Answer:
CaCO3 -> CaO + CO2
Explanation:
Woahhhh, did you balance it yourself just then?
where do you think water vapor in air comes from?
Which of the following is an advantage of asexual reproduction compared to sexual reproduction?
Both will produce genetically identical offspring from the parent.
Sexual reproduction will increase genetic variability within a species.
Asexual reproduction requires less energy and will produce more offspring over time.
Sexual reproduction has minimal changes of mutations compared to asexual reproduction.
Explanation:
sexual reproduction has minimal changes of mutations compared to asexual reproduction
Answer:
sexual reproduction has minimal changes of mutations compared to asexual reproduction
I hope this helps
Using your freshly made 5M stock aqueous solution of NaCl and your 10% aqueous stock of SDS, you find a prepackaged bottle of 1M Tris-Hcl (aqueous solution) along with a 95% solution of liquid NP-40 in a bottle. Using these stock reagents calculate the amount needed for the following final concentrations for each reagent as well as the final volume of water needed to obtain:
Total Final volume of 500 mL
Final Concentrations:
150 mM NaCl
50 mM Tris-HCl
1% NP-40 .
1% SDS
Answer:
1. Volume of stock required = 15 mL
Volume of water required = 485 mL
2. Volume of stock required = 5 mL
Volume of water required = 495 mL
3. Volume of stock required = 5.30 mL
Volume of water required = 494.70 mL
4. Volume of stock required = 50 mL
Volume of water required = 450 mL
Explanation:
Using the dilution formula C₁V₁ = C₂V₂
Where C₁ = initial concentration; C₂ = final concentration; V₁ = initial volume; V₂ = final volume
1. C₁ = 5 M NaCl, C₂ = 150 mM NaCl = 0.15 M NaCl
V₁ = ?; V₂ = 500 mL
V₁ = C₂V₂/C₁
V₁ = 0.15 × 500/ 5 = 15 mL
Volume of stock required = 15 mL
Volume of water required = 500 mL - 15 mL
Volume of water required = 485 mL
2. C₁ = 1 M Tris-HCl, C₂ = 50 mM Tris-HCl = 0.05 M Tris-HCl
V₁ = ?; V₂ = 500 mL
V₁ = C₂V₂/C₁
V₁ = 0.05 × 500/ 5 = 5 mL
Volume of stock required = 5 mL
Volume of water required = 500 mL - 5 mL
Volume of water required = 495 mL
3. C₁ = 95% NP-40, C₂ = 1% NP-40
V₁ = ?; V₂ = 500 mL
V₁ = C₂V₂/C₁
V₁ = 1 × 500/ 95 = 5.30 mL
Volume of stock required = 5.30 mL
Volume of water required = 500 mL - 5.30 mL
Volume of water required = 494.70 mL
4. C₁ = 1% SDS, C₂ = 10% SDS
V₁ = ?; V₂ = 500 mL
V₁ = C₂V₂/C₁
V₁ = 1 × 500/ 10 = 50 mL
Volume of stock required = 50 mL
Volume of water required = 500 mL - 50 mL
Volume of water required = 450 mL
The shadow of a groundhog ( or anything else ) is determined what?
The size, length, and height of the figure are the main factors which determine the shadow of a organism.
The size, length, and height of the figure are the main factors which determine the shadow of a organism.
What is a shadow?A shadow is a dark area where light from a light source is blocked by an opaque object. It occupies all of the three-dimensional volume behind an object with light in front of it. The cross section of a shadow is a two-dimensional silhouette, or a reverse projection of the object blocking the light.
A point source of light casts only a simple shadow, called an "umbra". For a non-point or "extended" source of light, the shadow is divided into the umbra, penumbra, and antumbra. The wider the light source, the more blurred the shadow becomes. If two penumbras overlap, the shadows appear to attract and merge. This is known as the shadow blister effect.
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100.0 g of water was placed in a simple, constant-pressure calorimeter. The temperature of the water was recorded as 295.0 K. A 20.0 g copper block was heated to 353.0 K and then dropped into the water in the calorimeter. What was the final temperature of the water if the specific heat capacities of copper is 0.385 J/g K
Answer:
[tex]296.05\ \text{K}[/tex]
Explanation:
[tex]m_w[/tex] = Mass of water = 100 g
[tex]c_w[/tex] = Specific heat of water = [tex]4.184\ \text{J/g K}[/tex]
[tex]m_c[/tex] = Mass of copper = 20 g
[tex]c_c[/tex] = Specific heat of copper = [tex]0.385\ \text{J/g K}[/tex]
[tex]\Delta T_w[/tex] = Temperature change in water = [tex](T-295)[/tex]
[tex]\Delta T_c[/tex] = Temperature change in cooper = [tex](353-T)[/tex]
T = Final temperature of the system
The heat balance of the system is given by
[tex]m_wc_w\Delta T_w=m_cc_c\Delta T_c\\\Rightarrow 100\times 4.184\times (T-295)=20\times 0.385\times (353-T)\\\Rightarrow 418400\left(T-295\right)=7700\left(353-T\right)\\\Rightarrow 418400T-123428000=2718100-7700T\\\Rightarrow T=\frac{1261461}{4261}\\\Rightarrow T=296.05\ \text{K}[/tex]
The final temperature of the water is [tex]296.05\ \text{K}[/tex].
The final temperature of the water when placed in a calorimeter is 296.05K
HOW TO CALCULATE FINAL TEMPERATURE:
The final temperature of water placed in a calorimeter can be calculated using the following expression:Q(water) = - Q(copper)(m × c × ∆T) water = - {m × c × ∆T} copperWhere;
Mass of water = 100 gSpecific heat of water = 4.184 J/g KMass of copper = 20 gSpecific heat of copper = 0.385 J/g KTemperature change in water = T - 295KTemperature change in copper = T - 353K100 × 4.184 × (T - 295) = - {20 × 0.385 × (T - 353)}418.4T - 123428 = - (7.7T - 2718.1)418.4T - 123428 = -7.7T + 2718.1418.4T + 7.7T = 123428 + 2718.1426.1T = 126146.1T = 126146.1 ÷ 426.1T = 296.05KTherefore, the final temperature of the water when placed in a calorimeter is 296.05K.Learn more at: https://brainly.com/question/10987564?referrer=searchResults
Seeds, flowers, and fruits work together to help a flowering plant reproduce.
Each of these structures is made up of different kinds of tissues specialized
to perform a specific function. What level of body organization does this
group (plants, seeds, and flowers) represent?
A. Organ
B. Cell
C. Cell system
D. Body system. not B
Answer:
I think the body system
Explanation:
Answer:body system
Explanation:
A student thermally decomposed a 0.150 gram sample of impure potassium chlorate. Manganese dioxide was used as a catalyst in the reaction. The student collected 43.60 mL of oxygen gas over water in a eudiometer. Potassium chloride was the other product of the reaction. The temperature and pressure at collection time were 20.00 oC and 762.10 mm Hg respectively. The water level in the eudiometer was 4.22 cm below the outside water level in the beaker.
1) What is the corrected pressure of the dry oxygen gas?
2) What is the volume in mL, of the dry oxygen gas at STP conditions?
3) How many molecules of oxygen were collected?
4) what is the percent purity of the original potassium chlorate sample?
Answer:
1. Vapor pressure of dry oxygen gas = 747.68 torr
2. Volume at STP = 39.97 mL
3. Number of oxygen gas molecules = 1.074 × 10²¹ molecules
4. Percent purity of KClO3 = 97.3 %
Explanation:
The balanced equation for the reaction is given below :
2 KClO3 (s) ------> 2 KCl (s) + 3 O2 (g)
1) Since the water level in the eudiometer was below the outside water level in the beaker,
Vapor pressure of dry oxygen gas = Total pressure + pressure due to difference in water levels - vapor pressure of water
Vapor pressure of water at 20 °C is 17.535 mm (torr).
Pressure due to difference in water level = 4.22 cm × 10mm/cm / 13.534 (13.534 is the density of mercury) = 3.118 mm (torr).
Vapor pressure of dry oxygen gas = 762.10 torr + 3.118 torr - 17.535 torr
Vapor pressure of dry oxygen gas = 747.68 torr
2) P₁ = 747.68 torr; V₁ = 43.60 ml; T1 = 20 °C + 273.15 = 293.15 K
P₂ = 760 torr; T₂ = 273.15 K; V₂ = ?
Using the general gas equation = P₁V₁/T₁ = P₂V₂/T₂
V2₂= P₁V₁T₂ / P₂T₁
V₂ = (747.68 × 43.60 × 273.15 ) / (760 × 293.15)
V₂ = 39.97 ml
Volume of dry oxygen gas at STP = 39.97 mL
3) Volume of oxygen gas at STP 39.97 mL = 0.03997 L
Number of moles of oxygen gas in 0.03997 L = volume of gas at STP /molarvolume at STP
Number of moles of oxygen gas = 0.03997/22.4 L
Number of molecules of oxygen gas = 0.03997/22.4 L × 6.03 × 10²³ molecules
Number of oxygen gas molecules = 1.074 × 10²¹ molecules
e) Number of moles of oxygen gas = 0.03997/22.4 = 0.001784 moles
From the equation, mole ratio of oxygen gas and potassium chlorate is 3 : 2
Moles KClO3 = 2/3 × 0.001784 moles = 0.001189 moles
Molar mass of KClO3 = 39 + 35.5 + 3 × 16 = 122.5 g
Actual mass of KClO3 decomposed = 122.5 grams × 0.001189 mole = 0.146 grams
Percent purity = (actual mass KClO3 decomposed / sample mass of impure KClO3) × 100%
Percent purity = (0.146/0.150) × 100% = 97.3 %
What is the compound of c4?
Answer:
c4 is an explosive..
contains RDX, DOS, DOA, and PIB.
Explanation:
A group of elements with similar properties, which usually falls into columns on the periodic table. A.period b.ductile c.atomis d.family
The size of the orbital is determined by the
The size of the orbital is determined by the blank quantum number, so the size of the orbital blank as this value increases. Therefore, an electron in a blank orbital is closer to the nucleus than is an electron in a blank orbital.
quantum number, so the size of the orbital
The size of the orbital is determined by the blank quantum number, so the size of the orbital blank as this value increases. Therefore, an electron in a blank orbital is closer to the nucleus than is an electron in a blank orbital.
as this value increases. Therefore, an electron in a
The size of the orbital is determined by the blank quantum number, so the size of the orbital blank as this value increases. Therefore, an electron in a blank orbital is closer to the nucleus than is an electron in a blank orbital.
orbital is closer to the nucleus than is an electron in a
The size of the orbital is determined by the blank quantum number, so the size of the orbital blank as this value increases. Therefore, an electron in a blank orbital is closer to the nucleus than is an electron in a blank orbital.
orbital.
orbital.
Answer: The size of the orbital is determined by the principal quantum number, so the size of the orbital increases as this value increases. Therefore, an electron in a (n-1) orbital is closer to the nucleus than is an electron in a 'n' orbital.
Explanation:
In an atom, the position and energy of an electron is described by a set of numbers and these sets are called quantum numbers.
There are four quantum numbers. These are as follows.
1). Principal quantum number - This is denoted by "n" and it determines the size and energy of shell in which electron is present. The value of "n" can be 1, 2, 3, and so on but it can never be equal to zero.
2). Azimuthal quantum number - This is denoted by "l" and it determines the shape of an orbital. For s, p, d and f-shell the values of "n" will be 0, 1, 2, 3. The value of l can vary from -n to +n.
3). Magnetic quantum number - This is denoted by "[tex]m_{l}[/tex]." and it determines the orientation of an orbital. The value of ml can vary from -l to +l.
4). Spin quantum number -- This is denoted by "[tex]m_{s}[/tex]" and it determines the spin of an electron. It is independent of the values of n, l and [tex]m_{l}[/tex].
This means that the size of an orbital is determined by principal quantum number. Lower is the value of 'n' (principal quantum number) more closer will be an electron to the nucleus. Hence, more is the value of 'n' more will be the size of nucleus and vice-versa.
For example, an electron present in a 2s-orbital is closer to the nucleus as compared to the electron present in a 3s-orbital.
Thus, we can conclude that the size of the orbital is determined by the principal quantum number, so the size of the orbital increases as this value increases. Therefore, an electron in a (n-1) orbital is closer to the nucleus than is an electron in a 'n' orbital.
What will change more solid NiCl2 is added
un MODELO ATÓMICO es:
a. Una esfera con partículas positivas y negativas
b. La estructura mínima de la materia.
c. Una serie de descubrimientos.
d. La representación de un átomo donde se explica su comportamiento y características.
Answer:
Creo que es D pero no tan segura
Explanation:
what is scienceand technogy
Answer:
Science and technology is an interdisciplinary topic encompassing science, technology, and their interactions: Science is a systematic enterprise that builds and organizes knowledge in the form of explanations and predictions about nature and the universe.
Explanation:
If 1.00 g of KCl is completely dissolved in 24.5 g of water, what is the percent composition (by mass) of the solution that is formed?
Answer:
3.92%
Explanation:
The solution that is formed is of KCl in water. This means that the percent composition by mass is given by the formula:
Mass of KCl / Mass of Solution * 100%We now calculate the mass of solution:
Mass of Solution = Mass of KCl + Mass of Water = 1.00 g + 24.5 gMass of Solution = 25.5 gFinally we calculate the percent composition:
1.00 g / 25.5 g * 100% = 3.92%Your friend says that the animal in this picture is a predator. What are 2 questions you can ask your friend to help prove that this animal is a predator.
please help please please please please please please please please please please please please please please please please please please please.
NO LINKS PLEASE PLEASE .
Answer: Does the animal prey on other animals? Is the animal a carnivore?
How many molecules are in 3.7 g H2O
Explanation:
Find out number of molecules first. To find out number of molecules, first we need to know the number of moles present. The number of moles can be obtained by dividing the weight by molecular mass. The Molecular mass of water is 18. Now, by multiplying the moles with the Avogadro number we can find out the number of molecules. Avogadro number is 6×(10 to the power 23). Hence the final result is 3.7/18 ×6 × ( 10 to the power 23).
Hope this helps, if not I'm very sorry.
If 7.4 moles of carbon dioxide is produced in this reaction, how many moles of oxygen gas would be needed?
1 C7H16 + 11 O2 = 7 CO2 + 8 H2O
Answer:
11.6 mol O₂
Explanation:
C₇H₁₆ + 11 O₂ → 7 CO₂ + 8 H₂OIn order to solve this problem we need to convert moles of carbon dioxide (CO₂) into moles of oxygen gas (O₂). To do so we'll use a conversion factor containing the stoichiometric coefficients of the balanced reaction:
7.4 mol CO₂ * [tex]\frac{11molO_2}{7molCO_2}[/tex] = 11.6 mol O₂Are sperm and egg cells exact copies of the plant cell
Answer:
No
Explanation:
thats scientifically impossible
How many liters would you need to make a 0.8 M solution with 20 grams of lithium chloride?
Answer:
0.5875L
Explanation:
concentration = mole/ volume
n(LiCl) = 20 / (7 + 35.5) = 0.47 mol
volume = mole / conc.
volume = 0.47 /0.8
= 0.5875 dm³ = 0.5875L
Will give brainliest
In an experiment, the molar mass of the compound was determined to be 228.276 g/mol. What is the molecular formula of the compound?
List 2 ways that the increase in human population has had a negative impact on
the environment.
I
5.0 g of copper was heated from 20°C to 80°C. How much energy was used to heat Cu?
Answer:
100 J of energy are needed to heat the copper from 20∘C to 80∘C .
Calculate the final concentration of each of the following:
2.0 L of a 6.0 M HCl solution is added to water so that the final volume is 6.0 L
--
Water is added to 0.50 L of a 12 M NaOH solution to make a 3.0 L of a diluted NaOH solution
Answer:
1. 2 M
2. 2 M
Explanation:
1. Determination of the final concentration.
Initial Volume (V₁) = 2 L
Initial concentration (C₁) = 6 M
Final volume (V₂) = 6 L
Final concentration (C₂) =?
The final concentration can be obtained as follow:
C₁V₁ = C₂V₂
6 × 2 = C₂ × 6
12 = C₂ × 6
Divide both side by 6
C₂ = 12 / 6
C₂ = 2 M
Therefore, the final concentration of the solution is 2 M
2. Determination of the final concentration.
Initial Volume (V₁) = 0.5 L
Initial concentration (C₁) = 12 M
Final volume (V₂) = 3 L
Final concentration (C₂) =?
The final concentration can be obtained as follow:
C₁V₁ = C₂V₂
12 × 0.5 = C₂ × 3
6 = C₂ × 3
Divide both side by 3
C₂ = 6 / 3
C₂ = 2 M
Therefore, the final concentration of the solution is 2 M
The _________ law of Newton’s Laws of Motion helps us add intensity to any activity.
A.
third
B.
first
C.
second
D.
second and third
Answer: A
The third law is the law of Newton’s Law of motion.
What is true of an earthquake that causes major damage to buildings in an area?
It has a high magnitude.
It has a high frequency.
It has a low frequency.
It has a low magnitude.
The correct option is :
=》It has a high magnitude.
the damage caused by an earthquake is proportional to its magnitude, as much the magnitude is, that much damage will be caused by it.
The term used to indicate and earthquake that causes major damage to buildings in an area is called a high magnitude earthquake. Hence, option a is correct.
What is high magnitude earthquake?The most typical way to gauge an earthquake's size is by its magnitude. No matter where you are or how violent the shaking is, it is the same number since it represents the size of the earthquake's source.
The USGS no longer uses the outmoded Richter scale to determine the magnitude of major, teleseismic earthquakes. Several magnitude scales measure various aspects of the earthquake, but the Richter scale measures the biggest wobble (amplitude) on the recording.
Currently, the USGS uses the Moment Magnitude scale to report earthquake magnitudes, however many different magnitudes can be calculated for comparison and research. Therefore, option a is correct.
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3. Determine the moles of sodium, Na, containing 7.9x1024 atoms.
Answer:
12.7mol Na.
Explanation:
Hello there!
In this case, according to the concept of mole, which stands for the amount of substance, we can recall the concept of Avogadro's number whereby we understand that one mole of any substance contains 6.022x10²³ particles, for the given atoms of sodium, we can calculate the moles as shown below:
[tex]7.9x10^{23}atoms*\frac{1mol}{6.022x10^{23}atoms} \\\\[/tex]
Thus, by performing the division we obtain:
[tex]12.7molNa[/tex]
Regards!
A 3mL sample of a 200 Molar solution is left open on a lab
counter for two weeks, after which the concentration of the solution is 6 M. What is the new volume of the solution?
Answer: New volume of the solution is 100 mL.
Explanation:
Given: [tex]V_{1}[/tex] = 3 mL, [tex]M_{1}[/tex] = 200 M
[tex]M_{2}[/tex] = 6 M, [tex]V_2[/tex] = ?
Formula used to calculate the new volume of solution is as follows.
[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]
Substitute the values into above formula as follows.
[tex]M_{1}V_{1} = M_{2}V_{2}\\200 M \times 3 mL = 6 M \times V_{2}\\V_{2} = \frac{200 M \times 3 mL}{6 M}\\= 100 mL[/tex]
Thus, we can conclude that new volume of the solution is 100 mL.
The absorption of infrared (IR) radiation results in vibrations in the molecules or ions that make up a chemical sample. Vibrations cause bond lengths or angles to expand and contract. The energy of infrared radiation (i.e., frequency) required for a vibration depends on the type of bond and the mass of the atoms involved. Typically, the higher the bond order, the stronger the bond, and therefore, the more energy (i.e., higher frequency) required to make the bond vibrate. Also, lighter atoms vibrate at higher frequencies than heavier atoms. The order of vibrational frequencies (from largest to smallest) of the given carbon-nitrogen and carbon-sulfur bonds is
Answer:
the order of vibrational frequency is:
C ≡ N > C=N > C=S > S-C
Explanation:
The bond's vibration frequency is determined using the following equation:
[tex]\zeta = \dfrac{1}{2 \pi c}\sqrt{\dfrac{k}{\mu}}[/tex]
where;
reduced mass[tex]\mu = \dfrac{m_1m_2}{m_1+m_2}[/tex]
velcoity of light = c
force constant = k
The frequency of vibration, on the other hand, is inversely proportional to the atom's mass, because the heavier the atom, the lower the frequency.
In addition, the value of a bond's stretching frequency rises as the bond's intensity rises. As a result, the frequency is as follows:
triple > double > single
The reduced mass [tex](\mu)[/tex] of C-N bond.
[tex]\mu = \dfrac{m_1m_2}{m_1+m_2}[/tex]
[tex]\mu = \dfrac{12*14}{12+14} \\ \\ \mu = 6.46[/tex]
The reduced mass of C-S bond;
[tex]\mu = \dfrac{m_1m_2}{m_1+m_2}[/tex]
[tex]\mu = \dfrac{12\times 32}{12+32} \\ \\ \mu = 8.72[/tex]
Thus, the order of vibrational frequency is:
C ≡ N > C=N > C=S > S-C
How can a cation be formed?
Add 1 clectron
Take away 1 clectron
Add 1 proton
Take away 1 prekon
What type of climate conditions are needed to form coal deposits.
Answer:
Subbituminous coal can form at temperatures as low as 35 to 80 °C (95 to 176 °F) while anthracite requires a temperature of at least 180 to 245 °C (356 to 473 °F).
Sub-types: Cannel coal
Child material class: Lignite
Explanation: