An office clerk earns $120 for two 4-hour work shifts. How much will she earn
for 15 hours of work?

Answer:

1

Step-by-step explanation:

(3,3) has a positive x value and a positive y value which means it is in the first quadrant

The probability that she will obtain a scholarship given that she is accepted by the college is 0.54.

Given that the probability that Samantha will be accepted by the college of her choice and obtain a scholarship is 0.35, to determine, if the probability that she is accepted by the college is 0.65, the probability that she will obtain a scholarship given that she is accepted by the college, the following calculation must be performed:

Therefore, the probability that she will obtain a scholarship given that she is accepted by the college is 0.54.

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Answer:

-4d

Step-by-step explanation:

L.c.m=15

15×2/5(d-10)-2/3×15(d+6)

3×2(d-10)-2×5(d+6)

6(d-10)-10(d+6)

6d-60-10d-60

6d-10d-60-60

-4d-0

-4d

Answer:

4x/y¹¹

Step-by-step explanation:

1) take out constants

40/10 * x⁻⁴y⁻⁶/x⁻⁵y⁵

2) simplify 40/10 to 4

4 * x⁻⁴y⁻⁶/x⁻⁵y⁵

3) Use Quotient Rule: xᵃ/xᵇ=xᵃ⁻ᵇ

4x⁻⁴⁺⁵y⁻⁶⁻⁵

4) Simplify -4 + 5 to 1

4x¹y⁻⁶⁻⁵

5) simplify -6-5 to -11

4x¹y⁻¹¹

6) use rule of one: ₓ¹=ₓ

4xy⁻¹¹

7) use negative power rule: x⁻ᵃ=1/xᵃ

4x * 1/y¹¹

8) simplify

4x/y¹¹

Answer:

Molly played 4 games

Answer:

An amusement park studied methods

Step-by-step explanation:

Answer: 1 1/2 x 4 4/7

= 3/2 x 32/7

= 96/14

Step-by-step explanation:

1. Write the whole number as a fraction with a denominator of 1.

2. Multiply the numerators.

3. Multiply the denominators

4. Simplify. If needed, if your answer is greater than 1, you may want to write your answer as a mixed number.

Answer:

Rate of change of length of shadow is [tex]\frac{15}{7} ft/s[/tex]

Step-by-step explanation:

Consider the figure

We have

[tex]\begin{aligned}&\frac{d x}{d t}=\text { rate of person walking } \\&\frac{d y}{d t}=\text { rate of change of shadow length } \\&\frac{d x}{d t}+\frac{d y}{d t}=\text { rate of change of tip of shadow }\end{aligned}[/tex]

[tex]\begin{aligned}&\frac{6}{20}=\frac{y}{x+y} \\&6(x+y)=20 y \\&6 x+6 y=20 y \\&6 x=14 y\end{aligned}[/tex]

[tex]6\left(\frac{d x}{d t}\right)=14\left(\frac{d y}{d t}\right)\\\\6(5)=14\left(\frac{d y}{d t}\right)\\\\\frac{30}{14}=\frac{d y}{d t}\\\\\frac{15}{7}=\frac{d y}{d t}\\\\[/tex]

Rate of change of length of shadow is [tex]\frac{15}{7} ft/s[/tex]

Answer: y = mx + b is the slope intercept form of writing the equation of a straight line

Step-by-step explanation:

Answer:

Step-by-step explanation:

, y=mx+b, of linear equations, emphasizes the slope and the y-intercept of the line.

Answer:

Let x be the number of dimes and y the number of quarters

x +y = 100

a dime is $0.10 and a quarter is $0.25

0.1x + 0.25y = 21.40 multiply by 100 to remove the decimals

10x + 25y = 2140, From the first equation y = 100 - x and plug it in to the second equation.

10x + 25(100 -x) = 2140

10x + 2500 - 25x =2140

2500 - 15x = 2140

360 = 15x x = 24 and y = 76

There are 24 dimes and 76 quarters

Answer:

76 Quarters = $19.00

24 Dimes = $2.40

$19.00 + $2.40 = $21.40

Step-by-step explanation:

Yaga

Answer:

389

Step-by-step explanation:

MARK BRAINLIEST PLEASE

Answer: 1 =.43, 2=.26, 3=.16 4=.33

Step-by-step explanation: So to find all these answers we have to know the total number of people in the chart 30. Then we have to find what info we need from the chart and divide it by the total number of people. I hope this helped I tried to make it simple.

By knowing that S is bisected by the line shown, we will conclude that PD = 8

So here we know that PC = 8, we also can see that:

Notice that because the blue line bisects S, the angle at "S" on both of these right triangles is the same, and because both of these are right triangles, both must have a 90° angle.

Finally, if two angles are equal, then the 3 angles must be equal between these two triangles.

And notice that both of these triangles share one side, then:

Triangles we know for sure that triangles PCS and PDS have the same angles and one equal side.

This implies that the triangles are congruent, thus, the measures of the corresponding sides must be the same.

Then the length of the shorter side of both triangles must be the same, in triangle PCS the short leg measures 8 units, then in triangle PDS the short leg, PD, also must measure 8 units.

So you are correct.

If you want to learn more about congruent triangles, you can read:

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Answer:

66n-31m

Step-by-step explanation:

26n-7m+4(10n-6m)

26n-7m+40n-24m

66n-31m

Answer:

Cardiovascular system

Step-by-step explanation:

We have: [tex](-\frac{15}{18})[/tex] ÷ [tex](-\frac{20}{24})[/tex] = [tex]\frac{-15}{18} .\frac{-24}{20} = \frac{(-3)(5).(-4)(6)}{(3)(6).(4)(5)} = 1[/tex]

ANSWER: 1

ok done. Thank to me :>

Answer:

1

Step-by-step explanation:

[tex]( - \frac{15}{18} ) \div ( - \frac{20}{24} ) \\ now \: you \: have \: fraction \: divided \: by \: fraction \: then \: do \: reciprocal \: \\ ( - \frac{15}{18} ) \times ( - \frac{24}{20} ) \\ = 1[/tex]

Answer:

Since the logarithmic function is define for ×>-3,thus,the graph has a vertical asymptote at ×=-3.

Answer:

Option A: [tex]\{0,\frac{\pi}{2},\frac{3\pi}{2}\}[/tex]

Step-by-step explanation:

[tex]sin^2(\theta)=2sin^2(\frac{\theta}{2}), [0,2\pi)[/tex]

[tex]sin^2(\theta)=2sin^2(\frac{\theta}{2})[/tex]

[tex]sin^2(\theta)=2sin(\frac{\theta}{2})sin(\frac{\theta}{2})[/tex]

[tex]sin^2(\theta)=2(\sqrt{\frac{1-cos(\theta)}{2}})(\sqrt{\frac{1-cos(\theta)}{2}})[/tex]

[tex]sin^2(\theta)=2(\frac{1-cos(\theta)}{2})[/tex]

[tex]sin^2(\theta)=\frac{2-2cos(\theta)}{2}[/tex]

[tex]sin^2(\theta)=1-cos(\theta)[/tex]

[tex]1-cos^2(\theta)=1-cos(\theta)[/tex]

[tex]-cos^2(\theta)=-cos(\theta)[/tex]

[tex]cos^2(\theta)=cos(\theta)[/tex]

[tex]cos^2(\theta)-cos(\theta)=0[/tex]

[tex]cos(\theta)[cos(\theta)-1]=0[/tex]

[tex]cos(\theta)=0[/tex]

[tex]\theta=\frac{\pi}{2},\frac{3\pi}{2}[/tex]

[tex]cos(\theta)-1=0[/tex]

[tex]cos(\theta)=1[/tex]

[tex]\theta=0[/tex]

Therefore, the solutions contained within the interval are [tex]\{0,\frac{\pi}{2},\frac{3\pi}{2}\}[/tex]

Helpful Tips:

Half-Angle Formula: [tex]sin(\frac{\theta}{2})=\pm\sqrt{\frac{1-cos(\theta)}{2}}[/tex]

Pythagorean Identity: [tex]sin^2(\theta)+cos^2(\theta)=1,sin^2(\theta)=1-cos^2(\theta),cos^2(\theta)=1-sin^2(\theta)[/tex]

[tex]\sin^2 \theta = 2 \sin^2 \left(\dfrac{\theta}2 \right)\\\\\implies \sin^2 \theta = 1- \cos 2 \cdot \dfrac{\theta}2\\\\\implies \sin^2 \theta = 1- \cos \theta \\\\\implies 1-\cos^2 \theta = 1 - \cos \theta \\\\\implies -\cos^2 \theta - \cos \theta = 0\\\\\implies \cos^2 \theta - \cos \theta = 0\\\\\implies \cos \theta( \cos \theta -1) = 0\\\\\\\text{Now,}\\\\\cos \theta = 0\\\\\implies \theta = n\pi + \dfrac{\pi}2\\\\\text{For n = 0,1 and}~ [0.2\pi)\\\\[/tex]

[tex]\theta = \dfrac{\pi}2, \dfrac{3\pi}2[/tex]

[tex]\text{Again,} \\\\\cos \theta -1= 0\\\\\implies \cos \theta = 1\\\\\implies \theta = 2n\pi\\\\\text{For n= 0 and}~ [0,2\pi)\\\\\theta = 0\\\\\text{Combine solutions,}\\\\\theta = 0, \dfrac{\pi}2, \dfrac{3\pi}2[/tex]

[tex]\stackrel{\textit{reciprocal ident.}}{csc(\theta)=\cfrac{1}{sin(\theta)}} ~\hfill \stackrel{\textit{symmetry ident.}}{sin(-\theta )=-sin(\theta)}~\hfill \begin{array}{llll} \stackrel{\textit{pythagorean ident.}}{sin^2(\theta)+cos^2(\theta)=1}\\ sin^2(\theta)=1-cos^2(\theta)\\ cos^2(\theta)=1-sin^2(\theta) \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}[/tex]

[tex]\cfrac{csc^2(-x)-1}{1-cos^2(-x)}\implies \cfrac{~~\frac{1}{sin^2(-x)}-1~~}{sin^2(-x)}\implies \cfrac{~~ \frac{1-sin^2(-x)}{sin^2(-x)}~~}{\frac{sin^2(-x)}{1}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{keeping in mind that}~\hfill }{sin^2(-x)\implies [sin(-x)]^2\implies [-sin(x)]^2\implies [sin(x)]^2\implies sin^2(x)} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\cfrac{~~ \frac{1-sin^2(x)}{sin^2(x)}~~}{\frac{sin^2(x)}{1}}\implies \cfrac{1-sin^2(x)}{sin^2(x)}\cdot \cfrac{1}{sin^2(x)}\implies \cfrac{cos^2(x)}{sin^2(x)}\cdot \cfrac{1}{sin^2(x)} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill cot^2(x)csc^2(x)~\hfill[/tex]

Answer:

b = 14

Step-by-step explanation:

Since both angles are diagonal each other, they are equal to each other.

5b = b + 56

-b      -b           (subtract b from both sides)

4b = 56

4       4            (divide both sides by 4 to solve for b)

 b = 14

Answer:

1. The cost of the fencing material for each side of the playground.

2. The perimeter of the park

3. The labor fee

4. The cost of the fencing material for the whole park.

Step-by-step explanation:

Hope this helps! :)

Answer:

19 dollars.

Step-by-step explanation:

0.20 x $95.00=$19.00.

Answer:

Step-by-step explanation:

let X be the quantity of 100% acid

let Y be the quantity of  10% acid

X + Y = 90

Y = 90 - X

         X(100) + Y(10) = 90(81)

X(100) + (90 - X)(10) = 90(81)

   100X + 900 - 10X = 7290

                         90X = 6390

                              X = 71 L

Therefore, the probability that at least 5 out of 100 women aged 60 to 64 who get the flu vaccine will die within the next year is 0.0000000059049%, making the event absolutely unusual.

Given that a group of 100 women aged 60-64 got a new flu vaccine in 2004, and 5 of them died the following year, to determine if this event is unusual, and specifically, how likely is it that at least 5 out of 100 women aged 60 to 64 who get the flu vaccine will die within the next year knowing that the chance of dying of a woman aged 60-64 getting a new flu vaccine in the next five years is 0.009, the following calculation must be performed:

Therefore, the probability that at least 5 out of 100 women aged 60 to 64 who get the flu vaccine will die within the next year is 0.0000000059049%, making the event absolutely unusual.

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Answer:

I believe it is f(2) = 12

Step-by-step explanation:

I don't know if the * symbol is supposed to be an x but if it is, it would be 12x instead of 12.

The recipe calls for 2 cups of flour. The double of this amount is :

[tex]\mathfrak{2*2} [/tex]

[tex]\underline{\mathfrak{=4}} [/tex]

If Ivan has 5 cups, then :

[tex]\mathfrak{5-4} [/tex]

[tex]\underline{\mathfrak{=1}} [/tex]

So, O A. Ivan has 1 cup of flour more than he needs.

[tex]\mathbb{MIREU} [/tex]

Answer:

Expression D

Step-by-step explanation:

all other answers are above 15! hope this helps :D