Answer:
Beryllium bromide
Explanation:
There exists 2 elements in the question
Beryllium Be with valence of +2, and it's a metal
Bromine Br with a valence of -1, and is a non - metal.
Both of them combine together forming an ionic bond:
Be + Br(2) -> BeBr(2)
In naming the compound, we would say that since the first is a metal, beryllium, and the second being a halogen, bromine. We name it by calling the first name together with the last name and changing the last name of the non metal from -ine to -ide.
So we have, Beryllium Bromide.
Answer: A. Beryllium Bromide
Explanation:
Got it right on edge 2023
When more energy is released when new bonds are formed. Which bonds are stronger. Please add why
1. The bonds that are formed
2. The bonds that are broken
Answer:
the bonds that are formed
Explanation:
Energy is absorbed in order to break bonds. Energy is released when new bonds are formed. Bond-making is a process of exothermic. Whether the reaction is endothermic or exothermic refers to the difference between the energy needed to break bonds and the energy released when new bonds are formed.
Under constant acceleration, the average velocity of a particle is half the sum of its initial and final
velocities. Is this still true if the acceleration is not constant? Explain.
Answer:
It is not still true that the average velocity of the particle is equal to half the sum of the initial and final velocities when the acceleration of the particle is not constant
Explanation:
The motion of a particle under constant acceleration, 'a', is be given by the following kinematic equations;
v² = u² + 2·a·s
v = u + a·t
Where;
v = The final velocity of the particle
u = The initial velocity of the particle
a = The acceleration of the particle
s = The distance through which the particle travels
t = The time of motion of the particle
By simplifying the above equation, we have;
v² - u² = 2·a·s
(v² - u²)/(2·a) = s
(v - u) × (v + u)/(2 × a) = s
((v - u)/a) × ((v + u)/2) = s
From v = u + a·t, we have;
t = (v - u)/a
∴ ((v - u)/a) × ((v + u)/2) = t × ((v + u)/2) = s
∴ ((v + u)/2) = s/t
The average velocity = (Total distance traveled by the particle) ÷ (The time of travel of the particle)
∴ The average velocity = s/t = ((v + u)/2) = Half the sum of the initial and final velocity
However, it is not still true that the average velocity of the particle is equal to half the sum of the initial and final velocities when the acceleration of the particle, 'a', is not constant, as the velocity time graph is no longer a straight line graph and the distance traveled by the particle, 's', which is the area under the velocity time graph, 'A', (given by the sum of area of the triangle and the rectangle given by the area under straight line graph for constant velocity) cannot be given directly by the product of the time and the average velocity.
A car engine produces a force of 2000N while moving a distance of 200m in a time of 10s. What is the power developed by the engine
A 2750 kg helicopter flies horizontally at constant speed. Air resistance creates a 7510 n backward force. What is the magnitude of the lift force created by the propellers
Answer:
Explanation:
Let lift force F be created by propellers at angle of Ф with the horizontal .
The vertical component of this force will balance the weight of helicopter and horizontal component will balance the air resistance .
F sinФ = mg = 2750 x 9.8 = 26950 N
F cosФ = 7510 N
Squaring and adding ,
F² = 26950² + 7510²
= 726302500 + 56400100
= 782702600
F = 27976.82 N .
________ 8. The pH of a solution is a measure of the concentration of H+ ions in it. TRUE OR FALSE
Answer:
False.
Explanation:
Potential of Hydrogen is the full form of PH.
Potential of Hydrogen tells about the acidity or basicity of the solution.
The pH of a solution is a measure of the concentration of hydrogen ions [tex](H+)[/tex] ions and hydroxide ions [tex](OH-)[/tex] in a solution.
So, the given statement is false.
Can someone please help me?
Please also explain how you got the net force, thank you.
The questions are in the picture i attached below.
Answer:
unbalanced 1st answer
right 2nd answerAnswer:
hi, your answers are correct
Explanation:
How much work is performed when a 50 kg crate is pushed 15 m with a force of 20 N?
Answer:
300 jules
Explanation:
The principal ran a marathon, 26.2 miles in 3 hours. This is an example of.....
A-speed
B-velocity
C-acceleration
The radius of the aorta is about 1 cm and the blood flowing through it has a speed of about 30 !" ! . Calculate the average speed of the blood in the capillaries given the total cross section of all the capillaries is about 2000 !"!
Answer:
The average speed of the blood in the capillaries is 0.047 cm/s.
Note: The question is incomplete. The complete question is as follows:
The radius of the aorta is about 1 cm and the blood flowing through it has a speed of about 30 cm/s. Calculate the average speed of the blood in the capillaries given the total cross section of all the capillaries is about 2000 cm².
Explanation:
From the given values:
radius of the aorta, r₁ = 1 cm
speed of blood, v₁ = 30 cm/s
Area of the aorta, A₁ = πr₁² where π = 3.142
Area of aorta = 3.142 × (1)² = 3.142 cm²
Area of the capillaries, A₂ = 2000 cm²
let the average speed of the blood in the capillaries = v₂
From the continuity equation of fluid flow, the product of cross-sectional area of the pipe and the fluid speed at any point along the pipe is always constant. In formula, A₁v₁ = A₂v₂
Using the continuity equation, the average the average speed of the blood in the capillaries can be calculated thus:
A₁v₁ = A₂v₂
v₂ = (A₁v₁) / (A₂)
v₂ = (3.142 x 30) / (2000)
v₂ = 0.047 cm/s
Therefore, the average speed of the blood in the capillaries is 0.047 cm/s.
Which is a benefit of strength training? O Decreased blood flow to muscles O Improved oxygen delivery Flexibility of tendons and joints O Increased lean muscle tissue
Answer:
Increased lean muscle tissue.
Explanation:
I hope this helps :) Tell me if I am wrong!
Answer:
Increased lean muscle tissue.
Explanation:
i took the test!
Which of the following is an example of an opposing force?
A.Gravity pulling a ball down a hill
B.Wind blowing a leaf off of a tree
C.Gravity holding a rock still on the ground
D.Water pushing against someone as they wade through a pool
EASY PLEASE HELP. As the rocket rises, it's kinetic energy changes. at the time the rocket reaches its highest point most of the energy of the rocket has been-
A) permanently destroyed
B) transformed into potential energy
C) converted to friction
D) stored inside the body of the
Answer:
c
Explanation:
Alyssa is taking a walk on a nature path near her neighborhood. She
carries a compass with her. As she walks along the path, she notices
the needle on the compass is occasionally deflected from its original
position. If she has not changed the direction she is walking, what is
most likely causing the occasional shift in the needle? (1 point)
O Changes in pressure
0 Changes in temperature
O Sources of electrical current
O Changes to Earth's magnetic field
Answer:
C. Sources of electrical current!
Hope this helps :)
Answer:
Sources of electrical current
Explanation:
Got it right on the test.
Transforme: a) 2 km em m b) 1,5 m em mm c) 5,8 km em cm d) 0,4 m em mm e) 27 mm em cm f) 126 mm em m g) 12 m em km
Answer:
a) 2000 m
b) 1500 mm
c) 580000 cm
d) 400 mm
e) 2.7 cm
f ) 0.126 m
g) 0.012 km
Explanation:
Transform
a) 2km to m
1 km = 1000m
hence : 2 km = 2 * 1000 = 2000 m
b) 1.5m to mm
1 m = 1000 mm
hence: 1.5 m = 1.5 * 1000 = 1500 mm
C) 5.8 km to cm
1 km = 100000 cm
hence ;5.8 km = 5.8 * 100000 = 580000 cm
D) 0.4 m to mm
1 m = 1000 mm
hence; 0.4 m = 0.4 * 1000 = 400 mm
E) 27 mm to cm
1 mm = 0.1 cm
hence ; 27 mm = 27 * 0.1 = 2.7 cm
F) 126mm to m
1 mm = 0.001 m
hence ; 126 mm = 126 * 0.001 = 0.126 m
G) 12m to Km
1 m = 0.001 km
hence ; 12 m = 12 * 0.001 = 0.012 km
Someone help me please I need to pass this quiz , this is the only quiz that It making me fail this class !!!
Select the correct items. Click the bottom right arrow to go to the next set . Click the checkmark ( Available on the last set ) to submit all your answers
Slow twitch muscle Fibers
Can contract repeatedly
Only anaerobic sources
Both aerobic & anaerobic
Produce most force
Endurance activities
Fast contraction speed
Fatigue quickly
Only aerobic sources
Speed, strength, power
Fast twitch Type lla muscle Fibers
Only aerobic sources
Fast contraction speed
Speed, strength, power
Only anaerobic sources
Fatigue quickly
Endurance activities
Produce most force
Can contract repeatedly
Both aerobic & anaerobic
Fast twitch type llx muscle Fibers
Can contract repeatedly
Only anaerobic sources
Only aerobic sources
Both aerobic & anaerobic
Fast contraction speed
Produce most force
Fatigue quickly
Endurance activities
Speed, strength, power
Answer:
1. Endurance activities
Only aerobic source
2. Can contract repeatedly
Speed strength and power.
Both aerobic and anaerobic sources
3. Fast contraction speed
Only anaerobic sources
Produce most force
Fatigue quickly
Speed, strength and power
Explanation:
I hope this helps. Although, I'm about 80% sure of the answer.
Is this spring or winter?
3. Bart ran 5000 meters from the cops and an average speed of 10 meters/second before he got
caught. How long did he run?
Answer:
8 minutes and 20 seconds
Explanation:
5000/10 to get the number of seconds, which is 500, then you convert 500 seconds to minutes and you get 8 minutes and 20 seconds
A wave has a wavelength of 0.02m and period of 8.0*10^-2 seconds. calculate it's speed. (showing working)
Answer:
[tex]v = 0.25m/s[/tex]
Explanation:
Given
[tex]\lambda = 0.02m[/tex] --- Wavelength
[tex]T = 8.0 * 10^{-2}s[/tex] --- Period
Required
Determine the velocity of the wave
This is calculated using:
[tex]v = \frac{\lambda}{T}[/tex]
[tex]v = \frac{0.02m}{8.0*10^{-2}s}[/tex]
[tex]v = \frac{0.02m}{8.0*0.01s}[/tex]
[tex]v = \frac{0.02m}{0.08s}[/tex]
[tex]v = 0.25m/s[/tex]
Hence, the velocity is 0.25m/s
5. If an object has an acceleration of 0 m/s2, then one can be sure that the object is not ____.
a. moving
b. changing position
c. changing velocity
6. If car A passes car B, then car A must be ____.
a. accelerating.
b. accelerating at a greater rate than car B.
c. moving faster than car B and accelerating more than car B.
d. moving faster than car B, but not necessarily accelerating.
7. Which one of the following is NOT consistent with a car which is accelerating?
a. A car is moving with an increasing speed.
b. A car is moving with a decreasing speed.
c. A car is moving at a high speed.
d. A car is changing direction.
8. A fullback is running down the football field in a straight line. He starts at the 0-yard line at 0 seconds. At 1 second, he is on the 10-yard line; at 2 seconds, he is on the 20-yard line; at 3 seconds, he is on the 30-yard line; and at 4 seconds, he is on the 40-yard line. This is evidence that
a. he is accelerating
b. he is covering a greater distance in each consecutive second.
c. he is moving with a constant speed (on average).
Answer: c
Explanation: for #5 it can still be moving, just at a constant speed; therefore, it will be c.
If an object has an acceleration of 0 m/s2, then one can be sure that the object is not changing velocity.
If car A passes car B, then car A must be moving faster than car B, but not necessarily accelerating.
The not consistent with a car that is accelerating is a car is moving at a high speed.
A fullback is running down the football field in a straight line. He starts at the 0-yard line at 0 seconds. At 1 second, he is on the 10-yard line; at 2 seconds, he is on the 20-yard line; at 3 seconds, he is on the 30-yard line; and at 4 seconds, he is on the 40-yard line. This is evidence that he is moving with a constant speed (on average).
What is Acceleration?Acceleration is the rate of change of the velocity of an object with respect to time. Accelerations are vector quantities (in that they have magnitude and direction). Speed is the distance covered in a unit of time while acceleration is the rate of change in speed. The unit of speed in the metric system is meters per second (m/s) while that of acceleration is meters per second squared (m/s2). Speed is a scalar quantity while acceleration is a vector quantity.To learn more about acceleration and speed, refer to: https://brainly.com/question/25086037
#SPJ2
A crate moves DOWN an inclined plane below with a
diagram for the crate?
Answer:
The answer should be the one on the top in the picture.
Explanation:
Friction is opposing the downward movement of the crate therefore the friction force is pointing upwards. that is why the answer should be the one on the top of the picture.
A minibus drives with a constant speed of 32 km/h. How long will it take to travel a distance of 48 kilometers?
Distance covered = (speed) x (time)
Time = (Distance covered) / (speed)
Time = (48 km) / (32 km/hr)
Time = (48/32) hr
Time = 1.5 hrs (1 hour 30 minutes)
Which radio wave technologies would be unaffected by satellites that are not working properly?
space communication and television broadcasting television broadcasting and GPS O MRI and radio telescopes
O radio telescopes and space communication
Answer:
MRI and Radio telescopes
MRI and radio telescopes would be unaffected by satellites that are not working properly.
What is radio wave?The longest wavelengths in the electromagnetic spectrum are found in radio waves, which typically have frequencies of 300 gigahertz (GHz) and lower. The wavelength for 300 GHz is 1 mm, which is shorter than a grain of rice, while the wavelength for 30 Hz is 10,000 km (6,200 miles) (longer than the radius of the Earth).
Radio waves move at the speed of light in a vacuum, as do all electromagnetic waves, and at a nearly identical speed in the Earth's atmosphere.
Among the given options, space communication and television broadcasting television broadcasting and GPS and radio telescopes and space communication are affected by satellites that are not working properly because they are operated by satellite technology.
Hence, only MRI and radio telescopes would be unaffected by satellites that are not working properly.
Learn more about radio waves here:
https://brainly.com/question/16188419
#SPJ6
Please answer fast!!!
which of the following is an example of unbalanced force?
1. A chair leaning on a wall
2. A stroller being pushed
3. A ball on the grass
4. A book sitting on a table
Answer:1. A chair leaning on a wall
Explanation:
Draw the position vs. time graph for a person walking at a constant speed of 1m/s for 10 seconds. On the same axes, draw graph for a person running at a constant speed of 4m/s
Plot a graph, constant speed of movements represented as straight lines. Time on X axis (seconds) and position on Y axis (metres) , calculated by moving, e.g 4metres in a second.
A body is at equilibrium under the action of three forces. One force is 10N acting due east and one is 5N in the direction 60° north east. What is the magnitude and direction of the third force?
Answer:
If the body is in equilibrium the two forces add up and the third is the opposite of the resultant.
F(1x)=F(1)=10 N
F(2x)=F(2)cos60=5•0.5=2.5 N
F(2y) =F(2)sin60 = 5•0.866= 4.33 N
F(3x) =- F(x)=- (10+2.5 )= -12.5 N
F(3y) =- F(2y)= - 4.33 N
F(3) = sqrt{ F(3x)²+F(3y)²} =13.23 N
tan φ = F(3y)/F(3x) =4.33/12.5=0.364
φ = 19.1⁰ (south-west)
Explanation:
Kerry drops her iPhone accidently as she is standing on an overview. How fast is the iPhone moving after 3s?
Answer:
really fast? xP
Explanation:
a body is thrown at an angle 30°to the horizontal with kinetic energy 40J.atbthe highest point of its motion the kinetic energy will be?
A bullet of mass 50 g travelling with a speed of 15ms penetrates into a
bag of sand and is uniformly brought to rest in 0.05s.
Find
(a) How for the bullet will penetrate into the bag of sand?
(b) The Average force exerted by the sand ?
Answer:
a) The bullet will penetrate 0.375 meters into the bag of sand.
b) The average force exerted by the sand is 15 newtons.
Explanation:
The statement is incorrectly written. The correct form is presented below:
A bullet of mass 50 grams travelling with a speed of 15 meters per second penetrates into a bag of sand and is uniformly brought to rest in 0.05 second.
a) How far the bullet will penetrate into the bag of sand?
b) The average force exerted by the sand?
b) The average force exerted by the sand on the bullet ([tex]F[/tex]), measured in newtons, is determined by Principle of Linear Momentum Conservation and Impulse Theorem:
[tex]F = \frac{m\cdot (v_{f}-v_{o})}{\Delta t}[/tex] (1)
Where:
[tex]m[/tex] - Mass of the bullet, measured in kilograms.
[tex]v_{o}[/tex], [tex]v_{f}[/tex] - Initial and final speeds of the bullet, measured in meter per second.
[tex]\Delta t[/tex] - Impact time, measured in seconds.
If we know that [tex]m = 0.05\,kg[/tex], [tex]v_{o} = 15\,\frac{m}{s}[/tex], [tex]v_{f} = 0\,\frac{m}{s}[/tex] and [tex]\Delta t = 0.05\,s[/tex], then the average force exerted by the sand is:
[tex]F = \frac{(0.05\,kg)\cdot \left(0\,\frac{m}{s}-15\,\frac{m}{s} \right)}{0.05\,s}[/tex]
[tex]F = -15\,N[/tex]
The average force exerted by the sand is 15 newtons.
a) The distance travelled by the bullet ([tex]\Delta s[/tex]), measured in meters, is determined by application of Principle of Energy Conservation and Work-Energy Theorem:
[tex]\Delta s = \frac{m\cdot (v_{f}^{2}-v_{o}^{2})}{2\cdot F }[/tex] (2)
If we know that [tex]m = 0.05\,kg[/tex], [tex]v_{o} = 15\,\frac{m}{s}[/tex], [tex]v_{f} = 0\,\frac{m}{s}[/tex] and [tex]F = -15\,N[/tex], then the distance travelled by the bullet is:
[tex]\Delta s = \frac{(0.05\,kg)\cdot \left[\left(0\,\frac{m}{s} \right)^{2}-\left(15\,\frac{m}{s} \right)^{2}\right]}{2\cdot (-15\,N)}[/tex]
[tex]\Delta s = 0.375\,m[/tex]
The bullet will penetrate 0.375 meters into the bag of sand.
What is the intensity of the electric current in one coil, if the number of the coils is 10, length of the coil is 5m, and magnetic induction is 8T?
Answer:
I think the answer is D...
Explanation:
What will be the value of both charges if they are 5 cm apart and suffer a
attraction force of 5.2 N.
Answer:
[tex] \boxed{q = 1.2 \times {10}^{ - 6} C}[/tex]
Explanation:
[tex]f_e = \frac{{q}^{2}k }{ {r}^{2} } \\ q = \sqrt{ \frac{f_e( {r}^{2} )}{k} } = \sqrt{ \frac{5.2(5 \times {10}^{ - 2} )^{2} }{9 \times {10}^{9} } } \\ q =\sqrt{ \frac{5.2(5 \times {10}^{ - 2} )^{2} }{9 \times {10}^{9} } } = \sqrt{ \frac{0.013}{9 \times {10}^{9} } } \\ q = 1.2 \times {10}^{ - 6} [/tex]