6-2)\implies S=720 \\\\[-0.35em] ~\dotfill\\\\ 2b+110+116+112+110~~ = ~~720 \\\\\\ 2b+448=720\implies 2b=272\implies b=\cfrac{272}{2}\implies b=136[/tex]

If Ling plans to collect data and plot them in a scatterplot to look for a relationship, the relationship is positive.

In basketball, players who spend more time on the court are likely to have more opportunities to score points. Therefore, as the playing time increases, the number of points scored by a player may also increase. This would result in a positive relationship between playing time and points scored in a basketball game.

A positive relationship in a scatterplot is characterized by a general upward trend in the data points. As one variable increases, the other variable also tends to increase.

In this case, Ling's scatterplot would likely show data points that are positively correlated, meaning that as the playing time increases, the number of points scored by a player would also tend to increase.

It is also possible for there to be no relationship or a negative relationship between playing time and points scored, but given the nature of basketball, a positive relationship is the most likely outcome.

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Jacobi measured the diagonals of three TV screens as 5/84 inches, 46 inches and 46. 625 inches.

The lengths of the diagonals in ascending order are 5/84 inches, 46 inches, and 46.625 inches.

The diagonals of the three TV displays are 5/84, 46, and 46.625 inches, respectively.

To determine the ascending order of the diagonals, we first convert the fraction 5/84 to a decimal. We may accomplish this by dividing 5 by 84 with a calculator or long division, yielding:

0.05952381

We can now contrast the three diagonal lengths:

0.05952381 inches

46 inches

46.625 inches

Hence, in increasing order, the diagonals are:

0.05952381 inches

46 inches

46.625 inches

As a result, the diagonal lengths in ascending order are 0.05952381 inches, 46 inches, and 46.625 inches.

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The distance AC is approximately 6.47 km, the bearing of A from C is approximately 313.8°, and the area of triangle ABC is approximately 14.8 km².

To solve this problem, we can use the law of cosines to find the length of AC and the law of sines to find the angle at A.

First, we can use the given information to draw a diagram and label the angles and sides:

       C

      / \

     /   \

 5 /     \ 7

   /       \

  /         \

A /___θ_____\ B

From the given information, we know that:

AB = 7 km

BC = 5 km

∠ABC = 100° (since ∠ABD = 180° - 30° - 70° = 80° and ∠DBC = 180° - 280° = 100°)

Using the law of cosines, we can find the length of AC:

AC^2 = AB^2 + BC^2 - 2ABBCcos(∠ABC)

AC^2 = 7^2 + 5^2 - 2(7)(5)cos(100°)

AC^2 ≈ 41.84

AC ≈ 6.47 km

Next, we can use the law of sines to find the angle at A:

sin(∠CAB)/AC = sin(∠ABC)/AB

sin(∠CAB)/6.47 = sin(100°)/7

sin(∠CAB) ≈ 0.276

∠CAB ≈ 16.2°

To find the bearing of A from C, we can use the fact that the bearing is the angle measured clockwise from north. Since ∠CAB is acute and the bearing of B from A is 30° east of north, the bearing of A from C is:

360° - (30° + ∠CAB) ≈ 313.8°

Finally, to find the area of triangle ABC, we can use the formula:

Area = (1/2)ABBCsin(∠ABC)

Substituting the given values, we get:

Area = (1/2)(7)(5)sin(100°)

Area ≈ 14.8 km²

Therefore, the distance AC is approximately 6.47 km, the bearing of A from C is approximately 313.8°, and the area of triangle ABC is approximately 14.8 km².

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Answer:

Yardley is approximately 5.7 miles away from the airport.

Step-by-step explanation:

Let's use the following variables:

x = distance between Yardley and the airport

Using the Pythagorean theorem:

x^2 + 7^2 = 9^2

x^2 + 49 = 81

x^2 = 32

x = sqrt(32)

x ≈ 5.7

Therefore, Yardley is approximately 5.7 miles away from the airport.

Answer:

5.7 miles

Step-by-step explanation:

To find:-

Answer:-

We are given that airport and Wildgrove are 7miles apart and the distance between Yardley and Wildgrove is 9miles . We are interested in finding out tge distance between Yardley and airport.

As you can see from the figure attached, the distance can be calculated using Pythagoras theorem ,

[tex]\rm\implies a^2+b^2 = h^2 \\[/tex]

where ,

Here the longest side is 9 miles and one other side is 7 miles . On substituting the respective values, we have;

[tex]\rm\implies a^2 + (7)^2 = 9^2 \\[/tex]

[tex]\rm\implies a^2 + 49 = 81 \\[/tex]

[tex]\rm\implies a^2 = 81 - 49 \\[/tex]

[tex]\rm\implies a^2 = 32 \\[/tex]

[tex]\rm\implies a =\sqrt{32} \\[/tex]

[tex]\rm\implies a = 5.65 \\[/tex]

[tex]\rm\implies \red{ a = 5.7 } \\[/tex]

Hence the distance between Yardley and airport is 5.7 miles .

Answer: D. Population: all the first-year students at the university

Sample: a group of 185 incoming first-year students

Conclusion: The reason for the majority of the students to choose the university was affordability.

Answer:

D. Population: all the first-year students at the university

Sample: a group of 185 incoming first-year students

Conclusion: The reason for the majority of the students to choose the university was affordability..

According to the question the exponential function that goes through the two points is: [tex]y = 4(9^x).[/tex]

Given,

We must first determine the values of a and b before we can build an exponential function with the form y = abx that passes through the points (0,4) and (2,324).

Using the point (0,4), we have:

4 = ab^0

4 = a(1)

a = 4

Using the point (2,324), we have:

324 = 4b^2

b^2 = 81

b = 9 (since b must be positive)

So the exponential function that goes through the two points is:

y = 4(9^x)

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The measured angle at position 1 is 63 degree. The angle which is  between the two tangents drawn from a outer side point to a circle is supplementary to  angle subtended

An angle is a geometric figure formed by two rays, or line segments that share a common endpoint, called the vertex of the angle. Angles are measured in degrees, radians, or other units, and are typically denoted using the symbol  θ

In geometry, the tangent to a circle is a line that intersects the circle at exactly one point, called the point of tangency. The tangent line is perpendicular to the radius of the circle that passes through the point of tangency.

In the given question ,

The angle which is  between the two tangents drawn from a outer side point to a circle is supplementary to  angle subtended by the line segment joining the points of contact at the center.

From the above theorem  we can write

angle at position 1 x= 360 - ((360-243)+90+90)

we get x=63

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Answer:

The formula for the area of a circle is A = πr^2, where r is the radius of the circle.

We know that the diameter of the circle is 10 ft, so the radius is half of that:

r = 10 ft ÷ 2 = 5 ft

Now we can plug in this value for r into the formula:

A = π(5 ft)^2

A = π(25 ft^2)

A ≈ 78.54 ft^2

Rounding this to the nearest whole number, we get:

A ≈ 79 ft^2

Therefore, the area of the circle to the nearest whole number is 79 square feet.

Answer:

79ft^2

Step-by-step explanation:

diameter=10ft

radius=5ft

5^2=25ft

25×π=25π

25π= 78.539....

to nearest whole number =79ft^2

A. Yes, because the rate of change is a constant $70 per year. We can observe that the amount owed increases by $70 for every year that passes.

This is due to the simple interest rate of 7% per year, which means that the boy owes an additional 7% of the original amount ($1000) each year. Thus, the  the amount owed after one year is $1000 + 0.07($1000) = $1070, after two years it is $1000 + 2(0.07($1000)) = $1140, and so on. $70  is the change rate per year.

B. It will be no due to the change rate is $0 per year in 2nd and 3rd years.

This statement is false because, as we calculated in part A, the rate of change is constant at $70 per year. Therefore, the amount owed will increase by $70 even during the second and third years, as long as the boy has not made any payments towards the loan.

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Answer: o find the maximum value of the objective function F=5x+2y and the values of x and y for which it occurs, we need to graph the constraints and determine the feasible region. Then, we can evaluate the objective function at the vertices of the feasible region to find the maximum value.

First, we will graph the constraints x+2y<6 and 2x+y<6. To do this, we can rewrite the inequalities as equations and graph the corresponding lines:

x+2y=6 (solid line)

2x+y=6 (dashed line)

Next, we need to determine which side of each line satisfies the inequality. To do this, we can choose a point on one side of each line and substitute its coordinates into the inequality. If the inequality is true, then that side of the line satisfies the inequality. If not, then the other side satisfies the inequality.

For example, let's choose the point (0,0) as a test point for the inequality x+2y<6:

0+2(0)<6

This is true, so the side of the line on which (0,0) lies satisfies the inequality. Similarly, we can choose the point (0,0) as a test point for the inequality 2x+y<6:

2(0)+0<6

This is also true, so the side of the line on which (0,0) lies satisfies the inequality.

Now, we can shade in the feasible region, which is the region of the graph that satisfies all of the constraints. It is the region bounded by the two lines and the axes, and it is shown in the figure below:

lua

   |              .

   |            .

   |          .

 3 |        .

   |      .

   |    .

 2 |  .

   |.

   ----------------

     0  1  2  3  4  5  6

The vertices of the feasible region are (0,3), (2,2), and (3,0). To find the maximum value of the objective function, we evaluate it at each vertex:

F(0,3) = 5(0) + 2(3) = 6

F(2,2) = 5(2) + 2(2) = 14

F(3,0) = 5(3) + 2(0) = 15

Therefore, the maximum value of the objective function is 15, and it occurs when x=3 and y=0.

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Answer: To calculate the p-value for a two-proportion z-test, we need to determine the test statistic, which is calculated as:

z = (p1 - p2) / SE

where p1 and p2 are the sample proportions for each group, and SE is the standard error of the difference between the two proportions.

The sample proportion for the group given the milk chocolate option first is:

p1 = (52 + 48) / 100 = 0.50

The sample proportion for the group given the dark chocolate option first is:

p2 = (41 + 59) / 100 = 0.60

The standard error of the difference between two proportions is:

SE = sqrt((p1*(1-p1))/n1 + (p2*(1-p2))/n2)

where n1 and n2 are the sample sizes for each group.

SE = sqrt((0.50*(1-0.50))/100 + (0.60*(1-0.60))/100) = 0.0748

Substituting the values into the test statistic formula, we get:

z = (0.50 - 0.60) / 0.0748 = -1.338

Using a standard normal distribution table or calculator, we find the p-value for a two-tailed test to be approximately 0.1814.

However, since we are testing whether the order of the options affects the response, this is a one-tailed test. To find the one-tailed p-value, we divide the two-tailed p-value by 2, since the area of the distribution in one tail is half of the area in both tails.

p-value = 0.1814 / 2 = 0.0907

Therefore, the correct answer is A. 0.0594 (rounded to four decimal places).

Step-by-step explanation:

Answer: We are given that GH = 4x - 3 and IJ = 3x + 14.

To find x, we can set GH equal to IJ and solve for x:

4x - 3 = 3x + 14

x = 17

Therefore, x = 17.

To find the length of GH, we can substitute x = 17 into the expression for GH:

GH = 4x - 3

GH = 4(17) - 3

GH = 68 - 3

GH = 65

Therefore, the length of GH is 65.

Step-by-step explanation:

Answer:

Train A= 249 tons

Train B= 87 tons

Step-by-step explanation:

Total weight of Train A and Train B= 336 tons

Weight of Train A > Weight of Train B

Difference of their weights= 162 tons

Let the weight of Train A be t.

Then weight of Train B= t-162

Total weight= 336 tons

         t+t-162= 336

                 2t= 336+162

                 2t= 498

                   t= [tex]\frac{498}{2}[/tex]

                   t= 249

t-162= 249-162

       = 87

∴ the weights of Train A and Train B are 249 tons and 87 tons respectively.

The amount of aspirin in the bloodstream will be about 0.838 times what it was before.

The function that represents the amount of aspirin, A, present in the bloodstream x hours after taking a 325 mg pill is:

[tex]A = A_0 \times b^x[/tex]

where A_0 is the initial amount of aspirin in the bloodstream (which is 325 mg), and b is a constant that represents the rate of decay of the aspirin in the bloodstream.

We are told that after 3 hours, there is about 199.6 mg of aspirin remaining in the patient's bloodstream. Using the function above, we can set up an equation based on this information:

[tex]199.6 = 325 \times b^3[/tex]

To solve for b, we can divide both sides by 325 and then take the cube root of both sides:

[tex]b^3[/tex]= 199.6 / 325

b = [tex](199.6 / 325)^{(1/3)[/tex]

b ≈ 0.838

So the value of b is approximately 0.838. In the context of the problem, this means that the amount of aspirin in the bloodstream decreases by a factor of approximately 0.838 every hour. In other words, if we wait one hour,  If we wait two hours, it will be about (0.838)^2 times what it was before, and so on. This exponential decay model can be useful in predicting how long it will take for the aspirin to be completely eliminated from the bloodstream.

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The cost of cementing the walls of the cuboidal well is Rs 3640.

A three-dimensional solid form with six rectangular sides is called a cuboid. It also goes by the name rectangular prism. The shapes and sizes of the faces on either side of each other are identical.

A cuboid's surface area is the sum of all of its faces. We can determine the area of each face and put them together to determine the cuboid's surface area.

Given that, the cost of cementing the walls of the well at the rate Rs 52 per square m.

Thus,

Area of one rectangular face = length x height = 2 x 10 = 20m².

Area of the other rectangular face = width x height = 1.5 x 10 = 15m².

Total surface area of the walls = 2(20) + 2(15) = 70m².

Now, the cost of cementing the walls of the well at the rate of Rs 52 per m² is:

Cost = 70m x Rs 52 = Rs 3640

Hence, the cost of cementing the walls of the well is Rs 3640.

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Answer:

Median = 42
LQ = 33
UQ = 52

Step-by-step explanation:

median is given by the term that divides the groups in two equally quantities. In this case is (n+1)/2 = (13+1)/2 = 14/2 = 7

the 7th term is: 42
(notice this means 6 values are below 42 and 6 values are above 42, the definition of a median)

the first (lower) quartile is given then by the (n+1)/4 value

(13+1)/4=3.5, this is the half between 3th and 4th terms.

since the term is the same (3th value is 33 and 4th value is 33)

LQ=33
(25% of the values are below 33)

for the upper quartile the value represents the top 75%, this is given by

3(13+1)/4 = 10.5

this is the half between 10th and 11th terms

(51+53)/2=52

(25% of the values are above 52)

Option (c) is true i.e. y is not a function of x, since the x-values do not correspond to exactly (precisely) one y-value.

A function in mathematics from a set X to a set Y allocates exactly (precisely) one element of Y to each element of X. The sets X and Y are collectively referred to as the function's domain and codomain, respectively.

The items that make up a set are referred to as its elements (or members), and the set is said to contain the elements when they are claimed to belong to it.

The mapping shows a relationship between x and y in this mapping is y is not a function of x, since the x-values do not correspond to exactly one y-value.

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The correct option is b. Sample_size for (0.01) = 4*Sample_size for (0.04).

When answering questions on Brainly, you should always be factually accurate, professional, and friendly. Additionally, you should be concise, provide a step-by-step explanation, and use the following terms in your answer: "estimate," "sample," and "confidence."For the given problem, we need to determine the sample size of the retailer's customers to estimate the proportion of Hispanic customers in a particular state with 0.04 accuracy and 99% confidence since there is no planning value for p*.

Now, we can use the formula for sample size to estimate the number of customers needed for the retailer, which is given by:n= z^2 p q/E^2 Where, z = the critical value from the standard normal distribution at the given confidence level p = the estimate of the proportion q = 1 - p E = the maximum likely difference between the sample and population proportion p = Proportion of Hispanic customers Let's use the values of z and E for the given problem, which isz=2.58 (at 99% confidence level, two-tailed)E=0.04 We need to find the sample size for the retailer's customers, so we can substitute the given values in the sample size formula and solve forn as shown:n = z^2pq/E^2 = (2.58)^2(0.5)(0.5)/(0.04)^2= 664.53 ≈ 665 So, the sample size of 665 customers would be needed to estimate the proportion of Hispanic customers in a particular state with 0.04 accuracy and 99% confidence.Now, we are asked to find the true statement if we decide to go for 0.01 accuracy instead of 0.04 accuracy.

The formula to calculate sample size for 0.01 accuracy can be written asn = (z^2pq)/(0.01)^2 Now, we need to find the relationship between sample size for 0.01 accuracy and 0.04 accuracy, which is given as follows :n1/n2 = (z1/z2)^2 (E1/E2)^2= (2.58/2.33)^2 (0.04/0.01)^2≈ 3.41 × 16n1/n2 = 54.56 Since sample size for 0.01 accuracy is larger than the sample size for 0.04 accuracy, we can say that option b. Sample_size for (0.01) = 4*Sample_size for (0.04) would be true if we decide to go for 0.01 accuracy instead of 0.04 accuracy. Hence, the correct option is b. Sample_size for (0.01) = 4*Sample_size for (0.04).

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The number of hours she can afford to rent the paddle boat is  x ≤ 6.8. Option D

we have the equation in the inequality as

1.25x + 6.50 ≤ 15

we would have to solve for x

hence we would take the like terms first

1.25x ≤ 15 - 6.50

then we would have

1.25x ≤ 8.5

Next we have to divide through by 1.25

1.25x / 1.25 ≤ 8.5 / 1.25

x ≤ 6.8

Hence the solution to the inequality is x ≤ 6.8. Elise can afford to rent the paddle boat for x ≤ 6.8

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Elise has $15 to spend on a paddle boat ride she uses this inequality to determine x the number of hours she can afford to rent the paddle boat

1.25x + 6.50 ≤ 15

What is the solution to the inequality?

x ≥ 17.2

x ≥ 6.8

x ≤ 17.2

x ≤ 6.8

​

Answer:

x ≤ 6.8

Step-by-step explanation:

By simplification the quadratic function [tex]y = x^2 + x - 8[/tex] in vertex form is[tex]y = (x + 1/2)^2 - 33/4[/tex], and its vertex is (-1/2, -33/4).

What is the vertex form of a quadratic equation?

The standard form of a quadratic function is:

[tex]y = ax^2 + bx + c[/tex]

where a, b, and c are constants and x is the variable.

The vertex form of a quadratic function is:

[tex]y = a(x - h)^2 + k[/tex]

where a, h, and k are constants and (h, k) is the vertex of the parabola.

To write the quadratic function [tex]y = x^2 + x - 8[/tex] in vertex form, we need to complete the square. The vertex form of a quadratic function is given by:

[tex]y = a(x - h)^2 + k[/tex]

where (h, k) is the vertex of the parabola.

So, first we need to factor out the coefficient of the x^2 term:

[tex]y = 1(x^2 + x) - 8[/tex]

Now, we need to complete the square for the expression inside the parentheses:

[tex]y = 1(x^2 + x + 1/4 - 1/4) - 8[/tex]

[tex]y = 1[(x + 1/2)^2 - 1/4] - 8[/tex]

Finally, we can simplify and write the function in vertex form:

[tex]y = (x + 1/2)^2 - 33/4[/tex]

Therefore, the quadratic function [tex]y = x^2 + x - 8[/tex] in vertex form is[tex]y = (x + 1/2)^2 - 33/4[/tex], and its vertex is (-1/2, -33/4).

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The probability that you test more than 9 people before getting a positive test is 0.42 (rounded to three decimals).

What is probability ?

Probability is a measure of the likelihood or chance that a particular event will occur. It is a number between 0 and 1, with 0 indicating that the event is impossible and 1 indicating that the event is certain to occur.

Given that 42% of the population has a virus, the probability that any given person has the virus is 0.42. We can use this information to answer the following questions:

a. The probability that the first positive test is person number 9 can be calculated using the binomial distribution:

[tex]P(X = 1) = (9-1)C(1) * 0.42^{1} * (1 - 0.42)^{(9-1)} = 0.251[/tex]

Therefore, the probability that the first positive test is person number 9 is 0.251 (rounded to three decimals).

b. The probability that the first positive test happens on or before person number 9 can be calculated using the cumulative binomial distribution:

P(X <= 1) = P(X = 0) + P(X = 1) = 0.58

Therefore, the probability that the first positive test happens on or before person number 9 is 0.58 (rounded to three decimals).

c. The probability that you test more than 9 people before getting a positive test can be calculated using the complementary probability:

P(X > 1) = 1 - P(X <= 1) = 1 - 0.58 = 0.42

Therefore, the probability that you test more than 9 people before getting a positive test is 0.42 (rounded to three decimals).

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The populations of Anville and Brinker will become equal in around 15.23 years.

Let's represent the current population of Anville by A and the current population of Brinker by B. Then we have:

A = 21000

B = 9000

Let t be the number of years we want to find. Then the population of Anville after t years will be:

A_t = A * (1 + 0.07)ᵗ

And the population of Brinker after t years will be:

B_t = B * (1 + 0.08)ᵗ

We want to find the value of t such that A_t = B_t. Substituting the above equations, we get:

A * (1 + 0.07)ᵗ = B * (1 + 0.08)ᵗ

Dividing both sides by A and B, respectively, we get:

(1 + 0.07)ᵗ = (1 + 0.08)ᵗ * (B/A)

Taking the natural logarithm of both sides, we get:

t * ln(1 + 0.07) = t * ln(1 + 0.08) + ln(B/A)

Simplifying and solving for t, we get:

t = ln(B/A) / (ln(1 + 0.07) - ln(1 + 0.08))

Substituting the given values of A and B, we get:

t = ln(9000/21000) / (ln(1 + 0.07) - ln(1 + 0.08)) ≈ 15.23

Therefore, it will take approximately 15.23 years for the populations of the two towns to be equal.

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We can factor the polynomial as:-32a^2 - 82a + 31 = 32(a - \frac{1}{2})(a - \frac{31}{32})

.To make the polynomial 32a^2 - 82a + C factorable, we need to find an integer value for C such that the quadratic expression can be factored into two binomials.

To do this, we can use the formula for the discriminant: b^2 - 4ac. Since we want the discriminant to be a perfect square, we can set it equal to some integer k^2 and solve for C:

82^2 - 4(32)(C) = k^2

6724 - 128C = k^2

We can try different values of k and solve for C until we find an integer solution. For example, if we let k = 10, we get:

10^2 = 6724 - 128C

C = 31

To verify that this value of C works, we can factor the trinomial using the X formula:

a = 32, b = -82, c = 31

X = (-b ± sqrt(b^2 - 4ac)) / 2a

X = (82 ± sqrt(82^2 - 4(32)(31))) / 2(32)

X = (82 ± 8) / 64

So, the roots of the quadratic are:

a = 32, X1 = 1/2, X2 = 31/32

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The answer is 4A+2B+5. This can be achieved by combining the like terms in the expression 4a-1+2B+6. First we add 4 and -1 to get 3 for the A-coefficient, then we add 2 and 6 to get 8 for the B-coefficient, and finally we combine the coefficients to get 4A+2B+5.

To combine the like terms in the expression 4a-1+2B+6, we need to simplify it. We can do this by combining the A-coefficients and the B-coefficients.

The A-coefficient is 4, so we add 4 and -1 to get 3. This means the expression is now 4A+2B+6.

The B-coefficient is 2, so we add 2 and 6 to get 8. This means the expression is now 4A+2B+8.

Finally, we combine the A-coefficient and the B-coefficient to get 4A+2B+5.

Therefore, the answer is 4A+2B+5.

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