Bats use sound to sense objects by sending out short ultrasound pulses and listening for the echo off the object. A. Sketch the ultrasound pulse leaving the bat, reflecting off the object and returning to the bat. B. If a stationary bat is 43 m from an object, how much time elapses between when the bat emits the pulse and it hears the echo

Answers

Answer 1

Answer:

B. t = 0.250s

Explanation:

A. An image with the sketch of the bat emitting a sound, which reflects on a surface and return to the bat is attached below.

B. In order to calculate the time that the pulse emitted by the bat, return to the bat, you first calculate the time that pulse takes to arrive to the object.

You use the following formula:

[tex]x=vt[/tex] (1)

x: distance to the object = 43m

t: time = ?

v: speed of sound beat = 343 m/s

You solve the equation (1) for t:

[tex]t=\frac{x}{v}=\frac{43m}{343m/s}=0.125s[/tex]

The time on which the bat hears the echo is twice the value of t, that is:

[tex]t'=2(0.125s)=0.250s[/tex]

The time on which bat heart the echo of its sound, from the moment on which bat emitted it, is 0.250s

Bats Use Sound To Sense Objects By Sending Out Short Ultrasound Pulses And Listening For The Echo Off

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How far does a roller coaster travel if it accelerates at 2.83 m/s2 from an initial
velocity of 3.19 m/s for 12.0 s?

Answers

Answer:

Explanation:

A body moves due north with velocity 40 m/s. A force is applied

on it and the body continues to move due north with velocity 35 m/s. W. .What is the direction of rate of change of momentum,if it takes

some time for that change and what is the direction of applied

external force?

Answers

Answer:

the direction of rate of change of the momentum is against the motion of the body, that is, downward.

The applied force is also against the direction of motion of the body, downward.

Explanation:

The change in the momentum of a body, if the mass of the body is constant, is given by the following formula:

[tex]\Delta p=\Delta (mv)\\\\\Delta p=m\Delta v[/tex]

p: momentum

m: mass

[tex]\Delta v[/tex]: change in the velocity

The sign of the change in the velocity determines the direction of rate of change. Then you have:

[tex]\Delta v=v_2-v_1[/tex]

v2: final velocity = 35m/s

v1: initial velocity = 40m/s

[tex]\Delta v =35m/s-40m/s=-5m/s[/tex]

Hence, the direction of rate of change of the momentum is against the motion of the body, that is, downward.

The applied force is also against the direction of motion of the body, downward.

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