Argon,oxygen and nitrogen are obtained from air by fractional distillation. Liquid air at -250 degree Celsius is warmed up and the gases are collected.

a) is liquid air a mixture or a pure substance

The reactance of the coil is approximately 6.16 kΩ. The rms current in the coil is approximately 39.2 mA.


To find the reactance of the coil, we use the formula Xl = 2πfL, where Xl is the reactance, f is the frequency, and L is the inductance. Substituting the given values, we get Xl = 2π(10.0 kHz)(260 mH) = 6.16 kΩ. This is the reactance of the coil.

To find the rms current in the coil, we use the formula Irms = Vrms/Xl, where Irms is the rms current, Vrms is the rms voltage, and Xl is the reactance. Substituting the given values, we get Irms = (240 V)/(6.16 kΩ) = 39.2 mA. This is the rms current in the coil.

The reactance of the coil represents the opposition to the flow of current in the coil due to the inductance of the coil. The higher the inductance and frequency, the higher the reactance. In this case, the reactance is relatively high, which means that the coil will not allow a significant amount of current to flow through it.

The rms current in the coil represents the effective value of the alternating current that flows through the coil. This current will produce a magnetic field around the coil that can be used for various applications, such as in radio receivers and transmitters.

Overall, the reactance and rms current in the coil are important parameters that are used to analyze and design electronic circuits.

To learn more about reactance visit:

brainly.com/question/17129912

#SPJ11

           2Cr₃⁺(aq) + 3Sn₂⁺(aq) → 2Cr(s) + 3Sn(s),

To determine the overall balanced reaction and calculate the standard cell potential,

we need to consider the reduction potentials of both half-reactions and their stoichiometric coefficients.

      Cr₃⁺(aq) + 3 e⁻ → Cr(s) E° = -0.41 V

      Sn₂⁺(aq) + 2 e⁻ → Sn(s) E° = -0.14 V

       2 × (Cr₃⁺ (aq) + 3 e⁻ → Cr(s)) gives us:

          2Cr₃⁺(aq) + 6 e⁻ → 2Cr(s)

       3 × (Sn₂⁺(aq) + 2 e⁻ → Sn(s)) gives us:

            3Sn₂⁺(aq) + 6 e⁻ → 3Sn(s)

Now, we can combine these two half-reactions to form the overall balanced reaction:

      2Cr₃⁺(aq) + 6 e⁻ + 3Sn₂⁺(aq) + 6 e⁻ → 2Cr(s) + 3Sn(s)

Simplifying this equation, we get:

      2Cr₃⁺(aq) + 3Sn₂⁺(aq) → 2Cr(s) + 3Sn(s)

Now, let's calculate the standard cell potential (E°) for the reaction.

       E°(cell) = E°(cathode) - E°(anode)

           (Cr₃⁺(aq) + 3 e⁻ → Cr(s)) is -0.41 V,

           (Sn₂⁺(aq) + 2 e⁻ → Sn(s)) is -0.14 V,

we can substitute these values into the equation:

           E°(cell) = -0.14 V - (-0.41 V)

           E°(cell) = -0.14 V + 0.41 V

           E°(cell) = 0.27 V

           2Cr₃⁺(aq) + 3Sn₂⁺(aq) → 2Cr(s) + 3Sn(s)

Learn more about balanced reaction

brainly.com/question/14258973

#SPJ11

To determine chlorine demand from a chlorine demand curve, you need to identify the point on the curve where the free chlorine residual (FCR) intersects with the demand curve. This point represents the chlorine dosage required to overcome the chlorine demand and achieve the desired FCR. The distance between the initial chlorine dosage and the intersection point on the curve represents the chlorine demand.

To calculate the chlorine demand, you need to subtract the initial chlorine dosage from the chlorine dosage required to achieve the desired FCR. For example, if the initial chlorine dosage is 2 mg/L and the chlorine dosage required to achieve the desired FCR is 4 mg/L, then the chlorine demand is 2 mg/L.

It's important to note that the chlorine demand curve is specific to a particular water source and treatment process. Therefore, it's essential to create a new curve when there are changes in the treatment process or water source to ensure accurate determination of chlorine demand.

Know more about Chlorine demand curve here:

https://brainly.com/question/31685536

#SPJ11

In this case, knowing the stoichiometry of the reaction allows us to determine that if we have six moles of potassium phosphate , we can expect to produce 18 moles of KNO3. This information is useful in a variety of applications, from predicting the yield of a chemical reaction

To determine how many moles of potassium nitrate are produced when six moles of potassium phosphate react, we need to first write out the balanced chemical equation for the reaction between these two compounds. The equation is:
[tex]2 K3PO4 + 3 Ca(NO3)2 -> 6 KNO3 + Ca3(PO4)2[/tex]

From this equation, we can see that for every two moles of [tex]K3PO4[/tex] that react, six moles of potassium nitrate are produced. Therefore, if six moles of [tex]K3PO4[/tex] are reacting, we can expect to produce 18 moles of potassium nitrate .

This relationship between the number of moles of reactants and products is known as the stoichiometry of the reaction. Stoichiometry is important because it allows us to predict how much product will be formed from a given amount of reactant, or how much reactant is required to produce a certain amount of product.

Know more about Stoichiometry here:

https://brainly.com/question/30215297

#SPJ11

The preferred reaction sequence for the conversion of CH3CH2COH (propionic acid) to CH3CH2CH2OH (1-propanol) is by using (C) BH3 and THF. This reaction is known as hydroboration-oxidation, which is commonly used to convert a carboxylic acid to the corresponding primary alcohol.The use of borane and THF (tetrahydrofuran) as a reagent for hydroboration is preferred because BH3 is highly reactive and tends to polymerize in the absence of a stabilizing solvent. THF acts as a Lewis base and coordinates with BH3 to form a stable BH3-THF complex, which can readily add to the carbonyl group of the carboxylic acid to form the corresponding alkylborane intermediate.

If you need to learn more about reaction sequence, click here

https://brainly.in/question/18527532?referrer=searchResults

#SPJ11

The pair of aqueous solutions that form a precipitate is d) KOH and Ba(NO3)2, and e) Li2CO3 and CSi.

A precipitate is formed when two aqueous solutions react to form an insoluble solid. To determine which pair of aqueous solutions forms a precipitate, we need to consider the solubility rules of common ionic compounds.a) NiBr2 and AgNO3 - According to the solubility rules, both NiBr2 and AgNO3 are soluble in water. Therefore, no precipitate will form. b) NaI and KBr - Both NaI and KBr are soluble in water, so no precipitate will form. c) K2SO4 and CrCl3 - K2SO4 is soluble in water, while CrCl3 is partially soluble.  d) KOH and Ba(NO3)2 - KOH is soluble in water, while Ba(NO3)2 is partially soluble.  e) Li2CO3 and CSi - According to the solubility rules, both Li2CO3 and CSi are insoluble in water.

To know more about solutions visit:-
https://brainly.com/question/30665317

#SPJ11

To calculate the mass of 3.21 x 10^21 molecules of dinitrogen tetroxide (N2O4), we need to determine the molar mass of N2O4 and then use the relationship between moles, molecules, and mass.

The molar mass of N2O4 is the sum of the atomic masses of two nitrogen (N) atoms and four oxygen (O) atoms.

Molar mass of N2O4 = (2 × Atomic mass of N) + (4 × Atomic mass of O)

Molar mass of N2O4 = (2 × 14.01 g/mol) + (4 × 16.00 g/mol)

Molar mass of N2O4 = 92.02 g/mol

Now, we can use the molar mass to convert the number of molecules to grams.

Moles of N2O4 = Number of molecules / Avogadro's number

Moles of N2O4 = 3.21 x 10^21 / 6.022 x 10^23

Moles of N2O4 ≈ 0.00533 mol

Mass of N2O4 = Moles of N2O4 × Molar mass of N2O4

Mass of N2O4 = 0.00533 mol × 92.02 g/mol

Mass of N2O4 ≈ 0.490 g

Therefore, the mass of 3.21 x 10^21 molecules of dinitrogen tetroxide is approximately 0.490 grams.

Learn more about molecules of dinitrogen tetroxide (N2O4) here

https://brainly.com/question/30623065

#SPJ11

To calculate the mole fraction of solute (NaCl), we need to determine the number of moles of NaCl and the number of moles of water in the solution.

Given:

Mass of NaCl = 5.85 g

Mass of water = 90 g

To find the number of moles of NaCl, we divide the mass of NaCl by its molar mass:

Molar mass of NaCl = 22.99 g/mol (atomic mass of Na) + 35.45 g/mol (atomic mass of Cl) = 58.44 g/mol

Number of moles of NaCl = 5.85 g / 58.44 g/mol

To find the number of moles of water, we divide the mass of water by its molar mass:

Molar mass of water (H2O) = 1.01 g/mol (atomic mass of H) + 16.00 g/mol (atomic mass of O) = 18.01 g/mol

Number of moles of water = 90 g / 18.01 g/mol

Now we can calculate the mole fraction of NaCl:

Mole fraction of NaCl = Moles of NaCl / (Moles of NaCl + Moles of water)

Mole fraction of NaCl = (5.85 g / 58.44 g/mol) / [(5.85 g / 58.44 g/mol) + (90 g / 18.01 g/mol)]

Calculating the expression, we find:

Mole fraction of NaCl ≈ 0.0197

Therefore, the mole fraction of solute (NaCl) is approximately 0.0197, which is closest to option A: 0.0196.

To know more about fraction refer here

https://brainly.com/question/10354322#

#SPJ11

The pOH of a solution at 25.0°C with [H₃O⁺]=9.90×10⁻¹² M is 4.00.

The pH and pOH of a solution are related through the equation pH + pOH = 14.

Therefore, to find the pOH of the solution, we need to first calculate the pH. The pH is given by the negative logarithm of the hydronium ion concentration, so we have:

pH = -log[H₃O⁺] = -log(9.90×10⁻¹²) = 11.00

Using the relationship pH + pOH = 14, we can find the pOH:

pOH = 14 - pH = 14 - 11.00 = 3.99 ≈ 4.00

Therefore, the pOH of the solution is 4.00.

To know more about pOH of a solution, refer here:

https://brainly.com/question/23227189#

#SPJ11

The bag contains 56 marbles. (35 yellow marbles can be expressed in the ratio as 5 yellow marbles for every 8 orange marbles.)

If a bag contains 35 yellow marbles, we can determine the total number of marbles in the bag using the given ratio. According to the ratio provided, for every 5 yellow marbles, there are 8 orange marbles. We can set up a proportion to find the total number of marbles in the bag.

Let x be the total number of marbles in the bag. The proportion can be written as: 5 yellow marbles / 8 orange marbles = 35 yellow marbles / x

Cross-multiplying, we get: 5x = 35 * 8

5x = 280

Dividing both sides by 5, we find: x = 56

Therefore, the bag contains 56 marbles.

According to the given ratio of 5 yellow marbles for every 8 orange marbles, we can set up a proportion to find the total number of marbles in the bag. By cross-multiplying, we find that 5 times the total number of marbles is equal to 35 times 8. Simplifying the equation, we get 5x = 280. Dividing both sides of the equation by 5, we find that the total number of marbles in the bag, represented by x, is equal to 56. Therefore, the bag contains 56 marbles in total. The given information of having 35 yellow marbles helps us determine the overall quantity of marbles in the bag using the provided ratio.

LEARN MORE ABOUT marbles here: brainly.com/question/32534055

#SPJ11

The complex ions that can have cis-trans isomers are [Pt(NH3)2Cl2] and [Pt(NH3)Cl3]. Among the given square planar complex ions, the one that can have cis-trans isomers is B. [Pt(NH3)2Cl2]. This complex ion has different ligands which allow for geometric isomerism, with cis and trans isomers based on the arrangement of ligands around the central atom.

This question requires a long answer as we need to analyze each complex ion individually to determine if they can have cis-trans isomers. A cis-trans isomerism occurs when two ligands in a coordination complex are arranged differently around the central metal atom. For square planar complexes, this is possible when there are two sets of identical ligands and two of them are adjacent to each other. This complex ion has four identical ammonia ligands arranged in a square planar geometry around the platinum atom. Since there are no other ligands present, there is no possibility of cis-trans isomerism.

To know more about isomers visit :-

https://brainly.com/question/30662191

#SPJ11

The balanced half-reaction in which ethanol is oxidized to ethanoic acid is a two-electron process.

To determine the number of electrons involved in the oxidation process, we need to look at the balanced half-reaction. The half-reaction for the oxidation of ethanol to ethanoic acid is:

CH₃CH₂OH → CH₃COOH + 2e⁻

This half-reaction shows that two electrons are involved in the oxidation process. For every ethanol molecule that is oxidized, two electrons are transferred to the oxidizing agent.


Ethanol can be oxidized to ethanoic acid by a variety of oxidizing agents, including potassium permanganate, potassium dichromate, and acidic or basic solutions of potassium or sodium dichromate. During the oxidation process, ethanol loses electrons and is converted to ethanoic acid. The balanced half-reaction for the oxidation of ethanol to ethanoic acid shows that two electrons are transferred during the process. This means that the reaction is a two-electron process. The oxidation of ethanol to ethanoic acid is an important reaction in organic chemistry and is used in the production of acetic acid, which is an important industrial chemical.

To know more about oxidizing agent, visit:

https://brainly.com/question/10547418

#SPJ11

We need 0.59 grams of ammonia to make 1.25 L of a solution with a pH of 11.68.

To determine the grams of ammonia needed to make a solution with a pH of 11.68, we need to use the base dissociation constant (Kb) of ammonia to calculate the concentration of ammonia in the solution.

Kb for ammonia is 1.8 x 10⁻⁵. The relationship between the concentration of ammonia ([NH3]), the concentration of hydroxide ions ([OH-]), and Kb is:

Kb = [NH3][OH-] / [NH4+]

At pH 11.68, the concentration of hydroxide ions can be calculated using the following equation:

pOH = 14 - pH

[OH-] = [tex]10^{(-pOH)[/tex]

pOH = 14 - 11.68 = 2.32

[OH-] = [tex]10^{(-2.32)[/tex]

         = 5.48 x 10⁻³ M

Since ammonia and ammonium ion are in equilibrium, the concentration of ammonium ion ([NH4+]) can be calculated as follows:

Kw = [H+][OH-]

1.0 x 10⁻¹⁴ = [H+][OH-]

[H+] = [tex]10^{(-pH)[/tex] = [tex]10^{(-11.68)[/tex]

       = 2.24 x 10⁻¹² M

[NH4+] = Kw / [H+]

            = (1.0 x 10⁻¹⁴) / (2.24 x 10⁻¹²)

            = 4.46 x 10⁻³ M

Now we can use the Kb equation to find the concentration of ammonia:

1.8 x 10⁻⁵ = [NH3](5.48 x 10⁻³) / (4.46 x 10⁻³)

[NH3] = 2.22 x 10⁻² M

Finally, we can use the definition of molarity (moles per liter) and the volume of the solution (1.25 L) to calculate the amount of ammonia needed:

mass = molarity x volume x molar mass

The molar mass of ammonia is 17.03 g/mol.

Substituting our values, we get:

mass = (2.22 x 10⁻² mol/L) x (1.25 L) x (17.03 g/mol)

         = 0.59 g

Therefore, we need 0.59 grams of ammonia to make 1.25 L of a solution with a pH of 11.68.

To know more about dissociation constant refer here

brainly.com/question/31607191#

#SPJ11

The proportional gain [tex]$K_p$[/tex] is 0.775.

Proportional gain, often denoted as Kp, is a parameter used in control systems to adjust the output of a controller proportional to the error signal. In other words, it is the gain applied to the error signal to produce a corrective action.

In a closed-loop control system, the proportional gain is multiplied by the error signal, which is the difference between the setpoint and the process variable, to generate the controller output. A higher value of Kp results in a larger output for the same error signal, meaning that the control action is more aggressive. On the other hand, a lower value of Kp results in a smaller output, meaning that the control action is more gentle.

Proportional gain is just one of several parameters that can be adjusted in a control system to achieve the desired performance. The selection of the appropriate gain values depends on the dynamics of the process being controlled, as well as the desired response characteristics of the closed-loop system.

The transfer function of the closed-loop system is given by:

[tex]$$G_c(s) = \frac{K_p G(s)}{1 + K_p G(s)}$$[/tex]

The characteristic equation of the closed-loop system is given by:

[tex]$$1 + K_p G(s) = 0$$[/tex]

The desired closed-loop pole location is given by:

[tex]$$s_{c\ desired} = -\zeta w_n + jw_n\sqrt{1-\zeta^2}$$[/tex]

Substituting the given values, we get:

[tex]$$s_{c\ desired} = -8.32 + j12.6$$[/tex]

Since the closed-loop pole is a complex conjugate pair, the open-loop transfer function must have a pole at the same location. Therefore, we set:

[tex]$$s_{p\ desired} = -\zeta w_n = -8.32$$[/tex]

Solving for [tex]$K_p$[/tex] using the desired pole location, we get:

[tex]$$K_p = \frac{w_n^2}{a} \cdot \frac{1}{|s_{c\ desired} + 22 + 2|} = 0.775$$[/tex]

Therefore, the proportional gain [tex]$K_p$[/tex] is 0.775.

To learn more about proportional gain refer here:

https://brainly.com/question/31463018

#SPJ11

The oxidation half reaction of Zn(s) is: Zn(s) → Zn2+ (a q) + 2e-.This half-reaction shows the loss of electrons by the Zn atoms, which are oxidized to Zn2+ ions.

In the redox reaction Zn(s) + Cu2+ (a q) → Zn2+ (a q) + Cu(s), Zn is the reducing agent, as it undergoes oxidation (loses electrons), and Cu2+ is the oxidizing agent, as it undergoes reduction (gains electrons). The overall reaction is a redox reaction, in which electrons are transferred from Zn to Cu2+, resulting in the formation of Zn2+ and Cu. The oxidation half reaction of Zn(s) shows the conversion of Zn(s) to Zn2+ (aq) and the loss of two electrons.

Learn more about oxidation half here;

https://brainly.com/question/1528621

#SPJ11

When 1,3-butadiene is heated with chlorine gas (Cl₂) in water (H₂O), two products are formed: 3-chloro-1-butene and 1,4-dichloro-2-butene.

1,3-Butadiene is a conjugated diene that consists of a four-carbon chain with two double bonds located at positions 1 and 3. Its molecular formula is C₄H₆. 1,3-butadiene is a highly reactive molecule due to the presence of its double bonds, which can participate in a variety of chemical reactions such as addition reactions, Diels-Alder reactions, and polymerization reactions.

The alcohol-containing product is not formed in this reaction. However, 3-chloro-1-butene can be further reacted with water in the presence of a strong acid catalyst to form 3-chlorobut-1-ene-3-ol, which is an alcohol-containing product. Here are the structures of the two products initially formed.

1,3-Butadiene is a colorless, highly flammable gas with a mild aromatic odor. It is an organic compound with the molecular formula C4H6 and has two double bonds. It is commonly used as a monomer in the production of synthetic rubbers, such as styrene-butadiene rubber and nitrile rubber.

To know more about conjugated diene here

https://brainly.com/question/17425564

#SPJ4

Answer:The reaction can occur since Cl2 gas has a higher activity than Br2 gas. Therefore, solid FeBr2 can react with Cl2 gas to produce solid FeCl2 and Br2 gas. The reaction can be represented as follows:

FeBr2 (s) + Cl2 (g) -> FeCl2 (s) + Br2 (g)

Thus, the correct answer is D: Yes, because Cl2 has higher activity than Br2.

Explanation:

An exothermic process is depicted in this figure. This is because the potential energy of the reactants is larger than the potential energy of the products.

As the reaction progresses, the potential energy of the reactants decreases while the potential energy of the products increases. This indicates that energy is released throughout the operation, as is characteristic of an exothermic reaction.

In an exothermic reaction, energy is released as the reaction progresses, and the products have a lower potential energy than the reactants. The graph depicts this by the decreasing slope of the reactant potential energy as the reaction progresses and the corresponding increase in the product potential energy.

The energy released during the reaction is typically in the form of heat, which can be seen as an explosion with an increase in the temperature.

Learn more about  energy  at:

https://brainly.com/question/1932868

#SPJ1

To determine which student's measurement has the largest percent error in measuring the acceleration of gravity, we need to calculate the percent error for each student's measurement and compare them to the expected value of 9.78 m/s^2. The percent error is calculated by subtracting the expected value from the measured value, dividing by the expected value, and multiplying by 100.

The student with the largest percent error will have the measurement that deviates the most from the expected value.

Explanation:

To calculate the percent error for each student's measurement, we can use the formula:

Percent Error = |(Measured Value - Expected Value) / Expected Value| * 100

Let's assume the measured values for the four students are A, B, C, and D.

The percent error for each student can be calculated as follows:

Percent Error(A) = |(A - 9.78) / 9.78| * 100

Percent Error(B) = |(B - 9.78) / 9.78| * 100

Percent Error(C) = |(C - 9.78) / 9.78| * 100

Percent Error(D) = |(D - 9.78) / 9.78| * 100

By comparing the calculated percent errors for each student, we can determine which measurement has the largest percent error. The student with the largest percent error will have the measurement that deviates the most from the expected value of 9.78 m/s^2.

To learn more about Gravity - brainly.com/question/31321801

#SPJ11

In order to calculate the molar solubility of lead (II) bromide (PbBr2) in pure water, we need to use the solubility product constant (Ksp) which is given as 4.67x10^-6.

The equation for the dissociation of PbBr2 in water is: PbBr2(s) ↔ Pb2+(aq) + 2Br-(aq).

The Ksp expression for this reaction is: Ksp = [Pb2+][Br-]^2.

Since we are given that the water is pure, we can assume that the initial concentrations of Pb2+ and Br- are both zero.

Let x be the molar solubility of PbBr2 in water. Then at equilibrium, the concentrations of Pb2+ and Br- are both equal to x.

4.67x10^-6 = x * (2x)^2.

Simplifying the expression gives: 4.67x10^-6 = 4x^3, x = 0.00309 M.

Therefore, the molar solubility of PbBr2 in pure water is 0.00309 M.

Read more about Molar solubility.

https://brainly.com/question/28170449

#SPJ11

Proton III is likely to be the most deshielded and therefore would absorb furthest downfield.

To determine which proton would absorb furthest downfield in an NMR spectrum, we need to consider the factors that affect chemical shift values, such as the electronic environment around the proton.

The proton that is most shielded from the applied magnetic field will experience the smallest magnetic field, and therefore will appear at a lower frequency or further downfield in the NMR spectrum. Conversely, the proton that is least shielded will experience the largest magnetic field and appear at a higher frequency or further upfield in the NMR spectrum.

Based on the structures given, proton III is likely to be the most deshielded and therefore would absorb furthest downfield. This is because proton III is directly attached to a carbonyl group, which is an electron-withdrawing group that reduces the electron density around the proton, making it less shielded.

Proton IV A is also attached to a carbonyl group, but it is further away from the group than proton III, so it will be less deshielded. Proton IV B is attached to a benzene ring, which is an electron-rich group that shields the proton, making it less deshielded than proton III.

Protons 11, I, and D are not attached to any electron-withdrawing or electron-donating groups, so their chemical shifts will be closer to the typical range for protons in organic molecules.

Learn more about downfield

brainly.com/question/30607938

#SPJ11

To find the minimum number of cans of paint Edward will need to paint all the doors, we first need to calculate the total area that needs to be painted. Each door has a front and a back, so there are 2 sides per Door .

The area of one side is the product of the width and length, which is 2.8 ft * 6.8 ft = 19.04 ft². Therefore, the total area for both sides of one door is 2 * 19.04 ft² = 38.08 ft².

Since Edward has 6 doors, the total area to be painted is 6 * 38.08 ft² = 228.48 ft².

Given that one can of paint covers 62.5 ft², we can calculate the minimum number of cans needed by dividing the total area by the coverage of one can: 228.48 ft² / 62.5 ft² = 3.6552.

Since we can't have a fraction of a can, Edward will need a minimum of 4 cans of paint to paint all the doors.

 To  learn  more  about fraction click here:brainly.com/question/10354322

#SPJ11

The thermal efficiency as a percentage is approximately 53.82%.

To calculate the thermal efficiency for a heat engine operating between a source and a sink, you can use the formula:

Thermal efficiency = 1 - (T_cold / T_hot)

First, convert the temperatures to Kelvin:

T_hot = 377°C + 273.15 = 650.15 K
T_cold = 27°C + 273.15 = 300.15 K

Now, substitute the values into the formula:

Thermal efficiency = 1 - (300.15 / 650.15) = 1 - 0.4618 ≈ 0.5382

As a percentage, the thermal efficiency is approximately 53.82%. Among the given options, the closest choice is 54%.

More on thermal efficiency: https://brainly.com/question/11900895

#SPJ11

The oxidation state of cobalt in [Co(NH3)5Cl]Cl2 is +3, while the oxidation state of ruthenium in [Ru(CN)3(CO)2]3− is +2.

In [Co(NH3)5Cl]Cl2, there are five ammonia (NH3) ligands and one chloride (Cl-) ligand, with two chloride counterions. Each ammonia ligand is neutral and has a charge of 0. The chloride ligand has a charge of -1, and there are two of them, giving a total charge of -2 for the complex. Since the overall charge of the complex is 0, the oxidation state of cobalt must be +3, as it contributes three positive charges to balance out the negative charges.

In [Ru(CN)3(CO)2]3−, there are three cyanide (CN-) ligands and two carbonyl (CO) ligands. Each cyanide ligand has a charge of -1, and each carbonyl ligand has a charge of 0. There is also a charge of -3 on the complex due to the three negative charges from the cyanide ligands. Therefore, the oxidation state of ruthenium must be +2, as it contributes two positive charges to balance out the negative charges.

learn more about oxidation here:

https://brainly.com/question/9496279

#SPJ11

The net ionic equation for the reaction that occurs when a small amount of nitric acid is added to a nano₂/hno₂ buffer is HNO₂ -> NO₂ is True.

When a small amount of nitric acid (HNO₃) is added to a NaNO₂/HNO₂ buffer solution, the following reaction occurs:

HNO₃ + HNO₂ ⇌ NO₂+ + H₂O + HNO₂
The net ionic equation for this reaction is:
H+ + NO₂- ⇌ HNO₂

In this reaction, the HNO₂ acts as a buffer and resists changes in pH when an acid or base is added. The HNO₃ reacts with the HNO₂ to form NO₂+ and H₂O, which then react with the excess HNO₂ to form H+ and HNO₂. The H+ ions combine with the NO₂- ions from the buffer to form HNO₂, which maintains the pH of the solution.

Therefore, the net ionic equation for the reaction that occurs when a small amount of nitric acid is added to a NaNO₂/HNO₂ buffer is H+ + NO₂- ⇌ HNO₂.

learn more about nitric here:

https://brainly.com/question/31605215

#SPJ11

The most likely identity of the unknown substance is silver.

To identify the substance, we need to determine its specific heat capacity using the provided information:

The formula to calculate specific heat capacity (c) is:

q = mcΔT

where q is the heat added (85.7 J), m is the mass (21.7 g), and ΔT is the change in temperature (44.1 °C - 27.3 °C = 16.8 °C).

Rearranging the formula for c:

c = q / (mΔT)

Plugging in the given values:

c = 85.7 J / (21.7 g × 16.8 °C) ≈ 0.231 J/g°C

Now, comparing the calculated specific heat capacity with the given substances:

- Copper: 0.385 J/g°C
- Silver: 0.235 J/g°C
- Aluminum: 0.903 J/g°C
- Iron: 0.449 J/g°C
- Water: 4.184 J/g°C
- Lead: 0.128 J/g°C

The substance with the closest specific heat capacity to our calculated value (0.231 J/g°C) is silver, with a specific heat of 0.235 J/g°C. Therefore, the most likely identity of the unknown substance is silver.

To learn more about silver, refer below:

https://brainly.com/question/6434391

#SPJ11

4.74 is the ph of a solution that is 0.10 m hc2h3o2 and 0.10 m nac2h3o2  (the conjugate base).

To determine the pH of this solution, we need to first calculate the concentration of the conjugate base, which is NaC2H3O2. Since the initial concentration of HC2H3O2 is 0.10 M and it reacts with NaOH in a 1:1 ratio, the concentration of the conjugate base is also 0.10 M.
Next, we can use the Ka value of HC2H3O2 to calculate the concentration of H+ ions in the solution:
Ka = [H+][C2H3O2-]/[HC2H3O2]
1.8 x 10^-5 = x^2 / (0.10 - x)
where x is the concentration of H+ ions
Solving for x, we get a concentration of 1.34 x 10^-3 M.
Now, we can use the pH formula to calculate the pH of the solution:
pH = -log[H+]
pH = -log(1.34 x 10^-3)
pH = 2.87
Therefore, the pH of the solution is 2.87.
The pH of a solution with 0.10 M HC2H3O2 and 0.10 M NaC2H3O2 can be determined using the Henderson-Hasselbalch equation. This equation relates the pH, pKa, and the ratio of the concentrations of the conjugate base (A-) and weak acid (HA).
Henderson-Hasselbalch equation: pH = pKa + log([A-]/[HA])
In this case, the weak acid (HA) is HC2H3O2 and its conjugate base (A-) is C2H3O2-. The Ka of HC2H3O2 is given as 1.8 x 10^-5. To find the pKa, use the formula:
pKa = -log(Ka) = -log(1.8 x 10^-5) ≈ 4.74
Since the solution is a buffer with equal concentrations of the weak acid and its conjugate base (0.10 M each), the ratio of [A-] to [HA] is 1.
Now, apply the Henderson-Hasselbalch equation:
pH = pKa + log([A-]/[HA]) = 4.74 + log(1) = 4.74
So, the pH of the solution is approximately 4.74.

To know more about conjugate base visit:

brainly.com/question/30225100

#SPJ11

The main answer to your question is that at 300 kelvin, the speed of sound through krypton is approximately 157.7 meters per second.

The speed of sound in a gas is determined by its temperature, molar mass, and the heat capacity ratio of the gas. The formula for calculating the speed of sound in a gas is:

v = sqrt(gamma * R * T / M)

where:
v = speed of sound
gamma = heat capacity ratio of the gas (for krypton, gamma is 1.67)
R = universal gas constant (8.314 J/mol*K)
T = temperature in kelvin
M = molar mass of the gas in kilograms per mole (for krypton, M is 0.0838 kg/mol)

Plugging in the given values:

v = sqrt(1.67 * 8.314 * 300 / 0.0838)
v = 157.7 m/s

Therefore, at 300 kelvin, the speed of sound through krypton is approximately 157.7 meters per second.

For more information on speed of sound visit:

https://brainly.com/question/15381147

#SPJ11

The number of bright fringes formed on either side of the central bright fringe can be determined using the formula:

n = (D/L) * (m + 1/2)

Where:

n = number of bright fringes

D = distance between the double slit and the screen

L = wavelength of light

m = order of the fringe

For the central bright fringe, m = 0.

For the first-order bright fringe, m = 1.

The distance between the double slit and the screen is not given in the question. Therefore, we cannot determine the exact number of bright fringes that can be formed on either side of the central bright fringe. However, we can use the maximum value of D/L, which is when sinθ = 1, to estimate the maximum number of bright fringes that can be formed.

For sinθ = 1, θ = 90°.

sinθ = (m + 1/2) * (L/d)

1 = (m + 1/2) * (625 nm/3.76 x 10-6 m)

m + 1/2 = 1.06 x 104

m ≈ 2.12 x 104

This means that the maximum order of bright fringe is about 2.12 x 104. Therefore, at most, there can be 2.12 x 104 bright fringes on either side of the central bright fringe.

To know more about fringes refer here

https://brainly.com/question/31315270#

#SPJ11

Therefore, the speed at which [Br2] is increasing is 0.066 m/s.

To solve this problem, we need to use the rate of reaction formula, which is:
Rate of reaction = (1/coeff. of reactant) x (d[reactant]/dt) = (1/coeff. of product) x (d[product]/dt)
Here, the coefficient of Br- is 5 and the coefficient of Br2 is 3. Therefore,
(d[Br2]/dt) = (3/5) x (-d[Br-]/dt)
Substituting the given value of d[Br-]/dt as -0.11 m/s, we get:
(d[Br2]/dt) = (3/5) x (0.11) = 0.066 m/s
The negative sign indicates that the concentration of Br- is decreasing, and the positive sign of the rate of [Br2] indicates that its concentration is increasing. The reaction involves the conversion of Br- to Br2, so as Br- concentration decreases, the Br2 concentration increases.

To know more about reaction visit:

https://brainly.com/question/29762834

#SPJ11