Approximately what percent of the landmass on earth receives
very little or no rainfall?

Answer:

1.73 M

Explanation:

Molarity is moles per liter, so we need to divide 7.47 moles by 4.31 liters to get the molarity of the solution.

7.47/4.31 ≈ 1.73 M

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Answer: behavior that is simple, untaught, and born knowing

Have a nice dam day!!

The term that describes innate behavior is:

D. behavior that is untaught but very complex

Intr-insic or "intuitive" ways of behaving are innate and don't need learning or related knowledge to be performed. Models incorporate romance and ways of behaving, departure and guarded moves, and hostility. Movement and Migration Innate or ins-tinctual behaviors rely on response to sti-muli.

Thus, option D is correct.

Find more information about Innate behavior here:

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Answer:

11.6 mol O₂

Explanation:

In order to solve this problem we need to convert moles of carbon dioxide (CO₂) into moles of oxygen gas (O₂). To do so we'll use a conversion factor containing the stoichiometric coefficients of the balanced reaction:

Answer:

because the water would diloute the chemicals in the vinegar

Explanation:

Answer:

Volume is reduced to half

Explanation:

Acid base titration are commonly used reactions in a lab, and are ofter used to get pH or different kind of solutions.

The neutralization of an acid base reaction is reached, when the solution (having added an indicator previously) changes its original color. chemically speaking, this occurs when the number of moles of the acid and the base are balanced and equal. In other words the following:

n₁ = n₂   (1)

This expression can also be expressed in function of concentration and volume:

M₁V₁ = M₂V₂   (2)

From here, solving for V₁:

V₁ = M₂V₂  / M₁

Now, this expression is true only when we have the same kind of substance that can lose or gain the same number of hydrogens.

Lets suppose that we have as base NaOH (Monoprotic base) and HCl (monoprotic acid), the titration reaction would be:

NaOH + HCl --------> NaCl + H₂O

As both of the species are monoprotic, the number of moles are the same  when they reach the equilibrium, so, expression  (2) can be used, and calculate volume or concentrations.

However, in this case, a partner made a mistake and use a diprotic acid, in this case, H₂SO₄, In this case, things chance because H₂SO₄ is diprotic, meaning that we need to dissociate two hydrogens in equilibrium, therefore, expression (2) would be something like this.

Acid: 1; Base: 2

H₂SO₄ + 2NaOH ------> Na₂SO₄ + H₂O

nH₂SO₄ = n₁ = 1

nNaOH = n₂ = 2

n₁/n₂ = 1/2

2n₁ = n₂   (3)

Writting this, in function of concentration and volume, it would be:

2M₁V₁ = M₂V₂   (4)

From here, if we solve for the volume of the acid (V₁):

V₁ = M₂V₂ / 2M₁

Therefore, according to this expression, we can see that the volume required of the acid would be half the volume required of the monoprotic acid. For example, if we need 50 mL of Chloridic acid to reach the equivalence point with NaOH, then, with H₂SO₄ it will only need 25 mL. This, of course, assuming that concentrations are the same, and volume of the base used, the same.

Hope this helps

Answer:

No

Explanation:

thats scientifically impossible

Answer:

1. 2 M

2. 2 M

Explanation:

1. Determination of the final concentration.

Initial Volume (V₁) = 2 L

Initial concentration (C₁) = 6 M

Final volume (V₂) = 6 L

Final concentration (C₂) =?

The final concentration can be obtained as follow:

C₁V₁ = C₂V₂

6 × 2 = C₂ × 6

12 = C₂ × 6

Divide both side by 6

C₂ = 12 / 6

C₂ = 2 M

Therefore, the final concentration of the solution is 2 M

2. Determination of the final concentration.

Initial Volume (V₁) = 0.5 L

Initial concentration (C₁) = 12 M

Final volume (V₂) = 3 L

Final concentration (C₂) =?

The final concentration can be obtained as follow:

C₁V₁ = C₂V₂

12 × 0.5 = C₂ × 3

6 = C₂ × 3

Divide both side by 3

C₂ = 6 / 3

C₂ = 2 M

Therefore, the final concentration of the solution is 2 M

Answer:

3.92%

Explanation:

The solution that is formed is of KCl in water. This means that the percent composition by mass is given by the formula:

We now calculate the mass of solution:

Finally we calculate the percent composition:

Answer:

With Br2 - Bromobenzene

With Cl2 - Chlorobenzene

With HNO3- Nitrobenzene

With H2SO4 - Benzenesulphonic acid

With HCOCl - Benzoyl chloride

With 1-chloro-2,2-dimethylpropane - 2,2dimethyl-1-phenyl propane

Explanation:

The common thread joining all these reactions is that they are all electrophillic reactions. They are so called because the attacking agents in each reagent is an electrophile. Electrophiles are species that have electron deficient centers and are known to attack molecules that are high in electron density at regions of high electron density.

The benzene molecule has rich electron density. Any substituents that donates electrons to the ring improves the likelihood that benzene will undergo electrophillic substitution reactions while electron withdrawing substituents decrease the likelihood that benzene will undergo electrophillic substitution reactions.

The names of the compounds formed when benzene undergoes electrophillic reaction with the attacking agents listed in the question are displayed in the answer section.

Answer: Does the animal prey on other animals? Is the animal a carnivore?

Answer:

I think the body system

Explanation:

Answer:body system

Explanation:

Answer:

Science and technology is an interdisciplinary topic encompassing science, technology, and their interactions: Science is a systematic enterprise that builds and organizes knowledge in the form of explanations and predictions about nature and the universe.

Explanation:

Answer: New volume of the solution is 100 mL.

Explanation:

Given: [tex]V_{1}[/tex] = 3 mL,     [tex]M_{1}[/tex] = 200 M

[tex]M_{2}[/tex] = 6 M,     [tex]V_2[/tex] = ?

Formula used to calculate the new volume of solution is as follows.

[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]

Substitute the values into above formula as follows.

[tex]M_{1}V_{1} = M_{2}V_{2}\\200 M \times 3 mL = 6 M \times V_{2}\\V_{2} = \frac{200 M \times 3 mL}{6 M}\\= 100 mL[/tex]

Thus, we can conclude that new volume of the solution is 100 mL.

Explanation:

sexual reproduction has minimal changes of mutations compared to asexual reproduction

Answer:

sexual reproduction has minimal changes of mutations compared to asexual reproduction

I hope this helps

Answer:

Subbituminous coal can form at temperatures as low as 35 to 80 °C (95 to 176 °F) while anthracite requires a temperature of at least 180 to 245 °C (356 to 473 °F).

Sub-types: Cannel coal

Child material class: Lignite

Explanation:

Answer:

c4 is an explosive..

contains RDX, DOS, DOA, and PIB.

Explanation:

Answer:

[tex]296.05\ \text{K}[/tex]

Explanation:

[tex]m_w[/tex] = Mass of water = 100 g

[tex]c_w[/tex] = Specific heat of water = [tex]4.184\ \text{J/g K}[/tex]

[tex]m_c[/tex] = Mass of copper = 20 g

[tex]c_c[/tex] = Specific heat of copper = [tex]0.385\ \text{J/g K}[/tex]

[tex]\Delta T_w[/tex] = Temperature change in water = [tex](T-295)[/tex]

[tex]\Delta T_c[/tex] = Temperature change in cooper = [tex](353-T)[/tex]

T = Final temperature of the system

The heat balance of the system is given by

[tex]m_wc_w\Delta T_w=m_cc_c\Delta T_c\\\Rightarrow 100\times 4.184\times (T-295)=20\times 0.385\times (353-T)\\\Rightarrow 418400\left(T-295\right)=7700\left(353-T\right)\\\Rightarrow 418400T-123428000=2718100-7700T\\\Rightarrow T=\frac{1261461}{4261}\\\Rightarrow T=296.05\ \text{K}[/tex]

The final temperature of the water is [tex]296.05\ \text{K}[/tex].

The final temperature of the water when placed in a calorimeter is 296.05K

HOW TO CALCULATE FINAL TEMPERATURE:

Where;

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Answer:

the order of vibrational frequency is:

C ≡ N > C=N > C=S > S-C

Explanation:

The bond's vibration frequency is determined using the following equation:

[tex]\zeta = \dfrac{1}{2 \pi c}\sqrt{\dfrac{k}{\mu}}[/tex]

where;

reduced mass[tex]\mu = \dfrac{m_1m_2}{m_1+m_2}[/tex]

velcoity of light = c

force constant = k

The frequency of vibration, on the other hand, is inversely proportional to the atom's mass, because the heavier the atom, the lower the frequency.

In addition, the value of a bond's stretching frequency rises as the bond's intensity rises. As a result, the frequency is as follows:

triple > double > single

The reduced mass [tex](\mu)[/tex] of C-N bond.

[tex]\mu = \dfrac{m_1m_2}{m_1+m_2}[/tex]

[tex]\mu = \dfrac{12*14}{12+14} \\ \\ \mu = 6.46[/tex]

The reduced mass of C-S bond;

[tex]\mu = \dfrac{m_1m_2}{m_1+m_2}[/tex]

[tex]\mu = \dfrac{12\times 32}{12+32} \\ \\ \mu = 8.72[/tex]

Thus, the order of vibrational frequency is:

C ≡ N > C=N > C=S > S-C

Answer:

12.7mol Na.

Explanation:

Hello there!

In this case, according to the concept of mole, which stands for the amount of substance, we can recall the concept of Avogadro's number whereby we understand that one mole of any substance contains 6.022x10²³ particles, for the given atoms of sodium, we can calculate the moles as shown below:

[tex]7.9x10^{23}atoms*\frac{1mol}{6.022x10^{23}atoms} \\\\[/tex]

Thus, by performing the division we obtain:

[tex]12.7molNa[/tex]

Regards!

Answer:

Aneroid barometer and mercury barometer are such two types. The main difference between aneroid and mercury barometer is that aneroid barometer measures the atmospheric pressure using the expansion of a metal whereas mercury barometer measures the atmospheric pressure by adjusting the height of mercury inside a tube.

Explanation:

Answer:

2.3 * 10^-5

Explanation:

Recall that the solubility of a solute is the amount of solute that dissolves in 1 dm^3 or 1000cm^3 of solution.

Hence;

Amount of calcium oxalate = 154 * 10^-3/128.097 g/mol = 1.2 * 10^-3 mols

From the question;

1.2 * 10^-3 mols dissolves in 250 mL

x moles dissolves in 1000mL

x = 1.2 * 10^-3 mols * 1000/250

x= 4.8 * 10^-3 moldm^-3

CaC2O4(s) ------->Ca^2+(aq) + C2O4^2-(aq)

Hence Ksp = [Ca^2+] [C2O4^2-]

Where;

[Ca^2+] = [C2O4^2-] = 4.8 * 10^-3 moldm^-3

Ksp = (4.8 * 10^-3)^2

Ksp = 2.3 * 10^-5