Answer: C. The change in momentum is zero.
Explanation: When an object is in movement, to change its direction or speed we have to applied a force for determine amount of time. This change is called Change in Momentum or Impulse.
Change in momentum is a derivation of Newton's Second Law and can written as
[tex]F.t=m.\Delta v[/tex]
So, for the case discussed, object of mass 5kg already has momentum because it is already in motion. When another object collides with, applying a force for an interval of time, there is a change in momentum for the first object. Since the object stopped, it means velocity is 0, so as it is described in the formula, change in momentum is also 0.
In conclusion, "The change in momentum is zero" is the best prediction.
A 2.0 kg block of ice with a speed of 8.0 m/s makes an elastic collision with another block of ice that is at rest. The first block of ice proceeds in the same direction as it did initially, but with a speed of 2.0 m/s. What is the mass of the second block? (Hint: Use the conservation of kinetic energy to solve for the second unknown variable.)
Answer:
6kg
Explanation:
According to conservation of kinetic energy
m1u1+m2u2 = (m1+m2)v
m1 and m2 are the masses of the bodies
u1 and u2 are the initial velocities
v is the final velocity
Given
m1 =2kg
u1 = 8.0m/s
m2 = ?
u2 = 0m/s (second ice at rest)
v = 2.0m/s
Substitute into the formula
2(8)+m2(0) = (2+m2)(2)
16+0 = 4+2m2
16-4= 2m2
12 = 2m2
m2 =12/2
m2 = 6kg
Hence the mass of the second block is 6kg
If 86 W is produced in 18 seconds, how much work is done?
Answer:86 parts = x + (x * 1.15)
86 = 2.15x
x = 40 parts and 1.15x = 46 parts
Explanation:
Forces have ________________________ and are expressed in ________________.
Answer:
Forces have strength and direction and are expressed in Newtons
A 53.5-g Super Ball traveling at 27.5 m/s bounces off a brick wall and rebounds at 21.5 m/s. A high-speed camera records this event. If the ball is in contact with the wall for 4.05 ms, what is the magnitude of the average acceleration of the ball during this time interval
Answer:
12,098.77m/s²Explanation:
Acceleration is the rate of change of velocity of a body. It is expressed as;
acceleration = change in velocity/time
acceleration a = v-u/t
Given
v = 27.5m/s
u = -21.5m/s (rebounds in the opposite direction)
time t = 4.05ms = 0.00405secs
Required
acceleration
Substitute the given values into the formula
a = 27.5-(-21.5)/0.00405
a = 27.5+21.5/0.00405
a = 49/0.00405
a = 12,098.77m/s²
Hence the magnitude of the average acceleration of the ball during this time interval is 12,098.77m/s²
A heat engine cycle is executed with steam in the saturation dome. The pressure of steam is 1.1 MPa during heat addition and 0.3 MPa during heat rejection. The highest possible efficiency of this heat engine is:
Answer:The highest possible efficiency of this heat engine is 11%
Explanation:
Saturated water temperature at P1, Pressure in Heat addition,
1.1 MPa=185°C +273= 458K
Saturated water temperature at P2, Pressure in Heat rejection,
0.3MPa=133.5°C+ 273=406.5K
The highest possible efficiency of any heat engine is the Carnot efficiency given as
Carnot efficiency, ηmax = 1- (T2/ T1)
1- (406.5K/458K)
1-0.88755=0.112
=11%
The pressure exerted by a liquid column of depth 0.5 m on the base of its
container is 5000 Nm Find the density of the liquid
e Density of water is 1000 kg/m". What will be the volume of 35000 kg water?
Answer:
1020.4kg/m³
35m³
Explanation:
Given parameters:
Depth = 0.5m
Pressure exerted = 5000N/m²
Unknown = density of the liquid = ?
Solution:
To find the density of this unknown liquid, we use the expression below:
Pressure of liquid = density x height x acceleration due to gravity
5000 = density x 0.5 x 9.8
Density = 1020.4kg/m³
B.
Density of water = 1000kg/m³
Mass of water = 35000kg
Unknown:
Volume of water = ?
Solution:
The volume of water can be derived from the expression below:
Volume = [tex]\frac{mass}{density}[/tex]
Volume = [tex]\frac{35000}{1000}[/tex] = 35m³
A Shaolin monk of mass 60 kg is able to do a ‘finger stand’: he supports his whole weight on his two index fingers, giving him a total contact area of 4 cm 2 with the ground. Calculate the pressure he exerts on the ground (include units), and write your answer to two significant figures.
Answer:
1500000 Pa
Explanation:
The formula for pressure is force per unit area.
P=F/A where F is force and A is area
Given that ;
F= mass * acceleration due to gravity
F= 60 * 9.81 = 588.6 = 589 N
A= area = 4cm² = 0.0004 m²
P= F/A = 589 / 0.0004
P= 1471500
P=1500000 Pa
If a car takes a banked curve at less than the ideal speed, friction is needed to keep it from sliding toward the inside of the curve (a real problem on icy mountain roads). (a) Calculate the ideal speed to take a 100 m radius curve banked at 15.0o. (b) What is the minimum coefficient of friction needed for a frightened dri
Answer:
a) The ideal speed = 16.21 m/s
b) Minimum co-efficient of friction = 0.216
Explanation:
From the given information:
The ideal speed can be determined by considering the centrifugal force component and the gravity component.
[tex]\dfrac{mv^2}{r}cos \theta = mg sin \theta[/tex]
[tex]v = \sqrt {gr \ tan \theta}[/tex]
[tex]= \sqrt{(9.8 \ m/s^2) (100) \ tan 15^0}[/tex]
= 16.21 m/s
(b)
Let assume that it requires 25 km/h to take the same curve.
Then, using the equilibrium conditions;
[tex]mg \ sin \theta = \dfrac{mv^2}{r} cos \theta + \mu ((\dfrac{mv^2}{r}) sin \theta + mg cos \theta)[/tex]
[tex]\mu = \dfrac{mg sin \theta - \dfrac{mv^2}{r} cos \theta }{((\dfrac{mv^2}{r}) sin \theta + mg cos \theta) }[/tex]
[tex]\mu = \dfrac{g sin \theta - \dfrac{ v^2}{r} cos \theta }{((\dfrac{v^2}{r}) sin \theta + g cos \theta) }[/tex]
[tex]\mu = \dfrac{(9.8 \ m/s^2 ) sin (15^0) - \dfrac{ \dfrac{(25 \times 10^3}{3600} \ m/s)^2 }{100 \ m } cos (15^0) }{((\dfrac{(\dfrac{25 \times 10^3}{3600} )^2}{100}) sin 15^0 + (9.8 \ m/s^2) cos 15^0 ) }[/tex]
[tex]\mathbf{\mu = 0.216}[/tex]
Set the radius to 2.0 m and the velocity to 1.0 m/s. Keeping the radius the same, record the magnitude of centripetal acceleration for each given velocity. Include units.
Answer:
[tex]a=4\ m/s^2[/tex]
Explanation:
Given that,
Radius, r = 2 m
Velocity, v = 1 m/s
We need to find the magnitude of the centripetal acceleration. The formula for the centripetal acceleration is given by :
[tex]a=\dfrac{v^2}{r}\\\\a=\dfrac{(2)^2}{1}\\\\=4\ m/s^2[/tex]
So, the magnitude of centripetal acceleration is [tex]4\ m/s^2[/tex].
Suppose the posted designated speed for a highway ramp is to be 30 mph and the radius of the curve is 700 ft. At what angle must the curve be banked? No Friction
Answer:
4.92°
Explanation:
The banking angle θ = tan⁻¹(v²/rg) where v = designated speed of ramp = 30 mph = 30 × 1609 m/3600 s = 13.41 m/s, r = radius of curve = 700 ft = 700 × 0.3048 m = 213.36 m and g = acceleration due to gravity = 9.8 m/s²
Substituting the variables into the equation, we have
θ = tan⁻¹(v²/rg)
= tan⁻¹((13.41 m/s)²/[213.36 m × 9.8 m/s²])
= tan⁻¹((179.8281 m²/s)²/[2090.928 m²/s²])
= tan⁻¹(0.086)
= 4.92°
Two force vectors are oriented such that the angle between their directions is 46 degrees and they have the same magnitude. If their magnitudes are 2.81 newtons, then what is the magnitude of their sum
Answer:
F = 5.17 N
Explanation:
If we know the magnitudes of both vectors, and the angle between them, we can find the magnitude of their sum, applying the cosine theorem, as follows:[tex]F =\sqrt{F_{1} ^{2} +F_{2} ^{2} + 2*F_{1} * F_{2} * cos \theta} (1)[/tex]
Replacing by the givens, F₁ = F₂ = 2.81 N, θ = 46º, we get:[tex]F =\sqrt{2.81 N ^{2} +2.81 N ^{2} + 2*2.81N* 2.81N* cos 46} = 5.17 N (2)[/tex]
1. Amy uses 30N of force to push a lawn mower 10 meters. How much work does she do?
Determine the gravitational field of Earth at a height 2.88 x 10^8 m above its surface (the height of the moon above Earth). Earth's mass is 6.0 x 10^24 kg and its radius is 6.4 x 10^6 m.
Answer:
12
Explanation:
Need help asap please......
Answer:
The Answer is A. The slope is upward.
Explanation:
Answer:
Im pretty sure it is A!
Explanation:
It is A because the velocity is increasing, and acceleration is positive, plz mark as brainliest if correct!
100 POINTS. PLEASE EXPLAIN
Answer:
Explanation:
Note the charge balls on the top and bottom row are identical. So those charges cancel each other out. The only charges in the net electric field are the two in the middle row.
Electric field strength = k*Q/r^2
= (8.99 *10^9) * (3-(-3)) * 5*10^(-6) / (2*0.5)^2
= 269700 N/C
Answer:
Explanation:
(b) cuz the 1st n 3nd row cancel out, net electric field will go from +3Q to -3Q. the direction is right.
help it’s actually physical science but plz help
Chemical energy is the stored form of chemical bonds containing combinations of which elements? Select THREE (3) elements. *
Carbon
Nitrogen
Helium
Hydrogen
Oxygen
Gold
An inventor claims to have developed a resistance heater that supplies 1.2 kWh of energy to a room for each kWh of electricity it consumes. Is this a reasonable claim, or is it true that the inventor has developed a perpetual-motion machine
Answer:
if we are to go by the first law of thermodynamics, the Inventors claims are not reasonable.
The inventor has developed a perpetual-motion machine { any device that violates the first law of thermodynamics}
Explanation:
Given that;
energy supplied to a room Qh= 1.2 kWh
for each for each kWh of electricity it consumes, i.e work input W = 1 kWh
W know that; the first law of thermodynamics says energy can neither be created nor destroyed but can flow from one body to another;
which means ∑Q should or must be equal to ∑W; ∑Q = ∑W
but in the given system; Qh⇒1.2 kWh is NOT equal to W⇒1 kWh
i.e Qh⇒1.2 kWh ≠ W⇒1 kWh
which simply means his device create energy and that violate the first law of thermodynamics.
Therefore, if we are to go by the first law of thermodynamics, the Inventors claims are not reasonable.
The inventor has developed a perpetual-motion machine { any device that violates the first law of thermodynamics}
A physics grad student has a machine that measures how
many electrons are whizzing through a ring. If she measures 2
Coulombs of charge flowing through the ring every second,
what is the current passing through the ring?
1 = _A
Answer:
2A
Explanation:
Given parameter:
Quantity of charge = 2C
Time taken = 1s
Unknown:
The current passing through the ring = ?
Solution:
Current can also be defined as the quantity of charge that passes through a conductor per unit of time:
I = [tex]\frac{q}{t}[/tex]
So;
I = [tex]\frac{2}{1}[/tex] = 2A
A jumbo egg (80 grams) is dropped from a height of 15 meters onto a 1 inch of foam. Using kinematics, determine the velocity of the egg the instant before impact.
Answer:
the velocity of the egg the instant before impact is 17.15 m/s.
Explanation:
Given;
mass of the egg, m = 80 g = 0.08 kg
height through which the egg was dropped, h = 15 m
The velocity of the egg before impact will be maximum, and the final velocity is given by the following kinematic equation;
v² = u² + 2gh
where;
u is the initial velocity of the egg = 0
v is the final velocity of the egg before impact
v² = 0 + 2 x 9.8 x 15
v² = 294
v = √294
v = 17.15 m/s
Therefore, the velocity of the egg the instant before impact is 17.15 m/s.
_3) Which of the following is the unit for forces?
What is the wavelength of a wave that has a speed of 350 meters second and a frequency of 140 hert??
Wavelength is the distance between identical points (adjacent crests) in the adjacent cycles of a waveform signal propagated in space or along a wire. In wireless systems, this length is usually specified in meters (m), centimeters (cm) or millimeters (mm).
Hope this helped
The temperature in Edinburgh falls by 2°C.
c) What is the new temperature in Edinburgh?
Answer:
E-2 E is Edinburgh
Explanation:
3. Explain why it is, regardless of the location, at a certain distance between the two points, you will perceive the two points as a single point rather than as two distinct points.
Answer:
Hello your question is missing some parts attached below is the missing part of your question
answer: many primary sensory Neurons will converge and become a single Neuron and the single Neuron will send a single harmonized signal to the Brain.
Explanation:
The reason regardless of the location that will make you perceive the two points as a single point rather than as two distinct points is that many primary sensory Neurons will converge and become a single Neuron and the single Neuron will send a single harmonized signal to the Brain.
A toy car, mass of 0.025 kg, is traveling on a horizontal track with a velocity of 5 m/s. If
the track then starts to climb upwards, how high up the track can the car reach?
Answer:
1.25 m
Explanation:
This is the vertical height not the distance along the slope.
[tex]K=U\\\frac{1}{2}mv^{2} = mgh\\h = \frac{v^{2}}{2g}=\frac{25}{20}=1.25 m[/tex]
The height the car can reach if the the track starts to climb upwards is 1.2742 meters up.
What is kinetic and potential energy?Kinetic energy is energy possessed by a body by virtue of its movement. Potential energy is the energy possessed by a body by virtue of its position or its relation with its surrounding systems.
P.E. = mass × g × height
K.E. = 0.5 × mass × (velocity)²
Given that the toy car has a mass of 0.025 kg and is traveling on a horizontal track with a velocity of 5 m/s. Now, the car starts to climb up vertically, therefore, the kinetic energy will be converted to potential energy.
Kinetic Energy = Potential Energy
0.5 × mass × (velocity)² = mass × g × height
Cancel mass from both the sides,
0.5 × (velocity)² = g × height
0.5 × (5 m/s)² = 9.81 m/sec² × height
height = 1.2742 meters
Hence, the car will travel 1.2742 meters up.
Learn more about Kinetic and Potential Energy here:
https://brainly.com/question/15764612
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A 15 Kilogram anvil is hung from a ceiling . While it is hanging there , it has been determined to have 65 Joules of gravitational potential energy relative to the floor . If the anvil is released , what would be its speed just before it hits the floor ?
Answer:
v = 2.94 m/s
Explanation:
Given that,
Mass of anvil, m = 15 kg
The gravitational potential energy relative to the floor, P = 65 J
We need to find the speed just before it hits the floor when the Anvil is released. Let it is v.
We can use the conservation of energy.
[tex]\dfrac{1}{2}mv^2=mgh\\\\65=\dfrac{1}{2}mv^2\\\\v=\sqrt{\dfrac{65\times 2}{15}} \\\\v=2.94\ m/s[/tex]
So, the required speed is 2.94 m/s.
Uri looks through a telescope for two stars. He knows that both stars have the same absolute brightness and that the second star is twice as far from Earth as the first star. How bright will the second star appear compared to the first star? SC.8.E.5.5
A. It will appear brighter than the first star.
B. It will appear dimmer than the first star.
C. It will appear as bright as the first star.
D. It will appear redder then the first star.
Answer:
b
Explanation:
Which two of the following involve the same energy transfer. Assume that the same substance and the same mass is involved in all four processes.
a. melting
b. evaporation
c. sublimation
d. condensation
A Shaolin monk of mass 60 kg is able to do a ‘finger stand’: he supports his whole weight on his two index fingers, giving him a total contact area of 4 cm 2 with the ground. Calculate the pressure he exerts on the ground (include units), and write your answer to two significant figures.
Answer:
P = 1471500 [Pa]
Explanation:
We must remember that pressure is defined as the relationship between Force over the area.
[tex]P=F/A[/tex]
where:
P = pressure [Pa] (units of pascals)
F = force [N] (units of Newtons)
A = area of contact = 4 [cm²]
But first we must convert from cm² to m²
[tex]A = 4[cm^{2}]*\frac{1^{2} m^{2} }{100^{2} cm^{2} }[/tex]
A = 0.0004 [m²]
Also, the weight should be calculated as follows:
[tex]w = m*g[/tex]
where:
m = mass = 60 [kg]
g = gravity acceleration = 9.81 [m/s²]
Now replacing:
[tex]w = 60*9.81\\w = 588.6[N][/tex]
And the pressure:
[tex]P=588.6/0.0004\\P=1471500 [Pa][/tex]
Because 1 [Pa] = 1 [N/m²]
A person throws a 10kg rock straight up. If the person exerted 3500N of force on the rock over a distance
of 0.5m, how high does the rock move?
Pls help and can you tell me the energy conversions too!!
Answer:
h = 17.83[m]
Explanation:
By means of the working equation which is equal to the product of force by distance, we can find the energy printed at the launch.
[tex]W=F*d[/tex]
where:
W = work [J]
F = force = 3500 [N]
d = distance = 0.5 [m]
Now replacing:
[tex]W= 3500*0.5\\W=1750[J][/tex]
Now, this same work is converted to kinetic energy, necessary for the body to move with an initial velocity. And by energy conservation, we can say that kinetic energy is transformed into potential energy. That is, the kinetic energy will be equal to the potential energy.
[tex]W=E_{kin}=E_{pot}[/tex]
where:
Ekin = kinetic energy [J]
Epot = potential energy [J]
Therefore:
[tex]1750 = m*g*h\\1750=10*9.81*h\\h = 17.83[m][/tex]