QUESTION 1
(Show your work)
mi
R
Two children, of masses m1 = m2 = 20 kg,
ride on the perimeter of a small merry-
go-round. The merry-go-round is a disk
of mass M = 30 kg
and radius R = 3 m, as shown in the figure
below.
The moment of inertia of the system
(merry-go-round, child 1, child 2) about
the center of the merry-go-round is
equal to:
M M
m2
which lever is human arm
Answer:
The human arm is a class 3 lever
Explanation:
Answer:
A bent arm is a Class 3 lever. The pivot is at the elbow and the forearm acts as the lever arm. The biceps muscle provides the effort (force) and bends the forearm against the weight of the forearm and any weight that the hand might be holding.
Explanation:
Define heat according to molecular theory .
I think ....... the answer will be ......
like a theory
Select the correct answer from each drop-down menu.
Photosynthesis is a process in which plants prepare food using carbon dioxide, chlorophyll, and water in the presence of sunlight.
During photosynthesis,(blank)
energy is transformed into(blank)
1.Chemical,electrical,kinetic, Solar ?
2.Chemical, Electrical, Kinetic, Solar
Answer:
During photosynthesis solar energy is converted into chemical energy
Explanation:
During photosynthesis solar energy is converted into chemical energy in the form of energy rich bond of ATP molecule.
ATP (Adenosine triphosphate) and ADP (Adenosine diphosphate) molecules are termed currency of energy. ADP molecule is converted into ATP molecules, whenever energy is available in certain exothermic reactions of metabolism.
ATP molecules are store- house of energy. ATP molecule is broken down into ADP molecule in presence of enzyme ATPase, releasing energy whenever energy is required.
The synthesis of ATP molecules, utilizing solar energy during photosynthesis, is termed photo-phosphorylation.
These ATP molecules produced during light reaction of photosynthesis are utilized in dark reaction of photosynthesis (Calvin cycle).
ATP molecules synthesized during photo-phosphorylation may also be used in other metabolic reactions.
Photo-phosphorylation is of 2 types, i.e. Cyclic and Non-cyclic photo-phosphorylation.
Chlorophyll molecules entrap solar energy . There are 2 types of photo-systems in chlorophyll. These are photo-system -I and photo-system-II .
The electrons of chlorophyll molecule of photo-system I get excited which pass through series of electron carriers in electron transport system arranged in the order of decreasing energy level.
During the passage of electrons from carriers of higher energy level to the carriers of lower energy level, the energy is lost which is utilized for converting ADP molecule into ATP molecule.
Photo-system I is concerned with light reaction of photosynthesis only, constituting cyclic photo-phosphorylation.
The electron transport during Photo-system II results in the synthesis of NADPH2 in presence of enzyme NADP reductase. NADPH2 is used in reduction reaction of Calvin cycle.
Both Photo-systems participate in non-cyclic photo-phosphorylation that results in the synthesis of NADPH2 in addition to the synthesis of ATP molecules.
An ant walks 15 m east, then 40 m north, and finally 20 m west. What is the total displacement from the starting point
Answer: 40.311 m
Explanation:
Given
Ant walks 15 m east
then 40 m North and finally 20 m west
from the figure, ant is 40 m North and 5 m west
Using Pythagoras, we can write
[tex]\Rightarrow d=\sqrt{40^2+5^2}\\\Rightarrow d=\sqrt{1625}=40.311\ m[/tex]
3 ways objects can be grouped are
Answer:
Transparent = lets light pass through without significant interference
Translucent = lets light pass through with significant interference
Opaque = Doesn't let light pass, instead absorbs it
1. A student lifts a box of books that weighs 200 N. The box is lifted 2.5 m. How much work
does the student do on the box?
Answer:
The student does a work of 500 Newton meter on the box.
Explanation:
Plzzz help!! A stationary speed gun emits a
microwave beam at 2.10x1010 Hz. It
reflects off a car and returns 1030 Hz
higher. What is the speed of the car?
(Unit = m/s)
Answer:
The speed of the car is 14.7m/second or 15 m/second approximately.
Explanation:
A microwave beam at [tex]2.10\times10^1^0Hz[/tex] is generated by a stationary speed gun. It bounces off a car and returns at a higher frequency of 1030 Hz. The car's observed frequency would be the product of adding the two frequencies. That is to say,
F =[tex]2.1\times10^1^0+1030[/tex] =[tex]2.100000103\times10^1^0Hz[/tex]
Using doppler effect formula
[tex]F=\frac{C}{C-V}\times f[/tex]
Where
F = observed frequency
f = source frequency
C = speed of light = [tex]3\times10^8[/tex]
V = speed of the car
Putting the values in the formula -
[tex]2.100000103\times10^1^0=\frac{3\times10^8}{3\times10^8-V}\times2.1\times 10^1^0[/tex]
[tex]\frac{2.100000103\times10^1^0}{2.1\times10^1^0}[/tex] [tex]=\frac{3\times10^8}{3\times10^8-V}[/tex]
[tex]1.000000049=\frac{3\times10^8}{3\times10^8-V}[/tex]
by cross multiplication ,
300000014.7 - 1.000000049V = [tex]3\times10^8[/tex]
Collect the like terms
1.000000049V = 14.71429
Make V the subject of formula
V = [tex]\frac{14.71429}{1.000000049}[/tex]
V = 14.7 m/s
Therefore , the speed of the car is 15m/second approximately.
Pls helppp. Is this right?
Answer:
yes you are totally right
Compared to the amount of carbon atoms on the earth, the amount of radioactive carbon atoms is infinitesimal in this sentence, what is the best synonym for infinitesimal
Answer:
See the answer below
Explanation:
The literal meaning for infinitesimal is for something to be small.
Other meanings include, but not limited to minute, insignificant, tiny, microscopic, minuscule.
Thus, the statement can be reconstructed by saying:
Compared to the amount of carbon atoms on the earth, the amount of radioactive carbon atoms is small.
Which describes Einstein’s second postulate about the special theory of relativity? The speed of light in a vacuum is constant, and nothing is faster than the speed of light. The speed of light in a vacuum is constant, and some things are faster than the speed of light. The speed of light in a vacuum fluctuates, but nothing is faster than the speed of light. The speed of light in a vacuum fluctuates, and some things are faster than the speed of light.
Answer:A
Explanation:
Answer: A)The speed of light in a vacuum is constant, and nothing is faster than the speed of light.
Explanation:
Answered Correctly on Edg.
3. How does the wavelength of green different from violet-indigo?
Answer:
As the full spectrum of visible light travels through a prism, the wavelengths separate into the colors of the rainbow because each color is a different wavelength. Violet has the shortest wavelength, at around 380 nanometers, and red has the longest wavelength, at around 700 nanometers.
Explanation:
A potato is which part of the plant?
root
stem
leaf
flower
Use words to describe the relationship between the acceleration of an object and the net force acting on the object
A block of size 100cmX50cm applies a force of 100N on the ground. Calculate the pressure
exerted by the block on the ground.
(2 Points)
Answer:
200 N/m²
Explanation:
Pressure = Force / Area
Force =100N
Area = 100cm x 50 cm= 5000cm² =0.5m²
Hence Pressure = 100N / 0.5m²
Pressure = 200N/m²
At t = 3 seconds, what is the velocity of the object
Answer:
NO ANSWER
Explanation:
there is no tragectory or diagram given
WHICH OBJECT?
A centrifuge used in DNA extraction spins at a maximum rate of 7000rpm producing a "g-force" on the sample that is 6000 times the force of gravity. If the centrifuge takes 10 seconds to come to rest from the maximum spin rate: a) What is the angular acceleration of the centrifuge? b)what is the angular displacement of the centrifuge during this time
Answer:
A) a = 73.304 rad/s²
B) Δθ = 3665.2 rad
Explanation:
A) From Newton's first equation of motion, we can say that;
a = (ω - ω_o)/t. We are given that the centrifuge spins at a maximum rate of 7000rpm.
Let's convert to rad/s = 7000 × 2π/60 = 733.04 rad/s
Thus change in angular velocity = (ω - ω_o) = 733.04 - 0 = 733.04 rad/s
We are given; t = 10 s
Thus;
a = 733.04/10
a = 73.304 rad/s²
B) From Newton's third equation of motion, we can say that;
ω² = ω_o² + 2aΔθ
Where Δθ is angular displacement
Making Δθ the subject;
Δθ = (ω² - ω_o²)/2a
At this point, ω = 0 rad/s while ω_o = 733.04 rad/s
Thus;
Δθ = (0² - 733.04²)/(2 × 73.304)
Δθ = -537347.6416/146.608
Δθ = - 3665.2 rad
We will take the absolute value.
Thus, Δθ = 3665.2 rad
what is a benefit of fossil fuel consumption?
Answer:
increased greenhouse gases
Explanation:
I think this is the right answer...
Neptune and Uranus are called the "ice giants" due to the presence of ice on their surface. Which is a reasonable explanation for why there aren't any ice giants in the group of terrestrial planets? A. They have rocky surfaces. B. They do not have rings. C. They are too close to the sun.
Answer:
C. They are too close to the sun.
Explanation:
Due to their relative location the gas giant such as neptune and Uranus are mostly cold and icy planets as they are located deep into the solar system and have large distance firm the sun.As compared to those of the earth and other rocky planets. Due to their distance they consist of primitive atmosphere and have slow rotation and movement.Use the term chemical bond in a complete sentence
You ride your bike 5 miles east to school, then 2 miles east to Wawa, return to school, then ride 2 miles west to the library to work on your homework. What is your displacement?
Answer:
3 miles
Explanation:
5 + 2 - 2 - 2 = 3 miles
It's almost always difficult to select healthy foods at a fast-food restaurant. O True O False
Answer:
yesExplanation:
because its most likely to have chucks than heathy foodHow much power is needed to lift a 20-kg object to a height of 4.0 m in 2.5 seconds?
Answer:
313.92w
Explanation:
Formula for power:
P=W/∆t = Fv
Givens:
m=20kg
∆y=4.0m
∆t=2.5s
a=9.81m/s²
In order to find power, we first need to solve for work.
W=Fd (force*displacement), f=mg
W=mg∆y
W=(20kg)(9.81m/s²)(4.0m)
W=784.8J
P=W/∆t
P=784.8J/2.5s
P=313.92 watts
Una bola se lanza verticlamente de la parte superior de un edificio con una velocidad inicial 25 m/s la bola impacta al suelo en la base del edificio 7 segundos despues de ser lanzada ¿que altura subio la bola
Answer:
S = 415.1 meters
Explanation:
Dados los siguientes datos;
Velocidad inicial = 25 m/s
Tiempo, t = 7 segundos
Para encontrar la altura (desplazamiento) de la pelota, usaríamos la segunda ecuación de movimiento;
[tex] S = ut + \frac {1}{2}at^{2}[/tex]
Dónde;
S representa el desplazamiento o altura medida en metros.
u representa la velocidad inicial medida en metros por segundo.
t representa el tiempo medido en segundos.
a representa la aceleración medida en metros por segundo cuadrado.
Sustituyendo en la ecuación, tenemos;
[tex] S = 25*7 + \frac {1}{2}*(9.8)*7^{2}[/tex]
[tex] S = 175 + 4.9*49 [/tex]
[tex] S = 175 + 240.1 [/tex]
S = 415.1 meters
Define 1 pascal pressure
Answer:
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Explanation:
This is ur answer.....
A pascal is a pressure of one newton per square metre, or, in SI base units, one kilogram per metre per second squared. For example, standard atmospheric pressure (or 1 atm) is defined as 101.325 kPa. The millibar, a unit of air pressure often used in meteorology, is equal to 100 Pa.
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pascal is the SI unit of pressure symbolized by Pa
1 Pa=1N/m^2
1Pa=1kg/ms^2
An organism with the alleles Aa is called __________, while one with AA or aa is called __________.
A. heterozygous, hom/ zygous
B. heterozygous, homo/zygous
Answer:
Hetefrozygous, homofzygous
A 12 N [E] force is applied to a toy train with a mass of 2.7 kg. The toy train is attached by a light string to a wagon with a mass of 1.8 kg which is attached to a second wagon with a mass of 1.0 kg. If the train is pulled on a surface with a coefficient of kinetic friction of 0.05, determine the tension in the string between the first and the second wagon. (6T, 3C) Include free body diagrams for the three masses involved in the acceleration. (3 Comm.)
See the attached diagram for reference and free body diagrams. The acceleration a of each body will be the same since each connecting string is in tension.
By Newton's second law, we have
• net force on the train:
- - horizontal
[tex]\sum F = F - F_{k,T} - T_1 = m_Ta[/tex]
(where F = 12 N)
- - vertical
[tex]\sum F = N_T - m_Tg = 0[/tex]
• net force on wagon 1:
- - horizontal
[tex]\sum F = T_1 - T_2 - F_{k,1} = m_1a[/tex]
- - vertical
[tex]\sum F = N_1 - m_1g = 0[/tex]
• net force on wagon 2:
- - horizontal
[tex]\sum F = T_2 - F_{k,2} = m_2a[/tex]
- - vertical
[tex]\sum F = N_2 - m_2g = 0[/tex]
We want to determine T₂, the tension in the string connecting the two wagons.
For each body, the corresponding normal force has magnitude
N = mg
where m is the respective mass, and the kinetic friction has magnitude
Friction = 0.05 N = 0.05mg
So if µ = 0.05, then the frictional force on each body is
[tex]F_{k,T} = 0.05 (2.7\,\mathrm{ kg}) g = 1.323\,\mathrm N[/tex]
[tex]F_{k,1} = 0.05 (1.8\,\mathrm{ kg}) g = 0.882\,\mathrm N[/tex]
[tex]F_{k,2} = 0.05 (1.0\,\mathrm{ kg}) g = 0.49\,\mathrm N[/tex]
which leaves us with the system of equations,
[1] … 12 N - 1.323 N - T₁ = (2.7 kg) a
[2] … T₁ - T₂ - 0.882 N = (1.8 kg) a
[3] … T₂ - 0.49 N = (1.0 kg) a
Adding [1] and [2] eliminates T₁ :
(12 N - 1.323 N - T₁) + (T₁ - T₂ - 0.882 N) = (2.7 kg) a + (1.8 kg) a
[4] … 9.795 N - T₂ = (4.5 kg) a
Divide through both sides of [3] by 1.0 kg to solve for a :
a = (T₂ - 0.49 N) / (1.0 kg)
Substitute this into [4] and solve for T₂ :
9.795 N - T₂ = (4.5 kg) (T₂ - 0.49 N) / (1.0 kg)
(9.795 N - T₂) (1.0 kg) = (4.5 kg) (T₂ - 0.49 N)
9.795 N - T₂ = 4.5 T₂ - 2.205 N
12 N = 5.5 T₂
T₂ = (12 N) / 5.5 ≈ 2.1818 N ≈ 2.2 N
two children of masses m1 = m2 = 20 kg , ride on the perimeter of a small merry-go- round . the merry -go-round us a disk of mass M = 30 kg answer
Answer:
c
Explanation:
When the C4 key on a piano keyboard is pressed, a string inside the piano is struck by a hammer and begins vibrating back and forth at approximately 260 cycles per second.
a. What is the frequency in Hertz of the sound wave?
b. What is the wavelength of the wave?
Answer:
Frequency = 260 Hz and wavelength = 1.31 m
Explanation:
Given that,
A hammer begins vibrating back and forth at approximately 260 cycles per second.
(a) The frequency of an object is the number of vibrations per unit time. The frequency of the sound wave is 260 Hz.
(b) The speed of sound in air is 343 m/s. So,
[tex]v=f\lambda\\\\\lambda=\dfrac{v}{f}\\\\\lambda=\dfrac{343}{260}\\\\\lambda=1.31\ m[/tex]
Hence, this is the required solution.
5. What is the velocity of a 0.5 kg ball that has a momentum of 3.00 kg m/s?
Answer:
6 m/s
Explanation:
p=mv
p=3 kg.m/s
m=0.5 kg
rearrange and substitute to find v:
(3)=(0.5)v
v=3/0.5
v=6 m/s