Answer:
0.702 /s
Explanation:
Rate constant at [tex][298 \mathrm{~K}, \mathrm{~K}_{1}=3.46 \times 10^{-2} \mathrm{~s}^{-1}[/tex]
Rate constant at [tex]350 \mathrm{~K}, \mathrm{~K}_{2}=?[/tex]
[tex]T_{1}=298 \mathrm{~K}[/tex]
[tex]T_{2}=350 \mathrm{~K}[/tex]
Activation energy, [tex]\mathrm{Ea}=50.2 \times 10^{3} \mathrm{~J} / \mathrm{mol}[/tex]
Use the following equation to calculate [tex]K_{2}$ at $350 \mathrm{~K}[/tex]
Use the following equation to calculate [tex]K_{2}$ at $350 \mathrm{~K}[/tex]
[tex]\ln \frac{\mathrm{K}_{2}}{\mathrm{~K}_{1}}=\frac{\mathrm{Ea}}{\mathrm{R}}\left[\frac{1}{\mathrm{~T}_{1}}-\frac{1}{\mathrm{~T}_{2}}\right][/tex]
Therefore,
[tex]\ln \left(\frac{K_{2}}{3.46 \times 10^{-2} \mathrm{~s}^{-1}}\right) &=\frac{50.2 \times 10^{3} \mathrm{~J} / \mathrm{mol}}{8.314 \mathrm{JK}^{-1} \mathrm{~mole}^{-1}}\left[\frac{1}{298 \mathrm{~K}}-\frac{1}{350 \mathrm{~K}}\right][/tex]
[tex]\ln \left(\frac{K_{2}}{3.46 \times 10^{-2} \mathrm{~s}^{-1}}\right) &=\frac{50.2 \times 10^{3} \mathrm{~J} / \mathrm{mol}}{8.314 \mathrm{JK}^{-1} \mathrm{~mole}^{-1}}\left[\frac{52 \mathrm{~K}}{298 \mathrm{~K} \times 350 \mathrm{~K}}\right][/tex]
[tex]\frac{K_{2}}{3.46 \times 10^{-2} \mathrm{~s}^{-1}} &=\mathrm{e}^{3.01}[/tex]
[tex]\frac{K_{2}}{3.46 \times 10^{-2} \mathrm{~s}^{-1}} &=20.3[/tex]
[tex]K_{2} &=20.3 \times 3.46 \times 10^{-2} \mathrm{~s}^{-1}[/tex]
[tex]&=0.702 \mathrm{~s}^{-1}[/tex]
hence, the rate constant at [tex]350 \mathrm{~K} [/tex] is 0.702[tex]\mathrm{~s}^{-1}[/tex]
What are the parts of the glowstick? What are the chemicals inside?
chemical formula is given.
CO→C+O
What does the formula describe?
A.
It describes a mixture being separated by a physical process.
B
It describes an atom being separated by a chemical process.
C
It describes an element being broken down into the atoms from which it was formed.
D
It describes a compound being broken down into the elements from which it was formed.
Answer:
D . It describes a compound being broken down into the elements from which it was formed.
Explanation:
A compound consists of two or more elements chemically combined together in a chemical reaction. The compound carbon monoxide is represented by the chemical symbol, CO. This means that it contains 1 atom of the carbon element and 1 atom of the Oxygen element.
This compound is formed when carbon is directly oxidized in a limited supply of oxygen. In the above reaction, this compound is disintegrated into its individual components, namely, carbon and oxygen.
what were Lamarck's ideas about evolution and why were those ideas incorrect
What were Lamarck's ideas about evolution and Why were those ideas incorrect?
→ These and other examples show that Lamarck's theory does not explain how life formed and became the way it is. The other way that Lamarck's theory has been proven wrong is the study of genetics. Darwin knew that traits are passed on, but he never understood how they are passed on.
[tex]#CarryOnLearning[/tex]What is the relative formula mass of a compound?
Answer:
To find the relative formula mass (M r) of a compound, you add together the relative atomic mass values (A r values) for all the atoms in its formula.
Explanation: Find the M r of carbon monoxide, CO. Find the M r of sodium oxide, Na 2O. The relative formula mass of a substance, shown in grams, is called one mole of that substance.
balance
Al(OH)3 + H2SO4 → Al2(SO4)3 + H2O
Equation balance:
2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O
2Al(OH)3+3H2SO4
H=12
SO4=3
O=6
Al=2
Al2(SO4)3+6H2O
H=12
SO4=3
O=6
Al=2
Please help I need on this please and thank you
Explanation:
amount of baking soda = 2.01 g
---> 2.01 g NaHCO3 × (1 mol NaHCO3/84.007 g NaHCO3)
= 0.024 mol NaHCO3
mass of the product = 1.28 g
Possible reactions:
NaHCO3(s) ---> NaOH(s) + CO2(g)
0.024 mol NaHCO3 × (1 mol NaOH/1 mol NaHCO3)
= 0.024 mol NaOH × (39.997 g NaOH/1.mol NaOH)
= 0.96 g NaOH
2NaHCO3(s) ---> Na2O(s) + 2CO2(g) + H2O(g)
0.024 mol NaHCO3 × (1 mol Na2O/2 mol NaHCO3)
= 0.012 mol Na2O × (61.9789 g Na2O)
= 0.73 g Na2O
2NaHCO3(s) ---> Na2CO3(s) + CO2(g) + H2O(g)
0.024 mol NaHCO3 × (1 mol Na2CO3/2 mol NaHCO3)
= 0.012 mol Na2CO3 × (105.9888 g Na2CO3/1 mol Na2CO3)
= 1.27 g Na2CO3
Conclusion:
Based on the mass of the product in the crucible and comparing it with the predicted product mass in different reactions, I conclude that Na2CO3 is the most likely product in the crucible.
Name the layers of the atmosphere and one fact about each layer.
what is the proper formulanGaseous Butane (C4H10) that reacts with Gaseous Oxygen (O2) in a combustion reaction to form Carbon dioxide Gas and Gaseous Water (Dihydrogen monoxide).
Answer:
2C₄H₁₀(g) + 13O₂(g) —> 8CO₂(g) + 10H₂O(g)
Explanation:
The balanced equation for the reaction between butane and oxygen to produce carbon dioxide and water can be written as follow:
C₄H₁₀ + O₂ —> CO₂ + H₂O
Next, we shall balanced the equation. This is illustrated below:
C₄H₁₀ + O₂ —> CO₂ + H₂O
There are 4 atoms of C on the left side and 1 atom on the right side. It can be balance by writing 4 before CO₂ as shown below:
C₄H₁₀ + O₂ —> 4CO₂ + H₂O
There are 10 atoms of H on the left side and 2 atoms on the right side. It can be balance by writing 5 before H₂O as shown below:
C₄H₁₀ + O₂ —> 4CO₂ + 5H₂O
There are 2 atoms of O on the left side and a total of 13 atoms on the right side. It can be balance by writing 13/2 before O₂ as shown below:
C₄H₁₀ + 13/2O₂ —> 4CO₂ + 5H₂O
Multiply through by 2 to express in whole number ratio.
2C₄H₁₀(g) + 13O₂(g) —> 8CO₂(g) + 10H₂O(g)
Thus, the equation is balanced.
Cu2O + C -> Cu + CO2 balanced equation
Answer:
2Cu2O + C --> 4Cu + CO2
Explanation
The Law of conservation of Mass states You can not destroy or create math in a chemical reaction, meaning you must have the same amount at the beginning and the end. This equation keeps the same amount of atoms on both sides.
Answer: Yes, it is a balanced equation.
Explanation:
https://chemequations.com/en/?s=Cu2O+%2B+C+%3D+Cu+%2B+CO2
This is where I got the answer so you know. Hope this helps :)
Glucose is a compound made from three elements: carbon, oxygen, and hydrogen. For glucose to be broken down into these elements, it must undergo _____.
A. filtration or distillation
B. an irreversible physical change, such as tearing or slicing
C. a reversible physical change, such as boiling or melting
D. a chemical change
Answer:
D ) Chemical Change
Explanation:
If HA, an acid, is 15 percent dissociated in a 2.00 molar solution, what is the Ka for the solution?
A.5.3 × 10-2
B.6.4 × 10-3
C.1.1 × 10-2
D.1.2 × 10-2
Answer:
A. 5.3 X 10^-2
Explanation:
I got 100 on PLATO
answer asap
Food caught on fire on a restaurant's stove. How much thermal energy was present?
A. only a little compared to the total amount of energy
B. a lot of the energy was thermal
C. none of the energy was thermal
D. it was mostly potential energy, not thermal
79.4 grams of C3H8 are consumed with an excess of oxygen in the reaction 1 C3H8 + 5 O2 --> 3 CO2 + 4 H2O. How many moles of oxygen (O2) are consumed in this reaction?How many moles of carbon dioxide (CO2) are formed in this reaction? &
How many moles of water (H2O) are formed in this reaction?
Answer:
II would say there is co2 so i would say 30.4
Explanation:
Hope this helps
what is difference between asexual or sexual reproduction
Explanation:
asexual reproduction involves 1 parent and produces offspring that are genetically identical to each other and parent.
Sexual reproduction involves 2 parents and produces offspring that are genetically unique.
What is the molarity of a sodium hydroxide solution if 25 mL of the solution is neutralized by 69.5 mL of 1.5 M HCl?
Answer:
4.17M
Explanation:
m1v1/m2v2=n1/n2
Which of the following reactions is balanced?
Answer:
D
Explanation:
Because it has equal number of elements on each side of the arrow
an evacuated cylinder has a volume of 50 liters. if 20 liters of nitrogen fas and 20 liters of oxygen gas are pumped into this evacuated cylinder, how much of the cylinder is filled with the two gasses?
The nitrogen gas and the oxygen gas will both occupy 50 liters.
Volume of a gasLet us recall form the kinetic theory of gases that a gas is in constant random motion. The gas does not have a specific volume but takes on the volume of the container since it will expand and fill the container.
The volume occupied by the two gases will be the same as the volume of the container. Hence, the nitrogen gas and the oxygen gas will both occupy 50 liters.
Learn more about volume of a gas: https://brainly.com/question/4519953
Answer:
B. The entire container because gases will expand to fill it.
Explanation:
I took to test, plus it directly says this in the lesson
1: A50 L balloon is at 4 atm of pressure. What is the volume at 2 atm of pressure?
Answer:
100 L
Explanation:
Use Boyle's Law, p1v1 = p2v2.
p1 = 4 atm
v1 = 50L
p2 = 2 atm
v2 = ?
p1v1 = p2v2
(4 atm) (50L) = (2 atm) (v2)
v2 = (4 atm)(50L) / (2 atm) = 100 L
Pls hurry
Light is the fastest known entity in our universe.
O True
O False
Mark this and return
Save and Exit
Answer:
True
Explanation:
Answer:
true
Explanation:
source(s): trust me bro
Which statement best explains what causes the phase change from solid ice to liquid water?
a.Heat is released as ice turns into liquid water.
b.The mass increases when ice turns into liquid water.
c.Heat is absorbed as ice turns into liquid water.
d.The hydrogen bonds prevent the absorption of heat.
When something is hot , its atom has more energy
True or False
Will mark as brainliest if the answer is correct
Gather data: experiment with a variety of initial concentrations of no2 and n2o4. for each set of initial concentrations, use the gizmo to determine the equilibrium concentrations of each substance. in the last column, find kc for that trial. run three trials for each set of initial conditions.
Solution :
[tex]$H_2 +I_2\rightleftharpoons 2HI$[/tex]
Initial concentration Equilibrium concentration [tex]$K_c=\frac{[HI]^2}{[H_2][I_2]}$[/tex]
(mol/L) (mol/L)
[tex]$[H_2]$[/tex] [tex]$[I_2]$[/tex] [tex]$[HI]$[/tex] [tex]$[H_2]$[/tex] [tex]$[I_2]$[/tex] [tex]$[HI]$[/tex]
[tex]$2.4 \times 10^{-2}$[/tex] [tex]$1.38 \times 10^{-2}$[/tex] 0 [tex]$1.14 \times10^{-2}$[/tex] [tex]$0.12 \times 10^{-2}$[/tex] [tex]$2.52 \times 10^{-2}$[/tex] 46.42
[tex]$2.4 \times 10^{-2}$[/tex] [tex]$1.68 \times 10^{-2}$[/tex] 0 [tex]$0.92 \times10^{-2}$[/tex] [tex]$0.20 \times 10^{-2}$[/tex] [tex]$2.96 \times 10^{-2}$[/tex] 47.61
[tex]$2.4 \times 10^{-2}$[/tex] [tex]$1.98 \times 10^{-2}$[/tex] 0 [tex]$0.77 \times10^{-2}$[/tex] [tex]$0.31 \times 10^{-2}$[/tex] [tex]$3.34 \times 10^{-2}$[/tex] 46.73
[tex]$2.4 \times 10^{-2}$[/tex] [tex]$1.76 \times 10^{-2}$[/tex] 0 [tex]$0.92 \times10^{-2}$[/tex] [tex]$0.22 \times 10^{-2}$[/tex] [tex]$3.08 \times 10^{-2}$[/tex] 46.86
[tex]$0$[/tex] [tex]$0$[/tex] [tex]$3.04 \times 10^{-2}$[/tex] [tex]$0.345 \times10^{-2}$[/tex] [tex]$0.345 \times 10^{-2}$[/tex] [tex]$2.35 \times 10^{-2}$[/tex] 46.39
[tex]$0$[/tex] [tex]$0$[/tex] [tex]$7.58 \times 10^{-2}$[/tex] [tex]$0.86 \times10^{-2}$[/tex] [tex]$0.86 \times 10^{-2}$[/tex] [tex]$5.86 \times 10^{-2}$[/tex] 46.42
Average [tex]$K_c=46.738$[/tex]
How does the difference in air pressure masses affect wind speed? When low air pressure and high air pressure masses are far apart, air moves quickly from low to high pressure areas. When low air pressure and high air pressure masses are far apart, air moves quickly from high to low pressure areas. When low air pressure and high air pressure masses are close together, air moves quickly from high pressure to low pressure areas. When low air pressure and high air pressure masses are close together, air moves quickly from low to high pressure areas; this creates stronger wind speeds.
Answer:
it is from the currents the movements cause
Explanation:
Answer:The greater the difference in pressure, the faster the winds. When a high- and a low-pressure air mass are far apart, air moves slowly from high to low pressure. When a high- and a low-pressure air mass are far apart, air moves quickly from high to low pressure.
Explanation:
What is the specific heat capacity of silver metal if 110.00 g of the metal
absorbs 396 J of heat and the temperature rises 15.0°C ?
Answer:
"0.24 J/g.k" is the appropriate solution.
Explanation:
Mass of substance,
m = 110.00 g
Heat,
q = 396 J
Change in temperature,
ΔT = 15.0°C
Now,
The specific heat will be:
⇒ [tex]q=ms \Delta T[/tex]
On putting the given values, we get
⇒ [tex]396=110.00\times s\times 15.0[/tex]
⇒ [tex]396=s\times 1650[/tex]
⇒ [tex]s=\frac{396}{1650}[/tex]
⇒ [tex]=0.24 \ J/g.k[/tex]
2
CuCl2 +4KI -> 2 Cul + 4 KCI + 12
Answer:
Explanation:
This is an example of a limiting reactant question, and is very common as a general chemistry problem.
We first see the balanced equation, that is:
2CuCl2+4KI→2CuI+4KCl+I2
We first need to find the limiting reactant
We see that 0.56 g of copper(II) chloride (CuCl2) reacts with 0.64 g of potassium iodide (KI) . So, let's convert those amounts into moles.
Copper(II) chloride has a molar mass of
134.45 g/mol . So in 0.56 g of copper(II) chloride, then there exist
0.56g134.45g/mol≈4.17⋅10−3 mol
Potassium iodide has a molar mass of
166 g/mol . So, in 0.64 g of potassium iodide, there exist
if it wrong i am sorry
A molecule with one lone pair and three bond pair
▪︎Ammonia
▪︎carbon tetrachloride
choose correct option
It's ammonia (NH3).....
Answer:
A molecule with one lone pair and three bond pair
- Ammonia
HELP ASAPPP!!! ON EXAM!
The arrangement of electrons within an atom is called it's...
a
Electron Flow
b
Electron Configuration
c
Atomic Number
d
Ionization Energy
Answer:
The arrangement of electrons within an atom is called electron configuration
If I help you, will you help other people?
Actually "this is the worst question i've ever seen use the internet bud" why don't you do that.
A student has 475 mL of a 4.5 M HNO3 solution. He leaves the top of the container Monday morning the volume of solution is now 347 mL. What is the conventtration of the solution now
Answer:
6.1 M
Explanation:
Step 1: Calculate the moles of HNO₃ in the initial solution
A student has 475 mL (0.475 L) of a 4.5 M HNO₃ (4.5 mol HNO₃/ L) solution.
0.475 L × 4.5 mol HNO₃/ L = 2.1 mol HNO₃
He leaves the top of the container open, so water will evaporate, but the moles of HNO₃ will remain the same.
Step 2: Calculate the final concentration of the solution
2.1 moles of HNO₃ are in 347 mL (0.347 L) of solution.
[HNO₃] = 2.1 mol / 0.347 L = 6.1 M
At the Sprite bottling plant where the temperature is at 235K, each bottle can hold 3.80 atm of pressurized carbon dioxide gas (to make the soda fizzy). At room temperature 298K what is the new pressure?
Answer:
P2 = 4.76 atm
Explanation:
Given:
T1 = 235K. P1 = 3.80 atm
T2 = 298K. P2 = ?
Here, we use Gay-Lussac's law:
P1/T1 = P2/T2
Solving for P2, we get
P2 = (T2/T1)P1
= (298K/238K)(3.80 atm)
= 4.76 atm
balance the following equations:
a. ____AgI + _____Na2S → _____Ag2S + _____NaI
b. ____Na3PO4 + ____HCl →_____NaCl + _____H3PO4
c. _____Ba3N2 + _____H2O →_____Ba(OH)2 + _____NH3
d. _____TiCl4 + _____H2O →_____TiO2 + _____HCl
e. _____CaCl2 + _____Na3PO4 →_____Ca3(PO4)2 + _____NaCl
Answer:
A. 2AgI + Na2S → Ag2S + 2NaI
B. Na3PO4 + 3HCl → 3NaCl + H3PO4
C. Ba3N2 + 6H2O → 3Ba(OH)2 + 2NH3
D. TiCl4 + 2H2O → TiO2 + 4HCl
E. 3CaCl2 + 2Na3PO4 → Ca3(PO4)2 + 6NaCl
Explanation: