Answer:
carbonate ion < carbon dioxide < carbon monoxide
Explanation:
Bond strength depends on the bond order of a bond. The higher the bond order, the greater the bond strength since shorter bonds are stronger than longer bonds.
The carbonate ion has a bond order of 1.33, carbon dioxide has a bond order of 2 while carbon monoxide has a bond order of 3.
Since the compound with the highest C-O bond order has the strongest C-O bond, then carbon monoxide possesses the strongest C-O bond.
Answer: carbonate ion < carbon dioxide < carbon monoxide
Explanation: Carbon dioxide (chemical formula CO2) is a chemical compound made up of molecules that each have one carbon atom covalently double bonded to two oxygen atoms. It is found in the gas state at room temperature, and as the source of available carbon in the carbon cycle, atmospheric CO2 is the primary carbon source for life on Earth. In the air, carbon dioxide is transparent to visible light but absorbs infrared radiation, acting as a greenhouse gas. Carbon dioxide is soluble in water and is found in groundwater, lakes, ice caps, and seawater. When carbon dioxide dissolves in water, it forms carbonate and mainly bicarbonate (HCO−3), which causes ocean acidification as atmospheric CO2 levels increase. Bond strength depends on the bond order of a bond. The higher the bond order, the greater the bond strength since shorter bonds are stronger than longer bonds. The carbonate ion has a bond order of 1.33, carbon dioxide has a bond order of 2 while carbon monoxide has a bond order of 3. Since the compound with the highest C-O bond order has the strongest C-O bond, then carbon monoxide possesses the strongest C-O bond. It is a trace gas in Earth's atmosphere at 421 parts per million (ppm), or about 0.04% by volume (as of May 2022), having risen from pre-industrial levels of 280 ppm. Burning fossil fuels is the primary cause of these increased CO2 concentrations and also the primary cause of climate change.
A 5.00 g piece of metal is heated to 100.0 C then placed in a beaker containing 20.0 g of water at 10.0 C. The temperature of the water rises to 15.0 C. Calculate the specific heat of the metal
Combustion of hydrocarbons such as octane (C_8H_18) produces carbon dioxide, a "greenhouse gas." Greenhouse gases in the Earth's atmosphere can trap the Sun's heat, raising the average temperature of the Earth. For this reason there has been a great deal of international discussion about whether to regulate the production of carbon dioxide.
1. Write a balanced chemical equation, including physical state symbols, for the combustion of liquid octane into gaseous carbon dioxide and gaseous water.
2. Suppose 0.330 kg of octane are burned in air at a pressure of exactly 1 atm and a temperature of 10.0 ?C. Calculate the volume of carbon dioxide gas that is produced. Round your answer to 3 significant digits.
Answer: 1. [tex]2C_8H_{18}(l)+25O_2(g)\rightarrow 16CO_2(g)+18H_2O(g)[/tex]
2. The volume of carbon dioxide gas that is produced is 537 L
Explanation:
1. Combustion is defined as the type of chemical reaction where a hydrocarbon is combusted in the presence of oxygen to give carbon dioxide and water.
The balanced reaction for combustion of octane is:
[tex]2C_8H_{18}(l)+25O_2(g)\rightarrow 16CO_2(g)+18H_2O(g)[/tex]
2.
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex] [tex]\text{Moles of octane}=\frac{0.330\times 1000g}{114.23g/mol}=2.89moles[/tex]
According to stoichiometry:
2 moles of octane produce = 16 moles of carbon dioxide
2.89 moles of octane produce = [tex]\frac{16}{2}\times 2.89=23.1moles[/tex] of carbon dioxide
According to ideal gas equation:
[tex]PV=nRT[/tex]
P = pressure of gas = 1 atm
V = Volume of gas = ?
n = number of moles = 23.1
R = gas constant =[tex]0.0821Latm/Kmol[/tex]
T =temperature =[tex]10.0^0C=(10+273)K=283K[/tex]
[tex]V=\frac{nRT}{P}[/tex]
[tex]V=\frac{23.1\times 0.0821Latm/K mol\times 283K}{1atm}=537L[/tex]
Thus the volume of carbon dioxide gas that is produced is 537 L
Combustion Analysis of an unknown hydrocarbon resulted in the capture of 216.00 g of water vapor and 440.00 g of CO2. The total mass of the hydrocarbon before combustion was 144 g.
(1. How many moles of carbon dioxide are present after combustion?)
(2. What is the empirical formula for the unknown hydrocarbon?)
(3. How many water molecules does the water vapor trap capture?)
(4. The gram-formula mass for the unknown hydrocarbon was determined to be 72 g/mol. How many moles of the unknown hydrocarbon were present in the original sample?)
(5. infrared spectral analysis determines that the unknown hydrocarbon does NOT contain oxygen. How many moles of O2 are used in combusting the unknown sample?)
1: 10 mol CO2
2: C10H24
3: 12 mol H2O
4: 0.5 mol
5: 16 mol O2
The compound is C5H10.
From the information available in the question;
Number of moles of carbon dioxide = 440.00 g/44 g/mol = 10 moles
Number of moles of water vapor = 216.00 g/18 g/mol = 12 moles
Mass of carbon = 10 moles × 12 g/mol = 120 g of carbon
Moles of hydrogen = 12 moles × 2 g/mol = 24 g of hydrogen
Number of moles of carbon = 120 g/12 g/mol = 10 moles
Number of moles of hydrogen = 24 g/1 g/mol =24 moles
Divide through by the lowest number of moles =
C - 10/10 H - 24/10
C - 1 H - 2
The empirical formula is CH2
Molar mass of the compound = 72 g/mol
[12 + 2(1)]n = 72
14n = 72
n = 5
The compound is C5H10.
Learn more about hydrocarbons: https://brainly.com/question/1195122
5. Choose the best description of a reversible reaction.
a reaction that occurs in both directions at the same time
a reaction that has used up all the reactants and has stopped
a reaction that can only proceed to the right
a reaction that can only proceed to the left
Answer:
A reaction that can only move towards the right.
Explanation:
For a reversible reaction when one of the products of the reaction is removed the reaction moves towards right hand side. More and more reactants will be converted into products. This will nullify the effect of removal of product.
Which material would conduct heat best?
А.Air
B.Copper
C.Wood
D.Rubber
Answer:
I believe the best answer is B. Copper.
What might happen if an endocrine hormone such as thyroid hormone was controlled by positive instead of negative feedback?
Answer:
cdg I will be a little late to the party but I have to go to the store and get ❤️❤️❤️❤️❤️❤️
To determine the concentration of a sodium thiosulfate solution as in this experiment, a student pipetted 25.0 mL of 0.0100 M potassium iodate (KIO3) solution into a 125 mL Erlernmeyer flask. Potassium iodide and sulfuric acid were added as in this experiment. The titration needed 15.21 mL of the sodium thiosulfate to reach the end point. What is the concentration of the sodium thiosulfate solution
Answer:
0.0986M is the concentration of the Na₂S₂O₃ solution
Explanation:
Potassium iodate, KIO₃, reacts with sodium thiosulfate, Na₂S₂O₃, as follows:
KIO₃ + 6Na₂S₂O₃ +5KI + 3H₂SO₄ → 3H₂O + 3K₂SO₄ + 3Na₂S₄O₆ + 6NaI
To solve this question we must find the moles of sodium thiosulfate that reacts as follows:
Moles KIO₃:
0.0250L * (0.0100mol / L) = 2.5x10⁻⁴moles KIO₃
Moles Na₂S₂O₃:
2.5x10⁻⁴moles KIO₃ * (6mol Na₂S₂O₃ / 1mol KIO₃) = 1.5x10⁻³ moles Na₂S₂O₃
Molar concentration:
1.5x10⁻³ moles Na₂S₂O₃ / 0.01521L =
0.0986M is the concentration of the Na₂S₂O₃ solutionIs that flirting? I'm not sure and I really need to know-
Answer:
I mean ig it is, but i dk
Explanation:
(giving brainiest)
please answer correctly im failing school and these are my last points!
Answer:
i answered your other post with it
Explanation:
How many molecules of CO2 at standard temperature and pressure in 5.4 moles of CO2
Answer:
3.25×10²⁴ molecules.
Explanation:
From the question given above, the following data were obtained:
Number of mole of CO₂ = 5.4 moles
Number of molecules of CO₂ =?
The number of molecules of CO₂ in 5.4 moles can be obtained as follow:
From Avogadro's hypothesis,
1 mole of CO₂ = 6.02×10²³ molecules
Therefore,
5.4 moles of CO₂ = 5.4 × 6.02×10²³
5.4 moles of CO₂ = 3.25×10²⁴ molecules
Thus, 5.4 moles of CO₂ contains 3.25×10²⁴ molecules.
help out here plzzzzzzzzzzzzz
Answer:
Chromosomes are duplicated in the "s phase" of interphase.
KBr is the formula for an ionic compound. The fact that neither symbol is followed by a subscript means that there is a(an) of ions in the compound
Answer:
equal number of ions
Explanation:
They cancel each other out that's why there is none
Identify each of the patterns labeled in the ridge pattern diagram
Answer: The suspected and crime scene fingerprint patterns are similar which means they belong to the same individual.
Explanation:
A: Ending ridge between two lines forming a loop like structure common in both suspected and crimes scene patterns.
B: Bifurcation which includes the formation of fork like shape of the ridge.
C: Island is a dot or point like structure which is common in both patterns.
D: It includes delta which is seen in the case of loop and whorl patterns of the fingerprint in loop there is only one delta and in case of whorl there are two deltas. The delta have an island and a bifurcation in it which is common in both patterns of the fingerprints.
E: Intersection occurs when two ridges changes their directions. It is common in the two patterns.
This molecule undergoes a substitution reaction through an SN1 pathway when warmed and stirred with HBr. Draw the two substitution products of this reaction. Show the correct stereochemistry by using wedges and dashes at all chiral centers. In part two, select the term that correctly describes the relationship between the products.
Answer:
See explanation and image attached
Explanation:
The mechanism of this reaction is shown in the image attached. The image was obtained from HomeworkLib.
The first step in the reaction is protonation and loss of -OH2. A carbocation is now created which undergoes a 1,2 hydride shift. This yields a tertiary carbocation which is more stable.
A racemic mixture of two products, major and minor are now obtained as shown.
he image shows two air fronts moving in a region. The cold front is moving faster than the warm front.
Which will likely happen if the cold front continues to advance faster than the warm front?
Cold air will pass over the warm air, causing dry weather in the region.
Cold air will pass over the warm air, causing dry weather in the region.
Cold air will push up the warm air, resulting in heavy rainfall in the region.
Cold air will push up the warm air, resulting in heavy rainfall in the region.
Cold air will push up the warm a
Answer:
Cold air will push up the warm air, resulting in heavy rainfall in the region.
consider the following atoms and ion: Cl,Mg,P,K,Ce =
A)which one is an example of ns² family?
B)which one is an example of p-block element?
C) which is (are) isoelectronic with Argon?
D) Which one is an example of alkaline earth metal?
E) which one has core configuration [Ne]3s²?
F) which one is an example of f-block element?
G) which one is d-block element?
H) which one has outer shell configuration of ns²p³?
Answer:it would be f
Explanation:
help Tell me the answer.
Answer:
it's easy u just have to put them in a calculator the way they are it will give you your answer atleast I think so hope this helps
Explain why water and syrup are able to mix?
How much NaCl would you dissolve and dilute to the 100.00 mL mark in a volumetric flask with DI H2O to prepare a 0.825 M sodium chloride solution?
Answer:
4.82 g
Explanation:
To solve this problem we'll use the definition of molarity:
Molarity = moles / litersWe are given the volume and concentration (keep in mind that 100mL=0.100L):
0.825 M = moles / 0.100 LNow we calculate the number of NaCl moles required:
moles = 0.0825 molThen we convert 0.0825 NaCl moles into grams, using its molar mass:
0.0825 mol * 58.44 g/mol = 4.82 gChlorination of phenol gives para product but bromination of phenol gives Ortho para product why
Answer:
here you go
Explanation:
The reaction of phenol with bromine is known as bromination of phenol. Solvent has great influence on the reaction. In different solvents, different products are obtained. The action of bromine on phenol can be explained as:
Reaction with bromine in water:—-
Reaction with bromine in water
Phenol reacts with bromine water to give 2,4,6-tribromophenol.
In water, ionisation is facilitated. Phenol gets ionised to form phenoxide ion, which is even better ortho,para-directing. Bromine also gets ionised to a larger extent to form a large number of bromonium ions. And Bromine ions are highly stabilized in ionic solvents. So the formation of strong o,p-directing group and stabilization of Br+ enhances the formation of tribromophenol.
Reaction with bromine in CS2:—-
Reaction with bromine in non-polar organic solvents
Phenol reacts with bromine in a presence of Carbon disulphide to form a mixture of o-bromophenol and p-bromophenol. Among which p-bromophenol predominates. In CS2 ionisation is not facilitated that much. As it is a non-polar solvent it doesn't the Br+ on. Also −OH group is moderately o,p-directing. So as usual para-product is more formed.
(giving brainiest) solve please! dont copy I've looked up everything ill know if you copied something!
Answer:
Precipitation falls in liquid and solid
Evaporation changes liquid water to gas
Explanation:
Precipitation exists in snow, rain, sleet, many forms liquid or solid but NOT gas.
Evaporation is from a liquid to a gas change, also called vaporization.
arrow futhermost to left is evaporation (rising into air)
arrow futhermost to right is precipitation ( falling back to ground)
hope this helped xxx please mark brainliest
A student pours 800.0 mL of a 3.000 molar solution of sodium hydroxide into a 2.00 liter volumetric flask and fills the flask up with water. What is the new molarity of the solution?
A) 12.00 M
B) 1.20 M
C) 14.00 M
D) 0.0750 M
Which of the following compounds is the most stable?
Answer:
Hey mate......
Explanation:
This is ur answer......
fluoridesThus, fluorides are the most stable while iodides are the least stable.
Hope it helps!
Mark me brainliest pls.....
Follow me! :)
Answer:
LICI
Explanation:
a p e x :)
For many purposes we can treat propane (CH) as an ideal gas at temperatures above its boiling point of - 42°C. Suppose the temperature of a sample of propane gas is lowered from 25.0°C to - 22.0 °C, and at the same time the pressure is changed. If the initial pressure was 0.58 kPa and the volume decreased by 40.0%, what is the final pressure?
Answer: The final pressure is 0.81 kPa
Explanation:
The combined gas equation is,
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas = 0.58 kPa
[tex]P_2[/tex] = final pressure of gas = ?
[tex]V_1[/tex] = initial volume of gas = v
[tex]V_2[/tex] = final volume of gas = [tex]v-\frac{40}{100}\times v=0.6v[/tex]
[tex]T_1[/tex] = initial temperature of gas = [tex]25^0C=(25+273)K=298K[/tex]
[tex]T_2[/tex] = final temperature of gas = [tex]-22^0C=(-22+273)K=251K[/tex]
Now put all the given values in the above equation, we get:
[tex]\frac{0.58\times v}{298}=\frac{P_2\times 0.6v}{251}[/tex]
[tex]P_2=0.81kPa[/tex]
The final pressure is 0.81 kPa
does water burn? for my sister that says water does burn
Answer:
No, water doesn't burn. It only can burn under specific conditions in a lab.
Explanation:
Predict the shape of the molecule.....
Answer:
bent
Explanation:
help me with this question?!!
Answer:
Glow sticks and match would be light emission, slime would be preciptate, and cookies would be gas.
Explanation:
Balance the following equations:
C3H8 (g) + O2 (g) → CO2 (g) + H2O (g)
NH3 (g) O2 (g) NO2 (g) H2O (g)
Al(NO3) Na3S Al2S3 NaNO3
Explanation:
C3H8 + 502 ----> 3CO2 + 4H20
4NH3+7O2------> 4NO2+6H2O
2Al(NO3)3 + 3Na2S -------> Al2S3+6NaNO3
Which equation represents neutralization?
(1 ) 6Li(s)+N 2 (g)=>2Li3N(s)(2) 2Mg(s)+O2(g)=>2MgO(s) (3) 2KOH(aq)+H2SO4(aq) =>K 2 SO 4 (aq)+2H 2 O(l)
(4) Pb(NO 3 ) 2 (aq)+K 2 CrO 4 (aq) => 2KNO 3 (aq)+PbCrO 4 (s)
Answer:
3) 2KOH(aq) + H2SO4(aq) ⇒ K2SO4(aq) + 2H2O(l)
Explanation:
KOH is a strong base and a H2SO4 is a strong acid. The two react in a neutralization reaction, producing a salt and water.
Which of the following is true according the the Arrhenius theory of acids?
A strong acid increases the OH-ion concentration in an aqueous solution.
A strong acid decreases the OH-ion concentration in an aqueous solution.
O A strong acid decreases the H+ and OH-ion concentration in an aqueous
solution.
A strong acid increases the H+ ion concentration in an aqueous solution.