ayo who is wiining the election now?

Answer:

47.8

Step-by-step explanation:

What you want to do first is 5 1/5 - 5/12 which is 4.78,

then 1/6 x 2/3, which is 0.1,

then you do 4.78 divided by 0.1, which is 47.8

Answer:

BC = 1.7

Step-by-step explanation:

Since, cosine of any angle (except right angle) represents the ratio of base length and hypotenuse.

Cosθ = [tex]\frac{\text{Base}}{\text{Hypotenuse}}[/tex]

From the given right triangle ΔACB,

[tex]\text{Cos}(\angle B) = \frac{\text{Base}}{\text{Hypotenuse}}[/tex]

              [tex]=\frac{BC}{AB}[/tex]

Cos(70°) [tex]=\frac{BC}{5}[/tex]

BC = 5Cos(70°)

     = 1.71

     ≈ 1.7

Answer:

Step-by-step explanation:

(3m+2n)/(m-n2)+(5m+n)/(n-m2)-(2m-3n)/(m2-n)

Final result :

-3m3 - 2m2n + 7m2 - 7mn2 + mn + 2n3 + 2n2

—————————————————————————————————————————

(m - n2) • (n - m2)

Step by step solution :

Step 1 :

2m - 3n

Simplify ———————

m2 - n

Trying to factor as a Difference of Squares :

1.1 Factoring: m2 - n

Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

Proof : (A+B) • (A-B) =

A2 - AB + BA - B2 =

A2 - AB + AB - B2 =

A2 - B2

Note : AB = BA is the commutative property of multiplication.

Note : - AB + AB equals zero and is therefore eliminated from the expression.

Check : m2 is the square of m1

Check : n1 is not a square !!

Ruling : Binomial can not be factored as the difference of two perfect squares

Equation at the end of step 1 :

(3m+2n) (5m+n) (2m-3n)

(————————+————————)-———————

(m-(n2)) (n-(m2)) m2-n

Step 2 :

5m + n

Simplify ——————

n - m2

Trying to factor as a Difference of Squares :

2.1 Factoring: n - m2

Check : n1 is not a square !!

Ruling : Binomial can not be factored as the difference of two perfect squares

Equation at the end of step 2 :

(3m+2n) (5m+n) (2m-3n)

(————————+——————)-———————

(m-(n2)) n-m2 m2-n

Step 3 :

3m + 2n

Simplify ———————

m - n2

Trying to factor as a Difference of Squares :

3.1 Factoring: m - n2

Check : m1 is not a square !!

Ruling : Binomial can not be factored as the difference of two perfect squares

Equation at the end of step 3 :

(3m + 2n) (5m + n) (2m - 3n)

(————————— + ————————) - —————————

m - n2 n - m2 m2 - n

Step 4 :

Calculating the Least Common Multiple :

4.1 Find the Least Common Multiple

The left denominator is : m-n2

The right denominator is : n-m2

Number of times each Algebraic Factor

appears in the factorization of:

Algebraic

Factor Left

Denominator Right

Denominator L.C.M = Max

{Left,Right}

m-n2 1 0 1

n-m2 0 1 1

Least Common Multiple:

(m-n2) • (n-m2)

Calculating Multipliers :

4.2 Calculate multipliers for the two fractions

Denote the Least Common Multiple by L.C.M

Denote the Left Multiplier by Left_M

Denote the Right Multiplier by Right_M

Denote the Left Deniminator by L_Deno

Denote the Right Multiplier by R_Deno

Left_M = L.C.M / L_Deno = n-m2

Right_M = L.C.M / R_Deno = m-n2

Answer:

of what numbers

Step-by-step explanation:

Answer:

The answer is b

Step-by-step explanation:

The reason it is b is because i just did the question and it was right

Answer:

lol you cant

Step-by-step explanation:

Answer:

[tex] DE = 7.3 [/tex]

[tex] EF = 10.3 [/tex]

[tex] FD = 7.3 [/tex]

∆DEF is an isosceles ∆

Step-by-step explanation:

To find the 3 side lengths of ∆DEF, use the distance formula, which is given as [tex] d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex].

Distance between D(-2, 3) and E(5, 5):

[tex] DE = \sqrt{(5 -(-2))^2 + (5 - 3)^2} [/tex]

[tex] DE = \sqrt{(7)^2 + (2)^2} [/tex]

[tex] DE = \sqrt{49 + 4} [/tex]

[tex] DE = \sqrt{53} [/tex]

[tex] DE = 7.3 [/tex] (nearest tenth)

Distance between E(5, 5) and F(-4, 10):

[tex] EF = \sqrt{(-4 - 5)^2 + (10 - 5)^2} [/tex]

[tex] EF = \sqrt{(-9)^2 + (5)^2} [/tex]

[tex] EF = \sqrt{81 + 25} [/tex]

[tex] EF = \sqrt{106} [/tex]

[tex] EF = 10.3 [/tex] (nearest tenth)

Distance between F(-4, 10) and D(-2, 3):

[tex] FD = \sqrt{(-2 -(-4))^2 + (3 - 10)^2} [/tex]

[tex] FD = \sqrt{(2)^2 + (-7)^2} [/tex]

[tex] FD = \sqrt{4 + 49} [/tex]

[tex] FD = \sqrt{53} [/tex]

[tex] FD = 7.3 [/tex] (nearest tenth)

∆DEF has two equal sides, DE and FD. Therefore, ∆DEF can be classified as an isosceles triangle.

Answer:

Step-by-step explanation: The graph is vertically stretched by a scale factor of 0.5 and shifted up 3 units.

Here we need to explain what the two transformations applied to f(x) do, and then we also can see it graphically.

we can see that we have a vertical stretch of scale factor k = 0.5 followed by a vertical shift of 3 units upwards.

Now let's explain how we know that.

The two transformations applied are:

Vertical stretch:

For a given function f(x) we write a vertical stretch of scale factor as:

g(x) = k*f(x).

Which stretches or contracts the graph vertically, depending on the value of k.

Vertical shift.

For a function f(x) a vertical shift of N units is written as:

g(x) = f(x) + N

So here we have:

g(x) = 0.5*f(x) + 3

Comparing with the general transformations, we can see that we have a vertical stretch of scale factor k = 0.5 followed by a vertical shift of 3 units upwards.

The two functions are:

f(x) = |x|

g(x) = 0.5*|x| + 3

The graphs can be seen below, where the blue one is the graph of g(x), the transformed function.

If you want to learn more, you can read:

https://brainly.com/question/24401156

dy/dx=2x/3y^2

Differient each term with respect to x, then solve for y.

Answer:

Not 100 percent but im pretty sure it is 3(n+5)=-30 i found other sites saying its that its up to you if you wanna believe me

Step-by-step explanation:

Answer:

The average number of customers per night increased by 5 each month.

Step-by-step explanation:

hope this helps! :)

Answer: 0.0238

Step-by-step explanation:

Given : Proportion of politicians are lawyers: p= 0.56

Sample size : n= 787

Let [tex]\hat{p}[/tex] be th sample proportion.

The the probability that the proportion of politicians who are lawyers will differ from the total politicians proportion by greater than 4% will be :-

[tex]P(|\hat{p}-0.56|>0.04)=P(-0.04>\hat{p}-0.56>0.04)=\\\\ P(-0.04+0.56>\hat{p}>0.04+0.56)\\\\=P(0.52>\hat{p}>0.60)\\\\=P(\dfrac{0.52-0.56}{\sqrt{\dfrac{0.56(1-0.56)}{787}}}>\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}>\dfrac{0.60-0.56}{\sqrt{\dfrac{0.56(1-0.56)}{787}}})\\\\=P(-2.26>z>2.26)\ \ \ [Z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}]\\\\=1-P(-2.26<z<2.26)\\\\=1-(2P(Z > 2.26)-1)\ \ \ [P(-z<Z<z)=2P(Z > |z|)-1]\\\ =2-2P(Z > 2.26)\\\\=2-2(0.9881)=0.0238[/tex]

Hence, the required probability = 0.0238

The Answer Is most likely 191% but the proper percent is 95.5%

Answer:

ThousandsHundredsTensOnes7270

Step-by-step explanation:

Answer:

The answer is 109 degrees.

Step-by-step explanation:

Any triangle's angles add up to 180 in total, so we can create the equation 64+45+__=180. Using some simple algebra we can change this equation into the equation 180-109=71. This solves the inner triangle, and the outside angle, x is supplementary (meaning it adds up to 180) to 71. 180-71 = 109.

Glad I could help!

Answer:

im pretty sure its 6

Step-by-step explanation:

Answer:9(4x-6) is not equivalent to 36x-48.

Step-by-step explanation:

9 x 4x= 36x

9 x -6 = -54

Answer:

The Availability of tablets A,B and C are equal

Step-by-step explanation:

Computation for Which tablet has better Availability

Using this formula

Availability of Tablet=MTBF/ ( MTBF + MTTR)

Where,

MTBF represent Mean Time Between Failures

MTTR represent Mean Time To Repair

Let plug in the formula

Availability of Tablet A = 10,000hrs/(10,000hrs + 10hrs)

Availability of Tablet A= 0.999

Availability of tablet B = 11,000hrs/( 11,000hrs + 11hrs )

Availability of Tablet B= 0.999

Availability of Tablet C = 12,000hrs/ ( 12,000hrs + 12hrs)

Availability of Tablet C= 0.999

Based on the above calculation the Availability of all the 3 tablets are equal

Therefore the Availability of tablets A,B and C are equal.

Answer:50

Step-by-step explanation:

Answer: 50

Step-by-step explanation: according to pemdas you do exponets first so 5 over 2=5*5=25 then multiply by 2=25*2=50

Answer:

y= -0.6x + 4.4

Step-by-step explanation:

Answer:

$1435.50 is your answer

Step-by-step explanation:

$2610 - 45% = 1435.50

Answer:

y  =  -5x -24

Step-by-step explanation:

 Given parameters:

    Coordinates of the line = (5, - 4)

   Linear function ;

                            2x - 10y = 0

Solution:

The equation of the line perpendicular to this line will have a slope that is the a negative inverse of the given line;

                          2x - 10y = 0

Equation of a line is given as;

                          y  = mx + c

y and x are the coordinates

  m is the slope

  c is the y-intercept

We find the slope and y-intercept of the new line;

                      From:  2x - 10y = 0

 Rewrite;

                        -10y = -2x

                              y  = [tex]\frac{-2}{-10}[/tex]x

                              y = [tex]\frac{1}{5}[/tex]x

The slope of this line is  [tex]\frac{1}{5}[/tex] , the line perpendicular will have slope of -5

For the new line;

                   y  = mx + c

 let us find c;

                    -4  = -5( -4)  + c

                   -4  = 20 + c

                    c  = -20 - 4

                     c = -24

The equation of the perpendicular line is;

            y  =  -5x -24

Explanation:

Drawing out a diagram usually helps with these types of problem. See the diagram below.

We have angle 3 and angle 4 as corresponding angles (since they are both in the north east corner of each four-corner configuration). Angle 1 = angle 3 is one pair of vertical angles and angle 2 = angle 4 is another pair of vertical angles. We see that angles 1 and 2 are corresponding angles in the south west corners of each four-corner configuration. That's why the original statement is always true.

Answer:

y=1/3 x2

Step-by-step explanation:

Answer:

3.2

Step-by-step explanation:

Answer:

I believe it's 3.2!

Answer:

It's -4 -4i

Step-by-step explanation:

Because it is

A

-4-4i

For the person that commented. the 5 is an exponent.

Answer:

Following are the code to this questiuon:

def fiv(y):#defining a method fiv that hold a parameter  

  x = str(y) #defining a variable x that convert the value y in string  

  return three(x[0:3]) and three(x[1:4]) and three(x[2:5])#use return keyword to call the method three  

def three(x): #defining a method three that hold x variable as a parameter

   y = int(x) #use y to convert x in integer

   return y>=100 and (y%17==0 or y%23==0) #use return that gives a value which is divisiable by 17 or 23  

print([y for y in range(10000,40000) if fiv(y)])#use print method to print value

Output:

Please find the attached file.

Step-by-step explanation:

In the above code, two methods "fiv and three" is declared that accepts one variable as a parameter, which can be defined as follows: