As the temperature of a material increases, the average __(blank)__ of its particles increases.

kinetic energy

mass

specific heat

potential energy

Answer: [tex]\Delta H^{0}=-173.72[/tex] kJ/mol

Explanation: Enthalpy Change is the amount of energy in a reaction - absorption or release - at a constant pressure. So, Standard Enthalpy of Formation is how much energy is necessary to form a substance.

The standard enthalpy of formation of HCl is calculated as:

[tex]\Delta ^{0}=\Sigma H_{products}-\Sigma H_{reactants}[/tex]

[tex]Ca(OH)_{2}_{(aq)}+2HCl_{(aq)}[/tex] → [tex]CaCl_{2}_{(s)}+2H_{2}O_{(l)}[/tex]

Standard Enthalpy of formation for the other compounds are:

Calcium Hydroxide: [tex]\Delta H^{0}=[/tex] -1002.82 kJ/mol

Calcium chloride: [tex]\Delta H^{0}=[/tex] -795.8 kJ/mol

Water: [tex]\Delta H^{0}=[/tex] -285.83 kJ/mol

Enthalpy is given per mol, which means we have to multiply by the mols in the balanced equation.

Calculating:

[tex]-17.2=[-795.8+2(285.85)]-[-1002.82+2\Delta H][/tex]

[tex]-17.2=-1367.46+1002.82-2\Delta H[/tex]

[tex]2\Delta H=17.2-364.64[/tex]

[tex]\Delta H=-173.72[/tex]

So, the standard enthalpy of formation of HCl is -173.72 kJ/mol

Answer:

1.93391595 grams I hope this helps

Explanation:

Answer:

Mole fraction for benzene is 0.683

Explanation:

We need to determine the colligative property about vapour pressure which formula is:

ΔP = P° . Xm

where P° is vapour pressure of pure solvent.

ΔP = Vapor pressure of pure solvent - Vapor pressure of solution

In this case, our solvent is benzene and the solute is toluene. For this colligative property vapour pressure of solution is lower than pure solvent.

P° of benzene at 20°C is 74.7 Torr

Xm is the value for the mole fraction of solute.

Let's replace data: 74.7 Torr - 51 Torr = 74.7 Torr . Xm

Xm = 0.317 → That's the mole fraction for toluene.

Then, mole fraction for benzene will be: 1 - 0.317 → 0.683

Answer:

A. 16.0 grams

B. 3.1 mol of oxygen

Explanation:

A.

The oxygen atom has mass = 2.66x10^-23g

A mole of oxygen atoms can be calculated as:

[2.66x10^-23/1 oxygen atom] x [6.023x10²³ oxygen atoms/1 mol]

= 16.0 grams of oxygen

So a mole of oxygen has 16.0 grams of O2

B.

For 0.050 kg of water, we have 16.0 grams

(0.050x10³g/kg )x (1mol/16)

= 3.1 mol of oxygen

So 3.1 mol of oxygen has mass which is equal to the mass of water.

Answer:

We are tasked to solve for the volume of Gold given that the mass of Gold is equivalent to that of a copper.

Explanation:

Details:

Density of Copper= 8.96 g/ml

Volume of Copper=141 ml

mass of Gold = mass of Copper

Density of Gold=19.3 g/ml

In order to solve for the mass of copper, we need to use the density formula

Density= mass/volume

Since we are to solve for the mass of copper

mass of copper= Density of Copper * Volume of Copper

mass of copper= 8.96 g/ml* 141 ml= 1263.36 g

Thus,

mass of gold=mass of copper=1263.36 g

Hence,

Using still the density formula to solve for the volume of gold,

Volume of gold=mass of gold/ Density of gold

Volume of gold=1263.36 g/ 19.3 g/ml = 65.46 mL

Therefore, the volume of the gold must be 65.46 mL in order to have the same mass of a copper

Answer: 2 H2 + O2 → 2 H2O, you get the same number of moles of water as H2, as long as you have 1 mole of O2. So, with 3 moles of H2, as long as you have 1.5 moles of O2, you will get 3 moles of H2O. In my opinion.

Answer:

Some places have more earthquakes than others because they sit on the edges of tectonic plates.

Answer:See explanation

Explanation:

MOLECULAR REACTION EQUATION;

Al(NO3)3(aq) + 3NaOH(aq) --->Al(OH)3(s) +3NaNO3(aq)

complete ionic equation:

Al^3+(aq) + 3NO3^-(aq)  + 3Na^+(aq) + 3OH^-(aq) ---->Al(OH)3(s) + 3Na^+(aq) + 3NO3^-(aq)

Net ionic reaction equation;

Al^3+(aq) + 3OH^-(aq) ------> Al(OH)3(s)

Answer:

[tex]m_{H_2O_2}=0.317gH_2O_2[/tex]

Explanation:

Hello!

In this case, for the chemical reaction between hydrochloric acid and barium peroxide is:

[tex]BaO_2(s)+2HCl(aq)\rightarrow H_2O_2(aq)+BaCl_2(aq)[/tex]

Thus, since the barium peroxide (169.33 g/mol) and hydrochloric acid (36.45 g/mol) are reacting in a 1:2 mole ratio, we need to identify the limiting reactant first by computing the yielded moles of hydrogen peroxide by each reactant:

[tex]n_{H_2O_2}^{by\ BaO_2}=1.50gBaO_2*\frac{1molBaO_2}{169.33gBaO_2}*\frac{1molH_2O_2}{1molBaO_2}=0.00886molH_2O_2\\\\ n_{H_2O_2}^{by\ HCl}=0.0272\frac{gHCl}{mL}*25.0mL *\frac{1molHCl}{36.46gHCl}*\frac{1molH_2O_2}{2molHCl}=0.00933molH_2O_2[/tex]

That's why the HCl is the limiting reactant, so the resulting mass of hydrogen peroxide, theoretical yield, is:

[tex]m_{H_2O_2}=0.00933molH_2O_2*\frac{34.02gH_2O_2}{1molH_2O_2}\\\\m_{H_2O_2}=0.317gH_2O_2[/tex]

Best regards!

Answer:

0.422 M

Explanation:

Equation of the reaction,

2HCl(aq) + Ba(OH)₂(aq) ⇒ BaCl₂(aq)+2H₂O(l)

From the recation above,

2 moles of HCl is needed to neutralize 1 mole of Ba(OH)₂.

Using,

C'V'/CV = a/b......................... Equation 1

Where C' = concentration of acid, C = concentration of base, V' = volume of acid, V = volume of base, a = number of moles of acid, b = number of moles of base.

make C' the subject of the equation.

C' = aCV/bV'................. Equation 2

a = 2 mole, b = 1 mole, C = 0.0154 M, V = 27.4 mL, V' = 20 mL

Substitute into equation 2

C' = (2×0.0154×27.4)/(1×20)

C' = 0.422 M.

Hence the concentration of acid is 0.422 M

Answer:

electron and ignore this woejdnks

Answer:

i would say the first one!

Answer:it has one proton,

and one electron

Explanation:

It has one neutron and It has one nucleon

The [OH-] of NaF solution : 1.7 x 10⁻⁶

Given

0.2 M NaF

Ka of HF is 7.1 x 10⁻⁴

Required

[OH⁻]

Solution

Hydrolysis of NaF salt which is formed from weak acid HF and strong base NaOH

F⁻(aq) + H₂O(l) ⇄ HF(aq) + OH⁻(aq)

General formula :

[tex]\tt [OH^-]=\sqrt{\dfrac{Kw}{Ka}\times M }[/tex]

Input the value :

[OH⁻]=√(10⁻¹⁴/7.1 x 10⁻⁴) x 0.2

[OH⁻]= 1.678 x 10⁻⁶ ≈ 1.7 x 10⁻⁶

Answer:

0.010 $.

Explanation:

Hello!

In this case, since 1 troy ounce equals 31.1 grams, we can compute the price of gold per gram first:

[tex]1,838.80\frac{\$}{try\ ounce} * \frac{1try\ ounce}{31.1g} = 59.1\frac{\$}{g}[/tex]

Now, we need to compute the grams of copper in 5.17 x10¹⁷ atoms via the Avogadro's number:

[tex]m=5.17x10^{17}atomsAu*\frac{197.0gAu}{6.022x10^{23}atomsAu} \\\\m=1.69x10^{-4}g[/tex]

Thus, the price is:

[tex]\$ = 59.1\frac{\$}{g}*1.69x10^{-4}g \\\\\$ =0.010\$[/tex]

Best regards!

Answer:

32.76mole of P

Explanation:

The reaction expression is given as;

          P₄O₁₀  →    4P  +  5O₂

Given parameters:

Number of moles of   P₄O₁₀  = 8.19mol

Unknown:

Number of moles of P produced = ?

Solution:

From the balanced reaction expression;

             1 mole of P₄O₁₀  will produce 4 mole of P

         8.19mole of P₄O₁₀  will therefore produce 4 x 8.19  = 32.76mole of P

Answer:

168.56

Explanation:

Answer:

48 grams

Explanation:

If p and V are already given, calculate m by multiplying those two values.

m = pV

m = 4/5 * 60/1

m = 240/5

m = 48 grams

The mass of that substance is 48 grams.

Answer:

True

Explanation:

When ice is heated, the ice gains heat.

This heat gained by the ice is both used to break the intermolecular forces in ice to form water, as well as to raise the temperature of the water to it's final temperature.

Answer:

0.321 M

Explanation:

The neutralization reaction of HCl with NaOH is the following:

HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l)

So, 1 equivalent of HCl reacts with 1 equivalent of NaOH. In this case:

1 equivalent HCl = 1 mol HCl

1 equivalent NaOH = 1 mol NaOH

At the equivalence point, the amount of HCl reacts completely with the added amount of titrant (NaOH). As 1 mol of reactant is calculated from the product of the molarity of the solution and the volume, in the equivalent point:

moles HCl = moles NaOH

M(HCl) x V(HCl) = M(NaOH) x V(NaOH)

We have:

M(NaOH) = 0.150 M

V(NaOH) = 21.4 mL = 0.0214 L

V(HCl) = 10.0 mL = 0.01 L

Thus, we calculate the initial concentration HCl as follows:

M(HCl) = (M(NaOH) x V(NaOH))/ (V(HCl))

            = (0.150 M x 0.0214 L)/(0.01 L) = 0.321 M

Answer:

1. decreases

2. Transverse

3. Vibrations

Answer:

dunno

Explanation:

sorry

Answer:

Acid rain, like all acids, generates dissolution of chemical compounds, and reacts together with bases to be able to carry out oxide reduction reactions, which by deduction is very likely to form new substances as a result of the dissolution or acid erosion caused.

Explanation:

Acid rain is more likely to occur in large cities or large sources of pollution, since the excess of carbon dioxide in the atmosphere causes it to increase its partial pressure in a condensed way in the clouds, this is how then this cloud when being loaded with water and then generating the rain drags these masses of condensed carbon dioxide in the form of acid rain.

The degree of acidity is directly proportional to the amount of partial pressure of carbon dioxide in the atmosphere.

Answer:

The metal sphere was made of iron.

Explanation:

From the question,

Heat lost by the metal sphere = heat gained by the mercury.

Cm(t₁-t₃) = C'm'(t₃-t₂)................... Equation 1

Where C = specific heat capacity of the metal sphere, m = mass of the metal sphere, C' = specific heat capacity of the mercury, m' = mass of the mercury.

t₁ = initial temperature of the metal sphere, t₂ = initial temperature of the mercury, t₃ = Final temperature of the mixture.

Make C the subject of the equation

C = C'm'(t₃-t₂)/m(t₁-t₃)................. Equation 2

Given: m = 0.5 kg, m' = 4.08 kg, t₁ = 300 °C, t₂ = 20 °C, t₃ = 99 °C

Constant: C' = 140 J/kgK.

Substitute into equation 2

C = [140×4.08×(99-20)]/[0.5×(300-99)]

C = 45124.8/100.5

C = 449.0 J/kgK.

Hence from the specific heat capacity data sheet, the metal is suspected to  be  made of iron.

Answer:

tyduyfjhg

Explanation:

Answer:Moles of Mg, Cl,  0 =  5.40, 10.80, 43.2

Explanation:

1  mole of Mg(ClO4)2  contains  1 mole of Magnesium, Mg atoms

                                                    2 Moles of Chlorine, Cl atoms

                                                    8 Molresof Oxygen atoms

Such that to find the number of moles of each element, We have that

------1 mole Magnesum  atoms/ 1 mol of  Mg(ClO4)2   x 5.40 moles  of magnesium perchlorate, Mg(ClO4)2 = 1 x 5.40 =5.40 moles

------2 moles ofChlorine atoms/ 1 mol of Mg(ClO4)2   x 5.40 moles of magnesium perchlorate, Mg(ClO4)2 = 2 x 5.40 = 10.80 moles

------8 moles Oxygen atoms/ 1 mol of  Mg(ClO4)2   x 5.40 moles  of magnesium perchlorate, Mg(ClO4)2 = 8 x 5.40 = 43.2 moles

Answer:

Answer:

cointreau, tequila,lime juice