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The number of cups of frozen strawberries that are needed to make 3 gallons of punch is equal to 48 cups.

In this exercise, you're required to determine the number of cups of frozen strawberries that are needed to make 3 gallons of punch. Thus, we would apply direct proportion.

Note: There are 16 cups of frozen strawberries in a gallon.

By direct proportion:

16 cups = 1 gallon

X cups = 3 gallons

Cross-multiplying, we have:

X = 16 × 3

X = 48 cups of frozen strawberries.

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x= -1/2 is the answer to your question. Mark as brainliest!!!!

Answer:

MK bisects <LKN

Step-by-step explanation:

We can already say two sets of sides are equal; LK = NK because it is given and MK = MK because of reflexive property. In order to use Side-Angle-Side, we need to prove the angles between the sides are congruent. This means <LKM and <NKM. The only option that would help is with the is the lat option, MK bisects <LKN because, then we could say <LKM and NKM are congruent because MK would be an angle bisector. This is exactly what we want, so the answer is MK bisects <LKN.

Answer:

a) x* e∧ t/10  =  20 *e∧ t/10 + 2

b) x  =  14,2 gall. In 10 min. we get 14,2 gallons of bleach in the tank

c) After a very long time we will find 20 gallons of bleach in the tank

Step-by-step explanation:

The variation of bleach in water in the tank is Δ(x)t:

Δ(x)t  = [Amount of x added to the tank - Amount of x drain out of the tank]*Δt

Now the amount of x added to the tank is:

Rate of adding* the concentration

Rate of adding =  4 gallons per minute

Concentration  half and half ( water + bleach)  = 0,5

Rate of draining =  4 gallons per minute

Concentration of draining: Unknown but can be expressed as:

x(t)/40. According to this

Δ(x)t  =  [4 * 0,5  -  4 * x(t)/40]*Δt

Dividing by Δt on both sides of the equation and tacking limits we get

dx/ dt    =  2  - x / 10

dx/dt + x/10 =2

Multyiplying by e∧ t/10 on both sides

e∧ t/10* [ dx/dt  +  x/10 ]  =  2 *e∧ t/10

To solve it, integrating the first member is

x* e∧ t/10  =  20 *e∧ t/10 + C

for initial condition t = 0

4    =  20 + C

C = -16

a) x* e∧ t/10  =  20 *e∧ t/10 - 16

b) in 10 minutes

x* e∧ t/10  =  20 *e∧ t/10 - 16

x *e  =  20*e  - 16

x   =   20  -  16/e

x   =  20  -  16/2,718

x   =   20 -  5,88

x  =  14,2  gallons.

c) After a very long time we will find 20 gallons of bleach in the tank

Given:

In ΔOPQ, m∠Q=90°, m∠O=26°, and QO = 4.9 feet.

To find:

The measure of side PQ.

Solution:

In ΔOPQ,

[tex]m\angle O+m\angle P+m\angle Q=180^\circ[/tex]        [Angle sum property]

[tex]26^\circ+m\angle P+90^\circ=180^\circ[/tex]

[tex]m\angle P+116^\circ=180^\circ[/tex]

[tex]m\angle P=180^\circ -116^\circ[/tex]

[tex]m\angle P=64^\circ[/tex]

According to Law of Sines, we get

[tex]\dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}[/tex]

Using the Law of Sines, we get

[tex]\dfrac{p}{\sin P}=\dfrac{o}{\sin O}[/tex]

[tex]\dfrac{QO}{\sin P}=\dfrac{PQ}{\sin O}[/tex]

Substituting the given values, we get

[tex]\dfrac{4.9}{\sin (64^\circ)}=\dfrac{PQ}{\sin (26^\circ)}[/tex]

[tex]\dfrac{4.9}{0.89879}=\dfrac{PQ}{0.43837}[/tex]

[tex]\dfrac{4.9}{0.89879}\times 0.43837=PQ[/tex]

[tex]2.38989=PQ[/tex]

Approximate the value to the nearest tenth of a foot.

[tex]PQ\approx 2.4[/tex]

Therefore, the length of PQ is 2.4 ft.

Answer: b

Step-by-step explanation:

I don't know but i am right

Answer:30 boys

Step-by-step explanation: There are 120 students, three-fourths are girls. Nine out of twelve is equal to three fourths, if you add a zero to the end of twelve and nine you get 90 out of 120, which is how many girls there are. If you subtract 90 from 120 you get 30 or one-fourth. The number of boys is equal to one-fourth because there is only one-foutlrth left. So, there are 30 boys.

Answer:

[tex]Area = 24\ in^2[/tex]

Step-by-step explanation:

Given

Let

[tex]a, b \to[/tex] opposite sides of each trapezoid

[tex]h \to[/tex] height

[tex]a = 2; \ \ \ b = 4 \ \ \ \ h = 2[/tex]

See attachment for trapezoids

Required

The combined area of the 4

First, we calculate the area of 1

[tex]Area = \frac{1}{2}(a + b) * h[/tex]

So:

[tex]A_1 = \frac{1}{2}(2 + 4) * 2[/tex]

[tex]A_1 = \frac{1}{2}*6 * 2[/tex]

Using a calculator

[tex]A_1 = 6[/tex]

The combined area is:

[tex]Area =n * A_1[/tex]

Where

[tex]n = 4[/tex] --- 4 blades

So:

[tex]Area = 4 * 6[/tex]

[tex]Area = 24\ in^2[/tex]

Answer: 3¼ hours

Step-by-step explanation:

Number of hours used in baking = 2¾ hours

Number of hours used in cleaning up the kitchen = ½ hour

Therefore, the time used in the kitchen will be the addition of the time used in baking plus the time used in cleaning the kitchen which will be:

= 2¾ + ½

= 2 3/4 + 2/4

= 2 5/4

= 2 + 1¼

= 3¼ hours

Therefore, 3¼ hours was used in the kitchen.

Answer:

First point: -4 on y axis.

Second point: (2, -5)

Step-by-step explanation:

When graphing, we always set the equation as y=mx+b where m = slope and b = y intercept

y = mx + b

y = [tex]-\frac{1}{2}x-4[/tex]  

Then we plot by starting with the y intercept going four units down, one unit below and two units to the right.

Answer:

x=28

y=28

Step-by-step explanation:

Equation 1:

Dived both sides by 0.75 to remove 3/4 from x.

(x-12)=16

Now, add 12 to both sides.

x=28

Equation 2:

Same here, divide both sides by 0.75.

y-12=16

Add 12 to both sides.

y=28

Answer:

here,radius =2 in

now use formula pie (r)^2 where pie is 3.14

=pie *(r)^2

=3.14*(2in.)^2

=3.14*4in.^2

12.56in.^2

Step-by-step explanation:

Answer:

good luck always brings luck the answer is 12

Step-by-step explanation:

Answer:

Area of the figure = 25 square units

Step-by-step explanation:

Area of the given figure = Area of ΔCDE + Area of rectangle BCEI + Area of ΔABH + Area of GIF

Area of ΔCDE = [tex]\frac{1}{2}(\text{Base})(\text{Height})[/tex]

                       = [tex]\frac{1}{2}(CE)(DK)[/tex]

                       = [tex]\frac{1}{2}(8)(4)[/tex]

                       = 16 units²

Area of rectangle BCEI = Length × Width

                                      = CE × EI

                                      = 8 × 1

                                      = 8 units²

Area of ΔABH = Area of ΔGIF = [tex]\frac{1}{2}(1)(1)[/tex]

                                                 = [tex]\frac{1}{2}[/tex] units²

Area of the complete figure = 16 + 8 + [tex]\frac{1}{2}[/tex] + [tex]\frac{1}{2}[/tex]

                                               = 25 units²

Answer:

a. true

b. false

c. false

d. true

e. false

Step-by-step explanation:

A. true, a shape is not warped by a rotation

b. false, the points on the figure will change

c. false, the size is not affected by a rotation

d. true, the orientation changes in a rotation

e. false, the coordinate points on the figure are altered

Answer:

A- The shapes of the figure does not change.

C- The size of the figure does not change.

D- The orientation of the figure does not change

Answer:

[tex]x = 7[/tex]

[tex]y =16[/tex]

Step-by-step explanation:

Given

The attached image

Required

Find x and y

From the sign on each line, we have:

[tex]y - 4 = x + 5[/tex]

[tex]2x + 5 = x + 12[/tex]

Collect like terms

[tex]2x-x=12 - 5[/tex]

[tex]x = 7[/tex]

We have: [tex]y - 4 = x + 5[/tex]

Substitute [tex]x = 7[/tex]

[tex]y - 4 = 7+5[/tex]

[tex]y - 4 = 12[/tex]

So:

[tex]y = 12+4[/tex]

[tex]y =16[/tex]

Answer:

3

Step-by-step explanation:

Answer:

301

Step-by-step explanation:

3 + 0 + 1 = 4

301 / 7 = 43

301 / 2 = 105.5

Answer:

301

Step-by-step explanation:

301 divided by 7 = 43

301 is not divisible by 2

3 + 1 + 0 = 4

Hope this helps :)

Answer:

the correct answer is 1ft

Step-by-step explanation:

4ft-3ft

=1ft

Answer:

the other angle equal 52

we can use the specail trangle 3 4 5

300 400 500

the 38 degrees angle meet 300

and the 52 degrees angle meet 400

so the answer is 300 i dont know if you understand but i hope you are

pls ask in the comments and i will try to explain because my ebgilish the baddest

Answer:

t = 4 seconds

Step-by-step explanation:

The height of a soccer ball as a function of time is given by :

[tex]h(t)=-16t^2+48t+64[/tex]

We need to find the time when the ball hit the ground i.e. h = 0

Put h = 0 in above equation. So,

[tex]-16t^2+48t+64=0\\\\16(-t^2+3t+4)=0\\\\-t^2+3t+4=0[/tex]

It is a quadratic equation such that,

t = -1 s and t = 4 s

Neglecting -1 s, the ball will hit the ground after 4 seconds.

Answer:

[tex]I =\frac{P*R*T}{100} = \frac{10000 * 11 * T}{100} = 1100T[/tex]

Given A =20000

[tex]Amount = Interest + Principal\\20000 = 1100T + 10000\\20000 - 10000 = 1100T\\\\T= \frac{10000}{1100} = \frac{100}{11} = 9.09 years[/tex]

T =9years

Answer:m

Step-by-step explanation:

Answer:

-15

Step-by-step explanation:

When m=3 and n=-4

So, put the values

7(3)+3(3)(-4)

-> -15

Answer:

-15

Step-by-step explanation:

= 7(3) + 3(3)(-4)

= 21 + 3(3×-4)

= 21 + 3(-12)

= 21 + -36

= 21-36

= -15

I'm still doing the rest but number 1 is D

Answer:

The answer Is 1/3(b-21)

Step-by-step explanation:

Answer:

(3,6)

Step-by-step explanation:

Using the midpoint segment formula

M(X, Y) = [(ax1+bx2/2, ay1+by2/2)]

Given (-2 -6) and (4,6) divided in the ratio 1:5

X = 1(-2) + 5(4)/1+5

X = -2+20/6

X = 18/6

X = 3

Similarly

Y = 1(-6)+ 5(6)/1+5

Y = -6+30/6

Y = 24/6

Y = 4

Hence the required coordinate of C is (3,6)