Anne Kates house is 20c. She had just made a fresh cup of tea (100c). Five minutes after she made her mad scientist nephew came in,stuck a thermometer in the cup and announced that the tea was now only 70c Write the possible equation with asymptotes

Answers

Answer 1

Answer:

The possible equation is; T(t) = 20 + 80·[tex]e^{(-0.094 \cdot t)}[/tex]

The horizontal asymptotes is Lim(t → ∞), T → 20°C

The vertical asymptote is Lim(t → 0) T → 100°C

Step-by-step explanation:

The given parameters are;

The temperature of the house = 20°C

The initial temperature of the tea = 100°C

The temperature of the tea after 5 minutes = 70°C

From Newton's law of cooling, is given as follows;

[tex]T(t) = T_s + (T_0 - T_s) \cdot e^{k \cdot t}[/tex]

[tex]\dfrac{dT}{dt} = -k(T - T_a)[/tex]

Where;

T(t) = The temperature after time, t =

[tex]T_s[/tex] =The room temperature = 20°C

T₀ = The initial temperature of the tea = 100°C

k = Constant

T(5) = 70°C, therefore, we have;

[tex]70 = 20 + (100 - 20) \cdot e^{k \cdot 5}[/tex]

50/80 = [tex]e^{k \cdot 5}[/tex]

5·k = ㏑(5/8)

k = ㏑(5/8)/5 ≈ -0.094

Therefore, the possible equation is given as follows;

T(t) = 20 + 80·[tex]e^{(-0.094 \cdot t)}[/tex]

The asymptotes are Lim(t → ∞), T → 20°C  and Lim(t → 0) T → 100°C


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