Ashton is depositing money into a checking account. After 3 months there is $120 in the account. After 6 months, there is $240 in the account. Determine the constant rate of change of the account.

Answers

Answer 1

The constant rate of change of the account is $40 or Increasing by $40 per month.

Step-by-step explanation:

Consider the provided information.

Joanne is depositing money into a bank account. After 3 months there is $120 in the account. After 6 months there is $240 in the account.

Rate of change is known as how one quantity change in relation to other.

The rate of change can be calculated as:

y2-y1/x2-x1  

Now use the above formula to calculated the rate of change.

240 - 120/6-3

120/3

40

Hence, the constant rate of change of the account is $40 or Increasing by $40 per month.


Related Questions

What is the equation of the line that passes through the point (5,2) and has a slope
of -3/5

Answers

Answer:y = -0.6x + 5

Step-by-step explanation:

Answer:

yessir the one on top is right btw

Step-by-step explanation:

hope this helped

If you bake 3/4 of a cake in 5/6 of an hour, how long does it take to bake 18 cakes

Answers

Answer: 15

Step-by-step explanation: 5/6 times 18 = 15 hours

I think that it would be 20 hours

Find the area of the shape shown below

Answers

Answer:

18 MARK AS BRAINLIEST OR ELSE!!!!

Step-by-step explanation:

area = 1/2h(sum of bases)

area = 1/2x3(3+9)

area = 1/2 of 36

area = 18

A total of 710 tickets were sold for the school play . They were either adult tickets or student tickets. There were 60 more student tickets sold than adult tickets. How many adult tickets were sold ?

Answers

Answer: 325

Explanation:

Let the number of adult tickets be x

( since there are an unknown amount of tickets for adults, we already know how many student tickets there are)

Let the number of student tickets be x+60

710=x+x+60

710=2x+60

 -60        -60

650=2x

650/2

= 325

Adult tickets=325

Student tickets=385

         


The sum of two numbers is 38. The smaller number is 22 less than the larger number. What are the numbers?

Answers

Answer:

30 and 8

Step-by-step explanation:

30 - 8 = 22

Which ordered pair is a solution to the equation below? 3x + 2y = 10
Question 1 options:

(4, 0)

(6, -4)

(-1, 4)

Answers

Answer:

(6,-4)

Step-by-step explanation:

I have tried replacing each option with x, y in the equation.

Let's replace (6, -4) with x and y

3x+2y=10

3(6)+2(-4)=10

3(6)= 18 2(-4)= -8

18+(-8)=10

in other words:

18-8=10

The statement is true, so the correct answer is:

(6, -4)

What value of θ makes the statement true?
cos(θ)=sin(θ/3−10)

Answers

The required value of  θ  for the trigonometric function cos(θ)=sin(θ/3-10) is 60°.

What are trigonometric functions?

The  basic Trigonometric functions are sine, cosine, tangent, secant, cosecant and cotangent.

The given equation is,

cos(θ)=sin(θ/3-10)          (1)

To find the value of θ,

Change the whole equation into one trigonometric function,

Since, cos(θ)=sin(90-θ)

Substitute this value in equation (1)

sin(90-θ)=sin(θ/3-10)

⇒90-θ=θ/3-10

⇒4θ/3=80

⇒θ=60

The value of θ is 60°.

To know more about Trigonometric Function on:

https://brainly.com/question/15768633

#SPJ2

plsss help 6th grade math

Answers

Answer:  D

Step-by-step explanation:

If you put -5 and +5 on a number line and count their distance from zero they are both the same distance.

C
Kris is cutting ribbon that each measure 2 ft
long. If Kris is cutting from a piece that measures
8zft
, how many pieces can Kris cut?

Answers

Answer:

4

Step-by-step explanation:

because 2+2+2+2=8 pretty self explanatory

Answer:

13

Step-by-step explanation:

How do you do these two questions?

Answers

Answer:

(x − π)⁷ / 5040

(x − 1)³ / 16

Step-by-step explanation:

Taylor series expansion of a function is:

f(x) = ∑ₙ₌₀°° f⁽ⁿ⁾(x₀) / n! (x − x₀)ⁿ

where f⁽ⁿ⁾(x₀) is the nth derivative evaluated at x₀.

For the first problem, f(x) = sin x and x₀ = π.  We want the seventh degree term, so n = 7.

The seventh degree term is therefore: f⁽⁷⁾(π) / 7! (x − π)⁷

Find the seventh derivative of sin x:

f(x) = sin x

f⁽¹⁾(x) = cos x

f⁽²⁾(x) = -sin x

f⁽³⁾(x) = -cos x

f⁽⁴⁾(x) = sin x

f⁽⁵⁾(x) = cos x

f⁽⁶⁾(x) = -sin x

f⁽⁷⁾(x) = -cos x

Evaluated at π, f⁽⁷⁾(x) = 1.  So the seventh degree term is (x − π)⁷ / 5040.

For the second problem, f(x) = √x and x₀ = 1.  We want the third degree term,  so n = 3.

The third degree term is therefore: f⁽³⁾(1) / 3! (x − 1)³

Find the third derivative of √x:

f(x) = √x

f⁽¹⁾(x) = ½ x^-½

f⁽²⁾(x) = -¼ x^-³/₂

f⁽³⁾(x) = ⅜ x^-⁵/₂

Evaluated at 1, f⁽³⁾(x) = ⅜.  So the third degree term is (x − 1)³ / 16.

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