The 40th percentile for X is approximately 67.98. To find the 40th percentile for X, we need to use a standard normal distribution table or calculator.
We first need to standardize the random variable X by subtracting the mean and dividing by the standard deviation:
z = (X - mean) / standard deviation
z = (X - 70) / 8
We can then find the z-score corresponding to the 40th percentile, which is -0.253:
z = invNorm(0.4)
z = -0.253
Using this z-score and the formula for standardizing a random variable, we can solve for X:
z = (X - 70) / 8
-0.253 = (X - 70) / 8
-2.024 = X - 70
X = 67.976
Therefore, the 40th percentile for X is approximately 67.98.
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Helpppp (FIND THE LENGTH OF THE MAJOR ARC)
Answer:
290 degrees
Step-by-step explanation:
To find the length of the major arc subtracts 360-70.
You do this because angle LKM is a central angle, so the arc of LKM will be the same as the angle which is 70. If LKM was an inscribed angle the arc angles would be twice the degrees as the inscribed angle. And because arc LNM is a major arc and because a circle is 360 degrees all you have to do is subtract 70 from 360.
The image below shows an inscribed angle and a central angle.
Find
(sec A x sin C - tan A x tan C)/sin B
where
A triangle ABC is right angled at B
The given expression, (sec A x sin C - tan A x tan C)/sin B, simplifies to (x/40) x AB, where AB is the length of the side opposite the right angle in triangle ABC.
Since triangle ABC is right-angled at B, we can use the following trigonometric ratios:
sin A = opposite/hypotenuse = AC/BC
cos A = adjacent/hypotenuse = AB/BC
tan A = opposite/adjacent = AC/AB
sin C = opposite/hypotenuse = AB/BC
cos C = adjacent/hypotenuse = AC/BC
tan C = opposite/adjacent = AB/AC
Using these ratios, we can simplify the given expression as follows:
(sec A x sin C - tan A x tan C)/sin B
= [(1/cos A) x sin C - tan A x tan C]/sin B (using sec A = 1/cos A)
= [(1/cos A) x (AB/BC) - (AC/AB) x (AB/AC)]/sin B (substituting sin C and tan C)
= [(AB/BCcos A) - (AC/BC)]/sin B (simplifying)
= [(AB/BC) - (ACcos A/BCcos A)]/sin B (getting a common denominator)
= [(AB - ACcos A)/BC]/sin B (simplifying)
= [(AB - ABsin A)/BC]/sin B (substituting)
Since triangle ABC is right-angled at B, we can use the following trigonometric ratios:
sin A = opposite/hypotenuse = AC/BC
cos A = adjacent/hypotenuse = AB/BC
tan A = opposite/adjacent = AC/AB
sin C = opposite/hypotenuse = AB/BC
cos C = adjacent/hypotenuse = AC/BC
tan C = opposite/adjacent = AB/AC
Using these ratios, we can simplify the given expression as follows:
(sec A x sin C - tan A x tan C)/sin B
= [(1/cos A) x sin C - tan A x tan C]/sin B (using sec A = 1/cos A)
= [(1/cos A) x (AB/BC) - (AC/AB) x (AB/AC)]/sin B (substituting sin C and tan C)
= [(AB/BCcos A) - (AC/BC)]/sin B (simplifying)
= [(AB/BC) - (ACcos A/BCcos A)]/sin B (getting a common denominator)
= [(AB - ACcos A)/BC]/sin B (simplifying)
= [(AB - ABsin A)/BC]/sin B (substituting sin A = AC/BC)
= [AB(1 - sin A)/BC]/sin B (factoring out AB)
= [(AB/BC) x (cos A/sin A)]/sin B (using sin A = opposite/hypotenuse and cos A = adjacent/hypotenuse)
= [cot A x (AB/BC)]/sin B (using cot A = cos A/sin A)
= (AB/BC) x (cos A/sin A) x (1/sin B) (multiplying fractions)
= (AB/BC) x (cos A/sin A) x csc B (using csc B = 1/sin B)
= (AB/BC) x cot A x csc B (using cot A = cos A/sin A)
= (BC/AB) x tan A x sin B (taking the reciprocal of both sides)
= (2BC/2AB) x (sin B/cos B) x (sin A/cos A) (multiplying and dividing by cos B and cos A)
= (BC/AB) x (2sin Bcos A)/(2sin A cos B) (simplifying)
= (BC/AB) x (sin (B + A)/sin (A + B)) (using sum and difference formulae)
= (BC/AB) x (sin C/sin 90) (since A + B + C = 90 degrees in a right-angled triangle)
= (BC/AB) x sin C
Substituting the given values, we get:
= [(2x + 20)/80] x AB
= (x/40) x AB
Therefore, the final answer is (x/40) x AB.
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What is | –10 |
Ignore thissssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssss
Answer: 10
Step-by-step explanation:
| –10 | = 10
Because that's the number of spaces it's from 0. :-)
What is the correct set of image points for trapezoid W’X’Y’Z’?
W’(4, –2), X’(3, –4), Y’(1, –4), Z’(0, –2)
W’(4, 2), X’(3, 4), Y’(1, 4), Z’(0, 2)
W’(–2, –4), X’(–4, –3), Y’(–4, –1), Z’(–2, 0)
W’(2, 4), X’(4, 3), Y’(4, 1), Z’(2, 0)
The correct set of image points for trapezoid W’X’Y’Z’ for 180 degrees rotation is (a) W’(4, –2), X’(3, –4), Y’(1, –4), Z’(0, –2)
The set of image points for trapezoid W’X’Y’Z’From the question, we have the following parameters that can be used in our computation:
W(-4, 2), X(-3, 4), Y(-1, 4), Z(0, 2)
Rule: 180 degrees rotation
The rule of 180 degrees rotation is
(x, y) = (-x, -y)
Substitute the known values in the above equation, so, we have the following representation
W’(4, –2), X’(3, –4), Y’(1, –4), Z’(0, –2)
Hence, the image = W’(4, –2), X’(3, –4), Y’(1, –4), Z’(0, –2)
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the number of hours worked per year per person in a state is normally distributed with a standard deviation of 39. a sample of 15 people is selected at random, and the number of hours worked per year per person is given below. calculate the 98% confidence interval for the mean hours worked per year in this state. round your answers to the nearest integer and use ascending order. time 2051 2061 2162 2167 2169 2171 2180 2183 2186 2195 2196 2198 2205 2210 2211 provide your answer below:
Using a t-distribution with 14 degrees of freedom (n-1) and a 98% confidence level (α = 0.02/2 = 0.01 for each tail), we have:
sample mean (x) = (2051+2061+2162+2167+2169+2171+2180+2183+2186+2195+2196+2198+2205+2210+2211)/15 = 2180.6
sample standard deviation (s) = 39
standard error of the mean (SEM) = s/√n = 39/√15 ≈ 10.077
t-score for a 98% confidence level and 14 degrees of freedom (from t-distribution table or calculator) = 2.977
Margin of error (ME) = t-score × SEM = 2.977 × 10.077 ≈ 30.05
Therefore, the 98% confidence interval for the mean hours worked per year in this state is:
(x- ME, x+ ME) = (2180.6 - 30.05, 2180.6 + 30.05) = (2150, 2211)
Rounding to the nearest integer and putting the limits in ascending order, we get:
(2150, 2211)
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Calculate the area and circumference of a circle with diameter 8cm
There is a drawer with 10 red socks, 10 blue socks, and 10 white socks what is the least number of socks?
The least number of socks you need to pick is 10 red socks, 10 blue socks, and 10 white socks to ensure you have a matching pair. The least number of socks that can be taken from the drawer is one.
Follow these steps:
1. Pick one sock from the drawer (it could be any color, let's say red).
2. Pick a second sock from the drawer (if it's red, you have a matching pair; if not, let's say it's blue).
3. If you don't have a matching pair yet, pick a third sock from the drawer (now, it's either red, blue, or white, and you'll have a matching pair for sure).
So, the least number of socks you need to pick to ensure a matching pair is 3.
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13 Consider the system of equations below.
5x + 2y = -3
8x-6y= -14
Which of the following is a graph of this system of equations?
The graph of the system of linear equation is attached below
What is graph of system of linear equationsThe graph of a linear equation is a line. Each point on the line is a solution to the equation. For a system of two equations, we will graph two lines. Then we can see all the points that are solutions to each equation. And, by finding what the lines have in common, we’ll find the solution to the system.
In this given problem, we can use a graphing calculator to plot the lines of the graph as well as find the point of intersection which will give us our solution.
The equations given are;
5x + 2y = -3 ...eq(i)
8x - 6y = -14 ...eq(ii)
Plotting this in a graphing calculator;
We can see that the solution to this graph which is the point of intersection is at (1, 1)
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solve the proportion 9/3x-15 = 3/12
suppose that the mean daily viewing time of television is 8.35 hours. use a normal probability distribution with a standard deviation of 2.5 hours to answer the following questions about daily television viewing per household (a) what is the probability that a household views television between 4 and 12 hours a day? (round your answer to four decimal places.)
Therefore, it is approximately 0.8911, or 89.11% (rounded to four decimal places), that a household watches television for between 4 and 12 hours per day.
z = (x - μ) / σ
For part (a), we want to find the probability that a household views television between 4 and 12 hours a day. We can translate this into finding the probability that a random variable X with mean μ = 8.35 and standard deviation σ = 2.5 falls between 4 and 12:
P(4 ≤ X ≤ 12)
To find this probability, we first standardize the values 4 and 12:
z1 = (4 - 8.35) / 2.5
= -1.74
z2 = (12 - 8.35) / 2.5 = 1.46
Now that we have the area under the curve between these two z-scores, we can use a normal distribution table or calculator to determine it:
P(-1.74 ≤ Z ≤ 1.46) ≈ 0.8911
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Taylor Polynomial: Consider the approximation of the exponential by its third degree Taylor Polynomial: ex≈P3(x)=1+x+x^2/2+x^3/6
Compute the error e^x−P3(x) for various values of x.
The error between the exponential function e^x and its third degree Taylor polynomial P3(x) is given by e^x - P3(x).
Let's compute this error for various values of x:
For x = 0, we have e^0 - P3(0) = 1 - 1 = 0.
For x = 1, we have e^1 - P3(1) = e - (1 + 1 + 1/2 + 1/6) = e - 2.16667 ≈ -0.0803.
For x = -1, we have e^-1 - P3(-1) = 1/e - (1 - 1 + 1/2 - 1/6) = 0.581976 ≈ 0.582.
For x = 2, we have e^2 - P3(2) = e^2 - (1 + 2 + 4/2 + 8/6) = e^2 - 5.33333 ≈ 2.995.
For x = -2, we have e^-2 - P3(-2) = 1/e^2 - (1 - 2 + 4/2 - 8/6) = 0.133151 ≈ 0.133.
Overall, we can see that the error between the exponential function and its third degree Taylor polynomial decreases as x gets closer to 0. This is because the Taylor polynomial is centered at x = 0 and becomes a better approximation as x gets closer to the center. However, for larger values of x, the error can become quite significant.
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The histogram shows the numbers of magazines read last month by the students in a class.
A histogram, titled Magazines. The vertical axis is labeled frequency. The horizontal axis is labeled magazines read and has bins with the following intervals: For 0 to 1, the bar height is 2. For 2 to 3, the bar height is 15. For 4 to 5, the bar height is 0. For 6 to 7, the bar height is 3.
a. Which interval contains the fewest data values?
Responses
0–1
0–1
2–3
2–3
4–5
4–5
6–7
6–7
Question 2
b. How many students are in the class?
The class has
students.
c. What percent of the students read fewer than six magazines?
% read fewer than six magazines.
Skip to navigation
The histogram shows the numbers of magazines read last month by the students in a class.
A histogram, titled Magazines. The vertical axis is labeled frequency. The horizontal axis is labeled magazines read and has bins with the following intervals: For 0 to 1, the bar height is 2. For 2 to 3, the bar height is 15. For 4 to 5, the bar height is 0. For 6 to 7, the bar height is 3.
a. Which interval contains the fewest data values?
Responses
0–1
0–1
2–3
2–3
4–5
4–5
6–7
6–7
Question 2
b. How many students are in the class?
The class has
students.
c. What percent of the students read fewer than six magazines?
% read fewer than six magazines.
Skip to navigation
The histogram shows the numbers of magazines read last month by the students in a class.
A histogram, titled Magazines. The vertical axis is labeled frequency. The horizontal axis is labeled magazines read and has bins with the following intervals: For 0 to 1, the bar height is 2. For 2 to 3, the bar height is 15. For 4 to 5, the bar height is 0. For 6 to 7, the bar height is 3.
a. Which interval contains the fewest data values?
Responses
0–1
0–1
2–3
2–3
4–5
4–5
6–7
6–7
Question 2
b. How many students are in the class?
The class has
students.
c. What percent of the students read fewer than six magazines?
% read fewer than six magazines.
Skip to navigation
The histogram shows the numbers of magazines read last month by the students in a class.
A histogram, titled Magazines. The vertical axis is labeled frequency. The horizontal axis is labeled magazines read and has bins with the following intervals: For 0 to 1, the bar height is 2. For 2 to 3, the bar height is 15. For 4 to 5, the bar height is 0. For 6 to 7, the bar height is 3.
a. Which interval contains the fewest data values?
Responses
0–1
0–1
2–3
2–3
4–5
4–5
6–7
6–7
Question 2
b. How many students are in the class?
The class has
students.
c. What percent of the students read fewer than six magazines?
% read fewer than six magazines.
Skip to navigation
The histogram shows the numbers of magazines read last month by the students in a class.
A histogram, titled Magazines. The vertical axis is labeled frequency. The horizontal axis is labeled magazines read and has bins with the following intervals: For 0 to 1, the bar height is 2. For 2 to 3, the bar height is 15. For 4 to 5, the bar height is 0. For 6 to 7, the bar height is 3.
a. Which interval contains the fewest data values?
Responses
0–1
0–1
2–3
2–3
4–5
4–5
6–7
6–7
Question 2
b. How many students are in the class?
The class has
students.
c. What percent of the students read fewer than six magazines?
% read fewer than six magazines.
Skip to navigation
The histogram shows the numbers of magazines read last month by the students in a class.
A histogram, titled Magazines. The vertical axis is labeled frequency. The horizontal axis is labeled magazines read and has bins with the following intervals: For 0 to 1, the bar height is 2. For 2 to 3, the bar height is 15. For 4 to 5, the bar height is 0. For 6 to 7, the bar height is 3.
a. Which interval contains the fewest data values?
Responses
0–1
0–1
2–3
2–3
4–5
4–5
6–7
6–7
Question 2
b. How many students are in the class?
The class has
students.
c. What percent of the students read fewer than six magazines?
% read fewer than six magazines.
Skip to navigation
The histogram shows the numbers of magazines read last month by the students in a class.
A histogram, titled Magazines. The vertical axis is labeled frequency. The horizontal axis is labeled magazines read and has bins with the following intervals: For 0 to 1, the bar height is 2. For 2 to 3, the bar height is 15. For 4 to 5, the bar height is 0. For 6 to 7, the bar height is 3.
a. Which interval contains the fewest data values?
Responses
0–1
0–1
2–3
2–3
4–5
4–5
6–7
6–7
Question 2
b. How many students are in the class?
The class has
students.
c. What percent of the students read fewer than six magazines?
% read fewer than six magazines.
Skip to navigation
1. The interval contains the fewest data values is 4-5.
2. The total number of students are 20.
3. The percent of the students read fewer than six magazines is 85%.
We have histogram that shows the numbers of magazines read last month by the students in a class.
1. The interval contains the fewest data values is 4-5 as it has 0 data.
2. The total number of students are
= 2 + 15 + 0 + 3
=20
3. The percent of the students read fewer than six magazines
= 17/20 x 100
= 85%
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identify the type i error and the type ii error for a hypothesis test of the indicated claim. the percentage of adults who have a job is greater than 88%.
Type I Error: Concluding that the percentage of adults with jobs is greater than 88% when it is actually equal to 88%, Type II Error: Concluding that the percentage of adults with jobs is equal to 88% when it is actually greater than 88%
In a hypothesis test, a Type I error occurs when we reject a true null hypothesis. In the case of the indicated claim, this would mean rejecting the hypothesis that the percentage of adults who have a job is not greater than 88%, when in fact it is true. This would be a serious mistake as we would be making a false claim.
On the other hand, a Type II error occurs when we fail to reject a false null hypothesis. In this case, it would mean failing to reject the hypothesis that the percentage of adults who have a job is not greater than 88%, when in fact it is false. This error would lead us to miss the true claim that the percentage of adults who have a job is greater than 88%, which could have important implications for policy and decision-making.
Therefore, in the hypothesis test of the indicated claim, the Type I error would be to falsely claim that the percentage of adults who have a job is greater than 88%, while the Type II error would be to miss the true claim that it is indeed greater than 88%.
First, let's set up our null hypothesis (H0) and alternative hypothesis (H1):
- Null hypothesis (H0): The percentage of adults who have a job is equal to 88% (P = 0.88)
- Alternative hypothesis (H1): The percentage of adults who have a job is greater than 88% (P > 0.88)
Now, let's identify the Type I and Type II errors for this hypothesis test:
1. Type I Error: This occurs when we reject the null hypothesis (H0) when it is actually true. In this context, a Type I error would be concluding that the percentage of adults who have a job is greater than 88% (P > 0.88) when, in reality, it is equal to 88% (P = 0.88).
2. Type II Error: This occurs when we fail to reject the null hypothesis (H0) when it is actually false. In this context, a Type II error would be concluding that the percentage of adults who have a job is equal to 88% (P = 0.88) when, in reality, it is greater than 88% (P > 0.88).
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what is meant by a marginal distribution? what is meant by a conditional distribution?
A marginal distribution refers to the distribution of one variable in a dataset without taking into account the other variables. It is the probability distribution of a single random variable. On the other hand, a conditional distribution refers to the distribution of one variable in a dataset given that another variable has a specific value. It is the probability distribution of a random variable, given that another random variable has a specific value. Marginal distributions are often used to calculate overall probabilities, while conditional distributions are used to calculate probabilities under specific conditions. Marginal and conditional distributions are important concepts in statistics and are used to analyze data and make predictions. In general, marginal distributions are useful when considering the overall distribution of a dataset, while conditional distributions are useful when considering the distribution of a dataset under specific conditions or circumstances.
Hi! A "marginal distribution" is meant to describe the probability distribution of a single variable in a multivariate setting, without considering the relationships with other variables. To find the marginal distribution, you sum or integrate the joint distribution over all possible values of the other variables.
A "conditional distribution," on the other hand, is meant to describe the probability distribution of a variable given the values of one or more other variables. In this case, you focus on a specific subset of the data where the given condition(s) hold true, and then calculate the probability distribution for the variable of interest within that subset.
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The graph below shows the value of the US dollar versus the Canadian dollar.
A graph titled Value of U S Dollar versus Canadian Dollar has month on the x-axis, from October 2012 to March 2013, and Canadian Dollars per U S Dollar on the y-axis, from 0.96 to 1.04. A line is drawn to connect the points on the graph. The line is at the lowest point in October, and it is the highest in March.
According to the graph, the American dollar was the strongest during which month?
October 2012.
November 2012.
February 2013.
March 2013.
Looking at the graph, the best time to make a purchase is in month March 2013.
Exchange rate refers to the value ascribed to a particular currency in a foreign currency.
We have to find on which month the American dollar was the strongest
Usually, currency exchange rates are not static but depend on many factors.
As such, it is always advisable to carry out trading activities when the exchange rate between currencies is favorable.
Looking at the graph, the best time to make a purchase is in March 2013.
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what is the diameter of a hemisphere with a volume of 557 m 3 , 557 m 3 , to the nearest tenth of a meter?
The diameter of the hemisphere with a volume of 557 m³ is approximately 12.8 m, to the nearest tenth of a meter.
The volume of a hemisphere can be calculated using the formula V = (2/3)πr³, where V is the volume and r is the radius. Given that the volume of the hemisphere is 557 m³, we can find the radius by solving for r:
557 = (2/3)πr³
To find the radius, first, we need to isolate r³ by multiplying both sides by 3/(2π):
r³ = (3 * 557) / (2 * π)
r³ ≈ 265.18
Now, take the cube root of both sides to find the radius:
r ≈ 6.4 m
To find the diameter, simply multiply the radius by 2:
d ≈ 2 * 6.4
d ≈ 12.8 m
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Cuál de las siguientes ecuaciones modela una recta creciente?
A. 2x+4y+12=0
B. 3x−2y+3=0
C. −x−3y−12=0
D. −5x+3y+9=0
The equations that models a growing line include the following:
B. 3x − 2y + 3 = 0
D. −5x + 3y + 9 = 0
What is a steeper slope?In Mathematics, a steeper slope simply means that the slope of a line is bigger than the slope of another line. This ultimately implies that, a graph with a steeper slope has a greater (faster) rate of change in comparison with another graph.
In order to determine an equation with a growing line, we would have to determine the slope of each line graphically and then taking note of the line with a positive slope because it indicates an increasing function.
In this context, we can reasonably infer and logically deduce that both 3x − 2y + 3 = 0 and −5x + 3y + 9 = 0 are equations that models a growing line.
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Complete Question:
Which of the following equations models a growing line?
A. 2x+4y+12=0
B. 3x−2y+3=0
C. −x−3y−12=0
D. −5x+3y+9=0
Education: College Graduates - A local professor claims that college graduates in his program earn an annual salary of $53,500 or more in the first year after the completion of their master's degree. A rival university's faculty dispute that claim and claim that the actual value is less than that. A random sample of 20 program graduates found they earned an annual salary of $50,994 in the first year after the completion of their master's degree with a standard deviation of $521. Use a 5% error. What is the critical value for this problem? O-1.729 0-1.645 1.645 1.729
The critical value for this problem would be 1.729, as this corresponds to a 5% error level and a two-tailed test.
To explain further, we can use hypothesis testing to determine whether the claim made by the local professor is supported by the sample data.
H0: The true mean salary for college graduates in the program is equal to or less than $53,500.
And our alternative hypothesis as:
Ha: The true mean salary for college graduates in the program is greater than $53,500.
We can then use the sample mean and standard deviation to calculate the test statistic:
t = (sample mean - hypothesized mean) / (standard deviation / sqrt(sample size))
t = (50994 - 53500) / (521 / sqrt(20))
t = -2.01
Using a t-distribution table with 19 degrees of freedom (sample size minus 1), and a significance level of 0.05 (corresponding to a 5% error), we can find the critical value for a two-tailed test:
t_critical = +/- 2.093
Since our calculated test statistic falls outside of the critical value range, we can reject the null hypothesis and conclude that there is evidence to suggest that the true mean salary for college graduates in the program is less than $53,500. Therefore, the rival university's faculty may have a valid point in disputing the local professor's claim.
To find the critical value for this problem, we will use a one-tailed t-test since we want to test if the actual value is less than $53,500.
Given:
- Sample size (n) = 20 graduates
- Significance level (α) = 5% or 0.05
- Degrees of freedom (df) = n - 1 = 20 - 1 = 19
Now, let's find the critical value (t) using the t-distribution table. For a one-tailed test at a 5% significance level and 19 degrees of freedom, the critical value is -1.729.
So, the critical value for this problem is -1.729.
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five hundred teenagers were sampled at random about their favorite movie genre. the results are listed in the table below. out of a population of three thousand teenagers, about how many will prefer action movies?
Out of the 500 teenagers sampled at random, the table presents their preferences in terms of favorite movie genres. To estimate the number of teenagers out of a population of 3,000 who prefer action movies, we can use the proportion of action movie fans from the sample.
Let's say the table shows that "x" out of the 500 sampled teenagers prefer action movies. To find the proportion of action movie fans in the sample, we divide the number of action movie fans by the total number of teenagers in the sample:
Proportion of action movie fans = (x / 500)
Now, we can use this proportion to estimate the number of teenagers who prefer action movies in the entire population of 3,000 teenagers. To do this, multiply the proportion of action movie fans by the total population:
[tex]Estimated action movie fans = Proportion of action movie fans * Total population[/tex]
Estimated action movie fans = (x / 500) * 3,000
By calculating this value, we can estimate the number of teenagers in the population of 3,000 who will prefer action movies based on the results of the random sample.
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Select ALL that are properties of isosceles trapezoids.
Group of answer choices
consecutive angles are supplementary
One pair of opposite parallel sides
Diagonals are congruent
Two pairs of opposite parallel sides
Opposite angles are congruent
base angles are congruent
Diagonals bisect each other
The answer is: one pair of opposite parallel sides, congruent diagonals, and congruent base angles.
What are the properties of an isosceles trapezoids?An isosceles trapezoid has the following properties:
- One pair of opposite parallel sides
- Diagonals are congruent
- Congruent base angles
As a result, the right options are:
- One set of opposite parallel sides
- Congruent diagonals
- Congruent base angles
Hence, answer is: one pair of opposite parallel sides, congruent diagonals, and congruent base angles.
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A recipe that makes s for 2/3 cup of flour how much flour is required to make 20 servings.
Answer:
14/13
Step-by-step explanation:
40/3
If these two shapes are similar, what is the measure of the missing length q?
[tex]\cfrac{q}{10}=\cfrac{98}{49}\implies \cfrac{q}{10}=2\implies q=20[/tex]
In a positively skewed distribution, what order (left to right) will we find the mean, median and more
So the order from left to right would be: Mode, Median, Mean.
In a positively skewed distribution, the mean is typically larger than the median, and the median is larger than the mode.
This can be illustrated in the following way:
Mean: The mean is affected by extreme values in the tail of the distribution, and will be pulled in the direction of the skew. Therefore, in a positively skewed distribution, the mean will be to the right of the median.
Median: The median is the value that separates the lower 50% of the data from the upper 50% of the data. In a positively skewed distribution, the tail of the distribution is on the right-hand side, which means that the median will be closer to the left-hand side than the mean.
Mode: The mode is the most frequent value in the distribution. In a positively skewed distribution, the mode will be the smallest value, located at the left-hand side of the distribution, while the mean and median will be to the right of it.
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a banker is interested in the percentage of banking customers who have a money market savings account. based on a recent banking newsletter, 50% of banking customers have a money market savings account. the banker believes this percent has decreased in recent months. if the banker wants to convert their test statistic to a probability, what is this called in hypothesis testing?
In hypothesis testing, converting a test statistic to a probability is called p-value. The p-value is the probability of obtaining a test statistic as extreme as the observed one or more extreme, assuming the null hypothesis is true.
If the p-value is less than the chosen level of significance, typically 0.05 or 0.01, the banker would reject the null hypothesis and conclude that there is evidence to support the alternative hypothesis, which is that the proportion of banking customers with a money market savings account has decreased. If the p-value is greater than the chosen level of significance, the banker would fail to reject the null hypothesis and conclude that there is not enough evidence to suggest that the proportion has decreased.
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How much energy is required to raise the temperature of 12.2 grams of gaseous nitrogen from 24.5 °C to 39.3 °C ?
Approximately 187.97 Joules of energy is required to raise the temperature of 12.2 grams of gaseous nitrogen from 24.5 °C to 39.3 °C.
To calculate the energy required to raise the temperature of 12.2 grams of gaseous nitrogen from 24.5°C to 39.3°C, we need to use the following formula:
Q = m x c x ΔT
Where Q is the energy required (in joules), m is the mass of the substance (in grams), c is the specific heat capacity of the substance (in J/g°C), and ΔT is the change in temperature (in °C).
The specific heat capacity of nitrogen gas at constant pressure is approximately 1.04 J/g°C. Therefore, we can calculate the energy required as follows:
Q = 12.2 g x 1.04 J/g°C x (39.3°C - 24.5°C)
Q = 163.52 J
Therefore, it would require 163.52 joules of energy to raise the temperature of 12.2 grams of gaseous nitrogen from 24.5°C to 39.3°C.
To calculate the energy required to raise the temperature of 12.2 grams of gaseous nitrogen from 24.5 °C to 39.3 °C, you can use the formula:
q = mcΔT
where:
- q is the energy required (in Joules)
- m is the mass of the substance (in grams)
- c is the specific heat capacity of the substance (in J/g°C)
- ΔT is the change in temperature (in °C)
For gaseous nitrogen, the specific heat capacity (c) is approximately 1.04 J/g°C.
Now, let's calculate the energy required:
1. Calculate the mass (m): 12.2 grams
2. Calculate the change in temperature (ΔT): 39.3°C - 24.5°C = 14.8°C
3. Use the formula q = mcΔT:
q = (12.2 g) * (1.04 J/g°C) * (14.8 °C)
q ≈ 187.97 Joules
So, approximately 187.97 Joules of energy is required to raise the temperature of 12.2 grams of gaseous nitrogen from 24.5 °C to 39.3 °C.
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A circle has a circumference of 7{,}8507,8507, comma, 850 units. What is the radius of the circle?
Use 3. 14 for pi and enter your answer as a decimal
Average Cost Graph The total daily cost in dollars) of producing a mountain bikes is given by C(x) = 936 +80+ 0.12 The average cost function C(x) decreases until e = cand increases afterwards. If the goal of the company is to make the mountain bike as affordable as possible, they should target the production level of c mountain bikes daily Find c Round to 2 decimal places. mountain bikes daily
The given function is C(x) = 936 + 80x + 0.12x^2, where x represents the number of mountain bikes produced daily. The average cost function is also given by C(x).
To make the mountain bike as affordable as possible, the company should target a production level of 333.33 mountain bikes daily, where the average cost function is at its minimum. Rounded to 2 decimal places, the answer is
c = 333.33.
First, let's correct the given cost function: C(x) = 936x + 80x^2 + 0.12x^3. Now, we'll use the terms "function," "average," and "increases."
To find the average cost function, we need to divide the total cost function, C(x), by the number of mountain bikes produced daily, x. Let A(x) represent the average cost function:
A(x) = C(x) / x
Now, let's substitute C(x) into this equation:
A(x) = (936x + 80x^2 + 0.12x^3) / x
Simplify by canceling out an x term:
A(x) = 936 + 80x + 0.12x^2
To find the production level c where the average cost function decreases and then increases, we need to find the minimum point on the A(x) curve. To do this, we'll differentiate A(x) with respect to x to obtain the first derivative:
A'(x) = 80 + 0.24x
Now, set the first derivative equal to zero and solve for x:
80 + 0.24x = 0
0.24x = -80
x = c = -80 / 0.24
Round to 2 decimal places:
c ≈ 333.33
So, to make the mountain bike as affordable as possible, the company should target a production level of approximately 333.33 mountain bikes daily.
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Find the zeros of each function.
h(x) = 6x² + x − 1
The zeros of the function h(x) = 6x² + x − 1 are x = 1/3 and x = -1/2.
What are the zeros of the given function?Given the function in the question:
h(x) = 6x² + x − 1
To determine the zeros of the function, we need to solve for x when h(x) equals zero.
Plug in h(x) = 0
0 = 6x² + x − 1
6x² + x − 1 = 0
We can use the quadratic formula to solve for x:
x = [-b ± √(b² - 4ac)] / 2a
where a, b, and c are the coefficients of the quadratic equation.
In the function, a = 6, b = 1, and c = -1.
Plug these values into the above formula
x = [-1 ± √(1² - 4(6)(-1))] / 2(6)
x = [-1 ± √(1 + 24)] / 12
x = [-1 ± √(25)] / 12
x = [-1 ± 5] / 12
Hence, the zeros of the function are:
x = (-1 + 5) / 12 = 4/12 = 1/3
and
x = (-1 - 5) / 12 = -6/12 = -1/2
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i dont know what to write here the question is there
Answer:
53.93 cm
Step-by-step explanation:
The given arc is 38.95 and the angle is 260 degrees.
A full angle would be 360 degrees, so we can use a ratio to find what the full circle would be:
260/360 = 38.95/x
This equation is saying that 38.95 is equal to 260 degrees of the circle, while x is equal to 360 degrees.
Solving for x:
260x = 14022
x = 53.9306792
Round and it is:
53.93 cm
Pablo recorded the colors of cars driving by his house. The table below shows the colors of the last 250 cars that drive by Pablo’s house
The probability that the next car to drive by Pablo's house will be red or blue is 12 / 25.
How to calculate the probabilityFor given data probabilities are,
color no. of cars probability
blue 70 0.28
green 30 0.12
red 50 0.2
white 80 0.32
yellow 20 0.08
total 250 1
Hence, the probability that the next car to drive by Pablo's house will be red or blue is,
= P(car drived will be red) + P(car drived will be blue)
= (50 / 250) + (70 / 250)
= 12/25
The probability is 12/25
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