Answer:
Polarity.
Explanation:
The most important intermolecular force to allow a solvent to dissolve in water is polarity. This is because water is a polar substance and there is a chemical law that states that there is only solubility between substances of equal polarity. Thus, water is only able to dissolve a polar substance, just like it. In this case, we can say that the equal polarity between the two solvents is the most important for one to be able to dissolve the other.
Liquid octane CH3CH26CH3 will react with gaseous oxygen O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. Suppose 2.3 g of octane is mixed with 12.4 g of oxygen. Calculate the minimum mass of octane that could be left over by the chemical reaction. Round your answer to 2 significant digits.
Answer: Octane will be used completely.
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
[tex]\text{Moles of octane}=\frac{2.3g}{114g/mol}=0.0202moles[/tex]
[tex]\text{Moles of oxygen}=\frac{12.4g}{32g/mol}=0.388moles[/tex]
The balanced chemical reaction will be
[tex]2C_8H_{18}+25O_2(g)\rightarrow 16CO_2(g)+18H_2O(g)[/tex]
According to stoichiometry :
2 moles of octane require = 25 moles of [tex]O_2[/tex]
Thus 0.0202 moles of octane will require=[tex]\frac{25}{2}\times 0.0202=0.2525moles[/tex] of [tex]O_2[/tex]
Thus octane is the limiting reagent as it limits the formation of product and [tex]O_2[/tex] is the excess reagent.
Thus octane will be used completely.
Which of the following statements is false?
a. This class discussed four physical states of matter
b. An atom is the smallest particle of an element that still contains properties of the original element.
c. Gases can be colorless or colored
d. Mass is the measure of the earth’s gravitational attraction of a body
e. A pure substance has a fixed composition.
Answer:
d. Mass is the measure of the earth’s gravitational attraction of a body
This is FALSE. Mass is the measure of matter than an object contains.
Explanation:
b. An atom is the smallest particle of an element that still contains properties of the original element.
This is True
c. Gases can be colorless or colored
This is True
d. Mass is the measure of the earth’s gravitational attraction of a body
This is FALSE. Mass is the measure of matter than an object contains.
e. A pure substance has a fixed composition.
This is True.
Write the equilibrium expression of each chemical equation.
2H2S(g) 2H2(g) + S2(g)
Answer:
[H2]2[S2][H2S]2Kc=[H2]2[S2][H2S]2
Explanation:
2H2S(g)⇋2H2(g)+S2(g)2H2S(g)⇋2H2(g)+S2(g)
The equilibrium constant expression in terms of concentrations is:
Kc=[H2]2[S2][H2S]2Kc=[H2]2[S2][H2S]2.
The equilibrium expression for the given reaction can be written in terms of equilibrium constant which is the ratio of power of molar concentration of the product to the product of power of molar concentration of the reactants.
What is equilibrium?Equilibrium is a state for a reversible reaction where, the rate of forward reaction is equal to the rate of backward reaction. The rate of a reaction is the rate of decrease in the concentration of reactants or the rate of increase in the concentration of the products.
The given reaction at equilibrium state is written as:
[tex]\rm 2H_{2}S (g)\leftrightharpoons 2H_{2} (g)+ S_{2}(g)[/tex]
The equilibrium constant Kb is ratio of power of molar concentration of the product to the product of power of molar concentration of the reactants.
[tex]Kb = \rm \frac{[H_{2}S]^{2}}{[H_{2}]^{2} [S_{2}]}[/tex]
The rate of the reaction will be r = Kb [H₂]² [S₂].
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WILL MARK BRANLIEST FOR CORRECT ANSWER! Given the following equation, write the expression for its relative rate.
2N2O(g) — 2N2(g) + O2(9)
[tex]\tt -\dfrac{1}{2}\dfrac{d[N_2O]}{dt}=\dfrac{1}{2}\dfrac{d[N_2]}{dt}=\dfrac{1}{1}\dfrac{d[O_2]}{dt}[/tex]
Further explanationReaction
2N2O(g) — 2N2(g) + O2(g)
Required
relative rate
Solution
The reaction rate (v) shows the change in the concentration of the substance (changes in addition to concentrations for reaction products or changes in concentration reduction for reactants) per unit time.
so the relative rates for the reaction above are :
[tex]\tt -\dfrac{1}{2}\dfrac{d[N_2O]}{dt}=\dfrac{1}{2}\dfrac{d[N_2]}{dt}=\dfrac{1}{1}\dfrac{d[O_2]}{dt}[/tex]
Decide whether the element is a metal or nonmetal, if you can.
Element is a hard silvery-gray solid. Wires are fastened to each side of a 2 cm slab of it, and an ordinary household 9 V battery is hooked up so that it can feed electricity through the slab to an LED. But the LED stays dark
Answer:
The element is a nonmetal
Explanation:
Elements are broadly classified into metals and non metals. Metals conduct electricity while non metals do not conduct electricity.
If we look at this scenario described in the question, we can easily decipher that the element is a nonmetal because the LED stays dark. The LED should have been lit if electricity was passed through the element in question.
Hence, the element is a non metal.
how might the biodiversity of a mowed lawn compare to that of huge weedy field?
Answer: The mowed lawn is the one from where the grasses are removed by using the machines or tools.
Explanation:
The mowed lawn is expected to have low number of species as the grasses may be few or scanty thus can support the population of few species like insects, mice, birds, and small number of grazing animals. On the other hand the weedy field can be hub of insects, reptiles like snakes, small mammals, and large mammals. Large weed field can provide food, and habitat to the large number of species. This will support the increase in biodiversity as compared to the mowed lawn.
Binary compounds are formed by ............... ............... elements.
Answer: i think its A diatomic compound..
Explanation: hope i helped! sorry if im wrong!
1.5.2
(CST): Computer-Scored Unit Test
Question 2 of 25
What is the molality of a solution made by dissolving 6 moles of NaOH in 3 kg
of water?
A. 0.5 mol/kg
B. 3 mol/kg
C. 0.33 mol/kg
D. 2 mol/kg
The molality of a solution : m = 2 mol/kg
Further explanationGiven
6 moles of NaOH
3 kg water
Required
The molality
Solution
Molality shows the number of moles dissolved in every 1000 grams of solvent( 1 kg solvent)
m = n. (1000 / p)
m = Molality
n = number of moles of solute
p = Solvent mass (gram)
Input the value :
m = 6 moles : 3 kg
m = 2 mol/kg
Name each of the following organic molecules. 
Also what happens if you decrease NOCL
Answer:
el que paso del one jhaulio
Explanation:
Vitamin C is a covalent compound with the molecular
formula C6H8O6. The recommended daily dietary
allowance of vitamin C for children aged 4-8 years is
0.000142mol. What is the mass of this allowance in grams?
The mass allowance of Vitamin C for children aged 4-8 years is equal to 0.025 grams.
What is a mole?A mole can be defined as a standard unit that can be utilized to evaluate the number of entities such as atoms, molecules, ions, or other particular particles in a particular amount of the substance.
The number of elementary entities present in one mole of any chemical substance was found to be equal to 6.023 × 10²³ which is also known as the Avogadro number.
Given, the number of moles of vitamin C = 0.000142 moles
Given, the molecular formula of Vitamin C is C₆H₈O₆.
The mass of one mole of C₆H₈O₆ = 176 g
One mole of Vitamin C has mass = 176 g
0.000142 mol of Vitamin C has mass = 0.000142×176 = 0.025 g
Therefore, the mass of 0.000142 mol of Vitamin C is 0.025 g.
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How many atoms of Kr (Krypton) are in a balloon that contains 2.00 mol of Kr? (4)
Answer:
[tex]atoms= 1.204x10^{24}atoms[/tex]
Explanation:
Hello!
In this case, according to the Avogadro's number, it is possible to compute the atoms of Kr in 2.00 moles as shown below:
[tex]atoms=2.00mol*\frac{6.022x10^{23}atoms}{1mol} \\\\atoms= 1.204x10^{24}atoms[/tex]
Best regards!
Which statement accurately describes the atoms of an atom of Sulfur 10 points with a mass number of 33? A) There are 16 particles inside of the nucleus and 17 particles outside of the nucleus B) There are 33 particles inside of the nucleus and 33 particles outside of the nucleus. C) There are 17 particles inside of the nucleus and 17 particles outside of the nucleus. D) There are 33 particles inside of the nucleus and 16 particles outside of the nucleus.
Answer:
D) There are 33 particles inside of the nucleus and 16 particles outside of the nucleus.
Explanation:
Sulfur has an atomic number of 16. The atomic number represents the number of protons, so sulfur has 16 protons.
This atom of sulfur has a mass number of 33. The mass number is the sum of protons and neutrons. Then, the number of neutrons is 33 - 16 = 17
Sulfur is a neutral atom. Therefore, it has the same number of positive charges (protons) and negative charges (electrons). Thus, sulfur has 16 electrons.
Protons and neutrons are in the nucleus and electrons are outside the nucleus.
Taking all the above into account, the correct answer is:
D) There are 33 particles inside of the nucleus and 16 particles outside of the nucleus.
Answer:
D) There are 33 particles inside of the nucleus and 16 particles outside of the nucleus.
Explanation:
Sulfur has an atomic number of 16. The atomic number represents the number of protons, so sulfur has 16 protons.
This atom of sulfur has a mass number of 33. The mass number is the sum of protons and neutrons. Then, the number of neutrons is 33 - 16 = 17
Sulfur is a neutral atom. Therefore, it has the same number of positive charges (protons) and negative charges (electrons). Thus, sulfur has 16 electrons.
Protons and neutrons are in the nucleus and electrons are outside the nucleus.
Taking all the above into account, the correct answer is:
D) There are 33 particles inside of the nucleus and 16 particles outside of the nucleus.
A 9.725-g gaseous mixture contains ethane () and propane (). Complete combustion to form carbon dioxide and water requires 1.115 moles of oxygen gas. Calculate the mass percent of ethane in the original mixture.
Answer:
% = 33.83%
Explanation:
To do a better understanding of this, we can treat the mixture of the combustion as two separate reactions, in that way, we can have an idea of what is happening and how to calculate the mass percent.
So the combustion reactions in this mixture are:
2C₂H₆ + 7O₂ ---------> 4CO₂ + 6H₂O
C₃H₈ + 5O₂ ----------> 3CO₂ + 4H₂O
Now that we have both reactions (And balanced) we can hace an idea of the mole ratio between every compound in the mix.
For practical purposes, let's call "a" the mass of ethane, and "b" the mass of propane. The innitial mix have 9.725 g, so this means that:
a + b = 9.725 g (1)
Now that we have this, we can write a relation between the moles of oxygen and the moles of the gases. If we have 1.115 moles of oxygen, and also know the mole ratio of oxygen to "a" and "b", so:
moles O₂ = moles a (moles O₂/moles a) + moles b (moles O₂/moles b) (2)
And we know that moles a and moles b are:
moles a = a / MW
moles b = b / MW
The MW of a is 30 g/mol and the MW of b is 44 g/mol
Replacing the given data we have:
1.115 moles O₂ = (a/30)(7 moles O₂/2 moles a) + (b/44)(5 moles O₂/1 mole b)
1.115 moles O₂ = (0.1167a) moles O₂ + (0.1136b) moles O₂
To keep solving this, we can use expression (1) to solve for b, and then, replace here and have only one equation with 1 incognite:
a + b = 9.725 g
b = 9.725 - a (3)
Replacing above we have:
1.115 = 0.1167a + 0.1136(9.725 - a)
1.115 = 0.1167a + (1.1048 - 0.1136a)
1.115 - 1.1048 = 0.1167a - 0.1136a
0.0102 = 0.0031a
a = 3.29 g
Now, that we have the mass of the ethane, we can calculate the mass percent:
% = (3.29 / 9.725) * 100
% = 33.83%Hope this helps
It pulls everything down towards earth
18. What is one of the three things that cause the surface currents of the oceans?
A.differences in salinity
B.temperature differences
C. density differences
D. Coriolis effect
Answer:
b. temperature difference
Hi do you know this?
Answer:
2
Explanation
It seems logical
Please explain to me!!!
Answer:
nice handwrtting
Explanation:
Some antacid tables contain aluminum hydroxide. The aluminum hydroxide reacts with stomach acid according to the equation: Al(OH)3 + 3HCl →AlCl3 + 3H2O. Determine the moles of stomach acid (HCl) required if a tablet contains 8.89 moles of Al(OH)3.
Answer:
26.67 mol HCl
Explanation:
Al(OH)₃ + 3HCl → AlCl₃ + 3H₂O
In order to solve this problem, we need to convert Al(OH)₃ moles to HCl moles.
To do so we use the stoichiometric ratios of the balanced reaction:
8.89 mol Al(OH)₃ * [tex]\frac{3molHCl}{1molAl(OH)_{3}}[/tex] = 26.67 mol HClThus 26.67 moles of HCl would react completely with 8.89 moles of Al(OH)₃.
A catalyst will
a) Increase the reaction rate
b) Move the equilibrium to the right
c) Be consumed by the reaction
d) Increase the activation energy
Answer:
increase the chemical rate
How many grams of sulfur must be burned to give 100.0 g of So2
Answer:
50 g of S are needed
Explanation:
To star this, we begin from the reaction:
S(s) + O₂ (g) → SO₂ (g)
If we burn 1 mol of sulfur with 1 mol of oxygen, we can produce 1 mol of sulfur dioxide. In conclussion, ratio is 1:1.
According to stoichiometry, we can determine the moles of sulfur dioxide produced.
100 g. 1mol / 64.06g = 1.56 moles
This 1.56 moles were orginated by the same amount of S, according to stoichiometry.
Let's convert the moles to mass
1.56 mol . 32.06g / mol = 50 g
A reaction that proceeds by first-order irreversible kinetics is oxidizing chemical A in a wastewater treatment basin with a mean residence time of 1.5 hours. The reaction rate constant is The basin is unbaffled and may be characterized as two completely mixed tanks in series. If the steady-state influent concentration is 30 mg/l, find the effluent concentration. If baffles are placed in the basin so that the basin may be characterized as four completely mixed tanks in series, and the mean residence time remains constant, find the effluent concentration.
This question is incomplete, the complete question is;
A reaction that proceeds by first-order irreversible kinetics is oxidizing chemical A in a wastewater treatment basin with a mean residence time of 1.5 hours. The reaction rate constant is 2.0 Hr-1.The basin is unbaffled and may be characterized as two completely mixed tanks in series. If the steady-state influent concentration is 30 mg/l, find the effluent concentration.
If baffles are placed in the basin so that the basin may be characterized as four completely mixed tanks in series, and the mean residence time remains constant, find the effluent concentration.
Answer:
a) (two completely mixed tanks in series) the find the effluent concentration is 4.8 [tex]\frac{mg}{l}[/tex]
b) (four completely mixed tanks in series) find the effluent concentration is 3.2 [tex]\frac{mg}{l}[/tex]
Explanation:
Given the data in the question;
we can determine the effluent concentration of two completely mixed tanks in series for first order irreversible reaction using the following equation;
C = Co ( 1 / ( 1 + K[tex]\frac{t}{n}[/tex] )ⁿ
t is the mean hydraulic residence time for two completely mixed tanks in series ( 1.5 hr)
Co is initial concentration of the influent ( 30 [tex]\frac{mg}{l}[/tex] )
C is final concentration of effluent,
n is the number of tanks series ( 2)
k is rate constant for the given first order reaction( 2[tex]\frac{1}{hour}[/tex] )
so we substitute
C = 30 [tex]\frac{mg}{l}[/tex] ( 1 / ( 1 + 2[tex]\frac{1}{hour}[/tex] . [tex]\frac{1.5}{2}[/tex] )²
C = 30 [tex]\frac{mg}{l}[/tex] × ( 1/2.5)²
C = 30 [tex]\frac{mg}{l}[/tex] × 0.16
C = 4.8 [tex]\frac{mg}{l}[/tex]
Therefore, (two completely mixed tanks in series) the find the effluent concentration is 4.8 [tex]\frac{mg}{l}[/tex]
b)
using;
C = Co ( 1 / ( 1 + K[tex]\frac{t}{n}[/tex] )ⁿ
t is the mean hydraulic residence time for two completely mixed tanks in series ( 1.5 hr)
Co is initial concentration of the influent ( 30 [tex]\frac{mg}{l}[/tex] )
C is final concentration of effluent,
n is the number of tanks series ( 4)
k is rate constant for the given first order reaction( 2[tex]\frac{1}{hour}[/tex] )
so we substitute
C = 30 [tex]\frac{mg}{l}[/tex] ( 1 / ( 1 + 2[tex]\frac{1}{hour}[/tex] . [tex]\frac{1.5}{4}[/tex] )⁴
C = 30 [tex]\frac{mg}{l}[/tex] × ( 1/1.75)²
C = 30 [tex]\frac{mg}{l}[/tex] × 0.107
C = 3.2 [tex]\frac{mg}{l}[/tex]
Therefore, (four completely mixed tanks in series) find the effluent concentration is 3.2 [tex]\frac{mg}{l}[/tex]
What is the ratio
amount (mol) Fatoms
amount (mol) Xe atoms
Enter your answer as an integer.
Pls help
Answer:
Empirical formula
Explanation:
The empirical formula of a compound is the simplest whole number ratio of atoms of each element in the compound. It is determined using data from experiments and therefore empirical.
Menthol is a crystalline substance with a peppermint taste and odor. When 0.533 g of menthol is dissolved in 25.0 g of cyclohexane, the freezing point of the solution is lowered by 2.84 ∘C. Look up the freezing point and f constant for cyclohexane in the Colligative Constants table. Calculate the molar mass of menthol.
Answer: The molar mass of menthol is 156.15 g/mol
Explanation:
Depression in freezing point is given by:
[tex]\Delta T_f=K_f\times m[/tex]
[tex]\Delta T_f=T_f^0-T_f=2.84^0C[/tex] = Depression in freezing point
[tex]K_f[/tex] = freezing point constant = [tex]20.8^0C/m[/tex]
m= molality
[tex]\Delta T_f=K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}[/tex]
Weight of solvent (cyclohexane)= 25.0 g = 0.025 kg
Molar mass of solute (menthol) = ?
Mass of solute (menthol) = 0.533 g
[tex]2.84^0C=20.8\times \frac{0.533}{xg/mol\times 0.025}[/tex]
[tex]x=156.15g/mol[/tex]
The molar mass of menthol is 156.15 g/mol
What is the molecular formula of the molecule that has an empirical formula of C2H40 and a molar mass of 176.21 g/mol?
Type your answer using the following format:
CuCl2 for CuCl2.
Answer:
C8H16O4
Explanation:
C2H4O= 24+4+16
44
n=molar mass/empirical formula
n=176.21/44
=4
Therefore
Molar Formula= (C2H4O)4=C8H16O4
Pls give a detailed explanation about what are enzyme mutations
Answer:
Enzyme mutations can lead to serious or fatal human disorders and are the consequence of inherited abnormalities in the affected individual's DNA. The mutation may be at a specific position in an enzyme encoded by a mutated gene, just like a single abnormal amino acid residue.
Explanation:
I need help with this!
Answer:
2.68 cm^3
Explanation:
Density= Mass/Volume
so...
8.96 g/cm^3 = 24.01 g/ V
and then u solve so it would be 2.68 cm ^3
((:
number of balance electrons of a non ionized oxygen atom
There are four conditions an atom needs to meet to participate in hydrogen bonding. It needs to be_______ enough not to bump into other atoms when approaching the 1s orbital of the hydrogen, it needs to carry at least one________ atom, it needs to be_________enough to create a delta on the connected hydrogen, and it needs to have at least one________.
Answer:
The conditions are
1) Small enough
2) Electronegative atom
3) highly electronegative
4) lone pair of electrons
The correct statement therefore is
It needs to be small enough not to bump into other atoms when approaching the 1s orbital of the hydrogen, it needs to carry at least one electronegative atom, it needs to be highly electronegative enough to create a delta on the connected hydrogen, and it needs to have at least one lone pair of electrons.
Explanation:
Hydrogen bonding is a type of intermolecular bond that occurs between the partial positive charge (delta) on a hydrogen atom bonded to a small highly electronegative element (like nitrogen, oxygen or fluorine) and the free electrons on another electronegative element of another molecule.
The hydrogen atom with the partial positive charge (delta) is known as the hydrogen bond donor, while the electronegative element, carrying lone electrons is called the hydrogen bond acceptor.
Let's take a deeper look at these terms:
1) Hydrogen bond donor
Using water (H₂O) as an example, the high electronegativity of the oxygen atom covalently bonded to the hydrogen atom draws the lone electron in the 1s orbital of the hydrogen atom, creating a partial positive charge (d⁺) on the hydrogen atom. This is what happens within one water molecule
2) Hydrogen bond acceptor
When two or more molecules of water interact, the partial positive charge (d⁺) on the hydrogen atom of one molecule, is attracted to the valence or free electrons on the oxygen atom of a nearby molecule of water thus creating a dipole-dipole intermolecular bond known as a hydrogen bond.
For the hydrogen bond to be effective, the electronegative atom bonded to the hydrogen acting as the hydrogen bond donor in the first water molecule needs to be small enough so as not to disrupt the 1s orbital of the hydrogen atom. The smaller the size of the electronegative atom, the stronger the partial negative charge created on the hydrogen atom.
The valence or free pair of electrons on the electronegative (oxygen) atom of the second molecule of water (hydrogen bond acceptor) is what attracts the partial positive charge on the hydrogen atom to create the hydrogen bond
The mass fractions of a mixture of gases are 15 percent nitrogen, 5 percent helium, 60 percent methane, and 20 percent ethane with a total mixture molecular weight of 16.12 kg/kmole. Determine the mole fraction of each constituent, the partial pressure of each constituent when the mixture pressure is 1200 kPa and the apparent specific heats of the mixture when the mixture is at room temperature.
Answer:
Explanation:
mass fraction N₂ : He : CH₄ : C₂H₆ : : 15 : 5 : 60 : 20
mole fraction N₂ : He : CH₄ : C₂H₆ : : 15/28 : 5/4 : 60/16 : 20/30
mole fraction N₂ : He : CH₄ : C₂H₆ : : .5357 : 1.25 : 3.75 : .67
Total mole fractions = .5357 + 1.25 + 3.75 + 0.67 = 6.2057
mole fraction of N₂ = .5357 / 6.2057 = .0877
mole fraction of He = 1.25 / 6.2057 = .20
mole fraction of CH₄ = 3.75 / 6.2057 = .6043
mole fraction of C₂H₆ = .67 / 6.2057 = .108
Partial pressure = total pressure x mole fraction
Partial pressure of N₂ = 1200 kPa x .0877 = 105.24 kPa
Partial pressure of He = 1200 kPa x .20 = 240 kPa
Partial pressure of CH₄ = 1200 kPa x .6043 = 725.16 kPa
Partial pressure of C₂H₆ = 1200 kPa x .108 = 129.6 kPa