Answer:
1. Mechanical energy = 298.4 Joules.
2. Mechanical energy = 2140 Joules.
3. Mechanical energy = 0.2838 Joules.
Explanation:
Kinetic energy can be defined as an energy possessed by an object or body due to its motion.
Mathematically, kinetic energy is given by the formula;
[tex] K.E = \frac{1}{2}MV^{2}[/tex]
Where;
K.E represents kinetic energy measured in Joules.
M represents mass measured in kilograms.
V represents velocity measured in metres per seconds square.
Potential energy can be defined as an energy possessed by an object or body due to its position.
Mathematically, potential energy is given by the formula;
[tex] P.E = mgh[/tex]
Where,
P.E represents potential energy measured in Joules.
m represents the mass of an object.
g represents acceleration due to gravity measured in meters per seconds square.
h represents the height measured in meters.
Given the following data;
1. Kinetic energy = 182.2 J
Potential energy = 116.2 J
To find the mechanical energy;
Mechanical energy = kinetic energy + potential energy
Mechanical energy = 182.2 + 116.2
Mechanical energy = 298.4 Joules.
2. Mass = 40kg
Velocity = 3m/s
Height = 5m
We know that acceleration due to gravity is equal to 9.8m/s²
To find the mechanical energy;
We would determine the kinetic and potential energy respectively.
K.E = ½mv²
K.E = ½*40*3²
K.E = 20*9
K.E = 180 Joules.
P.E = mgh
P.E = 40*9.8*5
P.E = = 1960 Joules
Mechanical energy = K.E + P.E
Mechanical energy = 180 + 1960
Mechanical energy = 2140 Joules.
3. Mass = 0.002kg
Height = 3m
Velocity = 15m/s
To find the mechanical energy;
K.E = ½mv²
K.E = ½*0.002*15²
K.E = 0.001*225
K.E = 0.225 Joules.
P.E = mgh
P.E = 0.002*9.8*3
P.E = = 0.0588 Joules
Mechanical energy = K.E + P.E
Mechanical energy = 0.225 + 0.0588
Mechanical energy = 0.2838 Joules.
How many joules of heat energy are needed to raise the temperature of 10.0 g (0.0100 kg) of aluminum from 22 K to 55 K, if the specific heat of aluminum is 897 J/kg * K. Explain your answer
Answer:
296.01 J
Explanation:
From the question,
Q = cm(t₂-t₁)....................... Equation 1
Where Q = quantity of heat, c = specific heat capacity of aluminium, m = mass of aluminium, t₁ = Initial temperature, t₂ = Final temperature
Given: c = 897 J/kg.K, m = 0.01 kg, t₁ = 22 K, t₂ = 55 k
Substitute these values into equation 1
Q = 897×0.01×(55-22)
Q = 897×0.01×33
Q = 296.01 J
Hence 296.01 Joules of heat is required.
Convection currents will transfer heat throughout a gas until what condition arises?
A.
The gas condenses and forms a liquid.
B.
The gas particles stop moving entirely.
C.
The gas has the same temperature throughout.
D.
The gas has no thermal energy in it.
Answer:
C
Explanation:
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The gas has the same temperature throughout. (C)
How does a physicist define work? a force applied for a certain length of time a force applied over a distance power applied for a certain length of time power applied to something over a distance
Answer:
Work, in physics, measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement. ... To express this concept mathematically, the work W is equal to the force f times the distance d, or W = fd.
Explanation:
Definition of work in physics
A measure of energy expended in moving an object; most commonly, force times distance is work.When humans pollute lakes, rivers, and streams,
Answer:
when waterways are polluted it affects all forms of life in the area - including us
expression:
for example when Lakes streams and ponds are polluted it can kill or harsh fish and other Wildlife that lives there!
hope that helps !
PLZZZZZZZZZ HELPPPPP. BRAINLEST GIVEN What is a force of attraction between an object and the earth due to gravity?
Answer:
acceleration due to gravity: -9.8 m/s^2
Fg=mass of object*(-9.8)
Explanation:
This is a pretty vague question, but I'll answer as best I can.
All matter has gravity. YOU have gravity, although your gravitational pull is small. So, the force of attraction between the Earth and an object on Earth is modeled as
Force of gravity=(Gravitational constant*mass of object 1*mass of object 2)/distance between objects squared
Note that distance between an object on Earth and Earth is the radius of Earth (distance to Earth's core/center of mass)
PLEASE HELP—ITS PHYSICS AND I NEED ANSWERS ASAP
What happens to the force between two charges when each charge is doubled and the distance between them is 1/4 its original
magnitude?
Answer:
F' = 64 F
Explanation:
The electric force between charges is given by :
[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]
Where
q₁ and q₂ are charges
r is the distance between charges
When each charge is doubled and the distance between them is 1/4 its original magnitude such that,
q₁' = 2q₁, q₂' = 2q₂ and r' = (r/4)
New force,
[tex]F'=\dfrac{kq_1'q_2'}{r'^2}[/tex]
Apply new values,
[tex]F'=\dfrac{k\times 2q_1\times 2q_2}{(\dfrac{r}{4})^2}\\\\=\dfrac{k\times 4q_1q_2}{\dfrac{r^2}{16}}\\\\=64\times \dfrac{kq_1q_2}{r^2}\\\\=64F[/tex]
So, the new force becomes 64 times the initial force.
Caroline uses 20 N of force to move a box of books 10 m. How much work
did she do?
Work = (force) x (distance)
Work = (20 N) x (10 m)
Work = 200 Joules
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If a force of 3000 N can move a crate at an acceleration of 9.2 m/s2, what is the mass of the object?
Answer:
326 kg
Explanation:
m=f/a
3000/9.2=326 kg
A player prefers to make high passes that lift the puck above the ice. Which stick should the
player choose?
Answer:
i dont know
Explanation:
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If a motor is rated at 5.6KW, work done in 20minutes is equal to:
Answer:
given Power= 5.6×1000=5600watt
t=20min=20×60=1200sec. work done=?
P=w/t
w=pt=5600×1200=672×10^4Joule
The amount of work done by the motor is equal to 6.72 Megajoules.
Given the following data:
Time = 20 minutesPower = 5.6 Kilowatt = 5600 Watts.Conversion:
1 minute = 60 seconds20 minutes = [tex]20 \times 60 = 1200[/tex] seconds.To determine the amount of work done by the motor:
Mathematically, the work done by an object with respect to power and time is given by the formula:
[tex]Work\;done = power \times time[/tex]
Substituting the given parameters into the formula, we have;
[tex]Work\;done = 5600 \times 1200[/tex]
Work done = 6,720,000 Joules
Note: 1,000,000 Joules = 1 Megajoules.
Work done = 6.72 Megajoules.
Read more on work done here: https://brainly.com/question/13818347