Answer:
skateworld
Step-by-step explanation:
26x3+50=128 aka skate worlds price
26x5=130 aka roller land price
Antionio should use skateworld and he would save 2$
Answer: SkateWorld. He saves $2
Step-by-step explanation:
SkateWorld:
21 *3 =63
5*3=15
63+15=78
78+50= 128
Roller Land:
21*5= 105
5*5=25
105+25=130
130-128= 2
A coach collected data for his runners for 2 weeks. Week 1: Mean = 14.5 miles/ MAD = 1.15 Week 2: Mean = 16 miles/ MAD = 1.5. Which statement correctly compares the variability from Week 1 to Week 2? *
GUYS PLEASE HELP ALMOST DUE
Answer:
1/5
Step-by-step explanation:
y = 12
12 = 1/5 x 60
12= 12
y = 9
9 = 1/5 x 45
9 = 9
and so on and it always results to one fifth
What is the measure of angle c?
Answer:
c=29°
Step-by-step explanation:
angle b=97°{ vertically opposite angle}
now,
97°+54°+c=180°{ sum of angle of triangle}
x=180-151x=29°stay safe healthy and happy.Answer: I'm pretty sure it's 29 degrees.
Step-by-step explanation:
Angle b is directly opposite of 97, and is the same. So b is equal to 97. Every triangle is 180 degrees, so all you have to do is 180 - 54 - 97, which is 29. I hope that helps!!
At the neighborhood block party, Hassan served 3 gallons of hot chocolate and 1/2 of a gallon of apple cider. How much more hot chocolate than apple cider did Hassan serve?
Write your answer as a fraction or as a whole or mixed number.
Answer:
2 gallons and 1/2
Step-by-step explanation:
You just have to subtract 1/2 from 3.
3 - 1/2 = 2 1/2
or
3 - .5 = 2.5
And 2 1/2 is how much more he served.
Answer: 5 times more hot chocolate
Step-by-step explanation:
HELPPPPPPPPPPPPPPPPPPPPP
Answer:
2
35
6
Step-by-step explanation:
14/7=2
5*7=35
42/7=6
PLS ANWER ASAP!! person with correct answer will be marked brainliest
Answer:
62 degrees since there are supplementary angles
Step-by-step explanation:
∠PQO= 180 degrees - 118 degrees
∠PQO= 62 degrees is the answer.
∠PQO= 180°-∠RQO -------(Supplementary Angles)
∠PQO= 180° - 118°
∠PQO= 62° answer.
pls pls i need the answer and A REALLY GOOD EXPLANATION pls pls
Answer:
15/50 will be your answer 30%
Step-by-step explanation:
First add them all up.
Then you want to make a simple equation
15/50
Answer:
30%
Step-by-step explanation:
15+10+2+20+3 = 50
therefore 15 is 30% of 50
A radioactive substance decays to 30% of its original mass in 15 months. Determine the half-life of this radioactive substance to the nearest tenth. Show your work.
please help
Answer:
The half-life of this radioactive substance is of 8.6 months.
Step-by-step explanation:
Exponential decay of an amount:
The equation that models an amount after t units of time, subject to exponential decay, is given by:
[tex]A(t) = A(0)(1-r)^t[/tex]
In which A(0) is the initial amount and r is the decay rate, as a decimal.
A radioactive substance decays to 30% of its original mass in 15 months.
This means that [tex]A(15) = 0.3A(0)[/tex]. We use this to find 1 - r.
[tex]A(t) = A(0)(1-r)^t[/tex]
[tex]0.3A(0) = A(0)(1-r)^{15}[/tex]
[tex](1-r)^{15} = 0.3[/tex]
[tex]\sqrt[15]{(1-r)^{15}} = \sqrt[15]{0.3}[/tex]
[tex]1 - r = (0.3)^{\frac{1}{15}}[/tex]
[tex]1 - r = 0.9229[/tex]
So
[tex]A(t) = A(0)(0.9229)^t[/tex]
Determine the half-life of this radioactive substance to the nearest tenth.
This is t for which A(t) = 0.5A(0). So
[tex]A(t) = A(0)(0.9229)^t[/tex]
[tex]0.5A(0) = A(0)(0.9229)^t[/tex]
[tex](0.9229)^t = 0.5[/tex]
[tex]\log{(0.9229)^t} = \log{0.5}[/tex]
[tex]t\log{0.9229} = \log{0.5}[/tex]
[tex]t = \frac{\log{0.5}}{\log{0.9229}}[/tex]
[tex]t = 8.6[/tex]
The half-life of this radioactive substance is of 8.6 months.
8. True or False. The correlation coefficient is a measure of the strength of an
association between two variables.
Please Answer Correctly - Will Give Branliest & Extra Points. (links or unidentified/wrong answers will be reported and auto banned)
Answer:
Step-by-step explanation:
11 no
46+4x=90 degree(being perpendicular)
4x=90-46
x=44/4
x=11
12 no
They are complementary angles
6 no
angle B+27=180 degree(being straight line)
angle B=180-27
angle B=153
10 no
angle 38 +angle DFE=180 degree(being supplementary)
angle DFE=180-38
angle DFE=142 degree
5 no
They are vertically opposite angles.
7 no
angle AGF and angle CGD (because they have common arm and vertex)
Answer:
Solution given:
11.4x+46=90[being right angle]
4x=90-46
x=44/4
x=11
12.
Complementary angles
5.
vertical
6.
<ABD+27=180°[linear pair]
<ABD=180-27
<ABD=153° degree
10.
<DFE+38=180[being supplementary]
<DFE=180-38
<DFE=142 degrees.
7.
angle DGE and angle DGC
8.
<AGB and <AGE
Convert 10π/6 radians into degrees.
We know that ,
[tex]\pi rad = 180^o[/tex]
SOLUTION :Using Unitary Method ,
[tex]\implies 1 \ rad = \dfrac{180^o}{\pi } [/tex]
Therefore ,
[tex]\implies \dfrac{10\pi}{6} rad = \dfrac{10\pi}{6} * \dfrac{180^o}{\pi } [/tex]
[tex]= \boxed{\red{ 300^o }}[/tex]
Required answer !
7 x [(26 - 5) - (5 + 6)]
Answer:70x
Step-by-step explanation: FIND BY OWN
30 ft.
6 ft.
4 ft.
20 ft.
?
25 ft.
PLEASE HELP QUICK
Answer:
5 ft
Step-by-step explanation:
30/6 = 5
20/4 = 5
25/x = 5
25/5 = 5
x = 5
Answer:
5 feet
Step-by-step explanation:
the triangles are scaled by the factor of 5
Help I need this answer ASAP
Answer: c
Step-by-step explanation: because yes
Answer:
d po answer
yan po sinagot ko
hehe
23
A university administered a survey to all incoming students regarding living arrangements for the upcoming school year. The results of the survey are displayed in the following two-way relative frequency table.
University Living Arrangements
On-Campus Off-Campus Total
Freshmen 0.44 0.28 0.72
Transfer Students 0.21 0.07 0.28
Total 0.65 0.35 1
What percentage of incoming freshmen plan to live on-campus?
A.
61.11%
B.
67.69%
C.
56%
D.
44%
The probability of incoming freshmen who plan to live on-campus in percentage will be 61.11%. Then the correct option is A.
What is probability?Its basic premise is that something will almost certainly happen. The percentage of favorable events to the total number of occurrences.
A university administered a survey to all incoming students regarding living arrangements for the upcoming school year.
The results of the survey are displayed in the following two-way relative frequency table.
On-Campus Off-Campus Total
Freshmen 0.44 0.28 0.72
Transfer Students 0.21 0.07 0.28
Total 0.65 0.35 1
Then the probability of incoming freshmen who plan to live on-campus in percentage will be
P = (0.44 / 0.72) x 100
P = 0.6111 x 100
P = 61.11%
The probability of incoming freshmen who plan to live on-campus in percentage will be 61.11%.
Then the correct option is A.
More about the probability link is given below.
https://brainly.com/question/795909
#SPJ5
Solve 7/w+4 =5/w+4-6/w
Answer:
w=-1+[tex]\sqrt{2}[/tex], w=-1-[tex]\sqrt{2}[/tex]
Step-by-step explanation:
Find (−5x−9)−(−6x−1)
Select the correct answer. Which of the following is equal to the expression below? (8 - 320) 3 OA. 40 O B. 30 OC. 10 5 OD. 835
Answer:
Quesiton is not clear. here is the asnswer basing on our understand
Step-by-step explanation:
(8-32)3 = (-24*3) = =72
A baby whale gains about 250 pounds a day. It was 250 pounds at birth. Find an equation to find the number of days it will take for a baby to weigh its first ton.
Answer:
8 days
Step-by-step explanation:
1 ton=2,000 pounds and If you divide 2,000÷250=8 days. It will talk 8 days for the baby whale to weigh his first ton.
Tickets for the school play cost $5 for students and $8 for adults. For one performance, 128 tickets were sold for $751. How many tickets were for adults and how many were for students?
How can you rewrite -8 − 10 as an addition problem?
A
-8 + (-10)
B
-8 + 10
C
-8 + 18
D
-8 + (-18)
Answer:
A
Step-by-step explanation:
-8 + (-10) = -8 -10
POSSIBLE POINTS 50
Mr Franklin needs to pay for his three kids to go to college. He figured out that college will cost an average of
$50,000 per year per child when they are ready to go to college. To pay for this, Mr. Franklin bought a cylindrical
gas truck, The truck is 40 feet long and the radius of the base is 60 inches, Gas has a density of five pounds per
cubic foot. Mr. Franklin makes $2.50 per pound of gas when he sends a delivery. How many trips of full tanks of
gas will Mr. Franklin have to send to pay for his three kids to go to four years of college each?
Be sure to label each step and show all work. Don't forget units.
a) Find the volume of the cylinder
b) Find the mass of the gas in one truckload by using the density formula
c) Find the amount of money one truckload will generate.
d) Find the amount of money four years of college will cost for Mr. Franklin's three children.
e) Find the amount of trips it will take Mr. Franklin to make enough money to pay for college,
5
x Clear
Und
Answer:
2500
Step-by-step explanation:
Find the length of side y.
y=_ft
Answer:
y = 5.66388 feet, (round that to whatever you need to round to)
Step-by-step explanation:
cos (51) = y/9
cos(51)*9=
y = 5.66388 feet
If the integral of the product of x squared and e raised to the negative 4 times x power, dx equals the product of negative 1 over 64 times e raised to the negative 4 times x power and the quantity A times x squared plus B times x plus E, plus C , then the value of A B E is
Answer:
[tex]A + B + E = 32[/tex]
Step-by-step explanation:
Given
[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{1}{64}e^{-4x}[Ax^2 + Bx + E]C[/tex]
Required
Find [tex]A +B + E[/tex]
We have:
[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{1}{64}e^{-4x}[Ax^2 + Bx + E]C[/tex]
Using integration by parts
[tex]\int {u} \, dv = uv - \int vdu[/tex]
Where
[tex]u = x^2[/tex] and [tex]dv = e^{-4x}dx[/tex]
Solve for du (differentiate u)
[tex]du = 2x\ dx[/tex]
Solve for v (integrate dv)
[tex]v = -\frac{1}{4}e^{-4x}[/tex]
So, we have:
[tex]\int {u} \, dv = uv - \int vdu[/tex]
[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = x^2 *-\frac{1}{4}e^{-4x} - \int -\frac{1}{4}e^{-4x} 2xdx[/tex]
[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{x^2}{4}e^{-4x} - \int -\frac{1}{2}e^{-4x} xdx[/tex]
[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{x^2}{4}e^{-4x} +\frac{1}{2} \int xe^{-4x} dx[/tex]
-----------------------------------------------------------------------
Solving
[tex]\int xe^{-4x} dx[/tex]
Integration by parts
[tex]u = x[/tex] ---- [tex]du = dx[/tex]
[tex]dv = e^{-4x}dx[/tex] ---------- [tex]v = -\frac{1}{4}e^{-4x}[/tex]
So:
[tex]\int xe^{-4x} dx = -\frac{x}{4}e^{-4x} - \int -\frac{1}{4}e^{-4x}\ dx[/tex]
[tex]\int xe^{-4x} dx = -\frac{x}{4}e^{-4x} + \int e^{-4x}\ dx[/tex]
[tex]\int xe^{-4x} dx = -\frac{x}{4}e^{-4x} -\frac{1}{4}e^{-4x}[/tex]
So, we have:
[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{x^2}{4}e^{-4x} +\frac{1}{2} \int xe^{-4x} dx[/tex]
[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{x^2}{4}e^{-4x} +\frac{1}{2} [ -\frac{x}{4}e^{-4x} -\frac{1}{4}e^{-4x}][/tex]
Open bracket
[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{x^2}{4}e^{-4x} -\frac{x}{8}e^{-4x} -\frac{1}{8}e^{-4x}[/tex]
Factor out [tex]e^{-4x}[/tex]
[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = [-\frac{x^2}{4} -\frac{x}{8} -\frac{1}{8}]e^{-4x}[/tex]
Rewrite as:
[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = [-\frac{1}{4}x^2 -\frac{1}{8}x -\frac{1}{8}]e^{-4x}[/tex]
Recall that:
[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{1}{64}e^{-4x}[Ax^2 + Bx + E]C[/tex]
[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = [-\frac{1}{64}Ax^2 -\frac{1}{64} Bx -\frac{1}{64} E]Ce^{-4x}[/tex]
By comparison:
[tex]-\frac{1}{4}x^2 = -\frac{1}{64}Ax^2[/tex]
[tex]-\frac{1}{8}x = -\frac{1}{64}Bx[/tex]
[tex]-\frac{1}{8} = -\frac{1}{64}E[/tex]
Solve A, B and C
[tex]-\frac{1}{4}x^2 = -\frac{1}{64}Ax^2[/tex]
Divide by [tex]-x^2[/tex]
[tex]\frac{1}{4} = \frac{1}{64}A[/tex]
Multiply by 64
[tex]64 * \frac{1}{4} = A[/tex]
[tex]A =16[/tex]
[tex]-\frac{1}{8}x = -\frac{1}{64}Bx[/tex]
Divide by [tex]-x[/tex]
[tex]\frac{1}{8} = \frac{1}{64}B[/tex]
Multiply by 64
[tex]64 * \frac{1}{8} = \frac{1}{64}B*64[/tex]
[tex]B = 8[/tex]
[tex]-\frac{1}{8} = -\frac{1}{64}E[/tex]
Multiply by -64
[tex]-64 * -\frac{1}{8} = -\frac{1}{64}E * -64[/tex]
[tex]E = 8[/tex]
So:
[tex]A + B + E = 16 +8+8[/tex]
[tex]A + B + E = 32[/tex]
Which numbers are irrational? Select all that apply.
Answer:
I believe Option 1, 2 and 4 are all irrational numbers Hope this helps
Step-by-step explanation:
Mrs. Smith decides to buy three sweaters and a pair of Jeans. She has $129 in her wallet.
If the price of the Jeans Is $40.05, what is the highest possible price of a sweater, each sweater is the
same price?
Variable:
Equation:
Solution:
Answer:
Step-by-step explanation:Herely/3fcEdSx's li[tex]^{}[/tex]nk to the answer:
bit.[tex]^{}[/tex]
Only please help #2,3,5, and 6
Answer:
3.$0.9
5.9:3 =3:1
Step-by-step explanation:
3.$5.40÷6=$0.9
B Reading Choose the best estimate for the multiplication problem below. 85 x 86
A. 8100
B. 10,400
C. 12,200
Answer:
A. 8100
Step-by-step explanation:
85 x 86
To estimate, we multiply 85*100, which is the easiest multiplication, as a multiplication by 100 is the same as placing two zeros at the end of the number.
85*100 = 8500
Since 86 < 100, 85*86 < 8500. Thus, the correct estimate is given by option A.
The measure of an angle is 89. Find the measure of its supplementent
a. 91
b. 89
c.90
d. 80
Answer:
A) 91
Step-by-step explanation:
Supplementary angels are 2 angels whos sum is 180
To find the supplement of angle 89, substract 89 from 180
180-89 = x
91 = x
Suppose you are investigating the relationship between two variables, traffic flow and expected lead content, where traffic flow is a predictor of lead content. You find the 95% CI for expected lead content when traffic flow is 15, based on a sample of n= 10 observations, is (461.7, 598.1).
Required:
What parameter is this interval estimating?
Answer:
The answers is " Option B".
Step-by-step explanation:
[tex]CI=\hat{Y}\pm t_{Critical}\times S_{e}[/tex]
Where,
[tex]\hat{Y}=[/tex] predicted value of lead content when traffic flow is 15.
[tex]\to df=n-1=8-1=7[/tex]
[tex]95\% \ CI\ is\ (463.5, 596.3) \\\\\hat{Y}=\frac{(463.5+596.3)}{2}\\\\[/tex]
[tex]=\frac{1059.8}{2}\\\\=529.9[/tex]
Calculating thet-critical value[tex]t_{ \{\frac{\alpha}{2},\ df \}}=-2.365[/tex]
The lower predicted value [tex]=529.9-2.365(Se)[/tex]
[tex]463.5=529.9-2.365(Se)\\\\529.9-463.5=2.365(Se)\\\\66.4=2.365(Se)\\\\Se=\frac{66.4}{2.365} \\\\Se=28.076[/tex]
When [tex]99\%[/tex] of CI use as the expected lead content: [tex]\to 529.9\pm t_{0.005,7}\times 28.076 \\\\=(529.9 \pm 3.499 \times 28.076)\\\\=(529.9 \pm 98.238)\\\\=(529.9-98.238, 529.9+98.238)\\\\=(431.662, 628.138)\\\\=(431.6, 628.1)[/tex]