Answer:
h = 46.87 m
Explanation:
Given that,
Mass of an object, m = 16 kg
Gravitational potential energy of the object, E = 7500 J
We need to find the height of the object. The formula for the gravitational potential energy is given by :
[tex]E=mgh\\\\h=\dfrac{E}{mg}\\\\h=\dfrac{7500}{16\times 10}\\\\h=46.87\ m[/tex]
So, the required height is equal to 46.87 m.
When jumping straight down, you can be seriously injured if you land stiff-legged. One way to avoid injury is to bend your knees upon landing to reduce the force of the impact. A 63.5-kg man just before contact with the ground has a speed of 7.89 m/s. (a) In a stiff-legged landing he comes to a halt in 3.99 ms. Find the magnitude of the average net force that acts on him during this time. (b) When he bends his knees, he comes to a halt in 0.205 s. Find the magnitude of the average net force now. (c) During the landing, the force of the ground on the man points upward, while the force due to gravity points downward. The average net force acting on the man includes both of these forces. Taking into account the directions of the forces, find the magnitude of the force applied by the ground on the man in part (b).
Answer:
a) F = 1.26 10⁵ N, b) F = 2.44 10³ N, c) F_net = 1.82 10³ N directed vertically upwards
Explanation:
For this exercise we must use the relationship between momentum and momentum
I = Δp
F t = p_f -p₀
a) It asks to find the force
as the man stops the final velocity is zero
F = 0 - p₀ / t
the speed is directed downwards which is why it is negative, therefore the result is positive
F = m v₀ / t
F = 63.5 7.89 / 3.99 10⁻³
F = 1.26 10⁵ N
b) in this case flex the knees giving a time of t = 0.205 s
F = 63.5 7.89 / 0.205
F = 2.44 10³ N
c) The net force is
F_net = Sum F
F_net = F - W
F_net = F - mg
let's calculate
F_net = 2.44 10³ - 63.5 9.8
F_net = 1.82 10³ N
since it is positive it is directed vertically upwards
An ideal gas undergoes an adiabatic expansion, a process in which no heat flows into or out of the gas. As a result, (a) the temperature of the gas remains constant and the pressure decreases. (b) both the temperature and pressure of the gas decrease. (c) the temperature of the gas decreases and the pressure increases. (d) both the temperature and volume of the gas increase. (e) both the temperature and pressure of the gas increase. Group of answer choices a b c d e
Answer:
(b) both the temperature and pressure of the gas decrease.
Explanation:
An ideal gas undergoes an adiabatic expansion, a process in which no heat flows into or out of the gas. As a result, both the temperature and pressure of the gas decrease.
Gay Lussac states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas.
Mathematically, Gay Lussac's law is given by;
[tex] PT = K[/tex]
Also, according to the first law of thermodynamics which states that energy cannot be created or destroyed but can only be transformed from one form to another. Thus, the ideal gas does work on the environment with respect to the volume and temperature.
A concave lens cannot produce a real image.
A. True
B. False
Answer:
B. False
A concave mirror and a converging lens will only produce a real image if the object is located beyond the focal point.
~Hoped this helped~
~Brainiliest?~
HELP PLEASE DUE IN 3 MINUTES
Answer:
1. slides and scrapes
2. pulls away
3. crashes into each other
Explanation:
Answer:
transform
convergent
divergent
Explanation:
Converge means to come together
Diverge means to move away
Help me, 100 points to answer right, answer without context will be reported
1. In the situation below, a tractor pulls a 850 sledge along a ramp of height ℎ = 1 and large = 30 °. If the tractor applies a constant force to the sledge = 6750 , at an angle = 36.9 °, determine the total work performed by all forces on the sledge to move it along the ramp. The coefficient of kinetic friction between the sledge and the plane is = 0.3. Tip: for the calculation, remember that only the components of the windows that are parallel to the direction of travel contribute to the work. Disregard the dimensions of the sled.
2) When firing a 2 projectile at a 1.4 bloco block, initially at rest, it is observed that the projectile is stuck in the block and the system moves together for a distance = 0.1 before stop. If the coefficient of kinetic friction between the block and the surface is = 0.25, determine what was the velocity of the projectile in the instant before impact. Tip: here you must use the conservation of linear momentum and also energy, considering the work done by the frictional force
Why do people make this to the seashore?
Answer:
Protecting the Seashore
Seashore Conservation Code
When investigating a seashore it is important to remember that the welfare of the plants and animals must come first. If seaweeds are attached to rocks do not try to pull them off, just examine them where they are growing. Handle animals with great care, returning them to the place where they were found. Anemones and limpets are normally firmly stuck to rocks and any attempt to remove them may result in their death. Replace any large stones that are removed – animals that live on the underside soon die if left exposed.
Pollution Problems
Seas and seashores are under continual threat from pollution. Here are some examples:-
oil rigOil spills, either accidental or deliberate, have a devastating effect on marine life, especially seabirds. Black tar-like oil washed up on a rocky shore would obviously completely destroy the entire community of living things. Chemicals used to disperse oil spills on a shore may effectively clean up the oil, but they can also cleanse the shore of life! The best policy for marine life is to physically remove as much oil as possible and leave the rest to degrade naturally. A rocky shore will recover much more quickly if chemicals are not used.
Sewage and litter also upsets seashore ecosystem, making them unsightly and perhaps contaminated. Some litter can be dangerous to wildlife.
Toxic chemicals and radioactive waste - a cocktail of toxic chemicals have found their way into the sea over the years, affecting both marine and human life. For many years potentially deadly radioactive waste from nuclear power stations and other sources was disposed of in the sea, and beaches have been contaminated by accidental leakages from nuclear power stations.
Explanation:
Answer:
Hey mate....
Explanation:
This is ur answer....
REASONS:-
Soothing salt water. The minerals and salt in the ocean water soothe aching joints.
Exfoliate with sand. Sand acts as a natural exfoliator.
Workout in the waves.
Vital vitamin D.
Clear the mental clutter.
Technology detox.
Enjoying company.
Hope it helps!
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A geosynchronous Earth satellite is one that has an orbital period of precisely 1 day and has a radius of 42.2 km of its orbit about the Earth. For certain application, it is desirable to have a satellite that orbits the Earth with a period of precisely 2days. What should be the radius of such a (every-two-days) satellite
Answer:
66.98 km
Explanation:
Given :
Initial time period, [tex]$T_1$[/tex] = 1 day
Radius of initial orbit, [tex]$r_1$[/tex] = 42.2 km
Final Time period, [tex]$T_2$[/tex] = 2 days
We know that,
The time period of satellite is
[tex]$T= 2 \pi \sqrt{\frac{r^3}{GM}}$[/tex]
So, for [tex]$T_2=2\pi \sqrt{\frac{r_2^3}{GM}}$[/tex] ...........(i)
For [tex]$T_1=2\pi \sqrt{\frac{r_1^3}{GM}}$[/tex] ...................(ii)
Therefore, dividing equation (i) by (ii), we get
[tex]$\frac{T_2}{T_1}=\sqrt{\frac{r_2^3}{r_1^3}}$[/tex]
[tex]$\left(\frac{2}{1}\right)^2=\frac{r_2^3}{(42.2)^3}$[/tex]
[tex]$r_2 = 66.98 \ km$[/tex]
Therefore, the radius is 66.98 km.
which two options describes behaviors of particles that are related to the chemical properties of the materials
a- forming hydrogen bonds between them
b- reacting quickly with water
c- having a high mass
d- forming bonds with other atoms
Answer:
The two correct answers are B.) reacting quickly with water, and D.) forming bonds with other atoms.
Explanation:
I took the quiz on a.pex and these were correct.
pls help
How much work is done when a bucket of mass 2kg with 20kg
of water in it is pulled up from the bottom of a well 10m deep?
Answer:
2156 J
Explanation:
From the question,
Work done = Combined mass of the bucket and water×height×gravity.
W = (M+m)hg............................. Equation 1
Where M = mass of water, m = mass of the bucket, h = height, g = acceleration due to gravity.
Given: M = 20 kg, m = 2 kg, h = 10 m
Constant: g = 9.8 m/s²
Substitute these value into equation 1
W = (20+2)×10×9.8
W = 22×98
W = 2156 J
A sound wave was determined to have a frequency of 0.3 Hz, speed of 150 cm/s, and amplitude of 2 cm. Find its wavelength.
Answer:
5 m
Explanation:
From the question,
v = λf....................... Equation 1
Where v = speed of the sound wave, λ = wavelength of the sound wave, f = frequency of the sound wave.
make λ the subject of the equation
λ = v/f..................... Equation 2
Given: v = 150 cm/s = 1.5 m/s, f = 0.3 hz.
Substitute these values into equation 2
λ = 1.5/0.3
λ = 5 m.
If you wrap 150 coils of heavy wire around a big iron nail and attach the ends of the wire to a 6.0v battery, you have a A) radio B) electromagnet C) galvanometer D) ammeter
Answer:
B
Explanation:
Because of the voltage attached to the iron nail
P.E
1. Tukuyin ang mga galaw sa kahon kung ito ay pag-galaw sa low level, middle level o high
level. Isulat ang iyong sagot sa teybol sa ibaba.
pag-upo
paglakad
pagtakbo
pagdapa sa sahig
pagtalon
Answer:
pagtalon?
Explanation:
because that had to be the answer
Snell's law describes the relationship between the angle a light ray makes as it leaves a surface, the angle it makes incident on the surface, and the indices of refraction on both sides of the surface. If light incident in air at angle of 30 degrees from the normal onto glass with an index of refraction of 1.5 --Pick those answers that applya) Inside the material, the light leaving the surface is closer to the surface, makes a bigger angle with the normal, than the entering light makes in air.b) The light inside the glass is closer to the normal, makes a bigger angle with the surface, than the incident lightc) There is light reflected back into the air from the surfaced) The angle is too steep for light to refract and it is all reflected.
Answer:
b) and c)
Explanation:
Snell's law states that there exists a fixed relationship between the sine of the angle that makes with the normal an incident ray on the separation surface of two transparent media, the sine of the angle that is refracted off the surface, and the indexes of refraction of both media, as follows:[tex]\frac{sin_{\theta i}}{sin_{\theta r} } =\frac{n_{2} }{n_{1} } (1)[/tex]
Givens: θi = 30º n₁ = 1 (air) n₂= 1.5 (glass)Since sin 30º = 0.5, we can solve for sin r, as follows:[tex]sin \theta r = \frac{sin_{\theta i}}{n_{2}} = \frac{0.5}{1.5} = 0.333 (2)[/tex]As the sin r is lower than sin i, this implies that the angle that makes with the normal is lower than i, which means that it makes a bigger angle with the surface, as stated by b).Also there is some light that is reflected by the surface, making an angle with the normal equal to the incident ray, as stated by c). So, b) and c) are the right choices.A horse pulls a sled 100 meters. The horse applies 200 newtons of force. How many joules of work did the horse do?
Please hurry and help
Explanation:
work done = force × distance
= 200N × 100m
= 20000J
= 20KJ
A sports car accelerates at a constant rate from rest to a speed of 90 km/hr in 8 s. What is its acceleration?
3.13 m/s2
4.22 m/s2
5.31 m/s2
6.67 m/s2
none of the above
One thing that animals have not demonstrated the ability to do with language (that humans can) is use language to describe itself. This use is called
a. reflexiveness.
b. specialization.
C. prevarication.
d. duality of patterning sounds, which is used to produce an infinite number of unique utterances.
Answer:
The answer is letter B hope it helps
2. An electron and a proton are separated by 5 cm:
a) what is the magnitude of the force on the electron?
b) What is the net force on the system?
Answer:
a) the charge of an electron is equivalent to the magnitude of the elementary charge but barring a negative sign since the side of the elementary charge is roughly 1.602 * 10 - 19 Columbus then the charge of the electronic is-1.602 * 10 - 19
b) b=2T on the electron moving in the magnetic field
Describe an example of an assignment that could be used in science, technology, engineering, or mathematics that would allow a student to apply a concept he has learned.
Answer:
A notebook because they can take notes of what they have learned
Explanation:
One day, Peter put a leaf in hot water. After a while, he noted that a lot of air bubbles appeared on the lower surface of the leaf, but only a few air bubbles were found on the upper surface. Where did the air bubbles come from (name the part)?
Answer:
The air bubbles are oxygen coming out of the leaf
Explanation:
Though the leaf is in hot water, it is still using light to continue on the path of photosynthesis. Now, this path of photosynthesis involves letting oxygen out of the leaf. Thus, this oxygen is the one that we see as bubbles coming out of the water.
The reason for having more air bubbles at the lower surface than at the upper surface is because the leaf cells at the lower surface of the leaf possess faster photosynthetic rate in releasing
oxygen.
Un basquetbolista efectúa lo siguientes desplazamientos 6 metros al este 4 metros en dirección noroeste y finalmente 2 metros norte°Cual es la distancia total que recorre?
°Encuentra en forma gráfica el desplazamiento resultante en que dirección actúa y cual es el valor del angulo medido respecto al este
Answer:
R = 10.06 m, θ = 28.7º
Explanation:
o find the total displacement the best way is to find the displacement in the x (East) and y (North) axes
let's decompose the displacements
d₂ = 4 m
θ₂ = 45
let's use trigonometry
cos 45 = x₂ / d₂
sin 45 = y₂ / d₂
x₂ = d₂ cos 45
y₂ = d₂ sin 45
x₂ = 4 cos 45 = 2,828 m
y₂ = 4 sin 45 = 2,828 m
The shredding the x axis is
x_total = x₁ + x₂
x_total = 6 + 2,828
x_total = 8,828 m
The displacement in the y-axis
y_total = y₂ + y₃
y_total = 2,828 + 2
y_total = 4.828 m
Let's use Pythagoras' theorem for total displacement
R = [tex]\sqrt{x_{total}^2 + y_{total}^2 }[/tex]
R = [tex]\sqrt{8.828^2 + 4.828^2 }[/tex]
R = 10.06 m
for the direction let's use trigonometry
tan θ = [tex]\frac{x_{total} }{y_{total} }[/tex]
θ = tan⁻¹ \frac{x_{total} }{y_{total} }
θ = tan⁻¹ [tex]\frac{ 4.828}{ 8.828}[/tex]
θ = 28.7º
this angle is measured counterclockwise from the positive side of the x axis (Eat)
A car travels at a constant speed of 25 m/s. Find the power supplied by the engine if it can supply a maximum force of 18,000 N
Answer:
720
Explanation:
If a car is traveling 103 miles per hour and passes another vehicle which is at a complete stop, how many miles would it take the stopped vehicle to catch the traveling vehicle?
Answer:
206 mph i think
Explanation:
Which measures the amount of work you did?
I don’t get it
Answer:
Power is often measured in joules of work per second. The unit of measurement for power is the (W). One watt is equal to one joule of work done in one second. If an object does a large amount of work, its power is usually measured in units of 1000 watts, or kilowatts.
Explanation:
WILL REWARD 20 more pts once solved
4) If you have a diverging lens with a focal length of -15 cm and it produces an image that is 9
cm from the lens, what is the height of the image if the object was 4,5 cm tall?
b) Draw a ray tracing diagram of the situation below (label all points in cm) :
Explanation:
step 1. a diverging lens is "concave" on both side and always has a negative focal length
step 2. so 1/f = 1/s + 1/s' where f is the focal length, s is the object location, and s' is the image location (f, s, s' are all on the left side of the lens)
step 3. 1/-15 = 1/s + 1/-9 (image is virtual (negative))
step 4. 3/-45 = 1/s + 5/-45
step 5. s = 22.5cm (object is 22.5cm from lens)
step 6. s'/s = 9/22.5 ÷ 0.4 (magnification)
step 7. if the object is 4.5cm then the image is 4.5(0.4) = 1.8cm tall.
Describe a perfect day
Answer:
A bright and sunny day not worrying about work or school no family drama just a day you can relax and be yourself surrounded by the people you love.
hope this helps
have a good day :)
Explanation:
Answer:I'll describe a perfect day as a bright sunny day without rain,having no chores or homework to do.Going outside and enjoying the sun,have a glass of lemonade.No drama and no school,nothing to worry about.Going to the pool and going for a nice swim or a lake.Going fishing,playing basketball,watching television,or visiting a relative you haven't have much time to spend with.Going for a walk in the park,hanging out with some friends.Or just staying in the house doing nothing.
Explanation:
30. Easy Guided Online Tutorial One object is at rest, and another is moving. The two collide in a one-dimensional, completely inelastic collision. In other words, they stick together after the collision and move off with a common velocity. Momentum is conserved. The speed of the object that is moving initially is 25 m/s. The masses of the two objects are 3.0 and 8.0 kg. Determine the final speed of the two-object system after the collision for the case when the large-mass object is the one moving initially and the case when the small-mass object is the one moving initially.
Answer:
[tex]18.18\ \text{m/s}[/tex]
[tex]6.82\ \text{m/s}[/tex]
Explanation:
[tex]m_1[/tex] = Mass of large object = 8 kg
[tex]m_2[/tex] = Mass of smaller object = 3 kg
When large mass is moving
[tex]u_1[/tex] = 25 m/s
[tex]u_2[/tex] = 0
For completely inelastic collision we have the relation
[tex]m_1u_1+m_2u_2=(m_1+m_2)v\\\Rightarrow v=\dfrac{m_1u_1+m_2u_2}{m_1+m_2}\\\Rightarrow v=\dfrac{8\times 25+3\times 0}{8+3}\\\Rightarrow v=18.18\ \text{m/s}[/tex]
Speed of the combined mass when the larger object is moving is [tex]18.18\ \text{m/s}[/tex]
When smaller mass is moving
[tex]u_1[/tex] = 0
[tex]u_2[/tex] = 25 m/s
[tex]v=\dfrac{m_1u_1+m_2u_2}{m_1+m_2}\\\Rightarrow v=\dfrac{8\times 0+3\times 25}{8+3}\\\Rightarrow v=6.82\ \text{m/s}[/tex]
Speed of the combined mass when the smaller object is moving is [tex]6.82\ \text{m/s}[/tex]
1 poin 4. If the same strength force is exerted on two objects but the objects have different masses, the object with mass will have a greater change in velocity. O more O less O greater O the same
Answer:
hellli
Explanation:
Sir
can u help me in my physics exams
Match the descriptions with the graphs !
Answer:
Graph 1 matches with B, 2 with A, and 3 with C.
Explanation:
Graph 2 shows a car whose distance part of the graph is not going up or down, while the time going up. That means that the car is stopped. Graph 1 shows a straight line, meaning that the car is traveling at a constant speed. Graph 3 is a curved line, meaning the speed of the car is changing somehow, and since the line is becoming more horizontal, the car is getting slower.
How much work is done in pushing an object 7.0 m across a floor with a force of 50 N and then
pushing it back to its original position? How much power is used if this work is done in 20 sec?
Answer:
35/2 J/s
Explanation:
Just use the 2 formulas
Work done = Force * distance moved
Power = Work done/time
WD = 7 * 50 = 350
Power = 350 / 20
= 35/2 J/s
The force experienced by an electron in a field between parallel plates is proportional to which of the following? Select all that apply.
the potential difference between the plates
the current in the circuit
the inverse of the potential between the plates
the distance between the plates
the inverse of the distance between the plates
Answer:
2 and 5
Explanation:
it's correct i think