Andres buys a new scooter. He goes 8 Km north from the beach. He then
travels 5 Km to the east. Then chases a friend 8 Km north. What distance
did he cover?
What was Andres's displacement?

Answers

Answer 1

Answer:

Distance: 21km

Displacement: ~16.76km


Related Questions

a person walks 750m due north then 250 m due east of the entire walk takes 12 min find the person average velocity​

Answers

Answer:

v = 1.098 m/s

Explanation:

Given that,

A person walks 750m due north then 250 m due east of the entire walk takes 12 min.

We need to find the average velocity of the person.

Displacement,

[tex]d=\sqrt{750^2+250^2} \\\\d=790.56\ m[/tex]

Average velocity = displacement/time

[tex]v=\dfrac{790.56\ m}{12\times 60\ s}\\\\v=1.098\ m/s[/tex]

So, the average velocity of the person is 1.098 m/s.

If the radius of the Earth decreases to one fourth (1/4) its original size, what would your NEW weight become
1. 4 times as much
2.1/4 as much
3.16 times as much
4.1/16 as much

Answers

Answer:

1/4 as much

Explanation:

I don't know the explanation

Newton discovered that sunlight was composed of colors.


True or False

Answers

Answer:

True

Newton's Rainbow. In the 1660s, English physicist and mathematician Isaac Newton began a series of experiments with sunlight and prisms. He demonstrated that clear white light was composed of seven visible colors.

Explanation:

Hope it helps

Two cars approach each other from opposite directions each
with a velocity of 54 km/h. One of the cars emits a note of frequency 480 Hz. What will be the approximate frequency
heard in the other car before they cross each other?

Answers

Answer:524 Hz

Explanation:

Approximate frequency, heard in other car, when two car approaches each other, before they cross each other is 524 Hz.

What is frequency?

Frequency of wave is the number of waves, which is passed thorough a particular point at a unit time.

For the two cars approaching each other the Doppler formula to find the frequency of second car is given as,

[tex]f_2=\dfrac{V_s+V_2}{V_s-V_1}f_1[/tex]

Here, [tex]V_s[/tex] is the speed of the sound.

Two cars approach each other from opposite directions.The velocity of car one is 54 km/h and the velocity of the car two is also 54 km/h.

Convert the unit of velocity of the car as,

[tex]\rm 54km/s=54\times\dfrac{5}{18}m/s\\\rm 54km/s=15m/s[/tex]

As we know that the speed of the sound is 340 m/s and one of the cars emits a note of frequency 480 Hz.

Thus, putting the values in the above formula to find out the frequency heard in the other car before they cross each other as,

[tex]f_2=\dfrac{340+15}{340-15}480\\f_2=524.3\rm Hz[/tex]


The approximate frequency heard in the other car before they cross each other is 524 Hz.

Learn more about the frequency here;

https://brainly.com/question/1436295

11. Find the direction of the Force

Answers

Answer:

We answer that before but I forgot

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