Ben solved a fraction division problem using the rule “multiply by the reciprocal.” Look at his work.

StartFraction 7 Over 20 EndFraction divided by two-fifths. StartFraction 20 Over 7 EndFraction times two-fifths = StartFraction 40 Over 35 EndFraction = StartFraction 8 Over 7 EndFraction = 1 and StartFraction 1 Over 7 EndFraction

Did he solve the problem correctly?
Yes. He solved the problem correctly.
No. He multiplied the dividend by the divisor.
No. He multiplied the denominators instead of finding a common denominator.
No. He multiplied with the reciprocal of the dividend instead of with the reciprocal of the divisor.

Answer:

The slope is 0

Step-by-step explanation:

Answer:

The correct answer is D. 37.975.

Step-by-step explanation:

Answer:

[tex]95 \frac{3}{4} \: inch \leqslant x \leqslant 96 \frac{1}{4} \: inch[/tex]

Step-by-step explanation:

Given that a lumber supplier sells 96 inch Pieces of oak which must be within 1/4 of an inch.

This situation can be represented by the following absolute value inequality:

[tex]|x \: - 96| \: \leqslant \: \frac{1}{4} [/tex].

The absolute value can be thought of as the size of something because length cannot be negative. The length must be no more than 1/4 away from 96.

To simplify this, pretend this is a standard equality, |x-96| = 1/4. 1/4 is the range of acceptable length, 96 is the median of the range, and x is the size of the wood.

First apply the rule |x| = y → x = [tex]\pm[/tex]y

|x-96| = 1/4

x - 96 = [tex]\pm[/tex]1/4

x = [tex]96 \pm 1/4[/tex]

(These are just the minimum, and maximum sizes)

Now with a less than or equal to, the solutions are now everything included between these two values.

Therefore:

[tex]96 - 1/4 \: \leqslant x [/tex] [tex]\leqslant \: 96 + 1/4 [/tex]

With less than inequalities, you must have the lower value on the left, and the higher value on the right.

If x represents the size of the pieces, then the acceptable lengths are represented by this following inequality:

[tex]95 \frac{3}{4} \: inch \leqslant x \leqslant 96 \frac{1}{4} \: inch[/tex]

This is interpreted as x (being the size of the oak) is greater than or equal to 95 3/4, and less than or equal to 96 1/4 in inches.

Answer:

f(f(-4) = -2

Step-by-step explanation:

f(f(-4))

First find the value of f(-4)

f(-4) = 2

Now find f(2)

f(2) = -2

Answer:

Symbols= P(A^1)

Value: 2/5 , 4/25 , 3/5 , 16/25

Step-by-step explanation:

Answer:

172.72 centimeters

Step-by-step explanation:

1. 5 ft. = 60 in.

2. 60 in. + 8 in. = 68 in.

3. 68 x 2.54 = 172.72

4. add unit of measurement to your answer

Henry's height in centimeters is 172.72 cm

"A process of finding the value of a single unit, and based on this value we can find the required value. "

For given question,

Henry measured 5 feet 8 inches tall.

There are 2.54 centimeters in 1 inch.

that is, 1 inch = 2.54 cm

First we convert Henry's height in inches.

We know that 1 feet =  12 inches

⇒ 5 feet = 60 inches

so, Henry's height in inches would be,

5 feet 8 inches

= (60 + 8) inches

= 68 inches

From given, 1 inch = 2.54 cm

⇒ 68 inches = 172.72 cm

Therefore, Henry's height in centimeters is 172.72 cm

Learn more about the unitary method here:

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Answer:

False

Step-by-step explanation:

For the one on the left I got 234 and the one on the right I got 248

Answer:

The number of printers for type A = x = 80 printers

The number of printers for type B = y = 60 printers

Step-by-step explanation:

Let the number of printers for type A = x

Let the number of printers for type B = y

You can order no more than 140 printers this month

x + y ≤ 140

x + y = 140

x = 140 - y

Profit for type A = $25

Profit for type B = $11

You need to make at least $2660 profit

25x + 11y ≥ 2660

25x + 11y = 2660

Substitute 140 - y = x

25(140 - y ) + 11y = 2660

3500 - 25y + 11y = 2660

3500 - 2660 = 25y - 11y

840 = 14y

y = 840/14

y = 60 printers

x = 140 - y

x = 140 - 60

x = 80 printers

To minimize cost :

The number of printers for type A = x = 80 printers

The number of printers for type B = y = 60 printers

Answer:

The number of tickets sold at the gate is [tex] G = 211.25[/tex]

The number of tickets sold in advance is  [tex]  A = 311.25 [/tex]

Step-by-step explanation:

From the question we are told that

 The cost of a tickets at the gate is [tex]a =  \$ 5[/tex]  

  The cost of a ticket in advance is  [tex]b =  \$ 3[/tex]

Let the number of ticket sold in the gate be G

Let the number of ticket sold in advance  be   A

From the question we are told that

  One hundred more tickets were sold in advance than at the gate and this can be mathematically represented as

       [tex]G  +  100 =  A[/tex]

From the question we are told that

  The total revenue from ticket sales was $1990  and this can be mathematically represented as

    [tex]5 G  +  3A  =  1990[/tex]

substituting for  A in the equation above

    [tex]5 G  +  3[G  +  100]=  1990[/tex]    

    [tex]5 G  +  3G  +  300=  1990[/tex]    

    [tex] 8G  +  300=  1990[/tex]  

    [tex] 8G  =  1690[/tex]

=>  [tex] G = 211.25[/tex]

Substituting this for G in the above equation

     [tex]5 [211.25]  +  3A  =  1990[/tex]

=>    [tex]  3A  =  1990 - 1056.25[/tex]

=>    [tex]  A = 311.25 [/tex]

Answer:

3 : 1

Step-by-step explanation:

The biggest circle has a radius of 20 cm

So that means, its area will be,

Area = [tex]\pi r^{2}[/tex]

Area = [tex]\pi * 20^{2}[/tex]

A = [tex]\pi * 400[/tex]

=> A = 400[tex]\pi[/tex]

We do not need to solve this because it is nit required

Then, one small circle has an area of,

Area = [tex]\pi r^{2}[/tex]

Area = [tex]\pi *5^{2}[/tex]

Area = [tex]\pi *25[/tex]

=> Area = 25[tex]\pi[/tex]

As there are 4 circles in, we get that the area covered by the small squares,

=> [tex]25\pi * 4[/tex]

=> [tex]100\pi[/tex]

So, the amount shaded = 100/400 (We can omit the [tex]\pi[/tex] at this stage because we are finding out a ratio)

=> 1/4

So, there is 1 cut region and the remaining is the uncut region,

As we need to find uncut to cut, the ratio will be,

=> remaining : 1

=> 3 : 1

If my answer helped, kindly mark me as the brainliest!!

Thanks!!

Answer:

Step-by-step explanation:

Given the profit made by a company modeled by the function

p = -n² + 300n + 100,000

The company breaks even when p = 0

To get the number of boxes sold when the company breaks even, we will substitute p = 0 into the equation.

0 = -n² + 300n + 100,000

multiply through by -1

0 = n² - 300n - 100,000

n² - 300n - 100,000 = 0

(n² - 500n) + (200n - 100,000) = 0

n(n-500)+200(n-500) = 0

(n+200)(n-500) = 0

n+200 = 0 and n-500 = 0

n = -200 and n = 500

Since n cannot be negative

Hence n = 500

This means that the company breaks even when it sells 500 boxes

Slope: 1/2

y-intercept(s): (0, 7/3)

x: 0, 7

y: 7/3, 0

Step-by-step explanation:

y=-3 -1/3(1+2)=2/3.3=1.3=3

y=3

Answer:

A) The height of the trapezoid is 6.5 centimeters.

B) We used an algebraic approach to to solve the formula for [tex]b_{1}[/tex].  [tex]b_{1} = \frac{2\cdot A}{h}-b_{2}[/tex]

C) The length of the other base of the trapezoid is 20 centimeters.

D) We can find their lengths as both have the same length and number of variable is reduced to one, from [tex]b_{1}[/tex] and [tex]b_{2}[/tex] to [tex]b[/tex]. [tex]b = \frac{A}{h}[/tex]

Step-by-step explanation:

A) The formula for the area of a trapezoid is:

[tex]A = \frac{1}{2}\cdot h \cdot (b_{1}+b_{2})[/tex] (Eq. 1)

Where:

[tex]h[/tex] - Height of the trapezoid, measured in centimeters.

[tex]b_{1}[/tex], [tex]b_{2}[/tex] - Lengths fo the bases, measured in centimeters.

[tex]A[/tex] - Area of the trapezoid, measured in square centimeters.

We proceed to clear the height of the trapezoid:

1) [tex]A = \frac{1}{2} \cdot h \cdot (b_{1}+b_{2})[/tex] Given.

2) [tex]A = 2^{-1}\cdot h \cdot (b_{1}+b_{2})[/tex] Definition of division.

3) [tex]2\cdot A\cdot (b_{1}+b_{2})^{-1} = (2\cdot 2^{-1})\cdot h\cdot [(b_{1}+b_{2})\cdot (b_{1}+b_{2})^{-1}][/tex] Compatibility with multiplication/Commutative and associative properties.

4) [tex]h = \frac{2\cdot A}{b_{1}+b_{2}}[/tex] Existence of multiplicative inverse/Modulative property/Definition of division/Result

If we know that [tex]A = 91\,cm^{2}[/tex], [tex]b_{1} = 16\,cm[/tex] and [tex]b_{2} = 12\,cm[/tex], then height of the trapezoid is:

[tex]h = \frac{2\cdot (91\,cm^{2})}{16\,cm+12\,cm}[/tex]

[tex]h = 6.5\,cm[/tex]

The height of the trapezoid is 6.5 centimeters.

B) We should follow this procedure to solve the formula for [tex]b_{1}[/tex]:

1) [tex]A = \frac{1}{2} \cdot h \cdot (b_{1}+b_{2})[/tex] Given.

2) [tex]A = 2^{-1}\cdot h \cdot (b_{1}+b_{2})[/tex] Definition of division.

3) [tex]2\cdot A \cdot h^{-1} = (2\cdot 2^{-1})\cdot (h\cdot h^{-1})\cdot (b_{1}+b_{2})[/tex] Compatibility with multiplication/Commutative and associative properties.

4) [tex]2\cdot A \cdot h^{-1} = b_{1}+b_{2}[/tex] Existence of multiplicative inverse/Modulative property

5) [tex]\frac{2\cdot A}{h} +(-b_{2}) = [b_{2}+(-b_{2})] +b_{1}[/tex] Definition of division/Compatibility with addition/Commutative and associative properties

6) [tex]b_{1} = \frac{2\cdot A}{h}-b_{2}[/tex] Existence of additive inverse/Definition of subtraction/Modulative property/Result.

We used an algebraic approach to to solve the formula for [tex]b_{1}[/tex].

C) We can use the result found in B) to determine the length of the remaining base of the trapezoid: ([tex]A= 215\,cm^{2}[/tex], [tex]h = 8.6\,cm[/tex] and [tex]b_{2} = 30\,cm[/tex])

[tex]b_{1} = \frac{2\cdot (215\,cm^{2})}{8.6\,cm} - 30\,cm[/tex]

[tex]b_{1} = 20\,cm[/tex]

The length of the other base of the trapezoid is 20 centimeters.

D) Yes, we can find their lengths as both have the same length and number of variable is reduced to one, from [tex]b_{1}[/tex] and [tex]b_{2}[/tex] to [tex]b[/tex]. Now we present the procedure to clear [tex]b[/tex] below:

1) [tex]A = \frac{1}{2} \cdot h \cdot (b_{1}+b_{2})[/tex] Given.

2) [tex]b_{1} = b_{2}[/tex] Given.

3) [tex]A = \frac{1}{2}\cdot h \cdot (2\cdot b)[/tex] 2) in 1)

4) [tex]A = 2^{-1}\cdot h\cdot (2\cdot b)[/tex] Definition of division.

5) [tex]A\cdot h^{-1} = (2\cdot 2^{-1})\cdot (h\cdot h^{-1})\cdot b[/tex] Commutative and associative properties/Compatibility with multiplication.

6) [tex]b = A \cdot h^{-1}[/tex] Existence of multiplicative inverse/Modulative property.

7) [tex]b = \frac{A}{h}[/tex] Definition of division/Result.

Answer:

4/5

Step-by-step explanation:

Given:

A basketball player made 55 baskets in a season.

20% of these baskets were three-point shots.

To find:

The number of three-point shots.

Solution:

We have,

Total number of baskets = 55

Number of three-point shots = 20% of total baskets

Now,

[tex]\text{Number of three-point shots}=\dfrac{20}{100}\times 55[/tex]

[tex]\text{Number of three-point shots}=\dfrac{1}{5}\times 55[/tex]

[tex]\text{Number of three-point shots}=11[/tex]

Therefore, the number of three-point shots did made by the player is 11.

Answer:

10

Step-by-step explanation:

all red cars were sports cars (30) half of the blue cars were sports cars (20) if 30 is half of all the sports cars, and 20 is 2/3 of half, then the 1/3 left is 10.

Answer:

1/4 - 1/3i

Step-by-step explanation:

(4+3i)(-i) / 12i(-i)

= 3 - 4i / 12

Answer:

Step-by-step explanation:

The maximum profit will be found in the vertex of the parabola, which is what your equation is. You could do this by completing the square, but it is way easier to just solve for h and k using the following formulas:

[tex]h=\frac{-b}{2a}[/tex] for the x coordinate of the vertex, and

[tex]k=c-\frac{b^2}{4a}[/tex] for the y coordinate of the vertex.

x will be the selling price of each widget and y will be the profit. Usually, x is the number of the items sold, but I'm going off your info here for what the vertex means in the context of this problem.

Our variables for the quadratic are as follows:

a = -10

b = 600

c = -3588. Therefore,

[tex]h=\frac{-600}{2(-10)}=30[/tex] so the cost of each widget is $30. Now for the profit:

[tex]k=-3588-(\frac{(600)^2}{4(-10)})[/tex] This one is worth the simplification step by step:

[tex]k=-3588-(\frac{360000}{-40})[/tex] and

k = -3588 - (-9000) and

k = -3588 + 9000 so

k = 5412

That means that the profit made by selling the widgets at $30 apiece is $5412.

Hence,the profit made by selling the widgets at $[tex]30[/tex] apiece is $[tex]5412[/tex].

What is the maximum profit?

Maximum profit, or profit maximisation, is the process of finding the right price for your products or services to produce the best profit.

Here given that,

A company sells widgets. The amount of profit, [tex]y[/tex], made by the company, is related to the selling price of each widget, [tex]x[/tex], by the given equation.

As the maximum profit found in the vertex of the parabola,

Here, [tex]x[/tex] will be the selling price of each widget and [tex]y[/tex] will be the profit.

The number of items sold is [tex]x[/tex].

So, the quadratic equation is:-

[tex]a = -10b = 600c = -3588.[/tex]

Therefore, so the cost of each widget is $[tex]30[/tex].

For the profit:-

[tex]k = -3588 - (-9000) andk = -3588 + 9000 sok = 5412[/tex]

Hence,the profit made by selling the widgets at $[tex]30[/tex] apiece is $[tex]5412[/tex].

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Answer:

No -60 is not a solution

Step-by-step explanation:

x = 5/12 = 2.400

-60 is not a solution of 5/12, or 1/12*=5.

Hope I helped.

Answer:

99.7%

Step-by-step explanation:

Empirical rule formula states that:

• 68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ.

• 95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ.

• 99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ.

From the question, we have mean of 98.18 F and a standard deviation of 0.65 F

The approximate percentage of healthy adults with body temperatures between 96.23 F and100.13 ​F is

μ - 3σ

= 98.18 - 3(0.65)

= 98.18 - 1.95

= 96.23 F

μ + 3σ.

98.18 + 3(0.65)

= 98.18 + 1.95

= 100.13 F

Therefore, the approximate percentage of healthy adults with body temperatures between 96.23 F and 100.13 ​F which is within 3 standard deviations of the mean is 99.7%

Answer:

You're right!

Step-by-step explanation:

Answer:

Were you right?

Step-by-step explanation:

Answer:

no solution

Step-by-step explanation:

the x's cancel out, and if you plug in 0 for x, you get -8=6 (which isn't true)

Answer:

The answer is c. 5 5/8.

Step-by-step explanation:

Its c because your supposed to multiply them. When you multiply them you get 5 5/8. Hope this helped,have a great day!

Answer:

D.) 14.2*0.784

Step-by-step explanation:when you calculate it, there is 4 numbers behind the decimal point.

Answer:

-8z +724 + 5y +2c

Step-by-step explanation:

Combine like terms

Answer:

20°

Step-by-step explanation:

Step 1:

x + 40° = 3x       Vertical ∠'s

Step 2:

40° = 2x      Subtract x on both sides

Step 3:

x = 40° ÷ 2     Divide

Answer:

x = 20°

Hope This Helps :)

Answer:

a) 15.866%

b) Middle 95% = 350 ml to 750 ml

c) 0.3829

d) Middle 90% of men’s bladder fall = 385.5ml to 714.5 ml

Step-by-step explanation:

We solve using z score formula

z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

The distribution of bladder volume in men is approximately Normal with mean 550 ml and standard deviation 100 ml.

Required:

a. What percent of men have a bladder volume smaller than 450 ml?

z = 450 - 550/100

= -1

P-value from Z-Table:

P(x<450) = 0.15866

Convert to percentage

0.15866 × 100

= 15.866%

b. Between what volumes do the middle 95% of men’s bladders fall?

Middle 95% falls between 2 standard deviation of the mean

μ ± 2σ

μ - 2σ

550 - 2(100)

= 550 - 200

= 350 ml

μ + 2σ

= 550 + 2(100)

= 550 + 200

= 750 ml

Middle 95% = 350 ml to 750 ml

c. What proportion of male bladders are between 500 and 600 ml?

For 500ml

z = 500 - 550/100

= -0.5

Probability value from Z-Table:

P(x = 500) = 0.30854

For 600ml

z = 600 - 550/100

= 0.5

Probabilty value from Z-Table:

P(x = 600) = 0.69146

Proportion of male bladders are between 500 and 600 ml

P(x = 600) - P(x = 500)

0.69146 - 0.30854

= 0.38292

≈ 0.3829

d. What volumes do the middle 90% of men’s bladder fall?

The z score for middle 90% + / – 1.645

Hence,

1.645 = x - 550/100

1.645 × 100 = x - 550

164.5 + 550 = x

x = 714.5 ml

-1.645 = x - 550/100

-1.645 × 100 = x - 550

- 164.5 + 550 = x

x = 385.5ml

Middle 90% of men’s bladder fall = 385.5ml to 714.5 ml