and

Simplify.
13²
pls fast

Given:

The shape of all building blocks is a cube of side 4 cm.

To find:

The volume of six building blocks.

Solution:

Volume of a cube is:

[tex]V=a^3[/tex]

Where, a is the side length of the cube.

Putting [tex]a=4[/tex], we get

[tex]V=(4)^3[/tex]

[tex]V=64[/tex]

It means the volume of each building block is 64 cubic cm.

Now, the volume of six building blocks is

[tex]Volume=6\times V[/tex]

[tex]Volume=6\times 64[/tex]

[tex]Volume=384[/tex]

Therefore, the volume of six building blocks is 384 cubic cm.

Answer:

Step-by-step explanation:

square- 48*32=1536

triangle- .5*12*48= 288

Answer:

Steps:

ALI = 48×12/2 = 48×6 = 288 in²

AIEN = 48×32 = 1536 in²

ALIEN = ALI + AIEN

ALIEN = 288 + 1536

ALIEN = 1824 in²

Answer:

Yes because you would need to divide first before subtracting

Step-by-step explanation:

Answer:

yes, because of PEMDAS

divison always comes before subtraction

Answer:

where is the question

Step-by-step explanation:

chai

Answer:

1) g < -6

2) x < -5

3) f < 2

4) y ≤ -2

5) p ≥ 2

Answer:

option 3, double the height and with of original bottle

The methods which will create the larger water bottle with the intended volume is 1 and IV.

Volume of a three dimensional shape is the space occupied by the shape.

Given that,

A water bottle company is designing a new larger cylindrical water bottle that is intended to hold 4 times as much water as the original cylindrical water bottle.

Volume of a cylindrical shape = π r² h

Let V be the original volume.

If radius is doubled, then the new volume is,

V' = π (2r)² h = 4(π r² h) = 4V

So 1 is an option.

When the height is Quadrupled,

V' = π r² 4h = 4(π r² h) = 4V

Hence the correct options are 1 and IV.

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Answer:

f(x)=x^3-2x^2-5x+6

Step-by-step explanation:

this should be right if it isn't, then you probably wrote it wrong.

Answer:

x^3 - 2x^2 - 5x+ 6

Step-by-step explanation:

Answer:

The area of the polygon is 624.5 square feet.

Step-by-step explanation:

The total area of the figure ([tex]A[/tex]), in square feet, is the sum of the areas of two triangles and a rectangle, that is:

[tex]A = A_{I}+A_{II}+A_{III}[/tex] (1)

Where:

[tex]A_{I}[/tex] - Area of the big triangle, in square feet.

[tex]A_{II}[/tex] - Area of the small triangle, in square feet.

[tex]A_{III}[/tex] - Area of the rectangle, in square feet.

Then, we expand the formula by using all dimensions presented in the image attached:

[tex]A = \frac{1}{2}\cdot (25\,ft)\cdot (33\,ft-8\,ft) + \frac{1}{2}\cdot (8\,ft)\cdot (43\,ft-35\,ft) + (35\,ft)\cdot (8\,ft)[/tex]

[tex]A = 624.5\,ft^{2}[/tex]

The area of the polygon is 624.5 square feet.

Answer:

El valor total de la cuenta después de 5 años es de $3,598.

Step-by-step explanation:

Para encontrar la respuesta, tienes que utilizar la fórmula para encontrar el valor futuro:

VF=VP*(1+i)^n

VF=valor futuro

VP= valor presente=$3000

i=tasa de interés=0.037

n=número de periodos de tiempo=5 años

Ahora, puedes reemplazar los valores en la fórmula:

VF=3,000*(1+0.037)^5

VF=3,000*(1.037)^5

VF=3,598

De acuerdo a esto, la respuesta es que el valor total de la cuenta después de 5 años es de $3,598.

Answer:

∠A = 6x + 4

Step-by-step explanation:

Hello There!

We are given the exterior angle ∠ACD and an interior angle ∠B

If you didn't know this is the rule for exterior angles of a triangle:

An exterior angle is equal to the sum of its opposite interior angles

so ∠ACD = ∠A + ∠B ( ∠A and ∠B being the opposite interior angles)

So with the information that we are given we plug them into their corresponding angle

then we would have

8x+5 = ∠A + 2x + 1

now we solve for A

Well how do we solve for A?

Well we have to isolate the variable

To do so we want to get rid of 2x + 1

We do that by subtract each side by 2x and 1

8x + 5 - (2x + 1 ) = 6x + 4

we're left with

∠A = 6x + 4

Answer:

A

Step-by-step explanation:

is the circumference or perimeter of a cylinder

d=r×r

Answer:

hello

Step-by-step explanation:

yeah

Answer:

F= 42

C= 48

A= 48

B= 132

D= 132

Step-by-step explanation:

Answer:

75 %

Step-by-step explanation:

To solve for the above question,

The percentage of pupils that submitted their project on time

= Number of pupils that submitted their project on time/Number of pupils × 100

Number of pupils that submitted their project on time = 30 pupils

Number of pupils = 40 pupils

= 30/40 × 100

= 75 %

The percent of the pupils that submitted their project on time is 75%

Answer:

I got 270cm!

Hope this helped!

Answer:

The calculated value     t =   2.366 > 2.0301 at 0.05 level of significance

The null hypothesis is rejected

There is a difference between the means      

Step-by-step explanation:

Step(i):-

Given that the first sample size 'n₁' = 22

Given that the mean of the first sample x₁⁻ = 120

Given that the standard deviation of the sample (s₁) = 20

Given that the mean of the second sample x₂⁻ = 100

Given that the standard deviation of the second sample (S₂) = 30

Step(ii):-

T-test statistic

               [tex]t = \frac{x^{-} _{1} -x^{-} _{2} }{\sqrt{S^{2} (\frac{1}{n_{1} }+\frac{1}{n_{2} } ) } }[/tex]

     where

             [tex]S^{2} = \frac{n_{1} S_{1} ^{2}+n_{2} S_{2} ^{2} }{n_{1} +n_{2}-2 }[/tex]

            [tex]S^{2} = \frac{22( 20)^{2}+ 15(30) ^{2} }{22 +15-2 }[/tex]

           S² =  637.1428

           S = √637.1428 = 25.24168  

The standard deviation of the sample 'S' = 25.24168   

Step(iii):-

Null Hypothesis:H₀:

There is no difference between the means

Alternative Hypothesis:H₁:

There is a difference between the means

         T-test statistic

               [tex]t = \frac{x^{-} _{1} -x^{-} _{2} }{\sqrt{S^{2} (\frac{1}{n_{1} }+\frac{1}{n_{2} } ) } }[/tex]

              [tex]t = \frac{ 120 -100 }{\sqrt{637.14 (\frac{1}{22 }+\frac{1}{15 } ) } }[/tex]

             t =   2.366

Degrees of freedom

           γ = n₁+n₂ -2 = 22+15-2 = 35

     t₀.₀₅ = 2.0301

The calculated value     t =   2.366 > 2.0301 at 0.05 level of significance

The null hypothesis is rejected

There is a difference between the means          

The correct test statistic for the test of the hypothesis for the considered situation is 2.2619 approximately.

If the sample sizes < 30, and we want to test the difference between the sample means, then we perform t-test.

Let we have:

Then, the value of t-test statistic is obtained as:

[tex]t = \dfrac{\overline{x}_1 - \overline{x}_2}{\sqrt{\dfrac{s_1^2}{n_1} + \dfrac{s_2^2}{n_2}}}[/tex]

If the level of significance is [tex]\alpha[/tex], then as we have:

the degree of freedom (d.f) = [tex]n_1 + n_2 - 2[/tex],

the critical value of t is found to be [tex]t_{\alpha/2}[/tex] , then if we get:

[tex]|t| < t_{\alpha/2}[/tex] we cannot reject the null hypothesis

and if we get [tex]|t| > t_{\alpha/2}[/tex] , then we may reject the null hypothesis and thus, accept the alternate hypothesis.

For this case, we're specified that:

For sample of stray dogs:

For sample of stray cats:

Thus, the t-test statistic for the difference of mean of these two samples is calculated as:

[tex]t = \dfrac{\overline{x}_1 - \overline{x}_2}{\sqrt{\dfrac{s_1^2}{n_1} + \dfrac{s_2^2}{n_2}}}\\\\t = \dfrac{120-100}{\sqrt{20^2/22 + 30^2/15}} = \dfrac{20}{\sqrt{200/11 + 60}}\\\\\\t \approx 2.2619[/tex]

Thus, the correct test statistic for the test of the hypothesis for the considered situation is 2.2619 approximately.

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Answer:

ok so square 13 cm, and square 4 cm. then you will add those together then take that number and find the square root  plz mark brainliest

Given:

The given data set are:

8,12,14,14,20

8,12,14,14,22

9,13,14,15,19

All of the above

To find:

The set of data that has the highest interquartile range(IQR).

Solution:

We know that, the interquartile range(IQR) of a data set is the difference between the third quartile and first quartile.

[tex]IQR=Q_3-Q_1[/tex]

All the given data set has five values in ascending order. So, the first value is the minimum value, second value is the first quartile, third value is the median, the fourth value is the third quartile and the fifth value is the maximum value.

For 8,12,14,14,20,

[tex]IQR=14-12[/tex]

[tex]IQR=2[/tex]

For 8,12,14,14,22,

[tex]IQR=14-12[/tex]

[tex]IQR=2[/tex]

For 9,13,14,15,19,

[tex]IQR=15-13[/tex]

[tex]IQR=2[/tex]

All interquartile ranges are equal. So, all the data sets has t he highest interquartile range.

Therefore, the correct option is D.

Answer:5

Step-by-step explanation:

the answer is 5 because the mode is the one that has more of

Answer:

Solve for  x  in the first equation.

Subtract  8 y  from both sides of the equation.

2 x = 6 − 8 y

5 x + 20 y = 15

Divide each term by  2  and simplify.

Divide each term in  

2 x /2 =  6/2  − 8 y/2  

5 x + 20 y = 15

Cancel the common factor of  2 .

Cancel the common factor.

2 x /2  =  6 /2  + (− 8 y)/ 2

Step-by-step explanation:

I don't have room to put the rest. So go to math-way

[tex]\sqrt{11}=3.31(appx)[/tex]

3.31 lies b/w 3 and 4

Answer:

[tex]\sqrt{11}[/tex] lies between 3 and 4.

Answer:

1) N^2 + 1

2) 5*N - 9

3) n*5 + 1    (con n entero)

4) n*2 + 1    (con n entero)

Step-by-step explanation:

1)  El cuadrado de un número aumentado en 1.

Podemos definir a N como el número.

El cuadrado de N es:

N^2

Y a esto lo tenemos que aumentar en 1, entonces tenemos:

N^2 + 1

Esto es el cuadrado de un número aumentado en 1.

2)  Cinco veces un número menos 8.

Esto es:

5*N  (5 veces un número)

Y a esto le restamos 8, para obtener:

5*N - 8

3) El número siguiente a un múltiplo de 5

Un multiplo de 5 se escribe como:

n*5

Donde n es un número entero.

El numero siguiente es:

n*5 + 1

4) Un número impar.

Bien, sabemos que un número par es un multiplo de 2.

Entonces:

n*2 es un número par.

Entonces, n*2 + 1 tiene que ser un numero impar.

En este caso la expresión algebraica es:

n*2 + 1

Answer: 53 degrees

Step-by-step explanation:

Complementary angles add up to 90 degrees. Subtract Za from the 90. 90-37=53.

Answer:

the answer is c

Step-by-step explanation:

36x36 + 36x60

=3456 and add squared

Answer:

164

Step-by-step explanation: