Physics High School

Ball A is projected vertically upwards at a velocity of 16m.s-¹ fron the ground. ignore the effects of air friction. use the ground as zero reference. a) calculate the time taken by ball A to return to the ground. b) draw a velocity time graph for ball A​

Answers

Answer 1

Answer: 3.26 s

Explanation:

Given

The ball is projected upward with a velocity  [tex]u=16\ m/s[/tex]

Using the equation of motion

[tex]s=ut+\frac{1}{2}at^2[/tex]

Here, displacement is zero as the ball returns to its initial position

[tex]\Rightarrow 0=16\times t-0.5\times g\times t^2\\\Rightarrow t(16-0.5\times 9.8\times t)=0\\\text{i.e.}\ t=\dfrac{16}{4.9}=3.26\ s[/tex]

the velocity of the ball at any instant is given by

[tex]v=u+at\\v=16-9.8t[/tex]

Ball A Is Projected Vertically Upwards At A Velocity Of 16m.s- Fron The Ground. Ignore The Effects Of

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Answers

Answer:

Peach and Apple will take the same time as the gravitional pull acting on both of them is equal.

height of peach=initial velocity*time+1/2*gravitional pull*(time^2)

1.8=0*time+1/2*9.8*time^2

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Explanation:

The time it takes the peach to reach the ground is 0.61 sec

From the question,

We are to determine how long it would take the peach to reach the ground.

From one of the equations of kinematics for free falling objects,

We have that

[tex]H = ut + \frac{1}{2}gt^{2}[/tex]

Where

H is the height

u is the initial velocity,

t is the time

and g is the acceleration due to gravity ( g = 9.8 m/s²)

Since the object is dropped with no velocity, then the initial velocity is 0 m/s

From the given information

H = 1.8 m

u = 0 m/s

Putting the parameters into the formula,

We get

[tex]1.8 = 0(t) + \frac{1}{2}(9.8)t^{2}[/tex]

This becomes

[tex]1.8 = 0 + 4.9t^{2}[/tex]

[tex]1.8 = 4.9t^{2}[/tex]

Then,

[tex]t^{2} = \frac{1.8}{4.9}[/tex]

[tex]t^{2} = 0.367347[/tex]

∴ [tex]t =\sqrt{0.367347}[/tex]

t = 0.60609 sec

t ≅ 0.61 sec

Hence, the time it takes the peach to reach the ground is 0.61 sec

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