Answer is C

Zeke is attempting to react a piece of magnesium metal with sulfuric acid. The sulfuric acid is a 5M solution. What could Zeke do
to slow down the rate at which the magnesium will react with the acid?
A)
increase the temperature
B)
add a 10M sulfuric acid solution
9)
add water to the acid to decrease its molarity
D)
add more of the 5M sulfuric acid to the reaction

Answers

Answer 1

Answer:

c)

Explanation:

add water to the acid to decrease its molarity


Related Questions

Can animals and plants adapt to climate changes?

Answers

Answer:

Yes but will take a very very long time for them to adapt most will die but as gemeration passes they will get used to it

What percentage of a substance remains after 7 half-lives have passed?
A. 0.39
B. 2.5
C. 1.25
D. 0.78

Answers

Answer:

Not really sure, buts its either B or C.

That big lorry hit the new car.change to passive voice​

Answers

I don’t understand the question? Maybe try rewording it?

A Chemist reacted magnesium and aluminum oxide. A reaction takes place. Explain why

Answers

Explanation:

when Magnesium is reacted with Aluminum oxide, Aluminum being a less reactive metal than magnesium, is replaced by magnesium

Al2O3 + 3Mg - 3MgO + 2Al

hence reaction takes place

Clouds are made up of tiny droplets of water. Which two spheres are clouds a
part of?
A. Biosphere
B. Geosphere
C. Hydrosphere
D. Atmosphere

Answers

C & D, clouds are apart of the Hydro and Atmosphere!

In a neutral solution, the concentration of H+ is
Group of answer choices

Answers

Answer:

equal to [OH-]

Hydrogen ion concentration is more conveniently expressed as pH, which is the logarithm of the reciprocal of the hydrogen ion concentration in gram moles per liter. Thus, in a neutral solution the hydrogen ion (H+) and the hydroxyl ion (OH−)

What would make oppositely charged objects attract each other more?
increasing the positive charge of the positively charged object and increasing the negative charge of the negatively
charged object
decreasing the positive charge of the positively charged object and decreasing the negative charge of the negatively
charged object
increasing the distance between the positively charged object and the negatively charged object
maintaining the distance between the positively charged object and the negatively charged object

Answers

Answer: increasing the positive charge of the positively charged object and increasing the negative charge of the negatively charged object.

Explanation:

edge

Answer:

Your answer is A.

Explanation:

Which is true for a substance that releases energy?
OA. The energy release decreases the molecular motion and the kinetic energy of the substance.
B. The energy release decreases the molecular motion but increases the kinetic energy of the substance.
C. The energy release increases the molecular motion and the kinetic energy of the substance.
D. The energy release increases the molecular motion but decreases the kinetic energy of the substance.
E. The energy release is used only to change the state of the substance.

Answers

I’m not sure but I think it’s the first one

Whilst Et₃CCl is unreactive towards water even at elevated temperatures, Et₃SiCl is hydrolyzed rapidly. Explain the origin of these differences and provide a reaction scheme with mechanistic details for the hydrolysis of Et₃SiCl.

Answers

Answer:

See Explanation

Explanation:

In discussing the reason why Et₃SiCl is more easily hydrolysed than Et₃CCl, we must remember that the electronegativity difference between silicon and chlorine is much higher than the electronegativity difference between carbon and chlorine.

As a result of this, the Si-Cl bond in Et₃SiCl is more polar and hence susceptible to attack by water than the C-Cl bond in Et₃CCl.

Also, it is postulated that the presence of vacant d orbitals on silicon assists hydrolysis in Et₃SiCl. Such vacant orbitals are absent in carbon hence Et₃CCl does not undergo hydrolysis.

The reaction scheme is shown in the image attached to this answer.

What is the number of moles in a sample of gas that has a volume of 3.5 L, a
pressure of 200 kPa, and a temperature of 300 K?

Answers

Explanation:

[tex]PV = nRT \\ (200000 \times 3.5 \times {10}^{ - 6} ) = n \times 8.314 \times 300 \\ n = \frac{0.07}{2494.2 } \\ n = 2.81 \times {10}^{ - 5} [/tex]

[tex] \small{ \star{ \underline{ \blue{ becker}}}}[/tex]

If two half lives have passed since a scientist collected a 1.00- gram sample of a U-235, how much U-235 is left now?

answers for most finals chem test questions (10th)

Answers

Answer:

one quarter of the original amount, so 0.25 g

Explanation:

Answer:

C

Explanation:

What volume of 15.9 M Nitric acid would be required to make 7.2 L of 6.00 M nitric acid? (hint: dilution problem) will mark brainliest if correct

a. 2.72 L
b. 686.88 L
c. .075 L
d. 272

Answers

Answer:

d

Explanation:

What two things combine with oxygen to form ground-level ozone?

A) NOx and ODS
B) CFCs and halons
C) NOx and VOC
D) HFCs and HCFCs

Answers

Answer:

c) NOx and VOC

oxides of nitrogen (NOx) and volatile organic compounds (VOC)

Explanation:

-

Calculate how many grams of sodium chloride we would need to make a solution with the same molarity of seawater, which is about 0.598 M.

Answers

Answer:

34.92 grams NaCl (in 1 L of solution)

Explanation:

The chemical formula of sodium chloride is NaCl. From the formula, we can calculate the molar mass of NaCl:

MM(NaCl)= MM(Na) + MM(Cl) = 23 g/mol + 35.4 g/mol = 58.4 g/mol

A solution of NaCl with a molarity of 0.598 M has 0.598 moles of NaCl per liter of solution. So, we multiply the moles by the molar mass of NaCl to calculate the mass we need:

mass of NaCl = 0.598 mol x 58.4 g/mol = 34.92 g NaCl

Therefore, we need 34.92 grams of NaCl to prepare 1 liter of a solution with a molarity of 0.598 M.

20 mL of hydrogen measured at 15° C is heated to 35°C.
What is the new volume at the same pressure?

Answers

V2 = 21.4 ml

Explanation:

Note: When dealing with gases, make sure that you change the units from °C to K.

T1 = 15°C + 273 = 288K

T2 = 35°C + 273 = 308K

V1 = 20 ml

V2 = ?

We use Charles's law to solve V2:

V1/T1 = V2/T2

or

V2 = (T2/T1)V1

= (308K/288K)(20 ml)

= 21.4 ml

Two reasons that a plant from a rain forest would not survive in a desert home?

Answers

Answer: A planet from a rain forest would not survive in a desert home, for the fact they depend on water and as these live from water, without it, this leads to dehydration and with loss of water with plants, nothing is able to survive when it comes to a rain forest plant being in a desert home. Another reason is the high trees and leaves that are providing the plants enough sunlight or shade to grow, it guarantees to help keep the temperature normal. Being in a deserted area would mean that there would be a temperature change, something the plant is not used to. Without that needed shade and avoiding the scorching sun, they will die out from how different the temperature is, and how hot it is.

Explanation: I hope this helped you.

okay, the answer should be simple and easy, plants from a rainforest would not survive in a desert because the plants in the rainforest do get water, sunlight and air whereas the plants in the desert have Sunlight which is very hot. so if a plant in the rainforest was transferred to the desert it will hard to survive and it will eventually die because they will not get water that will be needed and the plant can get sunburns with the too hot temperature.

The reaction between solid aluminum and liquid bromine is exothermic. This reaction creates
the product aluminum bromide.
What equation includes the correct formulas and demonstrates conservation of mass?
A Al(s) + Br2(1) - AlBr3(s)
B Al(s) + Br(l) - AlBr(s)
C Al(s) + 3Br(1) - AlBr3(s)
D
2Al(s) + 3Br2(1) - 2AlBr3(s)

Answers

Answer:

correct answer is d)

Explanation:

This answer demonstrates law of conservation of mass because the mass of the products is equal to the mass of reactants with the help of the coefficients which is the process known as balancing. This answer also includes the correct formulas, as Br is a gas so it MUST be written as Br2. hope this helps:)

2Al(s) + 3Br2(1) - 2AlBr3(s) is the  correct formulas and demonstrates conservation of mass.

What is Conservation of Mass?

Every action has an equal and opposite response, states Newton's Third Law. This indicates that any force applied to an item will have an equal and opposite-directed response force of the same magnitude. A force pair is the collective name for these connected forces.

Each individual object will have a different force pair with each other object in systems of numerous objects where all things interact. In the case of charged particles, the charge of each object will dictate the direction of each force in the force pair.

Similar charges will cause particles to repel one another by directing their forces away from one another. With their forces pointing in the same direction, particles with opposing charges attract one another.

Therefore, 2Al(s) + 3Br2(1) - 2AlBr3(s) is the  correct formulas and demonstrates conservation of mass.

To learn more about mass, refer to the link:

https://brainly.com/question/19694949

#SPJ2

how do I calculate the density

Answers

the equation would be p=m/v so...
A) 1.1 g/cm^3
B) .95 g/cm^3
C) 1 g/cm^3
i hope this helps!!!

Convert 22 grams of copper Il chloride (Cucl2) to moles.
with work please ​

Answers

hope this helps!

https://youtu.be/MT5tKijKZwQ
Just click on there link the person gave

Using the balanced equation for the next few questions: 4 Fe(s) + 30 (9) - 2Fe2O3(s)
How many moles of Iron (11) Oxide would be produced by complete reaction of 0.15
moles of iron? (Be sure to show your work including the mole ratio you used)

Answers

Answer:

0.075 moles of iron oxide would be produced by complete reaction of 0.15  moles of iron.

Explanation:

The balanced reaction is:

4 Fe + 3 O₂ → 2 Fe₂O₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Fe: 4 molesO₂: 3 molesFe₂O₃: 2 moles

You can apply the following rule of three: if by stoichiometry 4 moles of Fe produce 2 moles of Fe₂O₃, 0.15 moles of Fe produce how many moles of Fe₂O₃?

[tex]moles of Fe_{2} O_{3} =\frac{0.15 moles of Fe*2 moles of Fe_{2} O_{3} }{4 moles of Fe}[/tex]

moles of Fe₂O₃= 0.075

0.075 moles of iron oxide would be produced by complete reaction of 0.15  moles of iron.

What is catalyst? Write its types.​

Answers

Answer:

A catalyst is a chemical substance that alters the rate of chemical reaction not consumed by the reaction. Hence, a catalyst can be recovered chen unchanged at the ends of chemical reaction. Catalyst can be divided into two typ the basis whether it speeds up or slowdowns the rate of chemical reaction. The positive catalyst and negative catalyst.

Answer:

A catalyst is a chemical substance thatalters therate of chemical reactions not consumed by the reactions.

18. How many grams are in 563 mL of chlorine gas at STP?

Answers

Answer:

[tex]at \: stp : \\ 22400 \: ml \: are \: occupied \: by \: 71 \: g \: of \: chlorine \\ 563 \: ml \: will \: be \: occupied \: by \: ( \frac{563}{22400} \times 71) \:g \\ = 1.78 \: g[/tex]

Select the correct mass for each of the samples described below.

3.01 × 1023 molecules H2O

Answers

Answer:

9.00 g H2O

Explanation:

Convert molecules to grams using stoichiometry

(3.01 * 10^23 molecules) * (1 mole H2O / 6.022 * 10^23 molecules) * (18.01 g / 1 mole H2O) = 9.00 g H2O

Answer:

answer  in picture

Explanation:

Please help this will determine my grade so I beg help me out and my grade

Answers

Answer:

C: checking your email

Explanation:

I believe that C would be impossible, as you cannot use wireless networks without radio waves

The answer is C (checking emails your email on laptop computer using coffee shop WiFi
Step by step explanation:
Radio waves are used for communications radio waves are a type of electromagnetic radiation best known for their use in communication technologies
So you can’t communicate or use WiFi’s without radio waves.
Have a nice day.
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