Ava is going to the county fair. The cost of admission is $5.50 and it is $1.50 for each ride. If Ava has $19.00, Write and solve an equation to determine how many rides Ava can ride.

Answer:

128°

Step-by-step explanation:

180-52=128

Answer:

38

Step-by-step explanation:

V = 4/3 (pie) r(cube)

V = 4/3 (3.14) 3(cube)

V = 4/3 (3.14) (9)

V = 4/3 (28.26)

V = 37.68

V = 38 (Rounded up)

Answer:

Sophie has 12 feet more

Step-by-step explanation:

Answer:

y=-5x+176

Step-by-step explanation:

Write an algebraic equation showing that the two points equal each other and then evaluate it.

Answer:

Step-by-step explanation:

[tex]\tan22=h_1/200,\ \tan29=h_2/200

h_2+h_1=200(\tan29+\tan22)

H\approx 191.667ft

H\approx 191’ 8”

Answer:

≈3.464

Step-by-step explanation:

1. the required 'x' belongs to the hypotenuse of the given triangle. It means, the formula of its length is:

x=4*cos30°=4*sin60°, note sin60°=cos30°=√3/2≈0.866.

2. according to the formula above the required length 'x' is:

x=4*0.866=3.464 (or 2√3)

Answer:

If your polynomial is x^2+x-30, then your answer is (−5)(+6)

Answer:

20/45

6/45

Step-by-step explanation:

A bag contains 1 green, 4 red, and 5 yellow balls. Two balls are selected at random. Find P( 1 red and 1 yellow) and P(2 red).

--------------------

# of red/yellow pairs: 4*5 = 20

# of random pairs: 10C2 = 45

P(1red & 1yellow) = 20/45

# of red pairs: 4C2 = 6

# of random pairs = 45

P(2 red) = 6/45

Answer:

A  , B, and C

Step-by-step explanation:

i just did it

Answer:

187

Step-by-step explanation:

10*4=40

40+147=187

Answer:

251

Step-by-step explanation:

x=4

104 +147=251

Answer:

problem

confusion

Step-by-step explanation:

hope it helps

Answer

problem and confusion

Step-by-step explanation:

I took the test and this is the correct answer

tell me if it is wrong :)

Step-by-step explanation:

5x - 5° = 40° ( being vertically opposite angles)

5x = 40° + 5°

5x = 45°

x = 45°/ 5

x = 9°

Now

< 1 = 5 * 9° - 5 = 45° - 5° = 40°

Hope it will help :)

185.193 Cm, 5.7x5.7x5.7 is the volume

The volume of the Rubik's cube is 183.51 cubic centimeters.

To find the volume of a Rubik's cube, we can use the formula V = s ³, where V represents the volume and s represents the length of each edge.

In this case, the length of each edge is given as 5.7 centimeters.

Substituting this value into the formula, we have:

V = (5.7 cm) ³

Calculating the volume:

V = 5.7 cm * 5.7 cm * 5.7 cm

V = 32.49 * 5.7

V = 183.51 cm ³

Therefore, the volume of the Rubik's cube is 183.51 cubic centimeters.

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Answer: -628

Step-by-step explanation:

F(140) = 212 - 6(140)

F(140) = 212 - 840

F(140) = -628

Answer:

1.52%

Step-by-step explanation:

Answer:

3n-4= 44

3n=40

no u can solve

Answer:

17°

Step-by-step explanation:

3n - 5° + 90° + 44° = 180° { being linear pair }

3n + 129° = 180°

3n = 180° - 129°

3n = 51°

n = 51° / 3

n = 17°

Hope it will help :)

Answer:

D= 110,400

Step-by-step explanation:

$48,000 is what she made last month and needs to make 230% more which you can think as a decimal of 2.30

so then you do 48,000*2.30= $110,400

The value of the expression is 17.

An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.

Example: 2 + 3x + 4y = 7 is an expression.

We have,

r + 4

When r = 13

r + 4

= 13 + 4

= 17

Thus,

The value is 17.

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Answer:

No

Step-by-step explanation:

A package has 6 cookies for $2.49

Ms. Morgan has 19 students. She wants to give each student 2 cookies, which means each package is enough for 3 students.

19 students × 2 cookies = 38 cookies is what you need

7 packages times $2.49 = $17.43

7 packages × 6 cookies = 42 cookies

42 cookies ÷ 19 students = 2.21 cookies for each student

Answer:

[tex]f(x) = \frac{6}{x^2} -8[/tex] or [tex]f(x) = -\frac{6}{x^2} + 4[/tex]

Step-by-step explanation:

Given

[tex](x,y) = (1,-2)[/tex] --- Point

[tex]\int\limits^6_2 {(1 + 144x^{-6})} \, dx[/tex]

The arc length of a function on interval [a,b]:  [tex]\int\limits^b_a {(1 + f'(x^2))} \, dx[/tex]

By comparison:

[tex]f'(x)^2 = 144x^{-6}[/tex]

[tex]f'(x)^2 = \frac{144}{x^6}[/tex]

Take square root of both sides

[tex]f'(x) =\± \sqrt{\frac{144}{x^6}}[/tex]

[tex]f'(x) = \±\frac{12}{x^3}[/tex]

Split:

[tex]f'(x) = \frac{12}{x^3}[/tex] or [tex]f'(x) = -\frac{12}{x^3}[/tex]

To solve fo f(x), we make use of:

[tex]f(x) = \int {f'(x) } \, dx[/tex]

For: [tex]f'(x) = \frac{12}{x^3}[/tex]

[tex]f(x) = \int {\frac{12}{x^3} } \, dx[/tex]

Integrate:

[tex]f(x) = \frac{12}{2x^2} + c[/tex]

[tex]f(x) = \frac{6}{x^2} + c[/tex]

We understand that it passes through [tex](x,y) = (1,-2)[/tex].

So, we have:

[tex]-2 = \frac{6}{1^2} + c[/tex]

[tex]-2 = \frac{6}{1} + c[/tex]

[tex]-2 = 6 + c[/tex]

Make c the subject

[tex]c = -2-6[/tex]

[tex]c = -8[/tex]

[tex]f(x) = \frac{6}{x^2} + c[/tex] becomes

[tex]f(x) = \frac{6}{x^2} -8[/tex]

For: [tex]f'(x) = -\frac{12}{x^3}[/tex]

[tex]f(x) = \int {-\frac{12}{x^3} } \, dx[/tex]

Integrate:

[tex]f(x) = -\frac{12}{2x^2} + c[/tex]

[tex]f(x) = -\frac{6}{x^2} + c[/tex]

We understand that it passes through [tex](x,y) = (1,-2)[/tex].

So, we have:

[tex]-2 = -\frac{6}{1^2} + c[/tex]

[tex]-2 = -\frac{6}{1} + c[/tex]

[tex]-2 = -6 + c[/tex]

Make c the subject

[tex]c = -2+6[/tex]

[tex]c = 4[/tex]

[tex]f(x) = -\frac{6}{x^2} + c[/tex] becomes

[tex]f(x) = -\frac{6}{x^2} + 4[/tex]

You can use the formula for finding the arc length on specified interval on x axis.
The curves whose arc length on the given interval is described are

[tex]f(x) = 6x^{-2} -8[/tex]

and

[tex]f(x) = -6x^{-2} + 4[/tex]

If the function is differentiable in the given interval, then we have:

[tex]s = \int_a^b\sqrt{(1 + (f'(x))^2)}\:dx[/tex]

where s denotes the length of the arc of the given function from x = a to x = b

Using the above formula, as we're already given the arc length, thus,

[tex]\int_a^b\sqrt{(1 + (f'(x))^2)}\:dx = \int_2^6\sqrt{(1 +144x^{-6})}\:dx[/tex]

This gives us

[tex]f'(x) = \pm \sqrt{144x^{-6}} = \pm 12x^{-3}[/tex]

Integrating both sides with respect to x, we get:

[tex]f(x) = \pm \int 12x^{-3}\\\\f(x) = \pm 6x^{-2} + c[/tex]

where c is constant of integration.

Since the curve passes through (1,-2), thus, putting f(x) = -2, x = 1, we get:

[tex]f(x) = \pm 6x^{-2} + c\\-2 = \pm 6 + c\\c = -2 \mp 6 = -8, or ,4[/tex]

c = -8 when we have [tex]f(x) = 6x^{-2} + c[/tex]

c = + 4 when we have [tex]f(x) = -6x^{-2} + c[/tex]

The curves whose arc length on the given interval is described are

[tex]f(x) = 6x^{-2} -8[/tex]

and

[tex]f(x) = -6x^{-2} + 4[/tex]

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Step-by-step explanation:

Using Pythagoras theorem

x=✓(35²-21²)=✓784=28 units

Answer:

16/3

Step-by-step explanation:

Answer: A (1:2)

Step-by-step explanation:

Since there are 12 puppies total and 8 of the puppies are yellow labs, there must be 12 - 8 = 4 black labs. Now, the ratio of black labs to yellow labs is 4:8 because there are 4 black labs and 8 yellow labs. However, we can simplify this ratio by dividing the entire ratio by 4. In this case, we would get (4/4):(8/4), which simplifies to 1:2, which is the answer.

Answer:

I love alegbra anyways

The ans is in the picture with the steps how i got it

(Hope it helps can i plz have brainlist :D hehe)

Step-by-step explanation:

Hello!

[tex]\large\boxed{\frac{2\pi}{3} \text{ and } \frac{4\pi}{3}}[/tex]

2cosФ + 1 = 0

Begin by isolating for cosФ. Subtract both sides by -1:

2cosФ = -1

Divide both sides by 2:

cosФ = -1/2

Using the unit circle, we know that from [0, 2π), values that have a cosine of -1/2 are 2π/3 and 4π/3.

Therefore, the solutions of this equation are:

Ф = 2π/3 and 4π/3

Answer:

4, ∛64, -∛64

explanation:

they all mean the same thing

The expression [tex]y^{3} = 64[/tex] can be written as :[tex]y= \sqrt[3]{64}[/tex] or y= 4

The correct option is (II) and (VI)

The cube root of a number is the factor that we multiply by itself three times to get that number.

We have given that:

[tex]y^{3} = 64[/tex]

 we can write it as:

[tex]y= \sqrt[3]{64}[/tex]

y = [tex]\sqrt{4*4*4}[/tex]

y= 4

The answer is : [tex]y^{3} = 64[/tex]

[tex]y= \sqrt[3]{64}[/tex] or y= 4

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