Assume the clock for a 4-bit binary counter is 80 kHz. The output frequency of the fourth stage (Q3) is

Answer:

5kHz

Explanation:

There are four stages so N = 2⁴ = 16.

The frequency at nth stage is given by

[tex]f_n = \frac{f_{clk}}{N} = \frac{80kHz}{16} = 5kHz[/tex]

The output frequency of the fourth stage (Q3) is 5kHz. Thus the correct option is A.

On each clock cycle, the 4-bit synchronous counter successively counts up from 0 (0000) to 15 as outputs ( 1111 ). It is also known as a 4-bit Synchronous Up Counter as result.

We required four Flip Flops to create a 4-bit counter, as indicated by the number 4 Flip Flops. The counter also has a reset pin, which enables it to enter an all-zero mode in which its output is "0."

The Q output of the previous flip-flop triggers the CLK input in the 4-bit counter above, as opposed to the Q output as in the up counter configuration, where the output of each flip-flop changes state on the rising edge.

There are four stages so N = 2⁴ = 16.

The 4-bit binary counter is 80 kHz.

In order to calculate the output frequency the  4-bit binary counter is divided by 16 which is equal to 5kHz.

Therefore, option A  is appropriate.

Learn more about the 4-bit binary counter, here:

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The complete question is Probably

Assume the clock for a 4-bit binary counter is 80 kHz The output frequency of the fourth stage (Q3) is. a) 5kHz. b) 10 kHz. c) 20 kHz. d) 320 kHz.