Answer: find the answer in the explanation
Explanation:
When a magnet is placed at the centre of the paper, and the nails are sprinkled on the paper, what will happen to the nails is that, the nails will form a pattern on the paper according to the magnetic field of the bar magnetic pole.
Other phenomena you can observe are:
1.) The nails will align themselves and show some lines of forces which is equivalent to the magnetic field lines
2.) The direction of the line of forces
3.) The strength of the magnetic field pole.
What are the units of impulse
Answer:
Newton Second
Explanation:
The SI unit of impulse in Newton Second (N.s)
Elements in the same periodic table group have the same___
Answer:
elements in the same periodic table group have the same valence electrons
Supriya has a pre-paid electricity connection at home. On a sultry Sunday afternoon, she checks that she only has ₹9 left in the balance. She wants to use the air conditioner (AC), rated at 1.2 kW. The price of electricity is ₹10 /unit in her area. How long can she run the AC before her balance is over and the power runs out?
Answer: 0.75 hour(s) or 45 minutes
Explanation:
1 unit of electricity = 1kwh
Amount of energy consumed by 1kw load in one hour
Price per unit = ₹10
Air conditioner rating(power) = 1.2Kw
Given that balance = ₹9
Therefore, supriya's total energy cost = energy balance = ₹9
Total energy cost = power in kilowatt × time of operation (in hour) × cost per unit
₹9 = 1.2kw × time × ₹10
₹9 = 12 × time
Time = 9 / 12
Time = 0.75 hours
0.75 × 60 = 45 minutes
A speeding truck travels in the positive x direction. It hits a car traveling in the positive y direction. The vehicles are deformed and travel together at an
angle with the positive x-axis. What can you say about the kinetic energy of the system after the collision?
Kinetic energy of the system is conserved.
B.
Kinetic energy of the system is partially used up in the deformation of the vehicles
Kinetic energy of the system is unrelated to the deformation of the vehicles.
C.
D.
Kinetic energy of the system is completely transformed to heat energy
Answer:
B. Kinetic energy of the system is partially used up in the deformation of the vehicles.
Explanation:
In an inelastic collision, momentum is conserved, but kinetic energy is not. Kinetic energy is lost as heat or lost in the deformation of the objects.
The correct statement about Kinetic energy of the system after the collision is that KE of the system will be partially used up in the deformation of the vehicles. Hence, option B is correct.
What is Kinetic energy?The force that an object has because it is moving is known as kinetic energy in physics. It is defined as the quantity of effort required to accelerate anybody of a specific mass from rest to its specified velocity. The body keeps its kinetic energy after acquiring it during acceleration, barring changes in speed.
When slowing from its current pace to a condition of rest, the body expends the very same amount of energy. Any term in the Lagrangian of a system that has a derivative in regard to time is formally referred to as kinetic energy.
The momentum of an object is conserved, but kinetic energy is not in an inelastic collision. In the form of heat or by the distortion of the objects, kinetic energy is lost.
To know more about kinetic energy:
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A ball is falling at terminal velocity. Terminal velocity occurs when the ball is in equilibrium and the forces are balanced. Which free body diagram shows the ball falling at terminal velocity? A free body diagram with one force pointing downward labeled F Subscript g Baseline 20 N. A free body diagram with 2 forces: the first pointing downward labeled F Subscript g Baseline 20 N and the second pointing upward labeled F Subscript air Baseline 20 N. A free body diagram with 2 forces. The first pointing downward labeled F Subscript g Baseline 20 N and the second pointing upward labeled F Subscript air Baseline 5 N. A free body diagram with 2 forces: the first pointing downward labeled F Subscript g Baseline 20 N and the second pointing upward labeled F Subscript air Baseline 30 N.
Answer:
A free body diagram with 2 forces: the first pointing downward labeled F Subscript g Baseline 20 N and the second pointing upward labeled F Subscript air Baseline 20 N.
Explanation:
This is because at terminal velocity, the ball stops accelerating and the net force on the ball is zero. For the net force to be zero, equal and opposite forces must act on the ball, so that their resultant force is zero. That is F₁ + F₂ = 0 ⇒ F₁ = -F₂
Since F₁ = 20 N, then F₂ = -F₁ = -20 N
So, if F₁ points upwards since it is positive, then F₂ points downwards since it is negative.
So, a free body diagram with 2 forces: the first pointing downward labeled F Subscript g Baseline 20 N and the second pointing upward labeled F Subscript air Baseline 20 N best describes the ball falling at terminal velocity.
Answer:
b
Explanation:
Un bombero alejado d = 31.0 m de un edificio en llamas dirige un chorro de agua desde una manguera contra incendios a nivel del suelo con un ángulo de θi = 33.0° arriba de la horizontal como se muestra en la figura siguiente. Si la rapidez del chorro cuando sale de la manguera es vi = 40.0 m/s, ¿a qué altura (en m) golpeará el edificio? m
Answer:
El chorro golpea el edificio a una altura de 15.943 metros con respecto al suelo.
Explanation:
El chorro de agua exhibe un movimiento parabólico, dado que este tiene una inclinación inicial y la única aceleración es debida a la gravitación terrestre. Las ecuaciones cinemáticas que modelan el fenómeno son:
Distancia horizontal (en metros)
[tex]x = x_{o} + v_{o}\cdot t \cdot \cos \theta[/tex]
Donde:
[tex]x_{o}[/tex] - Posición horizontal inicial, medida en metros.
[tex]t[/tex] - Tiempo, medido en segundos.
[tex]v_{o}[/tex] - Velocidad inicial, medida en metros por segundo.
[tex]\theta[/tex] - Angulo de inclinación del chorro de agua, medido en grados sexagesimales.
Distancia vertical (en metros)
[tex]y = y_{o} + v_{o}\cdot t \cdot \sin \theta + \frac{1}{2}\cdot g \cdot t^{2}[/tex]
Donde:
[tex]y_{o}[/tex] - Posición vertical inicial, medida en metros.
[tex]g[/tex] - Constante gravitacional, medida en metros por segundo al cuadrado.
Partiendo de la primera ecuación, se despeja el tiempo:
[tex]t = \frac{x - x_{o}}{v_{o}\cdot \cos \theta}[/tex]
Si [tex]x = 31\,m[/tex], [tex]x_{o} = 0\,m[/tex], [tex]v_{o} = 40\,\frac{m}{s}[/tex] and [tex]\theta = 33^{\circ}[/tex], entonces:
[tex]t = \frac{31\,m-0\,m}{\left(40\,\frac{m}{s} \right)\cdot \cos 33^{\circ}}[/tex]
[tex]t = 0.924\,s[/tex]
La altura máxima se calcula por sustitución directa de términos en la segunda ecuación. Si [tex]y_{o} = 0\,m[/tex], [tex]v_{o} = 40\,\frac{m}{s}[/tex], [tex]t = 0.924\,s[/tex] y [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], entonces:
[tex]y = 0\,m + \left(40\,\frac{m}{s} \right)\cdot (0.924\,s)\cdot \sin 33^{\circ} + \frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right) \cdot (0.924\,s)^{2}[/tex]
[tex]y = 15.943\,m[/tex]
El chorro golpea el edificio a una altura de 15.943 metros con respecto al suelo.
A transformer has 500 turns of the primary winding and 10 turns of the secondary winding. a) Determine the secondary voltage if the secondary circuit is open and the primary voltage is 120 V
Answer:
First we use the fact that the ratio of the voltage on the secondary and on the primary will be the same as the ratio of the number of turns of both coils,
u=u^2/U^1 = N^2/N^1
we evaluate the unkown secondary voltage
u^ 2=N^2/N^1 u1
We substitute the given values -
u^2= 10/500 * 120v = 2.4v
Hence, the answer is 2.4v.
Physics students study a piano being pulled across a room on a rug. They know that when it is at rest, it experiences a gravitational force of 2200 N. When it is being pulled with 1200 N it is sliding across the room in equilibrium, but the students feel like they had to pull harder than 1200 N at first to begin motion.
Answer:
4
Explanation:
hope this helps
Answer:
The static frictional force is greater than the kinetic frictional force, so the static frictional force is greater than 1200 N.
Explanation:
Edge 2021
The energy from 0.015 moles of octane was used to heat 250 grams of water. The temperature of the water rose from 293.0 K to 371.2 K. What is the enthalpy of combustion of octane? The specific heat capacity of water is 4.18 J/K g.
A. -1226 kJ/mol
B. -5448 kJ/mol
C. 293.25 kJ/mol
D. 1226 kJ/mol
Answer : The correct option is, (B) -5448 kJ/mol
Explanation :
First we have to calculate the heat required by water.
[tex]q=m\times c\times (T_2-T_1)[/tex]
where,
q = heat required by water = ?
m = mass of water = 250 g
c = specific heat capacity of water = [tex]4.18J/g.K[/tex]
[tex]T_1[/tex] = initial temperature of water = 293.0 K
[tex]T_2[/tex] = final temperature of water = 371.2 K
Now put all the given values in the above formula, we get:
[tex]q=250g\times 4.18J/g.K\times (371.2-293.0)K[/tex]
[tex]q=81719J[/tex]
Now we have to calculate the enthalpy of combustion of octane.
[tex]\Delta H=\frac{q}{n}[/tex]
where,
[tex]\Delta H[/tex] = enthalpy of combustion of octane = ?
q = heat released = -81719 J
n = moles of octane = 0.015 moles
Now put all the given values in the above formula, we get:
[tex]\Delta H=\frac{-81719J}{0.015mole}[/tex]
[tex]\Delta H=-5447933.333J/mol=-5447.9kJ/mol\approx -5448kJ/mol[/tex]
Therefore, the enthalpy of combustion of octane is -5448 kJ/mol.
Answer:
B.) -5448 kJ/mol
Explanation:
I got it correct on founders edtell
I NEED HELP PLEASE, THANKS! :)
Explain how the diffraction of light shows that light behaves like a wave.
Answer:
Diffraction of light shows that light behaves like a wave. It involves the change in the direction of waves while passing through any obstacle. Diffracted light can produce fringes of light, dark or colored bands (Just like the rainbow which is also a light wave). Diffracted light has certain wavelength, amplitude , frequency and speed which are the basic characteristics of being a wave which shows that light actually behaves like a wave.
The half-life of carbon-14 is 5730 years. How long will it take for the number of
carbon-14 nuclei in a sample to drop to a quarter of the original number?
Enter your answer as a number
years
Answer:
11460 years
Explanation:
Let N₀ be the initial amount of carbon present. After one half-life, its value is N₀/2, after two half-lives, it is N₀/4 = N₀/2². After n nalf-lives, it is N = N₀/2ⁿ.
Now, if the value of carbon-14 drops to a quarter of its initial value, then N = N₀/4.
So, N₀/4 = N₀/2ⁿ
1/4 = 1/2ⁿ
1/2² = 1/2ⁿ
Comparing the exponents, n = 2.
So the value of carbon-14 present drops to a quarter of its initial value in 2 half-lives.
Since one-half life equals 5730 years, then two-half-lives is 2 × 5730 years = 11460 years
So, it takes carbon-14 11460 years for the number of nuclei to drop to a quarter of its initial value.
Need Help !
A 1500 kg car on flat ground is
moving 5.25 m/s. Its engine
creates a 1250 N forward force as the car moves 42.8 m. What is its final velocity?
Answer: 5.96m/s
Explanation:
Given the following :
Mass of car (m) = 1500kg
Velocity (V) = 5.25m/s
Forward force of engine = 1250N
Diatance moved = 4.8m
Final Velocity =?
Final kinetic energy = Initial kinetic energy + work done by engine
Initial kinetic energy = 0.5 × mass × velocity^2
Initial kinetic energy = 0.5 × 1500 × 5.25^2
Initial kinetic energy = 20671.875 J
Work done by engine = Force × distance
Work done by engine = 1250 × 4.8 = 6000J
Final kinetic energy = (20671.875 + 6000) J
= 26671.875 J
From kinetic energy = 0.5mv^2
26671.875 = 1/2 × 1500 × v^2
53343.75 = 1500v^2
v^2 = 35.5625
v = sqrt(35.5625)
v = 5.96m/s
mass of a body is 10 kg what does it mean
Answer:
Explanation:
MASS of a body indicates the quantity or amount of matter contained in it.S.I, unit of mass is kg
A gardener uses 2700 J of work to push a wheelbarrow for 60 seconds. How much power does she use?
Answer:
I think 90 w I am not sure but I think it is right
I hope it is helpful for u
Answer:
45 WSolution,
Work(W)=2700 Joule
Time(t)=60 Seconds
Power=?
Now,
[tex]power = \frac{work \: done}{time \: taken} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{2700}{60} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 45 \: \: watt[/tex]
hope this helps..
Good luck on your assignment..
What is the energy of a photon with a frequency of 2.2 x 1016 Hz? Planck's constant is 6.63 x 10-34 Jos.
O 1.5 x 10-17
8.8 x 10-17
O 1.5 10-16
O 8.8 10-16
Answer: 1.5 × 10^-17
Explanation:
Given the following :
Frequency(f) = 2.2 × 10^16 Hz
Planck's constant(h) = 6.63 × 10^-34
The energy of a photon 'E' is given as the product of frequency and the planck's constant
E = hf
E = (6.63 × 10^-34) × (2.2 × 10^16)
E = 6.63 × 2.2 × 10^(-34 +16)
E = 14.586 × 10^-18
E = 1.4586 × 10^-17
E = 1.5 × 10-17 (2 S. F)
Answer:
C. 1.5 × 10–16 J
Explanation:
Which metal is used in thermometers?
Answer:
Mercury
Explanation:
Depends on the kind of thermometer.
But traditionally, Mercury has been used in "Liquid-In-Glass" Thermometers
Answer:
Mercury
Explanation:
Most metals are good conductors of heat and they are solids at room temperature. Mercury is the only one in liquid state at room temperature. It's used in thermometers because it has high coefficient of expansion.
a space shuttle travels in orbit at 21,000 km/hr. how far will it travel in 5 hr
Answer:
Explanation:
distance = speed * time
distance = 21000 * 5 = 105000 km
please mark me as Brainliest
2. Fill in the blanks with appropriate words.
a. The force which acts towards the centre is called .......
force.
Answer:
centripetal force
Explanation:
because this force always compels the body to move in circle
I NEED HELP PLEASE THANKS :)
Explain how the diffraction of light shows that light behaves like a wave.
Explanation:
Diffraction of light involves a change in direction of waves as they pass through an opening or around an obstacle in their path. Water waves have the ability to travel around corners, around obstacles and through openings.
The table shows data for the planet Uranus.
A 2 column table with 4 rows. The first column is labeled Quantity with entries, Escape velocity in kilometers per second, Gravitational acceleration in meters per second squared, Orbital velocity in kilometers per second, Length of day in hours. The second column is labeled Value with entries, 21.3, 8.7, 6.8, 17.2.
To the nearest whole number, how much would a 25.0 kg rock weigh on Uranus?
170 N | 218 N | 430 N | 532 N
Answer:
218 N
Explanation:
The weight of the object on Uranus W = mg' where m = mass of the object = 25.0 kg and g' = gravitational acceleration.
Since in the table, we are given different values, we look for the value of the gravitational acceleration because, that is the only variable there that can help us calculate the weight of the object.
From the table, the gravitational acceleration g' = 8.7 m/s².
So, the weight of the object W = mg'
= 25.0 kg × 8.7 m/s²
= 217.5 N
≅ 218 N
Answer:
B. 218 N
Explanation:
Edge 2020
As important as it is to plan ahead,sometimes you
Answer:
B. Cant stop things from going wrong.
Explanation:
To me it's the only reasonable answer...
To break a chemical bond, particles need to collide with a certain amount of a]energy. b]atoms. c]molecules. d]chemicals.
Answer:
Energy
Explanation:
The stronger the force it has the more quickly the bonds will break
As there will be more energy they will vibrate more and the bonds will separate easily..
What is the speed of a bus if it
covers 1.5km in 30 seconds?
a. 50km/Hr
b. 500m/s
c. 50m/s
d. 1500m/s
[tex]answer \\ = 50 \: m / s \\ solution \\ distance \: travelled\: by \: bus = 1.5 \: km \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 1.5 \times 1000 \: m \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 1500 \: m \\ time \: = 30 \: seconds \\ speed = \frac{distance}{time} \\ \: \: \: \: \: \: \: \: \: \: = \frac{1500m}{30s } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: = 50 \: m/s \\ hope \: it \: helps[/tex]
Answer:
C. 50 m/s
Explanation:
Given:
Distance = 1.5 km = 1500 m
Time = 30 sec
Required:
Speed = ?
Formula
Speed = Distance / Time
Solution:
Putting the given in the formula
Speed = 1500/30
Speed = 50 m/s
How much net force is required to keep a 3-kg object moving to the right with a constant speed of
6.0 m/s?
Answer:
Explanation:
Here,
m = 3 Kg
a = 0 m/s^2 (velocity is constant so the acceleration is zero)
We have,
F = ma
or, F = 3 x 0
or, F = 0 N
Constant velocity can always be associated with a zero net force.
A (an) __helps lessen the effects of thermal pollution
Answer:
Tree
Explanation:
It gets rid of the the degrading water temperature by blocking the sun's heat
Question: A swimmer has a swimming speed of 5.75 m/s in still water. When she
heads directly across the river, she ends up travelling downstream at an angle of 40°
(with respect to a line perpendicular to the shore).
(a) What is the speed of the current?
(b) What heading would the swimmer need to have in order to reach a point directly
across the river?
(c) If the river is 15 m wide, how long would a trip directly across the river take?
Answer:
(a) 4.82 m/s
(b) The simmer need to head 57.05° upstream of the river to reach a point directly opposite the river
(c) 4.024 seconds
Explanation:
The parameters given are;
The speed of the swimmer = 5.75 m/s
The direction of the resultant motion = 40° downstream
The speed of the current = x m/s
Therefore in a given second, we have that the swimmer moves 5.75 meters across the river while the current moves x meters downstream
Which gives;
[tex]tan(40^{\circ}) = \dfrac{x}{5.75}[/tex]
x = 5.75 × tan(40°) = 4.82 m/s
The speed of the current = 4.82 m/s
(b) If the swimmer swims at a direction θ to reach a point, p, directly opposite the river, we have;
The resultant speed across the river will be the swimmer's swimming speed which is 5.75 m/s
5.75² = y² + 4.82²
y = √(5.75² - 4.82²) = √9.78
tan(θ) = 4.82/(√9.78) = 1.54
θ = tan⁻¹(1.54) = 57.05°
The simmer need to swim 57.05° upstream to reach a point directly opposite the river
(c) If the river is 15 m wide, we have;
Time (t) = Distance/speed
The component of the swimmer's speed directly across the river = 5.75/(tan(57.05°)
The component of the swimmer's speed directly across the river = 3.73 m/s
The time, t, to cross the river is therefore;
t = 15/3.73 = 4.024 seconds
which two elements define a story's setting?
geographical location
character description
weather conditions
plot structure
dialogue and action
Reset
Next
Answer:
Geographical location, and time and weather conditions
Answer:
Georgraphical location and weather conditions
Explanation:
Setting is where the story takes place so the location would be vital and same with weather conditions because it determines what the character(s) do
what are the fundamental units used in physics?
Answer:
Metre, kilogram, second, ampere, kelvin, candela, and mole
Explanation:
A base unit (also referred to as a fundamental unit) is a unit adopted for measurement of a base quantity
The estimated distance of the earth from the sun is 149000000km. The speed of the light is 300000km/s. What is the time taken for the light to travel from the sun to the earth
Answer:
The time taken for the light to travel from the earth to the sun = 496.67 seconds
Explanation:
Estimated distance of the earth to the sun = 149000000km
Speed of light = 300000km/s
Time taken for the light to travel from the sun to the earth = ?
Speed = Distance/time
time = Distance/speed
time = 149000000/300000
time = 496.67 s
The time taken for the light to travel from the earth to the sun = 496.67 seconds
A block of mass m is placed on a smooth wedge of inclination θ . The whole system is accelerated horizontally so that the block does not slip on the wedge. The force exerted by the wedge on the block has a magnitude: (A) mg tan θ (B) mg sin θ (C) mg cos θ (D) mg sec θ
Answer: mg/Cosθ
Explanation:
Taking horizontal acceleration of wedge as 'a'
FCosΘ = FsinΘ
F = mass(m) × acceleration(a) = ma
For horizontal resolution g = 0
Therefore,
Horizontal = Vertical
maCosΘ = mgSinΘ
aCosΘ = gSinΘ
a = gSinΘ/CosΘ
Recall from trigonometry :
SinΘ/Cosθ = tanΘ
Therefore,
a = gtanΘ
Normal force acing on the wedge:
mgCosΘ + maSinΘ - - - - (y)
Substitute a = gtanΘ into (y)
mgCosΘ + mgtanΘsinΘ
tanΘ = sinΘ/cosΘ
mgCosΘ + mgsinΘ/cosΘsinΘ
mgCosΘ + mgsin^2Θ/cosΘ
Factorizing
mg(Cosθ + sin^2Θ/cosΘ)
Taking the L. C. M
mg[(Cos^2θ + sin^2Θ) /Cosθ]
Recall: Cos^2θ + sin^2Θ = 1
mg[ 1 /Cosθ]
mg/Cosθ