Answer:
P(10 packet) = 0.000976
Therefore, there is a 0.000976 probability of packet loss if the number of packets in residence is limited to 10.
Step-by-step explanation:
We are given an M/M/1 queuing system
The mean arrival rate is
λ = 500 packets/second
The mean service rate is
μ = 1000 packets/second
The number of packets in residence is
n = 10
The probability of packet loss is given by
P(n packet) = ρⁿ
When n is the number of packets and ρ is the gateway utilization
The gateway utilization is given by
ρ = λ/μ
Where λ is the mean arrival rate and μ is the mean service rate.
ρ = 500/1000
ρ =0.50
So, the probability is
P(10 packet) = (0.50)¹⁰
P(10 packet) = 0.000976
Therefore, there is a 0.000976 probability of packet loss if the number of packets in residence is limited to 10.
what is the next term in the pattern 2, 3/2, 4/3, 5/4
Answer:
6/5, 7/6
Step-by-step explanation:
The nth term is (n+1)/n
2/1, 3/2, 4/3, 5/4
Put n as 5 and 6.
(5+1)/5
= 6/5
(6+1)/6
= 7/6
Given the equation y = 7 sec(6x– 30)
The period is:
The horizontal shift is:
Answer:
The period is of [tex]\frac{\pi}{3}[/tex] units.
The horizontal shift is of 30 units to the left.
Step-by-step explanation:
The secant function has the following general format:
[tex]y = A\sec{(Bx + C)}[/tex]
A represents the vertical shift.
C represents the horizontal shift. If C is positive, the shift is to the right. If it is negative, it is to the left.
The period is [tex]P = \frac{2\pi}{B}[/tex]
In this question:
[tex]y = 7\sec{6x - 30}[/tex]
So [tex]B = 6, C = -30[/tex]
Then [tex]P = \frac{2\pi}{6} = \frac{\pi}{3}[/tex]
The period is of [tex]\frac{\pi}{3}[/tex] units.
The horizontal shift is of 30 units to the left.
The Department of Transportation (DOT) monitors sealed bids for new road construction. For new access roads in a certain state, let low bid (thousands of dollars) and let estimate of fair cost of building the road (thousands of dollars). The joint probability density of X and Y is f(x,y)= e^-y/10/10y 0< y
Complete Question
The complete question is shown on the first and second uploaded image
Answer:
The marginal density function of Y is [tex]f(y)= \frac{e^{\frac{-y}{10} }}{10}[/tex]
The distribution is exponential distribution
and the expected value is[tex]E[Y] = 10[/tex]
Step-by-step explanation:
From the question we are told that the function is
[tex]f(x,y) = \frac{e^{-\frac{y}{10} }}{10y} \ \ \ 0< y <x<2y[/tex]
Now the marginal density function of Y i.e f(y) is mathematically evaluated by obtaining the probability density function of y as follows
[tex]= \int\limits^{2y}_{y} { \frac{e^{\frac{-y}{10} }}{10y} } \, dx[/tex]
[tex]= \frac{e^{\frac{-y}{10} }}{10y} * (2y - y )[/tex]
[tex]= \frac{e^{\frac{-y}{10} }}{10}[/tex]
The distribution of the function above is exponential distribution with a rate parameter equals to
[tex]\lambda = \frac{1}{10}[/tex]
The mean DOT estimate E{Y} is mathematically evaluated as
[tex]E[Y] = \frac{1}{\lambda}[/tex]
substituting value
[tex]E[Y] = \frac{1}{\frac{1}{10} }[/tex]
[tex]E[Y] =10[/tex]
calculating the five number summary
Answer:
2) 43
4) 65
Step-by-step explanation:
The first and third quartile of the data can be found by calculating the median of the first and second halves of the data. For example, the first quartile of the data can be calculated thus:
40,41,43,50,56
41,43,50
43
and the third quartile thus:
62,63,65,78,97
63,65,78
65
Hope it helps <3
Answer:
A) 43
B) 65
Step-by-step explanation:
A) First Quartile = [tex](N+1)\frac{1}{4}[/tex]
Where N is the number of observations
=> 1st Quartile = (11+1)(1/4)
=> 1st Quartile = (12)(1/4)
=> 1st Quartile = 3rd number
=> 1st Quartile = 43B) Third Quartile = [tex](N+1)\frac{3}{4}[/tex]
=> 3rd Quartile = (11+1)(3/4)
=> 3rd Quartile = (12)(3/4)
=> 3rd Quartile = 3*3
=> 3rd Quatile = 9th number
=> 3rd Quartile = 65To test H0: μ=100 versus H1:≠100, a simple random sample size of nequals=24 is obtained from a population that is known to be normally distributed. Answer parts (a)-(d).(a) If x =104.2 and s=9.6, compute the test statistic.t= _ (Round to three decimal places as needed.)(b) If the researcher decides to test this hypothesis at the α=0.01 level of significance, determine the critical values.The critical values are __ .(c) Draw a t-distribution that depicts the critical region(s). Which of the following graphs shows the critical region(s) in thet-distribution?(d) Will the researcher reject the null hypothesis?
Answer:
a) Test statistic = 1.960
b) The critical values include -2.50 and 2.50.
The critical regions of rejection are thus
t < -2.50 or t > 2.50
c) The sketch of the curve is presented in the attached image to this solution. The shaded parents indicate the rejection regions.
d) The t-statistic obtained (1.96), lies within the acceptance region (-2.50 ≤ x ≤ 2.50), we fail to reject the null hypothesis.
Step-by-step explanation:
a) Test statistic is computed using the expression
t = (x - μ₀)/σₓ
x = Sample mean = 104.2
μ₀ = the standard we are comparing Against
σₓ = standard error of the mean = (σ/√n)
σ = 9.6
n = Sample size = 24
σₓ = (9.6/√24) =
t = (0.425 - 0.35) ÷ 0.07816
t = 1.9595917942 = 1.960
b) To obtain these critical values, we first find the degree of freedom
Degree of freedom = n - 1 = 24 - 1 = 23
The critical values for significance level of 0.01 and degree of freedom of 23 is given as
t(0.01, 23) = 2.50
So, since the test is two-tailled (we are testing in both directions; greater than or less than), the regions of rejection include
t < -2.50 and t > 2.50
c) since the test is two-tailled (we are testing in both directions; greater than or less than), the regions of rejection include
t < -2.50 and t > 2.50
The t-distribution curve is very similar to the normal distribution curve. The t-distribution curve is also a bell shaped curve, but it is heavier at the limits indicating that the t-distribution favours outliers more than the normal distribution.
The sketch of the curve is presented in the attached image with the shaded regions indicating the rejection region.
d) Since the t-statistic obtained (1.96), lies within the acceptance region (-2.50 ≤ x ≤ 2.50), we fail to reject the null hypothesis.
Hope this Helps!!!
Solve the two-step equation.-0.45x + 0.33 = -0.66What is the solution?x = -2.2x = -1.4x = 1.4x = 2.2f
Answer:
x = 2.2
Step-by-step explanation:
-0.45x + 0.33 = -0.66
Subtract .33 from each side
-0.45x + 0.33-.33 = -0.66-.33
-.45x = -.99
Divide each side by -.45
-.45x./-.45 = -.99/-.45
x = 11/5
x = 2.2
PLS HELP. The question is in the photo :)
Answer:
So each strawberry is 4 calories
Step-by-step explanation:
First find the slope of the line
Two points on the line are
(0,0) and (3,12)
m = (y2-y1)/(x2-x1)
= (12-0)/(3-0)
= 12/3
= 4
So each strawberry is 4 calories
researchers are interested in the average size of a certain species of mouse. They collect the length and gender of each mouse. What is the parameter likely estimated and the sample statistic
Answer:
E. The parameter is μmale - μfemale and the statistic is xmale - xfemale.
Step-by-step explanation:
The sample statistic is a piece of information about the individuals or objects that were selected from a given population. The sample is just a fraction of the total population. Since it is a herculean task studying an entire population, the sample forms a manageable size that allows us to have an insight into the entire population. The sample statistics are now the piece of information about the sample being studied such as the average, mean, median, or mode. The sample statistics have to be as specific as possible of the factors being measured. In the question, we would have to obtain the mean of both the male and female genders. This gives us an insight into the population under study.
The parameter, on the other hand, is a description of the entire population being studied. For example, we might want to determine the population mean. That is the factor we seek to measure. It is represented by the sign mu (μ).
SOMEONE HELP! (b+3)(c-4)
Answer
[tex]bc - 4b + 3c - 12[/tex]
solution,
[tex](b + 3)(c - 4) \\ = b(c - 4) + 3(c - 4) \\ = bc - 4b + 3c - 12[/tex]
hope it helps..
Answer:
[tex]bc - 4b + 3c - 12[/tex] apply de disruptive property by multiplying each term of b+3 by each term of c -4
the distance around the edge of a circular pond is 88m. the radius in meters is ?
(a)88π
(b)176π
(c)88/π
(d)88/2π
Answer: (d) 88/ 2π
Step-by-step explanation:
Perimeter = 88m
Perimeter of a circle = 2πr
88 = 2π x r
r = 88 / 2π
Answer:
88/2π = r
Step-by-step explanation:
The circumference is 88 m
The circumference is given by
C = 2*pi*r
88 = 2 * pi *r
Divide each side by 2 pi
88 / 2pi = 2 * pi *r / 2 * pi
88 / 2 pi = r
If f(x) = x² + x - 4, evaluate f(2i).
Can anyone show a step by step process to get the answer?
Answer:
-6+2i
Step-by-step explanation:
f(2i)=2i^2+2i-4
2i^2 is -2 because i^2 is-1, times 2 is -2.
Therefore, the equation becomes -2+2i-4, leaving the answer of -6+2i.
Please answer this correctly
Answer:
50%
Step-by-step explanation:
The radioactive isotope of lead, Pb-209, decays at a rate proportional to the amount present at time t and has a half-life of 3.3 hours. If 1 gram of this isotope is present initially, how long will it take for 95% of the lead to decay?
Answer:
[tex] N(t) =N_o (\frac{1}{2})^{\frac{t}{t_{1/2}}}[/tex]
Where [tex]t_{1/2}= 3.3 hr[/tex] represent the half life and the intial amount would be [tex] N_o = 1[/tex]
And we want to find the time in order to have a 95% of decay so we can set up the following equation:
[tex] 0.05 = 1 (0.5)^{t/3.3}[/tex]
If we apply natural log on both sides we got:
[tex] ln(0.05) = \frac{t}{3.3} ln (0.5)[/tex]
And solving for t we got:
[tex] t= 3.3 *\frac{ln(0.05)}{ln(0.5)}= 14.26[/tex]
So then would takes about 14.26 hours in order to have 95% of the lead to decay
Step-by-step explanation:
For this case we can define the variable of interest amount of Pb209 and for the half life would be given:
[tex] N(t) =N_o (\frac{1}{2})^{\frac{t}{t_{1/2}}}[/tex]
Where [tex]t_{1/2}= 3.3 hr[/tex] represent the half life and the intial amount would be [tex] N_o = 1[/tex]
And we want to find the time in order to have a 95% of decay so we can set up the following equation:
[tex] 0.05 = 1 (0.5)^{t/3.3}[/tex]
If we apply natural log on both sides we got:
[tex] ln(0.05) = \frac{t}{3.3} ln (0.5)[/tex]
And solving for t we got:
[tex] t= 3.3 *\frac{ln(0.05)}{ln(0.5)}= 14.26[/tex]
So then would takes about 14.26 hours in order to have 95% of the lead to decay
The hourly rate for a staff nurse is £13.75.
A staff nurse works 30 hours a week and 6 hours overtime at time-and-a-half.
What is her total pay for the week?
Answer:
P = £536.25
Her total pay for the week is £536.25
Step-by-step explanation:
The total pay can be written as;
P = t1(r1) + t2(r2)
Where;
t1 = normal time
r1 = normal time pay rate
t2 = overtime
r2 = overtime pay rate
Given;
t1 = 30 hours
t2 = 6 hours
r1 = £13.75
r2 = 1.5(r1) = 1.5(£13.75)
Substituting the given values into the equation 1;
P = 30(£13.75) + 6(1.5(£13.75))
P = £536.25
Her total pay for the week is £536.25
A certain group of test subjects had pulse rates with a mean of 80.9 beats per minute and a standard deviation of 10.7 beats per minute. Use the range rule of thumb to identify the limits separating values that are significantly low or significantly high. Is a pulse rate of 142.3 beats per minute significantly low or significantly high?
Answer:
We want to find the usual limits using the rule of thumb and for this case rule states that we have most of the values within 2 deviations from the mean so then we can find the usual limits like this:
[tex] \mu -2*\sigma = 80.9 -2*10.7= 59.5[/tex]
[tex] \mu +2*\sigma = 80.9 -2*10.7= 102.3[/tex]
And for this case a value of 142.3 is higher than the upper limti so then we can conclude that would be significantly high with the rule of thumb criteria
Step-by-step explanation:
For this case we have the follwing info given:
[tex] \mu = 80.9[/tex] represent the mean
[tex]\sigma = 10.7[/tex] represent the deviation
We want to find the usual limits using the rule of thumb and for this case rule states that we have most of the values within 2 deviations from the mean so then we can find the usual limits like this:
[tex] \mu -2*\sigma = 80.9 -2*10.7= 59.5[/tex]
[tex] \mu +2*\sigma = 80.9 -2*10.7= 102.3[/tex]
And for this case a value of 142.3 is higher than the upper limti so then we can conclude that would be significantly high with the rule of thumb criteria
The regular price of a baseball cleats is $80. If the cleats are on sale for 45% off.
then:
a) What is the value of the discount, in dollars?
b) What is the final selling price of the cleats, before tax?
a) $36.
b) $44.
- I hope this helps.
Mary invested $200 for 3 years at 5% per annum. John invested $300 at the same rate. If they both received the same amount of interest how much did john invest???
Answer:
Step-by-step explanation:
The electric field in the xy-plane due to an infinite line of charge along the z-axis is a gradient field with a potential function
V(x,y)equals=c ln (ro/√ x²+y²)
where c > 0 is a constant and r0 is a reference distance at which the potential is assumed to be 0.
Required:
Find the components of the electric field in the x- and y-directions, where E(x,y) =∇V (x,y )
Answer:
c(x,y)/(x²+y²)
Step-by-step explanation:
Since E(x,y) = -∇V (x,y ) and V(x,y) =c ln (ro/√ x²+y²)
Let ro/√(x²+y²) = u and √(x²+y²) = v
dV/du = c/u = c√(x²+y²)/ro,
du/dv = -ro/(x²+y²) = -ro/² and dv/dx = x/√(x²+y²)
Using the chain rule,
So dV/dx = dV/du × du/dv × dv/dx
= c√(x²+y²)/ro × -ro/(x²+y²) × x/√(x²+y²)
dV/dx = -cx/(x²+y²)
- dV/dx = -(-cx/(x²+y²)) = cx/(x²+y²)
Also, dv/dy = y/√(x²+y²)
Using the chain rule
dV/dy = dV/du × du/dv × dv/dy
= c√(x²+y²)/ro × -ro/(x²+y²) × y/√(x²+y²)
dV/dy = -cy/(x²+y²)
- dV/dy = -(-cy/(x²+y²)) = cy/(x²+y²)
E(x,y) = -∇V (x,y )
= -(dV/dx)i + [-(dV/dy)]j
= [cx/(x²+y²)]i +[ cy/(x²+y²)]j
= c(x,y)/(x²+y²)
AHH!! PLEASE HELP ME IM STUCK :(
Answer:
x = 6
Step-by-step explanation:
Compare the given formula to the equations shown in the attachment. First of all, you see that all of the numbers are scaled by a factor of 4. Removing that gives ...
[tex]r=\dfrac{6.6}{1+1.1\cos{\theta}}=\dfrac{1.1\cdot6}{1+1.1\cos{\theta}}[/tex]
This matches the formula for the hyperbola with e=1.1 and d=6, for a directrix of x = 6.
a. What is a residual? b. In what sense is the regression line the straight line that "best" fits the points in a scatterplot? a. What is a residual?
Answer:
a. A residual is how far off a point is from the expected value. For example, if I were to estimate the weight of my Southeastern Lubber Grasshopper, I would say it's maybe 5 ounces. But, in reality, it might be 4 ounces. So, the residual would be the reality minus the prediction, or 4 - 5, or -1 ounce.
b. The regression line is the line of predicted values for the points in the scatterplot. It tries to predict the points and make all the points be on the line.
Hope this helps!
what it 17.15 in 12hour clock
Answer:
Step-by-step explanation:
Hello friend
The answer is 5:15 in 12 hour clock
Answer:
5:15 PM
Step-by-step explanation:
12:00 + 5:00
17:00 in 12 hour clock is 5:00 PM.
15 minutes + 5:00 PM
⇒ 5:15 PM
solve for x.
x/3 < -6
Answer: x < -18
Step-by-step explanation:
Simply multiply both sides by three to get x < -18
Step-by-step explanation:
x/3 < - 6
x < - 18
This should be the answer
9) BRAINLIEST & POINTS!
Answer:
no supplement
Step-by-step explanation:
Supplementary angles add to 180 degrees
312 is greater than 180 degrees by itself, so it has no supplement
If f(x)=x/2+8what if f(x) when x=10
Answer:
f(10)=13
Step-by-step explanation:
f(x)=x/2+8
Let x = 10
f(10)=10/2 +8
= 5 + 8
= 13
In the figure angle G measures 102° and angle B measures 30° what is the measurement of angle B
Answer:
I hope this helps
Step-by-step explanation:
Need Assistance With This Problem
Answer:
not sure how to really answer this question.
Answer:
4.56, 4.65, 5.46, 5.64, 6.45, 6.54
Step-by-step explanation:
First we have to compare the first digits in each number as less is this digit as less is the number. So the least off all are
4.56 and 4.65
which of these two numbers is least ? Now we have to look to the 2-nd digits of these numbers:
they are 5 and 6 . 5<6 so 4.56<4.65
Lets select next numbers whicj first digit is 5. They are:
5.46 and 5.64. However the second digit of the number 5.64 -6 is bigger than the second digit of number 5.46 -4. That is why 5.46<5.64
Similarly 6.45< 6.54
Assume that adults have IQ scores that are normally distributed with a mean of 94 and a standard deviation of 14. Find the probability that a randomly selected adult has an IQ greater than 107.1. (Hint: Draw a graph.) To help visualize the area of interest, draw a standard normal curve. Label the given values for x and mu . x 94107.1
Answer:
0.6517
Step-by-step explanation:
z = (x - μ)/σ
Z= standard score
x= observed value
μ= mean of the sample
σ= standard deviation of the sample
z = (x - μ)/σ = (107.1 - 94 )/ 14 = 0.9357
probability that a randomly selected adult has an IQ greater than 107.1. = P(Z > 0.935) = 0.6517
NB: the value is 0.6517 is pulled from the z table which can be found at the back of most math text.
Write an equation of the line with the given slope, m and the y- intercept (o,b)
m = 4, b = 9
The equation is
Answer:
y=4x+9
Step-by-step explanation:
replace m with 4, which is the slope you gave, and
replace b with 9, the y-intercept you gave,
in the equation y=mx+b.
I want to fence in a rectangular vegetable patch. The fencing for the east and west sides costs $2 per foot, and the fencing for the north and south sides costs only $1 per foot. I have a budget of $40 for the project. What is the largest area I can enclose
Answer:
largets area is 32 feet cubed
Step-by-step explanation:
8=4 foot 2 for each side w and e and 32feet n and s 16 each side
PLEASE QUICK!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! Which number completes the system of linear inequalities represented by the graph? y > 2x – 2 and x + 4y > -12 -3 4 6
Answer:
-12
Step-by-step explanation:
Edge 2021